I use this function
Public Shared Function ChangeOpacity(ByVal img As Image, ByVal opacityvalue As Single) As Bitmap
Dim bmp As New Bitmap(img.Width, img.Height)
Dim graphics__1 As Graphics = Graphics.FromImage(bmp)
Dim colormatrix As New colormatrix
colormatrix.Matrix33 = opacityvalue
Dim imgAttribute As New ImageAttributes
imgAttribute.SetColorMatrix(colormatrix, ColorMatrixFlag.[Default], ColorAdjustType.Bitmap)
graphics__1.DrawImage(img, New Rectangle(0, 0, bmp.Width, bmp.Height), 0, 0, img.Width, img.Height, _
GraphicsUnit.Pixel, imgAttribute)
graphics__1.Dispose()
Return bmp
End Function
I use this command
picturebox.Image = ChangeOpacity(picturebox.Image, 0.3)
This is work ,The picturebox's opacity is fade out.
but when I try this
picturebox.Image = ChangeOpacity(picturebox.Image, 1.0)
It is nothing happen , The picture is still fade out I want to return picture into default
How to fix this ?
Thank you very much
Load the image form file like this
PictureBox1.Image = Image.FromFile("C:\Documents and
Settings\User3\Desktop\Sathish\image\calendar-icon-reportdate.png")
And use the call opacity like this
PictureBox1.Image.Dispose()
PictureBox1.Image = ChangeOpacity(Image.FromFile("C:\Documents and
Settings\User3\Desktop\Sathish\image\calendar-icon-reportdate.png"), 0.3)
PictureBox1.Image.Dispose()
PictureBox1.Image = ChangeOpacity(Image.FromFile("C:\Documents and
Settings\User3\Desktop\Sathish\image\calendar-icon-reportdate.png"), 1)
The second parameter in ChangeOpacity() function is the Opacity Percentage or factor of the picture in first parameter.
So (1.0) will not change the Opacity, it will return the picture without changes.
You have to multiply the previous opacity value to have (1) and return the picture into default OR reload your image from the source with the default opacity to first parameter.
In your example
The_Current_Opacity * Opacity_Factor = 1
0.3 * Opacity_Factor = 1
use: picturebox.Image = ChangeOpacity(picturebox.Image, 3.3)
I prefer the division (1/0.3). It's more accurate than ( 3.3).
Here is the code and you can do the math
dim OpacityPercentage as Single
OpacityPercentage = 0.3
'To fade out the picturebox's opacity
picturebox1.Image = ChangeOpacity(picturebox1.Image, OpacityPercentage )
'To return picture into default
picturebox1.Image = ChangeOpacity(picturebox1.Image, 1/OpacityPercentage )
Related
I need it so that in my code if something evaluates to true it changes the image location and size.
This is my code so far:
With picValueTwentySix
.Location = New Point(302, 134)
.Size = New System.Drawing.Size(169, 40)
.SizeMode = PictureBoxSizeMode.Zoom
End With
Anybody know why it isn't re-sizing?
Thanks!
As everyone has already mentioned, you need to work the the image. Here is a function I made up for ease of use.
Public Function ResizeImage(ByVal image As Image, ByVal size As Size, Optional ByVal preserveAspectRatio As Boolean = True) As Image
Try
Dim newWidth As Integer
Dim newHeight As Integer
If preserveAspectRatio Then
Dim originalWidth As Integer = image.Width
Dim originalHeight As Integer = image.Height
Dim percentWidth As Single = CSng(size.Width) / CSng(originalWidth)
Dim percentHeight As Single = CSng(size.Height) / CSng(originalHeight)
Dim percent As Single = IIf(percentHeight < percentWidth, percentHeight, percentWidth)
newWidth = CInt(originalWidth * percent)
newHeight = CInt(originalHeight * percent)
Else
newWidth = size.Width
newHeight = size.Height
End If
Dim newImage As Image = New Bitmap(newWidth, newHeight)
Using graphicsHandle As Graphics = Graphics.FromImage(newImage)
graphicsHandle.InterpolationMode = InterpolationMode.HighQualityBicubic
graphicsHandle.DrawImage(image, 0, 0, newWidth, newHeight)
End Using
Return newImage
Catch ex As Exception
Return image
End Try
End Function
Basically it creates a new blank graphic to the dimensions you request, then copies the original image to it while scaling it to fit. I think if you step throw it a line at a time you should be pretty self explanatory, but ask if you have questions...
