How to capture the unique identifier after the insert [duplicate] - sql

Question

This question already has answers here:
How do I return a new IDENTITY column value from an SQLServer SELECT statement?
(7 answers)
Closed 8 years ago.
I have to create new email records in an existing table in the joining table I would like to update a field that would denote that this is a new record.
Example:
INSERT INTO dbo.email.email (dbo.email.eml_address, dbo.email.eml_customer_key)
SELECT new_email, new_customer_key
FROM NEW_TABLE
Update dbo.email_ext
Set dbo.email_ext.new_eml = '1'
Where dbo.email_ext.eml_key_ext = 'Recently create key from insert statement shown above'

Answer 1

You'll want to use the SCOPE_IDENTITY() value, this will contain the ID of the record just created, but only one.
Assuming you're handling ONE record:
DECLARE #ID INT
INSERT INTO dbo.email (eml_address, eml_customer_key)
SELECT new_email, new_customer_key
FROM NEW_TABLE
SET #ID = SCOPE_IDENTITY()
Update dbo.email_ext
Set new_eml = '1'
Where eml_key_ext = #ID
If you're inserting multiples you need to output the list into a table (in this case a table variable) and you can update them all at once.
DECLARE #myIDs TABLE (NEWID INT)
INSERT INTO dbo.email (eml_address, eml_customer_key)
OUTPUT inserted.ID INTO #myIDs
SELECT new_email, new_customer_key
FROM NEW_TABLE
Update t
Set new_eml = '1'
from dbo.email_ext t
join #myIDs m
on t.eml_key_ext = m.ID

Answer 2

Use an OUTPUT clause to capture autogenerated ids/guids/defaults/etc.
CREATE TABLE #test (
id int identity(1,1) primary key,
uid uniqueidentifier DEFAULT NEWID(),
value varchar(max)
)
INSERT #test (value)
OUTPUT inserted.*
SELECT 'test'
id guid value
----------- ------------------------------------ ---------
1 72B70577-2679-4C2A-A575-62D30807B9D2 test
(1 row(s) affected)