I am writing a subroutine in VBA to cycle through all the listed job numbers in a multi-tab time sheet and create a list of all job numbers that have been used (so it takes the original list (with possibly multiple job number occurrences) and creates a list with only one occurrence of each job number. The job numbers on each sheet are found in range("A8:A30"). The code below seems to work for the first several job names on the sample that I'm testing, but then seems to stop filtering. A8:A21 of the first sheet is:
14GCI393
14GCI393
13GCI373
13GCI373
13GCI388
13GCI367:2
14GCI408
14GCI408
13GCI373
13GCI388
14GCI415
14GCI415
00GCI000
And the code is:
Sub listusedjobs()
Dim usedjobs() As String
Dim nextjob As String
Dim i, m, n, lastsheetindexnumber As Integer
Application.ScreenUpdating = False
lastsheetindexnumber = ThisWorkbook.Sheets.Count
m = 0
ReDim usedjobs(m)
usedjobs(m) = "initialize"
For i = 1 To lastsheetindexnumber
Sheets(i).Activate
For n = 8 To 30
nextjob = Range("A" & n).Value
If Not IsInArray(nextjob, usedjobs) Then 'determine if nextjob is already in usedjobs()
ReDim usedjobs(m)
usedjobs(m) = nextjob 'Add each unique job to array "usedjobs"
Sheets(lastsheetindexnumber).Cells(m + 40, 1).Value = nextjob 'Print job name that was just added
m = m + 1
End If
Next n
Next i
Application.ScreenUpdating = True
End Sub
Function IsInArray(stringToBeFound As String, arr As Variant) As Boolean
IsInArray = (UBound(Filter(arr, stringToBeFound, , vbTextCompare)) > -1)
End Function
Any help figuring out what is going wrong will be much appreciated! The current output I get for this code is below and contains multiple doubles.
14GCI393
13GCI373
13GCI388
13GCI367:2
14GCI408
13GCI373
13GCI388
14GCI415
00GCI000
I think that your problem may be not using ReDim Preserve inside your If Not
Related
I am creating a third party add in for my CAD program that has a sub in it that goes through a drawing and finds all the parts lists (BOMS), if any items in the parts list are shared between the BOM (1 part being used in 2 weldments for example) then it changes the item number of the second instance to be that of the first instance. It does this by comparing full file names between the two values. When they match change the number to that of the matcher. I have got this to work but it runs a little slow because for a 100 item BOM each item is compared to 100 and thus that takes a little longer then I would like (about 60seconds to run). After thinking about it I realized I did not need to compare each item to all the items, I just needed to compare until it found a duplicate and then exit the search loop and go to the next value. Example being Item 1 does not need to compare to the rest of the 99 values because even if it does have a match in position 100 I do not want to change item 1s number to that of item 100. I want to change item 100 to that of 1(ie change the duplpicate to that of the first encountered double). For my code however I am having trouble exiting the comparison for loops which is causing me trouble. An example of the trouble is this:
I have 3 BOMs, each one shares Part X, and is numbered 1 in BOM 1, 4 in BOM 2, and 7 in BOM 3. when I run my button because I cannot get it to leave the comparison loop once it finds it first match all the Part X's ended up getting item number 7 from BOM 3 because it is the last instance. (I can get this to do what I want by stepping through my for loops backwards and thus everything ends up as the top most occurrence, but I would like to get my exit fors working because it saves me on unnecessary comparisons)
How do I go about breaking out of the nested for loops using an if conditional?
