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If today is Friday, I would like to get data 7 to 9 days from now, if not 7 days. I am using SQL Server.
Before:
id
class
startdate
1
English
2020-12-21 00:00:00.000
2
English
2020-12-22 00:00:00.000
3
Math
2020-12-21 00:00:00.000
4
English
2020-12-27 00:00:00.000
5
Math
2020-12-27 00:00:00.000
If today is 14/12/2020 - Monday, it will produce the result below:
id
class
startdate
1
English
2020-12-21 00:00:00.000
3
Math
2020-12-21 00:00:00.000
I tried the following, but it doesn't work.
select id, class, startdate
from class
where case datepart(w, GETDATE())
when 6 then startdate between DateAdd(dd,+9,GETDATE() ) and DateAdd(dd,+10,GETDATE()))
else startdate between DateAdd(dd,+7,GETDATE() ) and DateAdd(dd,+8,GETDATE()))
end
order by startdate
OR usually prevents index usage anyway, so you can do:
where datediff(day, getdate(), startdate)
between 7 and
(case when datepart(weekday, GETDATE()) = 6 then 9 else 7 end)
If you are interested in performance, then use two separate queries:
select id, class, startdate
from class
where datepart(weekday, getdate()) = 6 and
startdate >= dateadd(day, 7, convert(date, getdate())) and
startdate <= dateadd(day, 9, convert(date, getdate()))
union all
select id, class, startdate
from class
where datepart(weekday, getdate()) <> 6 and
startdate = dateadd(day, 7, convert(date, getdate()));
SQL Server should find this easier to optimize.
You can't use a CASE expression like this in SQL Server.
Try this instead:
select id, class, startdate
from class
cross apply
(
select case datepart(dw, GETDATE())
when 6 then 9
else 7
end
) t(days)
where startdate between dateadd(dd, t.days ,GETDATE()) an dateadd(dd,t.days+1,GETDATE())
order by startdate
Demo here
To answer to your comment:
select id, class, startdate
from class
cross apply
(
select
case datepart(dw, GETDATE())
when 6 then 9
else 7
end,
case datepart(dw, GETDATE())
when 6 then 11
else 8
end
) t(days1, days2)
where startdate between dateadd(dd, t.days1 ,GETDATE()) and dateadd(dd,t.days2,GETDATE())
order by startdate
If you have datetime with actual hh:mi:ss in it - just change it to date and and it would be much easier
select id,
class,
startdate
from class
where (datepart(w, GETDATE()) = 6 and
startdate = CAST(DateAdd(dd,+9,GETDATE()) as date)
)
or (datepart(w, GETDATE()) != 6 and
startdate = CAST(DateAdd(dd,+7,GETDATE()) as date)
)
order by startdate
If it is not an option try this:
select id,
class,
startdate
from class
where (datepart(w, GETDATE()) = 6 and
startdate between DateAdd(dd,+9,CAST(GETDATE() as date))
and DATEADD(second,-1,datediff(dd,0,DateAdd(dd,+9,CAST(GETDATE() as date)))+1)
)
or (datepart(w, GETDATE()) != 6 and
startdate between DateAdd(dd,+7,CAST(GETDATE() as date))
-- to get YYYY-MM-DD 00:00:00
and DATEADD(second,-1,datediff(dd,0,DateAdd(dd,+7,CAST(GETDATE() as date)))+1)
-- to get YYYY-MM-DD 23:59:59
)
order by startdate
This has probably been made more complicated than it should.
Create two parameters #start and #end
If today is Friday set parameters as appropriate else if it is not set as needed.
Use parameters in your query
select *
from VP_TIMESHTPUNCHV42
where (EVENTDATE>=getdate()-8) AND (EVENTDATE <=getdate()-3)
AND PERSONNUM = '668795'
so it should -9 or -8 here? please help me understand about the dates and what dates will be included here ?
If my Tuesday is 15th Oct and the previous Sat is 12thoct and mon is 7thoct
I need data from Mon7th oct to sat12th oct
if you want to get data from Monday to Saturday. WeekDay is from 2(Monday) to 7(Saturday)
select *
from VP_TIMESHTPUNCHV42
where datepart(weekday, EVENTDATE) between 2 and 7 AND PERSONNUM = '668795'
or (if only within this week)
select *
from VP_TIMESHTPUNCHV42
where EVENTDATE between getdate() - 1 and getdate() + 5 AND PERSONNUM = '668795'
select *
from VP_TIMESHTPUNCHV42
where EVENTDATE between dateadd(day, -1, cast(getdate() as date)) and dateadd(day, 5, cast(getdate() as date))
and PERSONNUM = '668795'
I am looking for some T-SQL code that should pick the date which is "One Year back from current date (at the same time last Sunday in the month of January)".
