Starting with this sample text:
-- Search for relevant Title, second half of the screen, under "Context Field Values" lists the main parts of the Flexfield
-- This lists the bits users see in Core Applications when they click into the DFF plus shows if there is a LOV linked to the field
-- It's a test
-- So is this
SELECT fat.application_name
, fdfv.title
, fdfv.application_table_name
How can I use a RegEx in Notepad++ to find any lines starting with -- and containing a single speech mark '?, so that only this line is returned:
-- It's a test
I tried a silly amount of things, such as:
[^--']
[^--*']
[*--*']
--[']
[--][']
[']
^--[']
^--*\'*
^--*'*
But as you can see, I'm not too clever!
You may use this regex to match a line starting with -- containing only a single ':
^\s*--[^'\r\n]*'[^'\r\n]*$
Make sure to keep MULTILINE mode on since we are using anchor ^.
RegEx Demo
RegEx Breakup:
^: Start
\s*: Match 0 or more whitespaces
--: Match --
[^'\r\n]*: Match 0 or more of any char that is not ' and not a line break
': Match a '
[^'\r\n]*: Match 0 or more of any char that is not ' and not a line break
$: End
Ctrl+F
Find what: ^--.*'.*$
TICK Wrap around
SELECT Regular expression
UNTICK . matches newline
Find All in Current Document
Explanation:
^ # beginning of line
-- # 2 dashes
.* # 0 or more any character but newline
' # a single quote
.* # 0 or more any character but newline
$ # end of line
Screenshot:
I'm trying to replace newline etc kind of values using regexp_replace. But when I open the result in query result window, I can still see the new lines in the text. Even when I copy the result, I can see new line characters. See output for example, I just copied from the result.
Below is my query
select regexp_replace('abc123
/n
CHAR(10)
头疼,'||CHR(10)||'allo','[^[:alpha:][:digit:][ \t]]','') from dual;
/ I just kept for testing characters.
Output:
abc123
/n
CHAR(10)
头疼,
allo
How to remove the new lines from the text?
Expected output:
abc123 /nCHAR(10)头疼,allo
There are two mistakes in your code. One of them causes the issue you noticed.
First, in a bracket expression, in Oracle regular expressions (which follow the POSIX standard), there are no escape sequences. You probably meant \t as escape sequence for tab - within the bracket expression. (Note also that in Oracle regular expressions, there are no escape sequences like \t and \n anyway. If you must preserve tabs, it can be done, but not like that.)
Second, regardless of this, you include two character classes, [:alpha:] and [:digit:], and also [ \t] in the (negated) bracket expression. The last one is not a character class, so the [ as well as the space, the backslash and the letter t are interpreted as literal characters - they stand in for themselves. The closing bracket, on the other hand, has special meaning. The first of your two closing brackets is interpreted as the end of the bracket expression; and the second closing bracket is interpreted as being an additional, literal character that must be matched! Since there is no such literal closing bracket anywhere in the string, nothing is replaced.
To fix both mistakes, replace [ \t] with the [:blank:] character class, which consists exactly of space and tab. (And, note that [:alpha:][:digit:] can be written more compactly as [:alnum:].)
By using above logic I am trying to remove space from starting and ending of the sentence and removing special characters. It's removing space last and starting and removing special characters and also removing space in between word to word.But I don't want to remove space in between word to word.
Ex:1234whitegreen
Expected output: 1234 white green
"String".squeeze(' ').gsub(/, /, ',').gsub(/[^0-9A-Za-z,\r\n ]/i, '').strip
gsub!(/[^0-9A-Za-z ]/, '') will remove all special character without start end spaces.
strip will remove start and end space from string.
I have a column eventDate which contains trailing spaces. I am trying to remove them with the PostgreSQL function TRIM(). More specifically, I am running:
SELECT TRIM(both ' ' from eventDate)
FROM EventDates;
However, the trailing spaces don't go away. Furthermore, when I try and trim another character from the date (such as a number), it doesn't trim either. If I'm reading the manual correctly this should work. Any thoughts?
There are many different invisible characters. Many of them have the property WSpace=Y ("whitespace") in Unicode. But some special characters are not considered "whitespace" and still have no visible representation. The excellent Wikipedia articles about space (punctuation) and whitespace characters should give you an idea.
<rant>Unicode sucks in this regard: introducing lots of exotic characters that mainly serve to confuse people.</rant>
The standard SQL trim() function by default only trims the basic Latin space character (Unicode: U+0020 / ASCII 32). Same with the rtrim() and ltrim() variants. Your call also only targets that particular character.
Use regular expressions with regexp_replace() instead.
Trailing
To remove all trailing white space (but not white space inside the string):
SELECT regexp_replace(eventdate, '\s+$', '') FROM eventdates;
The regular expression explained:
\s ... regular expression class shorthand for [[:space:]]
- which is the set of white-space characters - see limitations below
+ ... 1 or more consecutive matches
$ ... end of string
Demo:
SELECT regexp_replace('inner white ', '\s+$', '') || '|'
Returns:
inner white|
Yes, that's a single backslash (\). Details in this related answer:
SQL select where column begins with \
Leading
To remove all leading white space (but not white space inside the string):
regexp_replace(eventdate, '^\s+', '')
^ .. start of string
Both
To remove both, you can chain above function calls:
regexp_replace(regexp_replace(eventdate, '^\s+', ''), '\s+$', '')
Or you can combine both in a single call with two branches.