Here is my current code:
Public Sub MatchingNumberR1()
Debug.Print ThisApplication.Caption
'define active document as drawing doc. Will produce an error if its not a drawing doc
Dim oDrawDoc As DrawingDocument
Set oDrawDoc = ThisApplication.ActiveDocument
'Store all the sheets of drawing
Dim oSheets As Sheets
Set oSheets = oDrawDoc.Sheets
Dim oSheet As Sheet
'Loop through all the sheets
For Each oSheet In oSheets
Dim oPartsLists As PartsLists
Set oPartsLists = oSheet.PartsLists
'Loop through all the part lists on that sheet
Dim oPartList As PartsList
'For every parts list on the sheet
For Each oPartList In oPartsLists
For i3 = 1 To oPartList.PartsListRows.Count
'Store the Item number and file referenced in that row to compare
oItem = FindItem(oPartList)
oDescription = FindDescription(oPartList)
oDescripCheck = oPartList.PartsListRows.Item(i3).Item(oDescription).Value
oNumCheck = oPartList.PartsListRows.Item(i3).Item(oItem).Value
'Check to see if the BOM item is a virtual component if it is do not try and get the reference part
If oPartList.PartsListRows.Item(i3).ReferencedFiles.Count = 0 Then
oRefPart = " "
End If
'Check to see if the BOM item is a virtual component if it is try and get the reference part
If oPartList.PartsListRows.Item(i3).ReferencedFiles.Count > 0 Then
oRefPart = oPartList.PartsListRows.Item(i3).ReferencedFiles.Item(1).FullFileName
End If
MsgBox (" We are comparing " & oRefPart)
'''''Create a comparison loop to go through the drawing that checks the oRefPart against other BOM items and see if there is a match.'''''
'Store all the sheets of drawing
Dim oSheets2 As Sheets
Set oSheets2 = oDrawDoc.Sheets
Dim oSheet2 As Sheet
'For every sheet in the drawing
For Each oSheet2 In oSheets2
'Get all the parts list on a single sheet
Dim oPartsLists2 As PartsLists
Set oPartsLists2 = oSheet2.PartsLists
Dim oPartList2 As PartsList
'For every parts list on the sheet
For Each oPartList2 In oPartsLists2
oItem2 = FindItem(oPartList2)
oDescription2 = FindDescription(oPartList2)
'Go through all the rows of the part list
For i6 = 1 To oPartList2.PartsListRows.Count
'Check to see if the part is a not a virtual component, if not, get the relevent comparison values
If oPartList2.PartsListRows.Item(i6).ReferencedFiles.Count > 0 Then
oNumCheck2 = oPartList2.PartsListRows.Item(i6).Item(oItem2).Value
oRefPart2 = oPartList2.PartsListRows.Item(i6).ReferencedFiles.Item(1).FullFileName
'Compare the file names, if they match change the part list item number for the original to that of the match
If oRefPart = oRefPart2 Then
oPartList.PartsListRows.Item(i3).Item(1).Value = oNumCheck2
''''''''This is where I want it to exit the loop and grab the next original value'''''''
End If
'For virtual components get the following comparison values
ElseIf oPartList2.PartsListRows.Item(i6).ReferencedFiles.Count = 0 Then
oNumCheck2 = oPartList2.PartsListRows.Item(i6).Item(oItem2).Value
oDescripCheck2 = oPartList2.PartsListRows.Item(i6).Item(oDescription2).Value
'Compare the descriptions and if they match change the part list item number for the original to that of the match
If oDescripCheck = oDescripCheck2 Then
oPartList.PartsListRows.Item(i3).Item(1).Value = oNumCheck2
''''''''This is where I want it to exit the loop and grab the next original value'''''''
End If
Else
''''''''This is where if no matches were found I want it to continue going through the comparison loop'''''''
End If
Next
Next
Next
Next
Next
Next
'MsgBox ("Matching Numbers has been finished")
End Sub
For escape from nested for loop you can use GoTo and specify where.
Sub GoToTest()
Dim a, b, c As Integer
For a = 0 To 1000 Step 100
For b = 0 To 100 Step 10
For c = 0 To 10
Debug.Print vbTab & b + c
If b + c = 12 Then
GoTo nextValueForA
End If
Next
Next
nextValueForA:
Debug.Print a + b + c
Next
End Sub
Here are a few examples that demonstrate (1) breaking out of (exiting) a loop and (2) finding the values in arrays.