For example:
Current day expected result
2017-02-05 2016-01-31
2017-01-05 2015-01-25
2018-02-19 2017-01-29
2018-01-19 2016-01-31
2019-02-28 2018-01-28
Please note: The year starts from last Sunday in January
I have some T-SQL code which is being used in SQL Server 2014:
select
convert(varchar(10), DATEADD(day, DATEDIFF(day, '19000107', DATEADD(month, DATEDIFF(MONTH, 0, CONVERT(date, CONVERT(VARCHAR(4), (CASE WHEN MONTH(GetDate()) = 1 THEN CONVERT(VARCHAR(4), GetDate(), 112) - 1 ELSE CONVERT(VARCHAR(4), GetDate(), 112) END), 112) + '0101')), 30)) / 7 * 7, '19000107'), 120)
The above code picks the date for current year's (last Sunday in January month). But I want T-SQL code to pick last year's (last Sunday's date in January month) date.
In detail - I want T-SQL code to produce expected result from below table
Current day T-SQL code answer expected result
2017-02-05 2017-01-29 2016-01-31
2017-01-05 2016-01-31 2015-01-25
2018-02-19 2018-01-28 2017-01-29
2018-01-19 2017-01-29 2016-01-31
2019-02-28 2019-01-27 2018-01-28
Any help please.
The best thing for this question is a numbers and date table. This answer shows you how to create one. Such a table is very handsome in many situations...
If I understand this correctly, you want the last Sunday in January of the previous year in all cases? Try this:
DECLARE #dummy TABLE(ID INT IDENTITY,YourDate DATE);
INSERT INTO #dummy VALUES
('2017-02-05'),('2017-01-05'),('2018-02-19'),('2018-01-19'),('2019-02-28');
WITH Years AS
(
SELECT * FROM (VALUES(2010),(2011),(2012),(2013),(2014),(2015),(2016),(2017),(2018),(2019),(2020)) AS t(Yr)
)
,LastSundays AS
(
SELECT Yr AS TheYear
,DATEADD(DAY,(DATEPART(WEEKDAY,LastOfJanuary) % 7)*(-1),LastOfJanuary) AS LastSundayOfJanuary
FROM Years
CROSS APPLY(SELECT CAST(CAST(Yr AS VARCHAR(4)) + '0131' AS DATE)) AS t(LastOfJanuary)
)
SELECT *
FROM #dummy AS d
INNER JOIN LastSundays AS ls ON YEAR(DATEADD(YEAR,-1,d.YourDate))=ls.TheYear;
The result (I do not understand row 2 and 4 completely...)
ID YourDate TheYear LastSundayOfJanuary
1 2017-02-05 2016 2016-01-31
2 2017-01-05 2016 2016-01-31 <--Your sample data is different...
3 2018-02-19 2017 2017-01-29
4 2018-01-19 2017 2017-01-29 <--Your sample data is different...
5 2019-02-28 2018 2018-01-28
Hint You might need to introduce ##DATEFIRST into your calculations...
Here is a way to do it without a date table (which is still a good idea BTW). Tested on all your inputs and it delivers the correct output each time. Obviously you would refactor this a bit as it's longwinded, just to show each step.
/* The input date. */
DECLARE
#input DATE = '2019-02-28';
/* The input date less one year. */
DECLARE
#date_minus_one_year DATE = DATEADD(yy,-1,#input);
/* The year part of the input date less one year. */
DECLARE
#year_date_part INT = DATEPART(yy,#date_minus_one_year);
/* 31 Jan of the previous year. */
DECLARE
#prev_year_jan_eom DATE = CAST(CAST(#year_date_part AS VARCHAR(4))+'-01-31' AS DATE);
/* What day of the week is 31 Jan of the previous year? */
DECLARE
#previous_eom_dw_part INT = DATEPART(dw,#prev_year_jan_eom);
/* Offest 31 Jan to the previous Sunday, won't change if the 31st is itself a Sunday. */
DECLARE
#output DATE = DATEADD(dd,1 - #previous_eom_dw_part,#prev_year_jan_eom);
/* Input and output */
SELECT
#input input
,#output [output];
I didn't think of a way to do it without the conditional in a case. It also uses the trick of casting a numeric year value to a January 1st date.