Add 'g' as 4th parameter to replace all matches, not just the first:
regexp_replace(eventdate, '^\s+|\s+$', '', 'g')
But that should typically be faster with substring():
substring(eventdate, '\S(?:.*\S)*')
\S ... everything but white space
(?:re) ... non-capturing set of parentheses
.* ... any string of 0-n characters
Or one of these:
substring(eventdate, '^\s*(.*\S)')
substring(eventdate, '(\S.*\S)') -- only works for 2+ printing characters
(re) ... Capturing set of parentheses
Effectively takes the first non-whitespace character and everything up to the last non-whitespace character if available.
Whitespace?
There are a few more related characters which are not classified as "whitespace" in Unicode - so not contained in the character class [[:space:]].
These print as invisible glyphs in pgAdmin for me: "mongolian vowel", "zero width space", "zero width non-joiner", "zero width joiner":
SELECT E'\u180e', E'\u200B', E'\u200C', E'\u200D';
'' | '' | '' | ''
Two more, printing as visible glyphs in pgAdmin, but invisible in my browser: "word joiner", "zero width non-breaking space":
SELECT E'\u2060', E'\uFEFF';
'' | ''
Ultimately, whether characters are rendered invisible or not also depends on the font used for display.
To remove all of these as well, replace '\s' with '[\s\u180e\u200B\u200C\u200D\u2060\uFEFF]' or '[\s]' (note trailing invisible characters!).
Example, instead of:
regexp_replace(eventdate, '\s+$', '')
use:
regexp_replace(eventdate, '[\s\u180e\u200B\u200C\u200D\u2060\uFEFF]+$', '')
or:
regexp_replace(eventdate, '[\s]+$', '') -- note invisible characters
Limitations
There is also the Posix character class [[:graph:]] supposed to represent "visible characters". Example:
substring(eventdate, '([[:graph:]].*[[:graph:]])')
It works reliably for ASCII characters in every setup (where it boils down to [\x21-\x7E]), but beyond that you currently (incl. pg 10) depend on information provided by the underlying OS (to define ctype) and possibly locale settings.
Strictly speaking, that's the case for every reference to a character class, but there seems to be more disagreement with the less commonly used ones like graph. But you may have to add more characters to the character class [[:space:]] (shorthand \s) to catch all whitespace characters. Like: \u2007, \u202f and \u00a0 seem to also be missing for #XiCoN JFS.
The manual:
Within a bracket expression, the name of a character class enclosed in
[: and :] stands for the list of all characters belonging to that
class. Standard character class names are: alnum, alpha, blank, cntrl,
digit, graph, lower, print, punct, space, upper, xdigit.
These stand for the character classes defined in ctype.
A locale can provide others.
Bold emphasis mine.
Also note this limitation that was fixed with Postgres 10:
Fix regular expressions' character class handling for large character
codes, particularly Unicode characters above U+7FF (Tom Lane)
Previously, such characters were never recognized as belonging to
locale-dependent character classes such as [[:alpha:]].
It should work the way you're handling it, but it's hard to say without knowing the specific string.
If you're only trimming leading spaces, you might want to use the more concise form:
SELECT RTRIM(eventDate)
FROM EventDates;
This is a little test to show you that it works.
Tell us if it works out!
If your whitespace is more than just the space meta value than you will need to use regexp_replace:
SELECT '(' || REGEXP_REPLACE(eventDate, E'[[:space:]]', '', 'g') || ')'
FROM EventDates;
In the above example I am bounding the return value in ( and ) just so you can easily see that the regex replace is working in a psql prompt. So you'll want to remove those in your code.
SELECT replace((' devo system ') ,' ','');
It gives: devosystem
A tested one that works like a charm:
UPDATE company SET name = TRIM (BOTH FROM name) where id > 0
Does anybody knows which formatting rules uses jsmin/jsformatter plugin of Notepad++? I need this because we are forced to use this formatter but I'm using intellij idea to write js code. So having this rules I can import it some how or, at least, apply manually.
Thanks everyone in advance!
The minimising rules applied are listed here:
http://www.crockford.com/javascript/jsmin.html
JSMin is a filter that omits or modifies some characters. This does
not change the behavior of the program that it is minifying. The
result may be harder to debug. It will definitely be harder to read.
JSMin first replaces carriage returns ('\r') with linefeeds ('\n'). It
replaces all other control characters (including tab) with spaces. It
replaces comments in the // form with linefeeds. It replaces comments
in the /* */ form with spaces. All runs of spaces are replaced with a
single space. All runs of linefeeds are replaced with a single
linefeed.
It omits spaces except when a space is preceded and followed by a
non-ASCII character or by an ASCII letter or digit, or by one of these
characters:
\ $ _
It is more conservative in omitting linefeeds, because linefeeds are
sometimes treated as semicolons. A linefeed is not omitted if it
precedes a non-ASCII character or an ASCII letter or digit or one of
these characters:
\ $ _ { [ ( + -
and if it follows a non-ASCII character or an ASCII letter or digit or
one of these characters:
\ $ _ } ] ) + - " '
No other characters are omitted or modified.
There are other custom formatting rules applied according to the plugin developer's page:
http://www.sunjw.us/jsminnpp/