As stated by #Plutonix, changing the Picturebox size will not affect the image size itself, you have to make sure the actual image size is bigger than the size of the picture box, set the size mode of the picturebox to stretchimage, in this case once you resize the picture box the change will reflect. Also refresh the picture box after resizing.
I'm working on making a paint-esq image manipulator in VB.Net, and I'm still new to vb. I want the user to be able to upload an image and make adjustments to it, such as adding lines and text. I also want the user to be able to transfer the drawings and text they added to a different baseimage. For example, if the user draws a dog on top of a picture of a park, they can change it so the dog is on a street instead.
I've been messing with the idea of loading the image as the picturebox.backgroundImage, but running into difficulties changing the backgroundImage without reseting the drawings and with croping the image. I've also been dabling in having two pictureboxes with the one on top for drawings, but I'm running into transparency and cropping issues
Here is the code I'm using to establish my picturebox by setting the base image as .backgroundImage
Private Sub LoadImage(thisImage As Image)
'we set the picturebox size according to image, we can get image width and height with the help of Image.Width and Image.height properties.
img.BackgroundImage = thisImage 'c'
img.Image = New Bitmap(thisImage.Width, thisImage.Height) 'c'
img.BorderStyle = BorderStyle.FixedSingle
End Sub
example of the image maniputlation
Private Sub ButtonDone_Click(sender As Object, e As EventArgs) Handles ButtonDone.Click, DoneToolStripMenuItem.Click
Cursor = Cursors.Default
Select Case LCase(stateFlag)
Case "header"
'Reset stuff back to normal
ButtonHeader.Text = "Header"
stateFlag = ""
Cancel_Button.Enabled = False
'set up space to draw on the image
Dim newBm As New Bitmap(img.Image.Width, img.Image.Height)
' First we define a rectangle with the help of already calculated points
Dim newGraphics As Graphics = Graphics.FromImage(newBM) ' create graphics
newGraphics.InterpolationMode = Drawing2D.InterpolationMode.HighQualityBicubic
newGraphics.PixelOffsetMode = Drawing2D.PixelOffsetMode.HighQuality
newGraphics.CompositingQuality = Drawing2D.CompositingQuality.HighQuality
'set image attributes
newGraphics.DrawImage(img.Image, New Rectangle(0, 0, img.Image.Width + 1, img.Image.Height + 1), _
0, 0, img.Image.Width + 1, img.Image.Height + 1, GraphicsUnit.Pixel)
'Draw Edges for header
newGraphics.DrawLine(Pens.Black, startPoint.X, borderSize - 20, startPoint.X, borderSize - 50)
newGraphics.DrawLine(Pens.Black, endPoint.X, borderSize - 20, endPoint.X, borderSize - 50)
Dim drawFont As New Font("Times New Roman", 12)
Dim drawBrush As New SolidBrush(Color.Black)
Dim stringSize As SizeF = newGraphics.MeasureString(HeaderLabel.Text, drawFont)
' Draw header label inbetween the two edges.