select case
when
datepart(dayofyear, dt) >
31 - datepart(weekday, dateadd(day, 30, cast(year(dt) as varchar(4))))
then
dateadd(day,
31 - datepart(weekday, dateadd(day, 30, cast(year(dt) as varchar(4)))),
cast(year(dt) as varchar(4))
)
else
dateadd(day,
31 - datepart(weekday, dateadd(day, 30, cast(year(dt) - 1 as varchar(4)))),
cast(year(dt) - 1 as varchar(4))
)
end
from (values
('20100201'), ('20110301'), ('20120401'),
('20130501'), ('20140601'), ('20150701'),
('20160801'), ('20170901'), ('20181001')
) t(dt)
Just for fun (untested)
select
dateadd(week,
-52 * ceil(sign(datediff(day, dt, hs)) + 0.5),
js
)
from
(select <date> dt) as t
cross apply
(
select 31 - datepart(weekday,
datefromparts(year(dt), 1, 31) as js
) t2;
SELECT
convert(varchar(10), DATEADD(day, DATEDIFF(day, '19000107', DATEADD(month, DATEDIFF(MONTH, 0, CONVERT(date, CONVERT(VARCHAR(4), (CASE WHEN MONTH(DATEADD(year,-1,GetDate())) = 1 THEN CONVERT(VARCHAR(4), DATEADD(year,-1,GetDate()), 112) - 1 ELSE CONVERT(VARCHAR(4), DATEADD(year,-1,GetDate()), 112) END), 112) + '0101')), 30)) / 7 * 7, '19000107'), 120)
I am having a problem with week numbers. The customers week starts on a Tuesday, so ends on a Monday. So I have done:
Set DateFirst 2
When I then use
DateAdd(ww,#WeeksToShow, Date)
It occasionally gives me 8 weeks of information. I think it is because it goes over to the previous year, but I am not sure how to fix it.
If I do:
(DatePart(dy,Date) / 7) - #WeeksToShow
Then it works better, but obviously doesn't work going through to previous years as it just goes to minus figures.
Edit:
My currently SQL (If it helps at all without any data)
Set DateFirst 2
Select
DATEPART(yyyy,SessionDate) as YearNo,
DATEPART(ww,SessionDate) as WeekNo,
DATEADD(DAY, 1 - DATEPART(WEEKDAY, SessionDate + SessionTime), CAST(SessionDate +SessionTime AS DATE)) [WeekStart],
DATEADD(DAY, 7 - DATEPART(WEEKDAY, SessionDate + SessionTime), CAST(SessionDate + SessionTime AS DATE)) [WeekEnd],
DateName(dw,DATEADD(DAY, 7 - DATEPART(WEEKDAY, SessionDate + SessionTime), CAST(SessionDate + SessionTime AS DATE))) as WeekEndName,
Case when #ConsolidateSites = 1 then 0 else SiteNo end as SiteNo,
Case when #ConsolidateSites = 1 then 'All' else CfgSites.Name end as SiteName,
GroupNo,
GroupName,
DeptNo,
DeptName,
SDeptNo,
SDeptName,
PluNo,
PluDescription,
SUM(Qty) as SalesQty,
SUM(Value) as SalesValue
From
PluSalesExtended
Left Join
CfgSites on PluSalesExtended.SiteNo = CfgSites.No
Where
Exists (Select Descendant from DescendantSites where Parent in (#SiteNo) and Descendant = PluSalesExtended.SiteNo)
AND (DATEPART(WW,SessionDate + SessionTime) !=DATEPART(WW,GETDATE()))
AND SessionDate + SessionTime between DATEADD(ww,#NumberOfWeeks * -1,#StartingDate) and #StartingDate
AND TermNo = 0
AND PluEntryType <> 4
Group by
DATEPART(yyyy,SessionDate),
DATEPART(ww,SessionDate),
DATEADD(DAY, 1 - DATEPART(WEEKDAY, SessionDate + SessionTime), CAST(SessionDate +SessionTime AS DATE)),
DATEADD(DAY, 7 - DATEPART(WEEKDAY, SessionDate + SessionTime), CAST(SessionDate + SessionTime AS DATE)),
Case when #ConsolidateSites = 1 then 0 else SiteNo end,
Case when #ConsolidateSites = 1 then 'All' else CfgSites.Name end,
GroupNo,
GroupName,
DeptNo,
DeptName,
SDeptNo,
SDeptName,
PluNo,
PluDescription
order by WeekEnd
There are two issues here, the first is that I suspect you are defining 8 weeks of data as having 8 different values for DATEPART(WEEK, in which case you can replicate the root cause of the issue by looking at what ISO would define as the first week of 2015:
SET DATEFIRST 2;
SELECT Date, Week = DATEPART(WEEK, Date)
FROM (VALUES
('20141229'), ('20141230'), ('20141231'), ('20150101'),
('20150102'), ('20150103'), ('20150104')
) d (Date);
Which gives:
Date Week
-----------------
