How to make right outer join? - sql

I am using OE schema and trying to see item # and quantity on hand in each warehouse and if any warehouse does not have item than it should show 0 item in hand. i am running following SQL and it is not showing 0 quantity for items.
select i.product_id,w.warehouse_name ,(i.quantity_on_hand)
from inventories i
right outer join warehouses w
on (i.warehouse_id=w.warehouse_id)
order by 1
I want to see result like this:
PRODUCT_ID WAREHOUSE_NAME NVL(I.QUANTITY_ON_HAND,0)
---------- ----------------------------------- -------------------------
2262 Sydney 35
2262 Beijing 50
2262 Bombay 35
2262 San Francisco 155
2262 Seattle, Washington 77
Toronto 0
New Jersey 0
Southlake, Texas 0
Mexico City 0
3501 Toronto 220
3501 Sydney 320
3501 Mexico City 294
3501 Beijing 268
3501 San Francisco 353
New Jersey 0
Southlake, Texas 0
Seattle, Washington 0
Bombay 0

You want to see a row for every warehouse and every product. So, start with generating this list and use left outer join to bring in the values that exist:
select i.product_id, w.warehouse_name, coalesce(i.quantity_on_hand, 0)
from warehouses w cross join
(select distinct product_id from inventories) p left join
inventories i
on w.warehouse_id = i.warehouse_id and p.product_id = i.product_id
order by i.product_id, w.warehouse_name;

Related

Items in one location not in another. SQL

I'm trying to query, possibly with a self-join, to find which Products are on sale in Chicago that are not on sale in Miami.
ProductID Product_Type On Sale Stock_location
2201 Cereal Y chicago
2202 Beverage Y chicago
2203 Frozen Food y chicago
2204 Poultry N chicago
2205 Health N chicago
2206 Snacks Y chicago
2207 Household N chicago
2208 Personal N chicago
2209 Produce N chicago
2201 Cereal Y Miami
2202 Beverage Y Miami
2203 Frozen Food N Miami
2204 Poultry Y Miami
2205 Health N Miami
2206 Snacks Y Miami
2207 Household N Miami
2208 Personal N Miami
It's something like below
select Product_Type from Products
where [On Sale] = 'Y' and
Stock_location = 'chicago' and
Product_Type not in (Select Product_Type form Products where [On Sale] = 'N' and Stock_location = 'Miami' )
SELECT t1.*
FROM t AS t1
JOIN t AS t2 ON ( t1.Product_Type = t2.Product_Type )
WHERE t1.On_Sale = "Y"
AND t2.On_Sale = "N";
Useful resource:
https://www.w3schools.com/sql/sql_join_self.asp

How to statistics sales, city, customer of goods use oracle

I have a oracle view, and include the sale of goods details. It like this:
OrderId OrderDetailId GoodsId GoodsName UnitName SalesQty Price CustomerName Country City
200138 ddd0a3b42adb 770 A bag 5 18.00 AAAA USA NewYork
223448 70ca7ceb41c7 193 D bottle 10 10.00 BBB USA NewYork
200118 ab472857573e 1286 F cup 8 50.00 CCC China Beijing
244028 230a43920667 770 A bag 20 18.00 CCC China Beijing
251118 118fc2b3839b 5929 C box 40 6.00 DDDD Japan Tokyo
200000 abd0a3b42ddd 770 A bag 15 18.00 AAAA USA NewYork
111118 11111113839b 5929 C box 40 6.00 FFFF Japan Tokyo
And I want a SQL statement statistics sales, the number of cities, the number of customers of each goods. The result should be like this:
GoodsId GoodsName SalesQty(UnitName) CityQty CustomerQty
GoodsId GoodsName SalesQty(UnitName) CityQty CustomerQty
770 A 40(bag) 2 2
193 D 10(bottle) 1 1
1286 F 8(cup) 1 1
5929 C 80(box) 1 2
How to write sql statistical statement? Thanks!
Simply use GROUP BY
select GoodsId, GoodsName, UnitName,
sum(SalesQty) SalesQty,
count(distinct City) CityQty,
count(distinct CustomerName) CustomerQty
from goods_view
group by GoodsId, GoodsName, UnitName
demo
You may use cube, to include also sub&grand totals of quantities :
select GoodsId, GoodsName||'('||UnitName||')' GoodsName,
sum(SalesQty) SalesQty, count(distinct City) CityQty, count(distinct CustomerName) CustomerQty
from v_goods
group by cube(GoodsId, GoodsName||'('||UnitName||')')
order by GoodsId,GoodsName||'('||UnitName||')';