newGraphics.DrawString(HeaderLabel.Text, drawFont, drawBrush, (startPoint.X + endPoint.X) / 2 - (stringSize.Width / 2), borderSize - 45)
img.Image = newBm
PushUndo(img.Image.Clone)
End Sub
I would advise trying the following method to use one picturebox on top of the other, it is a lot simpler than some other methods. In your form load handler, do something like:
pctBackground.BackgroundImage = Bitmap.FromFile("park.jpg")
pctForeground.BackColor = Color.Transparent
pctForeground.Parent = pctBackground
pctForeground.Image = New Bitmap(pctForeground.ClientSize.Width, pctForeground.ClientSize.Height)
Then when you have drawn on the pctForeground, save it like:
pctForeground.Image.Save("dog_in_park.png", System.Drawing.Imaging.ImageFormat.Png)
I've been working on obtaining the ROI of an image, I'm trying to get a square shaped box that will hoover around the region an be able to click and get the standard deviation. I'm familiar with c so i used the c to VB converter, but im getting errors that the statement is not valid in namespace. Everything seems to compatible to VB code. I will be grateful for any suggestions on this matter. Thanks
Private Function DrawRoi(Image As Bitmap, rect As RectangleF) As oid
Dim roi As New Rectangle()
roi.X = CInt(CSng(Image.Width) * rect.X)
roi.Y = CInt(CSng(Image.Height) * rect.Y)
roi.Width = CInt(CSng(Image.Width) * rect.Width)
roi.Height = CInt(CSng(Image.Height) * rect.Height)
Dim timer As New Stopwatch()
timer.Start()
' graphics manipulation takes about 240ms on 1080p image
Using roiMaskImage As Bitmap = CreateRoiMaskImage(ImageWithRoi.Width, ImageWithRoi.Height, roi)
Using g As Graphics = Graphics.FromImage(ImageWithRoi)
g.DrawImage(Image, 0, 0)
g.DrawImage(roiMaskImage, 0, 0)
Dim borderPen As Pen = CreateRoiBorderPen(ImageWithRoi)
g.DrawRectangle(borderPen, roi)
End Using
End Using
Debug.WriteLine("roi graphics: {0}ms", timer.ElapsedMilliseconds)
Me.imagePictureBox.Image = ImageWithRoi
End Function
Private Function CreateRoiMaskImage(width As Integer, height As Integer, roi As Rectangle) As Bitmap
Dim image As New Bitmap(width, height, PixelFormat.Format32bppArgb)
Using g As Graphics = Graphics.FromImage(image)
Dim dimBrush As New SolidBrush(Color.FromArgb(64, 0, 0, 0))
g.FillRectangle(dimBrush, 0, 0, width, height)
Dim roiBrush As New SolidBrush(Color.Red)
g.FillRectangle(roiBrush, roi)
image.MakeTransparent(Color.Red)
Return image
End Using
End Function
I am struggling with the following problem: I have a small picture with is painted in red. This color must be changed to another color (users'choice). I used msdn and some googling did the following:
Private Function GetPicture(Iterator As Integer, tempfile As String) As String
Dim Rstring = ""
If Colors.Count = 0 OrElse Iterator >= Colors.Count Then
Rstring = tempfile
Else
Dim NewPicture = My.Computer.FileSystem.GetTempFileName()
My.Computer.FileSystem.CopyFile(tempfile, NewPicture, True)
Dim mypict = New Bitmap(NewPicture)
Dim ColorList As New List(Of Color)
For x = 0 To mypict.Width - 1
For y = 0 To mypict.Height - 1
Dim mypixel = mypict.GetPixel(x, y)
If ColorList.Contains(mypixel) = False Then
ColorList.Add(mypixel)
End If
Next
Next
Dim NewColor = Color.FromArgb(255, 0, 0, 255)
Dim ListOfColorMaps As New List(Of ColorMap)
For Each elem In ColorList
Dim newcolormap = New ColorMap
newcolormap.OldColor = elem
newcolormap.NewColor = NewColor
ListOfColorMaps.Add(newcolormap)
Next
Dim imageAttributes As New ImageAttributes()
Dim width As Integer = mypict.Width
Dim height As Integer = mypict.Height
Dim colorMap As New ColorMap()
'colorMap.OldColor = Color.FromArgb(255, 0, 0, 0) ' opaque red
'colorMap.NewColor = Color.FromArgb(255, 0, 0, 255) ' opaque blue
Dim remapTable As ColorMap() = ListOfColorMaps.ToArray
imageAttributes.SetRemapTable(remapTable, ColorAdjustType.Bitmap)
Dim tempBmp = New Bitmap(width, height)
Dim g = Graphics.FromImage(tempBmp)
g.DrawImage(tempBmp, New Rectangle(0, 0, width, height), 0, 0, width, height, GraphicsUnit.Pixel, imageAttributes)
g.Save()
g.Dispose()
mypict.Dispose()
Dim NewFileName = NewPicture.Remove(NewPicture.IndexOf("."c) - 1) & ".png"
tempBmp.Save(NewFileName, Imaging.ImageFormat.Png)
My.Computer.FileSystem.DeleteFile(NewPicture)
tempBmp.Dispose()
Rstring = NewPicture
End If
Return Rstring
The Code runs without exceptions, and it seems to find the desired colors but the saved tempbmp contains no picture. Does this happen because the code runs in a dll without graphic?
