sql order by best matched results from one specific where clause - sql

Question

Hi I'm using sql server 2008 and have a big stored procedure which has multiple where clauses. Within one of those clause I have the following:
WHERE clause1
AND (clause2)
AND (clause3)
AND (clause4)
AND (clause5)
AND (clause6)
AND ( COL1 LIKE '%' + #VARIABLE + '%' OR COL2 LIKE '%' + #VARIABLE + '%')
I'm looking to show results in an order, whereby I get the results where BOTH matched in clause 7 first, followed by if one matched. Is this possible? I've tried a few things but nothing has worked so far. E.g:
SELECT
BLAH BLAH
FROM MULTIPLE TABLE JOINS
WHERE clause1
AND (clause2)
AND (clause3)
AND (clause4)
AND (clause5)
AND (clause6)
AND ( COL1 LIKE '%' + #VARIABLE + '%' OR COL2 LIKE '%' + #VARIABLE + '%')
ORDER BY
(CASE WHEN COL1 LIKE '%'+ #VARIABLE + '%' AND COL2 LIKE '%' + #VARIABLE + '%' THEN 1 ELSE 0 END) DESC
and
SELECT BLAH BLAH, (case when COL1 LIKE '%'+ #VARIABLE + '%' then 1 else 0 end) +
(case when COL2 LIKE '%'+ #VARIABLE + '%' then 1 else 0 end) as [priority]
FROM MULTIPLE TABLE JOINS
WHERE clause1
AND (clause2)
AND (clause3)
AND (clause4)
AND (clause5)
AND (clause6)
AND ( COL1 LIKE '%' + #VARIABLE + '%' OR COL2 LIKE '%' + #VARIABLE + '%')
ORDER BY [Priority]
And a few more but nothing has worked...

Answer 1

Your first query is ordering based on your condition:
CASE WHEN COL1 LIKE '%'+ #VARIABLE + '%' AND COL2 LIKE '%' + #VARIABLE + '%' THEN 1 ELSE 0 END
But it's redundant with your WHERE clause:
COL1 LIKE '%'+ #VARIABLE + '%' AND COL2 LIKE '%' + #VARIABLE + '%'
Add the CASE statement from your ORDER BY to your SELECT and you'll see it's 1 for every row, so the ORDER BY is working as it should, it just has no impact since all records are being ordered by 1, you need to alter the ORDER BY criteria, if you give additional detail about how you want it ordered someone can surely help.