2014-12-29 52
2014-12-30 53
2014-12-31 53
2015-01-01 1
2015-01-02 1
2015-01-03 1
2015-01-04 1
So although you only have 7 days, you have 3 different week numbers. The problem is that DATEPART(WEEK is quite a simplistic function, and will simply return the number of week boundaries passed since the first day of the year, a better function would be ISO_WEEK since this takes into account year boundaries nicely:
SET DATEFIRST 2;
SELECT Date, Week = DATEPART(ISO_WEEK, Date)
FROM (VALUES
('20141229'), ('20141230'), ('20141231'), ('20150101'),
('20150102'), ('20150103'), ('20150104')
) d (Date);
Which gives:
Date Week
-----------------
2014-12-29 1
2014-12-30 1
2014-12-31 1
2015-01-01 1
2015-01-02 1
2015-01-03 1
2015-01-04 1
The problem is, that this does not take into account that the week starts on Tuesday, since the ISO week runs Monday to Sunday, you could adapt your usage slightly to get the week number of the day before:
SET DATEFIRST 2;
SELECT Date, Week = DATEPART(ISO_WEEK, DATEADD(DAY, -1, Date))
FROM (VALUES
('20141229'), ('20141230'), ('20141231'), ('20150101'),
('20150102'), ('20150103'), ('20150104')
) d (Date);
Which would give:
Date Week
-----------------
2014-12-29 52
2014-12-30 1
2014-12-31 1
2015-01-01 1
2015-01-02 1
2015-01-03 1
2015-01-04 1
So Monday the 29th December is now recognized as the previous week. The problem is that there is no ISO_YEAR built in function, so you will need to define your own. This is a fairly trivial function, even so I almost never create scalar functions because they perform terribly, instead I use an inline table valued function, so for this I would use:
CREATE FUNCTION dbo.ISOYear (#Date DATETIME)
RETURNS TABLE
AS
RETURN
( SELECT IsoYear = DATEPART(YEAR, #Date) +
CASE
-- Special cases: Jan 1-3 may belong to the previous year
WHEN (DATEPART(MONTH, #Date) = 1 AND DATEPART(ISO_WEEK, #Date) > 50) THEN -1
-- Special case: Dec 29-31 may belong to the next year
WHEN (DATEPART(MONTH, #Date) = 12 AND DATEPART(ISO_WEEK, #Date) < 45) THEN 1
ELSE 0
END
);
Which just requires a subquery to be used, but the extra typing is worth it in terms of performance:
SET DATEFIRST 2;
SELECT Date,
Week = DATEPART(ISO_WEEK, DATEADD(DAY, -1, Date)),
Year = (SELECT ISOYear FROM dbo.ISOYear(DATEADD(DAY, -1, Date)))
FROM (VALUES
('20141229'), ('20141230'), ('20141231'), ('20150101'),
('20150102'), ('20150103'), ('20150104')
) d (Date);
Or you can use CROSS APPLY:
SET DATEFIRST 2;
SELECT Date,
Week = DATEPART(ISO_WEEK, DATEADD(DAY, -1, Date)),
Year = y.ISOYear
FROM (VALUES
('20141229'), ('20141230'), ('20141231'), ('20150101'),
('20150102'), ('20150103'), ('20150104')
) d (Date)
CROSS APPLY dbo.ISOYear(d.Date) y;
Which gives:
Date Week Year
---------------------------
2014-12-29 52 2014
2014-12-30 1 2015
2014-12-31 1 2015
2015-01-01 1 2015
2015-01-02 1 2015
2015-01-03 1 2015
2015-01-04 1 2015
Even with this method, by simply getting a date 6 weeks ago you sill still end up with 7 weeks if the date you are using is not a Tuesday, because you will have 5 full weeks, and a part week at the start and a part week at the end, this is the second issue. So you need to make sure your start date is a Tuesday. The following will get you Tuesday of 7 weeks ago:
SELECT CAST(DATEADD(DAY, 1 - DATEPART(WEEKDAY, GETDATE()), DATEADD(WEEK, -6, GETDATE())) AS DATE);
The logic of this is explained better in this answer, the following is the part that will get the start of the week (based on your datefirst settings):
SELECT DATEADD(DAY, 1 - DATEPART(WEEKDAY, GETDATE()), GETDATE());
Then all I have done is substitute the second GETDATE() with DATEADD(WEEK, -6, GETDATE()) so that it is getting the start of the week 6 weeks ago, then there is just a cast to date to remove the time element from it.