The intersection of 2 arrays example can be modified to meet your need to "Create a comparison loop to go through the drawing that checks the oRefPart against other BOM items and see if there is a match." Note, you may find multiple matches between 2 arrays.
Option Explicit
Option Base 0
' Example - break out of loop when condition met.
Public Sub ExitLoopExample()
Dim i As Integer, j As Integer
' let's loop 101 times
For i = 0 To 100:
j = i * 2
'Print the current loop number to the Immediate window
Debug.Print i, j
' Let's decide to break out of the loop is some
' condition is met. In this example, we exit
' the loop if j>=10. However, any condition can
' be used.
If j >= 10 Then Exit For
Next i
End Sub
' Example - break out of inner loop when condition met.
Public Sub ExitLoopExample2()
Dim i As Integer, j As Integer
For i = 1 To 5:
For j = 1 To 5
Debug.Print i, j
' if j >= 2 then, exit the inner loop.
If j >= 2 Then Exit For
Next j
Next i
End Sub
Public Sub FindItemInArrayExample():
' Find variable n in array arr.
Dim intToFind As Integer
Dim arrToSearch As Variant
Dim x, y
intToFind = 4
arrToSearch = Array(1, 2, 3, 4, 5, 6, 7, 8, 9)
x = FindItemInArray(FindMe:=intToFind, _
ArrayToSearch:=arrToSearch)
If IsEmpty(x) Then
Debug.Print intToFind; "not found in arrToSearch"
Else
Debug.Print "found "; x
End If
intToFind = 12
y = FindItemInArray(FindMe:=intToFind, _
ArrayToSearch:=arrToSearch)
If IsEmpty(y) Then
Debug.Print intToFind; "not found in arrToSearch"
Else
Debug.Print "found "; y
End If
End Sub
Public Function FindItemInArray(FindMe, ArrayToSearch As Variant):
Dim i As Integer
For i = LBound(ArrayToSearch) To UBound(ArrayToSearch)
If FindMe = ArrayToSearch(i) Then
FindItemInArray = ArrayToSearch(i)
Exit For
End If
Next i
End Function
' Create a comparison loop to go through the drawing that checks
' the oRefPart against other BOM items and see if there is a match.
Public Sub ArrayIntersectionExample():
Dim exampleArray1 As Variant, exampleArray2 As Variant
Dim arrIntersect As Variant
Dim i As Integer
' Create two sample arrays to compare
exampleArray1 = Array(1, 2, 3, 4, 5, 6, 7)
exampleArray2 = Array(2, 4, 6, 8, 10, 12, 14, 16)
' Call our ArrayIntersect function (defined below)
arrIntersect = ArrayIntersect(exampleArray1, exampleArray2)
' Print the results to the Immediate window
For i = LBound(arrIntersect) To UBound(arrIntersect)
Debug.Print "match " & i + 1, arrIntersect(i)
Next i
End Sub
Public Function ArrayIntersect(arr1 As Variant, arr2 As Variant) As Variant:
' Find items that exist in both arr1 and arr2 (intersection).
' Return the intersection as an array (Variant).
Dim arrOut() As Variant
Dim matchIndex As Long
Dim i As Long, j As Long
' no matches yet
matchIndex = -1
' begin looping through arr1
For i = LBound(arr1) To UBound(arr1)
' sub-loop for arr2 for each item in arr1
For j = LBound(arr2) To UBound(arr2)
' check for match
If arr1(i) = arr2(j) Then
' we found an item in both arrays
' increment match counter, which we'll
' use to size our output array
matchIndex = matchIndex + 1
' resize our output array to fit the
' new match
ReDim Preserve arrOut(matchIndex)
' now store the new match our output array
arrOut(matchIndex) = arr1(i)
End If
Next j
Next i
' Have the function return the output array.