You can pretty much ignore the "IF" part - that has something to do with another usecase.
Greetings and sincere thanks
Christian Sauer
You are getting no picture displayed because you are drawing an empty bitmap.
Your problem starts here:
Dim tempBmp = New Bitmap(width, height)
Dim g = Graphics.FromImage(tempBmp)
g.DrawImage(tempBmp, New Rectangle(0, 0, width, height), 0, 0, width, height, _
GraphicsUnit.Pixel, imageAttributes)
You create a new bitmap (probably with a white background).
Then you create a new Graphics object from your empty bitmap.
Then you draw the empty bitmap onto itself.
What you should be doing is drawing the mypict object (which is the bitmap whose colors you want to change). Thus your third line should be as follows:
g.DrawImage(mypict, New Rectangle(0, 0, width, height), 0, 0, width, height, _
GraphicsUnit.Pixel, imageAttributes)
Since the Graphics object g is associated with tempBmp (which is empty prior to the DrawImage operation) drawing mypict will draw to it with your parameters.
One other recommendation is that you remove the g.Save() line. You save a graphics object when you plan to restore it later. Doing a Graphics.Save() does not save a picture. What really saves the changes you have made is the tempBmp.Save() line.
I have problem with Graphics.RotateTransfrom() with the following code :
Dim newimage As Bitmap
newimage = System.Drawing.Image.FromFile("C:\z.jpg")
Dim gr As Graphics = Graphics.FromImage(newimage)
Dim myFontLabels As New Font("Arial", 10)
Dim myBrushLabels As New SolidBrush(Color.Black)
Dim a As String
'# last 2 number are X and Y coords.
gr.DrawString(MaskedTextBox2.Text * 1000 + 250, myFontLabels, myBrushLabels, 1146, 240)
gr.DrawString(MaskedTextBox2.Text * 1000, myFontLabels, myBrushLabels, 1146, 290)
a = Replace(Label26.Text, "[ mm ]", "")
gr.DrawString(a, myFontLabels, myBrushLabels, 620, 1509)
a = Replace(Label5.Text, "[ mm ]", "")
gr.DrawString(a, myFontLabels, myBrushLabels, 624, 548)
gr.RotateTransform(90.0F)
gr.DrawString(a, myFontLabels, myBrushLabels, 0, 0)
PictureBox1.Image = newimage
I dont know why but my image in pictureBox1 is not rotated. Someone known solution ?
The issue at hand is that the RotateTransform method does not apply to the existing image.
Instead, it applies to the transformation matrix of the graphics object. Basically, the transformation matrix modifies the coordinate system used to add new items.
Try the following :
Dim gfx = Graphics.FromImage(PictureBox1.Image)
gfx.DrawString("Test", Me.Font, Brushes.Red, New PointF(10, 10))
gfx.RotateTransform(45)
gfx.DrawString("Rotate", Me.Font, Brushes.Red, New PointF(10, 10))
The first string is drawn normally, while the second is drawn rotated.
So what you need to do is create a new graphics object, apply your rotation, draw your source image onto the graphics (graphics.DrawImage), and then draw all your text :
' Easy way to create a graphisc object
Dim gfx = Graphics.FromImage(PictureBox1.Image)
gfx.Clear(Color.Black)
gfx.RotateTransform(90) ' Rotate by 90°
gfx.DrawImage(Image.FromFile("whatever.jpg"), New PointF(0, 0))
gfx.DrawString("Test", Me.Font, Brushes.Red, New PointF(10, 10))
gfx.DrawString("Rotate", Me.Font, Brushes.Red, New PointF(10, 10))
But beware of rotation, you'll find that you need to change the coordinates at which you draw your image (Or change the RenderingOrigin property of the graphics, setting it to the center of the image makes it easier to handle rotations), otherwise your picture won't be visible (it will be drawn, but off the visible part of the graphics).
Hope that helps