Query with sum functions

for a little project(hobby purpose) i am building a C# application with a SQL database behind it.
However I am trying to build a query with a sum function which calculates values from a different table.
Here are the relevant tables and sample data
Hotel table
Id, Name Adress Zipcode Phone
1 Ankunding Group 90 Shelley Terrace 649-6326 86-(672)239-5855
2 Gerlach-Gutmann 50776 Bartillon Road 27109 CEDEX 33-(412)226-8055
3 Breitenberg-Smith 3289 Talisman Avenue 59762 86-(141)636-8780
4 Smitham-Marks 5 Veith Plaza 216282 7-(400)484-7233
5 Beatty LLC 3 Center Pass 940028 212-(310)974-4364
Reservation table
id, customerid, Startdate Enddate Amount of persons
1 163 2016-06-19 2017-04-30 4
2 172 2016-12-02 2016-08-18 5
3 162 2017-01-20 2017-04-08 3
4 66 2017-04-06 2017-01-07 2
5 104 2017-05-07 2016-09-10 2
RoomReservation table
Roomid, reservationid
3 53
3 198
4 178
5 172
5 218
Room table
id, hotelid, Roomnumber, price
1 1 1.01 268.83
2 1 1.02 201.28
3 1 1.03 126.64
4 1 1.04 122.56
5 1 1.05 217.41
Now I am trying to make a query to which gives me an overview off income per hotel. So for each hotel I want to get the reservations, and do amount of persons * the price of the room for each room in the hotel.
I've tried different things without success, I read somewhere that I needed to use a subquery but I have no idea how.
I want it to look like;
Hotelname1; income
Hotelname2; income
Hotelname3; income
Hotelname4; income
Hotelname4; income
Why can't you just do this:
SELECT
Hotel.Name,
SUM(Room.Price*Reservation.Amountofpersons)
FROM
Hotel
JOIN Room
ON Hotel.HotelId=Room.HotelId
JOIN RoomReservation
ON Room.RoomId=RoomReservation.RoomId
JOIN Reservation
ON RoomReservation.ReservationId=Reservation.ReservationId
GROUP BY
Hotel.Name
You can try it whit this query:
select hotel.name,sum(reservation.amount*room.price)
from hotel_table as hotel
inner join room_table as room on (hotel.hotelid=room.hotelid)
inner join roomreservation_table as room_reservation on (room.roomid=room_reservation.roomId)
inner join reservation_table as reservation on (room.reservationId=reservation.reservationid)
group by hotel.hotelid