ArrayIntersect = arrOut
End Function
Good afternoon,
I am working on an innovative project and cannot seem to figure out the logic of what I need to do. Essentially, I am trying to assign a number of employees to tasks (right now just filling in numbers instead of their names and the actual tasks). Here is a basic look at what the spreadsheet looks like
Task | Task Location | Task Materials | Difficulty | Assignee | Employee List
There are currently 45 tasks, and 30 employees. What I need to do is:
Randomly assort the list of employees to randomize who is doing what
Check to see IF the employee has already been scheduled for 2 tasks, as everybody should have AT LEAST one with nobody having less than two
Loop through the "Employee List" column, IF the Task is blank AND the Employee hasn't been scheduled for more than 2 tasks already, copy that current value from Employee List into Assignee column.
I know this is vague, but I really would appreciate the help. I think the steps are three fold:
Randomize Employee List column
Assign each employee once
Re-randomize employee list
Check to see which tasks still need assigning, and then check to see if the employee has already been scheduled for 2, and, if not, assign them
If they have, skip over and move to the next one
Could anybody help me devise a solution? Here is my current code, which sorts the column, and works well:
Sub ShufflePA()
Application.ScreenUpdating = False
Dim tempString As String, tempInteger As Integer, i As Integer, j As Integer, lastRow As Integer
With Sheets("Test")
lastRow = .Range("F" & .Rows.count).End(xlUp).Row
End With
For i = 6 To lastRow
Cells(i, 7).Value = WorksheetFunction.RandBetween(0, 1000)
Next i
For i = 6 To lastRow
For j = i + 1 To lastRow
If Cells(j, 7).Value < Cells(i, 7).Value Then
'change the string, which is the pa column...
tempString = Cells(i, 6).Value
Cells(i, 6).Value = Cells(j, 6).Value
Cells(j, 6).Value = tempString
tempInteger = Cells(i, 7).Value
Cells(i, 7).Value = Cells(j, 7).Value
Cells(j, 7).Value = tempInteger
End If
Next j
Next i
Worksheets("Test").Range("N:N").EntireColumn.Delete
Application.ScreenUpdating = True
End Sub
I recognize I'll likely need some more subs, and would be willing to work with anybody who could help me. In advance, thank you very much. I am struggling to develop the logic to accomplish what I need.
Try this method for randomly assigning your employees.
Note: You will need to assign your employee column to an array
Here is the Function that will take an array of your employees, and output a random name:
Function randomEmployee(ByRef employeeList As Variant) As String
'Random # that will determine the employee chosen
Dim Lotto As Long
Lotto = randomNumber(LBound(employeeList), UBound(employeeList))
randomEmployee = employeeList(Lotto)
'Remove the employee from the original array before returning it to the sub
Dim retArr() As Variant, i&, x&, numRem&
numRem = UBound(employeeList) - 1
ReDim retArr(numRem)
For i = 0 To UBound(employeeList)
If i <> Lotto Then
retArr(x) = employeeList(i)
x = x + 1
End If
Next i
Erase employeeList
employeeList = retArr
End Function
Notice how I used ByRef? This was intentional because it will replace the input array you provided with a new array that contains all the names, except the one that the function used to give you your random name.
You will also need this function to choose your random number that is called in the above function:
Function randomNumber(ByVal lngMin&, ByVal lngMax&) As Long
'Courtesy of https://stackoverflow.com/a/22628599/5781745
randomNumber = Int((lngMax - lngMin + 1) * Rnd + lngMin)
End Function
This was the test sub I had used. Obviously, you don't want to keep my empListArr, but I kept it there so you can see how this works.
Sub test()
Dim empListArr()
empListArr = Array("Bob", "Joe", "Erin", "Amber")
Debug.Print "Employee Chosen: " & randomEmployee(empListArr)
Dim i As Long
For i = 0 To UBound(empListArr)
Debug.Print "Remaining Employee: ";
Debug.Print empListArr(i)
Next
End Sub
Again, the Test() sub is not intended to be added to your code. It serves as a general guide on using your array of employees with the randomEmployee function.
