Select Where Date Between - sql

Question

I would like to SELECT a table calendar and combine the results with the days of the month.
I mean,
Table: Calendar
ID TEAM EMPLOYER START END
17 19 8 04/08/2014 18:01:00 11/08/2014 07:59:00
18 19 39 11/08/2014 18:01:00 18/08/2014 07:59:00
19 19 44 18/08/2014 18:01:00 25/08/2014 07:59:00
20 19 38 25/08/2014 18:01:00 01/09/2014 07:59:00
And I have a SELECT for the days of the month.
Select Days.Dt
From (Select Trunc(To_Date('2014', 'YYYY'), 'y') - 1 + Rownum Dt
From All_Objects
Where Rownum <= Add_Months(Trunc(To_Date('2014', 'YYYY'), 'y'), 12) -
Trunc(To_Date('2014', 'YYYY'), 'y')) Days
Where To_Char(Dt, 'mm/yyyy') = '08/2014'
What I want is something like this:
DAY EMPLOYER_END EMPLOYER_START
1 01/08/2014
2 02/08/2014
3 03/08/2014
4 04/08/2014 4
5 05/08/2014 4 4
6 06/08/2014 4 4
7 07/08/2014 4 4
8 08/08/2014 4 4
9 09/08/2014 4 4
10 10/08/2014 4 4
11 11/08/2014 4 39
12 12/08/2014 39 39
The employer starts at 18:01 (always) and end at 07:59 (always).
Does anyone know if it's possible?
And the way I can do that.
Thanks!

Answer 1

Your desired results do not match your sample data. However, I think you want something like this:
with dates as (
Select Days.Dt
From (Select Trunc(To_Date('2014', 'YYYY'), 'y') - 1 + Rownum Dt
From All_Objects
Where Rownum <= Add_Months(Trunc(To_Date('2014', 'YYYY'), 'y'), 12) -
Trunc(To_Date('2014', 'YYYY'), 'y')
) Days
Where To_Char(Dt, 'mm/yyyy') = '08/2014'
)
select d.dt,
sum(case when c.employer_start = d.ddt then 0 else 1 end) as employer_end,
sum(case when c.employer_end = d.dt then 1 else 0 end) as employer_start
from dates d left outer join
calendar c
on d.dt between c.employer_start and c.employer_end
group by d.dt
order by d.dt;

Answer 2

I guess this can be useful to you
WITH mindates AS
(SELECT TRUNC(MIN(startdate),'month') st_date,
TRUNC(MAX(enddate)) ed_date
FROM calendar
) ,
dates AS
(SELECT st_date+ rownum-1 AS dates_col
FROM mindates,
dual
CONNECT BY rownum <= (ed_date- st_date)+1
)
SELECT d.dates_col dates,
MIN((
CASE
WHEN d.dates_col=c.startdate
THEN NULL
ELSE c.employer
END)) AS employer_end,
MIN((
CASE
WHEN d.dates_col=c.enddate
THEN NULL
ELSE c.employer
END )) AS employer_start
FROM dates d
LEFT OUTER JOIN calendar c
ON d.dates_col BETWEEN c.startdate AND c.enddate
GROUP BY d.dates_col
ORDER BY d.dates_col;