SQL- how would i Join these two queries

I have the following queries, and am attempting to join them
SELECT COUNTRY_NAME, COUNTRY_ID
FROM OEHR_COUNTRIES;
these results
COUNTRY_NAME CO
---------------------------------------- --
Argentina AR
Australia AU
Belgium BE
Brazil BR
Canada CA
Switzerland CH
China CN
Germany DE
Denmark DK
Egypt EG
France FR
HongKong HK
Israel IL
India IN
Italy IT
Japan JP
Kuwait KW
Mexico MX
Nigeria NG
Netherlands NL
Singapore SG
United Kingdom UK
United States of America US
Zambia ZM
Zimbabwe ZW
my second query
SELECT COUNTRY_ID, COUNT(COUNTRY_ID) AS "LCOUNT"
FROM OEHR_LOCATIONS
GROUP BY COUNTRY_ID;
results
CO LCOUNT
-- -------
US 4
SG 1
CA 2
CH 2
IT 2
MX 1
CN 1
DE 1
JP 2
IN 1
AU 1
UK 3
BR 1
NL 1
When i attempt to join these two results, so each country has the count after it
SELECT OEHR_COUNTRIES.COUNTRY_NAME, OEHR_COUNTRIES.COUNTRY_ID, COUNT(OEHR_LOCATIONS.COUNTRY_ID) AS LCOUNT
FROM OEHR_COUNTRIES
OUTER JOIN OEHR_LOCATIONS
ON OEHR_COUNTRIES.COUNTRY_ID = OEHR_LOCATIONS.COUNTRY_ID
ORDER BY LCOUNT;
i get this error
ON OEHR_COUNTRIES.COUNTRY_ID = OEHR_LOCATIONS.COUNTRY_ID
*
ERROR at line 4:
ORA-00904: "OEHR_COUNTRIES"."COUNTRY_ID": invalid identifier
ON OEHR_COUNTRIES.COUNTRY_ID = OEHR_LOCATIONS.COUNTRY_ID
*
ERROR at line 4:
ORA-00904: "OEHR_COUNTRIES"."COUNTRY_ID": invalid identifier
what is causing this error?
is there a simpler way to do what i am trying to achieve?
I assume this is something you need. It would list 0 for countries with no count. If you dont want to list countries with no count, use INNER JOIN
SELECT C.COUNTRY_NAME,
case
when L.LCOUNT is null
then 0
else L.LCOUNT
END as LCOUNT
FROM OEHR_COUNTRIES C
LEFT JOIN
(SELECT COUNTRY_ID, COUNT(COUNTRY_ID) AS LCOUNT
FROM OEHR_LOCATIONS
GROUP BY COUNTRY_ID) L
on C.COUNTRY_ID=L.COUNTRY_ID
order by LCOUNT DESC
You're missing the mandatory LEFT (or, in other scenarios, RIGHT) before the optional OUTER in the join syntax.
At the moment the word OUTER is being misinterpreted as a table alias, which is what is causing the error you're getting - there is, to the parser, now an OUTER.COUNTRY_ID but not a OEHR_COUNTRIES.COUNTRY_ID.
Add the missing word to stop it being seen as an alias, and to stop it defaulting to an inner join:
SELECT OEHR_COUNTRIES.COUNTRY_NAME, OEHR_COUNTRIES.COUNTRY_ID,
COUNT(OEHR_LOCATIONS.COUNTRY_ID) AS LCOUNT
FROM OEHR_COUNTRIES
LEFT OUTER JOIN OEHR_LOCATIONS
ON OEHR_COUNTRIES.COUNTRY_ID = OEHR_LOCATIONS.COUNTRY_ID
GROUP BY OEHR_COUNTRIES.COUNTRY_NAME, OEHR_COUNTRIES.COUNTRY_ID
ORDER BY LCOUNT;
I've added the missing group-by clause too. With your sample data that gets:
COUNTRY_NAME CO LCOUNT
------------------------ -- ----------
Belgium BE 0
Argentina AR 0
Zimbabwe ZW 0
...
Zambia ZM 0
Mexico MX 1
China CN 1
...
Germany DE 1
Switzerland CH 2
Canada CA 2
Japan JP 2
Italy IT 2
United Kingdom UK 3
United States of America US 4
25 rows selected.
Without adding that missing word, changing the other references to the table to use the (wrong) OUTER alias instead would have meant it would execute, again with the group-by clause added:
SELECT OUTER.COUNTRY_NAME, OUTER.COUNTRY_ID, COUNT(OEHR_LOCATIONS.COUNTRY_ID) AS LCOUNT
FROM OEHR_COUNTRIES
OUTER JOIN OEHR_LOCATIONS
ON OUTER.COUNTRY_ID = OEHR_LOCATIONS.COUNTRY_ID
GROUP BY OUTER.COUNTRY_NAME, OUTER.COUNTRY_ID
ORDER BY LCOUNT;
but it wouldn't have done quite what you wanted - assuming you want to see zero counts for countries with no locations - since it's now an inner join:
COUNTRY_NAME CO LCOUNT
------------------------ -- ----------
Netherlands NL 1
India IN 1
...
Australia AU 1
Switzerland CH 2
Japan JP 2
Canada CA 2
Italy IT 2
United Kingdom UK 3
United States of America US 4
14 rows selected.
The 11 countries with no locations aren't shown at all with an inner join.

SQL Select Distinct returning duplicates

I am trying to return the country, golfer name, golfer age, and average drive for the golfers with the highest average drive from each country.
However I am getting a result set with duplicates of the same country. What am I doing wrong? here is my code:
select distinct country, name, age, avgdrive
from pga.golfers S1
inner join
(select max(avgdrive) as MaxDrive
from pga.golfers
group by country) S2
on S1.avgdrive = s2.MaxDrive
order by avgdrive;
These are some of the results I've been getting back, I should only be getting 15 rows, but instead I'm getting 20:
COUN NAME AGE AVGDRIVE
---- ------------------------------ ---------- ----------
Can Mike Weir 35 279.9
T&T Stephen Ames 41 285.8
USA Tim Petrovic 39 285.8
Ger Bernhard Langer 47 289.3
Swe Fredrik Jacobson 30 290
Jpn Ryuji Imada 28 290
Kor K.J. Choi 37 290.4
Eng Greg Owen 33 291.8
Ire Padraig Harrington 33 291.8
USA Scott McCarron 40 291.8
Eng Justin Rose 25 293.1
Ind Arjun Atwal 32 293.7
USA John Rollins 30 293.7
NIr Darren Clarke 37 294
Swe Daniel Chopra 31 297.2
Aus Adam Scott 25 300.6
Fij Vijay Singh 42 300.7
Spn Sergio Garcia 25 301.9
SAf Ernie Els 35 302.9
USA Tiger Woods 29 315.2
You are missing a join condition:
select s1.country, s1.name, s1.age, s1.avgdrive
from pga.golfers S1 inner join
(select country, max(avgdrive) as MaxDrive
from pga.golfers
group by country
) S2
on S1.avgdrive = s2.MaxDrive and s1.country = s2.country
order by s1.avgdrive;
Your problem is that some people in one country have the same average as the best in another country.
DISTINCT eliminated duplicate rows, not values in some fields.
To get a list of countries with ages, names, and max drives, you would need to group the whole select by country.