So put your tasks in a loop, assigning each task one at a time with the randomEmployee function. This function will remove the employees as they are assigned.
Once your array of employees are exhausted you need to reassign your entire column of employees to your array again, so ensure you include a system that checks if your array is empty or not.
Edit:
I performed a test on the randomNumber function just to see how "random" it actually was, using a range between 0 to 10 on a million lines:
Each result hit roughly 9.1%, so it appears to be pretty reliable.
I have a function meant to return an array which is created out of a single-column list of data. I have been using this function's return value essentially as a pseudo-global variable (LINENAMES_ARRAY) which I pass to many functions. Those functions than do checks on it such as If Len(Join(LINENAMES_ARRAY)) = 0 Then or go through items with For Each statements. Here is the code:
Function LINENAMES_ARRAY() As Variant
'returns an array of all items in the main sheet linenames column
LINENAMES_ARRAY = Application.Transpose(MAIN.Range( _
MAIN.Cells(MAIN_HEAD_COUNT + 1, MAIN_LINENAMES_COLUMN), _
MAIN.Cells(LINENAMES_COUNT + 1, MAIN_LINENAMES_COLUMN)))
End Function
I recently stumbled on one of those you-don't-see-it-till-you-see-it problems while using this workbook for a new project, where if the array happens to be only 1 element, everything fails. Apparently in that case, this returns a single value so Join() will fail For Each __ in LINENAMES_ARRAY will too. Why won't it treat this as a 1x1 array rather than a free value? I have started to mitigate the problem by rewriting functions where this is called, to check whether it is an array, then do some other procedure. Things like:
For j = 1 To LINENAMES_COUNT
LINES_BOX.AddItem lineNames(j)
Next j
is changed to:
If Not IsArray(LINENAMES_ARRAY) Then
myListBox.AddItem CStr(LINENAMES_ARRAY)
Else
For j = 1 To LINENAMES_COUNT
LINES_BOX.AddItem LINENAMES_ARRAY(j)
Next j
End If
However this becomes messy and is adding many extra checks to my code that I would prefer to handle in the LINENAMES_ARRAY function. Is there a way to return a 1x1 array? Or any other workaround?
An array can have a single element if you create it as a single element array and populate it in an array manner.
Option Explicit
Dim MAIN_HEAD_COUNT As Long
Dim LINENAMES_COUNT As Long
Dim MAIN_LINENAMES_COLUMN As Long
Dim MAIN As Worksheet
Sub stuff()
Dim arr As Variant
Set MAIN = Worksheets("Sheet1")
MAIN_LINENAMES_COLUMN = 2
MAIN_HEAD_COUNT = 2
LINENAMES_COUNT = 2
arr = LINENAMES_ARRAY()
Debug.Print IsArray(arr)
Debug.Print LBound(arr) & ":" & UBound(arr)
End Sub
Function LINENAMES_ARRAY() As Variant
Dim a As Long, tmp() As Variant
ReDim tmp(0 To LINENAMES_COUNT - MAIN_HEAD_COUNT)
For a = 0 To LINENAMES_COUNT - MAIN_HEAD_COUNT
tmp(a) = MAIN.Range(MAIN.Cells(MAIN_HEAD_COUNT + 1, MAIN_LINENAMES_COLUMN), _
MAIN.Cells(LINENAMES_COUNT + 1, MAIN_LINENAMES_COLUMN)).Cells(a).Value2
Next a
'returns an array of all items in the main sheet linenames column
LINENAMES_ARRAY = tmp
End Function
Results from the VBE's Immediate window:
True
0:0
I have been trying to get this VBA script to work to automate a task, but I cannot get it to work.
Basically, I have a big task list in excel with multiple columns and over 1000 Rows. It contains the task, who it is assigned to, and if it is open or closed.
In column H is who it assigned to and column N is whether the task is opened or closed.