This will get you current week + 5 previous weeks starting tuesday:
WHERE dateadd(week, datediff(d, 0, getdate()-1)/7 - 4, 1) <= yourdatecolumn
This will show examples:
DECLARE #wks int = 6 -- Weeks To Show
SELECT
dateadd(week, datediff(d, 0, getdate()-1)/7 - 4, 1) tuesday5weeksago,
dateadd(week, datediff(d, 0, getdate()-1)/7 - 5, 1) tuesday6weeksago,
dateadd(week, datediff(d, 0, getdate()-1)/7 - 6, 1) tuesday7weeksago,
dateadd(week, datediff(d, 0, getdate()-1)/7 - #wks + 1, 1) tuesdaydynamicweeksago
Result:
tuesday5weeksago tuesday6weeksago tuesday7weeksago tuesdaydynamicweeksago
2015-01-27 2015-01-20 2015-01-13 2015-01-20
I have two working shifts: 8:00:00 to 16:30:00 and 20:00:00 to 06:00:00.
I want to create a stored procedure that will retrieve data from an SQL table when I pass the date
this are my tables
Table1 Emp
ID DateTime EmpID
47 2014-12-05 08:00:00 1111
47 2014-12-05 08:25:00 1235
47 2014-12-05 23:55:00 4569
47 2014-12-06 00:00:00 4563
47 2014-12-06 02:00:00 7412
59 2014-12-06 04:00:00 8523
59 2014-12-05 10:30:00 5632
Table2 Product
ID DateTime ProductMade
47 2014-12-05 11:00:00 Milk
47 2014-12-05 08:00:00 Juice
47 2014-12-06 00:00:00 Bread
47 2014-12-06 06:00:00 Cakes
query for shift 2 18:00 to 06:00
SELECT *
FROM Table 1 as T1
INNER JOIN Table_Product as Prod ON t1.ID=Prod.ID
WHERE T1.DateTime BETWEEN DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()-8), 0) + '18:00'
AND DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()-7), 0) + '06:00'
so this will get all the records that has the same ID matching
then i have to do another query for the first shift.
between 08:00 to 16:30
SELECT *
FROM Table 1 AS T1
INNER JOIN
Table_Product AS Prod ON t1.ID=Prod.ID
WHERE DATEDIFF(day, CONVERT(VARCHAR(10), GETDATE(),110), CONVERT(VARCHAR(10), T1.DateTime,110))=-1 AND DATEPART(HOUR,T1.DateTime) BETWEEN '07' AND '16'
How do i make this into one stored procdure and elminate having two queries.
Try this if you want it for a specific shift. Then you have to specify #Shift
Declare #Shift char(1),
#days int
Set #Shift = 'A' -- will only get information for SHIFT A. Change to B if you want the rest
Set #days = 1
Select *
from Table1 t
where t.DateTime between
case when #Shift = 'A' then DateAdd(hour, 8, Convert(date, GetDate() - #days))
else DateAdd(hour, 20, Convert(date, GetDate() - #days)) end
and
case when #Shift = 'A' then DateAdd(hour, 16, Convert(date, GetDate() - #days))
else DateAdd(hour, 30, Convert(date, GetDate() - #days)) end
Specify the Shift and a Date, and it should work.
You can always do something like this as well. This you only have to specify the number of days in the past, and it will retrieve the information and specify the Shift in the first Column
DECLARE #days int
SET #days = 1
Select case when DATEPART(hour, t.DateTime) between 8 and 16 then 'A' else 'B' end AS Shift, *
from Table1 t
where t.DateTime between DateAdd(hour, 8, Convert(date, GetDate() - #days))
and DateAdd(hour, 30, Convert(date, GetDate() - #days))
ORDER BY 1, t.DateTime
It seems that you have two shifts per day and the day shift begins before the night shift. So, let's enumerate the shifts and let you choose the one(s) you want that way:
select t.*
from (select t.*,
row_number() over (partition by cast(sp.datetime as date)
order by sp.datetime
) as shiftnumber
from table t
) t
where DATEDIFF(day, CAST(GETDATE() as DATE), CAST(SP.DateTime as DATE)) = -1 and
shiftnumber = 1;
Note that I also changed the date arithmetic. The conversion to dates uses the built-in DATE type. Converting a date to a string and back to a date is inelegant.