Parse data, single to multiple - sql

Question

have a single column Varchar(2000).
Data looks like in a single column,
12:10:08: Dialing12:10:08: Connecting12:10:08: ABC: abc:9433769781$100.88.77.0:878712:10:08: ABCD: 000012:10:09: Agent Initializing12:10:25: On Call12:10:25: Assigned to operator12:10:25: Waiting for Supervisor12:10:30: Waiting for Manager12:11:30: Call Ended12:11:30: Call Not connected..
I want to parse it like,
12:10:08: Dialing
12:10:08: Connecting
12:10:08: ABC: abc:9433769782$100.88.77.0:8787
12:10:08: ABCD: 0000
12:10:25: Agent Initializing
12:10:18: On Call
12:10:25: Assigned to operator
12:10:30: Waiting for Supervisor
12:10:30: Waiting for Manager
12:11:30: Call Ended
12:11:30: Call Not connected
Any help. Searched the complete forum, but I am really unsure about this, particularly an absence of a specific identifier. Appreciate your help.
P/S- This is just an example of a single time,time is not constant.

Answer 1

Yuck. But, you can do this with a recursive CTE. Here is how:
with t as (
select '12:10:08: Dialing12:10:08: Connecting12:10:08: ABC: abc:9433769781$100.88.77.0:878712:10:08: ABCD: 000012:10:09: Agent Initializing12:10:25: On Call12:10:25: Assigned to operator12:10:25: Waiting for Supervisor12:10:30: Waiting for Manager12:11:30: Call Ended12:11:30: Call Not connected.. ' as col
),
cte as (
select left(t.col, 9 + patindex('%[0-9][0-9]:[0-9][0-9]:[0-9][0-9]: %', substring(t.col, 11, 1000))) as val,
substring(t.col, 10 + patindex('%[0-9][0-9]:[0-9][0-9]:[0-9][0-9]: %', substring(t.col, 11, 1000)), 1000) as rest
from t
where t.col like '[0-9][0-9]:[0-9][0-9]:[0-9][0-9]: %[0-9][0-9]:[0-9][0-9]:[0-9][0-9]: %'
union all
select (case when rest like '[0-9][0-9]:[0-9][0-9]:[0-9][0-9]: %[0-9][0-9]:[0-9][0-9]:[0-9][0-9]: %'
then left(rest, 9 + patindex('%[0-9][0-9]:[0-9][0-9]:[0-9][0-9]: %', substring(rest, 11, 1000)))
else rest
end) as val,
substring(rest, 10 + patindex('%[0-9][0-9]:[0-9][0-9]:[0-9][0-9]: %', substring(rest, 11, 1000)), 1000) as rest
from cte
where rest like '[0-9][0-9]:[0-9][0-9]:[0-9][0-9]: %'
)
select val
from cte;
The SQL Fiddle is here.

Answer 2

Alternative;
DECLARE #string VARCHAR(1024) = '12:10:08: Dialing12:10:08: Connecting12:10:08: ABC: abc:9433769781$100.88.77.0:878712:10:08: ABCD: 000012:10:09: Agent Initializing12:10:25: On Call12:10:25: Assigned to operator12:10:25: Waiting for Supervisor12:10:30: Waiting for Manager12:11:30: Call Ended12:11:30: Call Not connected'
WITH T(last, pos) AS(
SELECT 0, 1
UNION ALL
SELECT pos, pos + PATINDEX('%[0-9][0-9]:[0-9][0-9]:[0-9][0-9]%', SUBSTRING(#string, pos + 1, LEN(#string)))
FROM T
WHERE pos != last
)
SELECT SUBSTRING(#string, last, CASE WHEN pos = last THEN len(#string) ELSE pos - last END)
FROM T
WHERE LAST > 0
For
(No column name)
12:10:08: Dialing
12:10:08: Connecting
12:10:08: ABC: abc:9433769781$100.88.77.0:8787
12:10:08: ABCD: 0000
12:10:09: Agent Initializing
12:10:25: On Call
12:10:25: Assigned to operator
12:10:25: Waiting for Supervisor
12:10:30: Waiting for Manager
12:11:30: Call Ended
12:11:30: Call Not connected

Answer 3

I know you are asking for an SQL solution but I am not sure that is possible without a while loop and extensive string manipulation which is quite inefficient.
If you are happy to bring the original varchar down to the BLL level, you can do it here using a regular expression. As I assume you want to do this in order to output to screen or log file then this should be possible.
For example:
Replace
/([0-9]{2}:[0-9]{2}:[0-9]{2}: ).*/gU
with
\n/1
Example:
http://regex101.com/r/eM4vD5/1