I am trying to search by last name and if it is OPEN to add one to the counter. The end goal is to get a total count of how many open tasks a person has. Also, some of the cells in column N (task status) has extra text like comments, etc. I am sure that a InStr Function to search for the one word within the Cell would work better, but I cannot figure it out...
here is my code
Sub statuscount()
Dim tasksheet As Worksheet
Dim simons_count As Integer
Set tasksheet = ThisWorkbook.Sheets("tasks")
lr = tasksheet.Cells(Rows.Count, 1).End(xlUp).Row
For x = 5 to lr
If tasksheet.Cells(x, 8) = "Simons" And tasksheet.Cells(x, 14) = "OPEN" Then
simons_count = simons_count + 1
End If
Next x
tasksheet.Range("$O$5").Value = simons_count
End Sub
Thanks for the help!
Using If/And gets tricky in VBA, you're better off nesting two if statements:
For x = 5 to lr
If tasksheet.Cells(x, 8) = "Simons" Then
If InStr(tasksheet.Cells(x, 14).Value, "OPEN") > 0 Then
simons_count = simons_count + 1
End If
End If
Next x
This is a more general function. Insert a module and past the below code in it. Than you can use the function just like any other Excel built-in function
Function LastNamecounter(lastName As String, status As String) As Long
LastNamecounter = 0
Dim tasksheet As Worksheet
Set tasksheet = ThisWorkbook.Sheets("tasks")
lr = tasksheet.Cells(Rows.Count, 1).End(xlUp).Row
For i = 5 To lr
If InStr(tasksheet.Cells(i, 8).Value, lastName) <> 0 And InStr(tasksheet.Cells(i, 14).Value, status) <> 0 Then
LastNamecounter = LastNamecounter + 1
End If
Next i
End Function
I have a database that has in excess on 200,000 rows. When I was writing a VBA script I had a database of about 20,000 rows in mind so I didn't care whether the database was filtered or not because the VBA script ran quickly. So given the realization that the database is huge and testing the VBA script I was surprised to notice how slowly it ran. So without further to say this is how my code looks like :
Set wsDB = ThisWorkbook.Sheets("DB")
Dim nameIndex As Long: nameIndex = Application.Match(name, wsDB.Rows(1), 0)
Dim formula As String
formula = "=IFERROR(AVERAGEIFS(" + GRA(nameIndex) + "," + GRA(dateIndex) + ",R2C," + GRA(cellNameIndex) + ",RC1" + "),"""")"
where GRA is a function that returns the address of the range of a column.
Private Function GRA(ByRef rngIndex As Long)
GRA = "DB!" + CStr(Range(Cells(2, rngIndex), Cells(rowNos, rngIndex)).Address(1, 1, xlR1C1, 0, 0))
End Function
So given that I now filter the table beforehand how can I adjust my code so that it ignores all the hidden rows and takes into account only what is visible. Of course I am aware that a simple dirty solution would be to simply copy the filter database and paste it in a new sheet but that will affect the performance which is what I'm trying to improve.
You can use the following function to return a range of only visible cells.
Function VisibleCells(Rng As Range) As Variant
Dim R As Range
Dim Arr() As Integer
Dim RNdx As Long
Dim CNdx As Long
If Rng.Areas.Count > 1 Then
VisibleCells = CVErr(xlErrRef)
Exit Function
End If
ReDim Arr(1 To Rng.Rows.Count, 1 To Rng.Columns.Count)
For RNdx = 1 To Rng.Rows.Count
For CNdx = 1 To Rng.Columns.Count
Set R = Rng(RNdx, CNdx)
If (R.EntireRow.Hidden = True) Or _
(R.EntireColumn.Hidden = True) Then
Arr(RNdx, CNdx) = 0
Else
Arr(RNdx, CNdx) = 1
End If
Next CNdx
Next RNdx
VisibleCells = Arr
End Function
The above code came from http://www.cpearson.com/excel/VisibleCells.aspx.
Normally I would only post code that I write however this does exactly what I was thinking.