How to make a picturebox hide when dragged over another picturebox? - vb.net-2010

Question

So I nailed the ability to drag a picturebox around the Windows form. I need it to hide itself when it's dragged and dropped over another picture. I've tried a few methods but none seem to work and I am now back at square one, the only code I have is so that I can move the picturebox around the form.

Answer 1

I Solved Your Problem
Here Is How The Form Should Look Like
And Here Is The Code I Made:
Private Sub CheckTimer_Tick(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles CheckTimer.Tick
CheckTimer.Stop()
CheckTimer.Interval = 1
If PictureBox2.Location = New System.Drawing.Point(TextBox1.Text, TextBox2.Text) Then
PictureBox2.Visible = False
End If
CheckTimer.Start()
End Sub
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
TextBox1.Text = PictureBox1.Location.X
TextBox2.Text = PictureBox1.Location.Y
CheckTimer.Start()
End Sub
Hope This Code Was Helpful To You.

Answer 2

I made an better code than the old one, try it.
Here Is How The Form Should Look Like:
and here is the code :
Public Class Form1
Dim Point As New Point
Dim X, Y As Integer
Private Sub Timer1_Tick(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Timer1.Tick
Timer1.Stop()
Timer1.Interval = 1
Point = Cursor.Position
PictureBox2.Location = New System.Drawing.Point(Point.X - X, Point.Y - Y)
Timer1.Start()
End Sub
Private Sub PictureBox2_MouseDown(ByVal sender As Object, ByVal e As System.Windows.Forms.MouseEventArgs) Handles PictureBox2.MouseDown
X = Cursor.Position.X - PictureBox2.Location.X
Y = Cursor.Position.Y - PictureBox2.Location.Y
Timer1.Start()
End Sub
Private Sub PictureBox2_MouseUp(ByVal sender As Object, ByVal e As System.Windows.Forms.MouseEventArgs) Handles PictureBox2.MouseUp
Timer1.Stop()
If PictureBox2.Location.X < PictureBox1.Size.Width Then
PictureBox2.Visible = False
End If
End Sub
End Class
I hope this code was useful to you.