How can I get String values rather than integer - vb.net

Question

How To get StartString And EndString
Dim startNumber As Integer
Dim endNumber As Integer
Dim i As Integer
startNumber = 1
endNumber = 4
For i = startNumber To endNumber
MsgBox(i)
Next i
Output: 1,2,3,4
I want mo make this like sample: startString AAA endString AAD
and the output is AAA, AAB, AAC, AAD

Answer 1

This is a simple function that should be easy to understand and use. Every time you call it, it just increments the string by one value. Just be careful to check the values in the text boxes or you can have an endless loop on your hands.
Function AddOneChar(Str As String) As String
AddOneChar = ""
Str = StrReverse(Str)
Dim CharSet As String = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
Dim Done As Boolean = False
For Each Ltr In Str
If Not Done Then
If InStr(CharSet, Ltr) = CharSet.Length Then
Ltr = CharSet(0)
Else
Ltr = CharSet(InStr(CharSet, Ltr))
Done = True
End If
End If
AddOneChar = Ltr & AddOneChar
Next
If Not Done Then
AddOneChar = CharSet(0) & AddOneChar
End If
End Function
Private Sub Button1_Click(sender As Object, e As EventArgs) Handles Button1.Click
Dim S = TextBox1.Text
Do Until S = TextBox2.Text
S = AddOneChar(S)
MsgBox(S)
Loop
End Sub

Answer 2

This works as a way to all the codes given an arbitrary alphabet:
Public Function Generate(starting As String, ending As String, alphabet As String) As IEnumerable(Of String)
Dim increment As Func(Of String, String) = _
Function(x)
Dim f As Func(Of IEnumerable(Of Char), IEnumerable(Of Char)) = Nothing
f = _
Function(cs)
If cs.Any() Then
Dim first = cs.First()
Dim rest = cs.Skip(1)
If first = alphabet.Last() Then
rest = f(rest)
first = alphabet(0)
Else
first = alphabet(alphabet.IndexOf(first) + 1)
End If
Return Enumerable.Repeat(first, 1).Concat(rest)
Else
Return Enumerable.Empty(Of Char)()
End If
End Function
Return New String(f(x.ToCharArray().Reverse()).Reverse().ToArray())
End Function
Dim results = New List(Of String)
Dim text = starting
While True
results.Add(text)
If text = ending Then
Exit While
End If
text = increment(text)
End While
Return results
End Function
I used it like this to produce the required result:
Dim alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
Dim results = Generate("S30AB", "S30B1", alphabet)
This gave me 63 values:
S30AB
S30AC
...
S30BY
S30BZ
S30B0
S30B1
It should now be very easy to modify the alphabet as needed and to use the results.

Answer 3

One option would be to put those String values into an array and then use i as an index into that array to get one element each iteration. If you do that though, keep in mind that array indexes start at 0.
You can also use a For Each loop to access each element of the array without the need for an index.

Answer 4

if the default first two string value of your output is AA.
You can have a case or if-else conditioning statement :
and then set 1 == A 2 == B...
the just add or concatenate your default two string and result string of your case.

Answer 5

I have tried to understand that you are looking for a series using range between 2 textboxes. Here is the code which will take the series and will give the output as required.
Dim startingStr As String = Mid(TextBox1.Text, TextBox1.Text.Length, 1)
Dim endStr As String = Mid(TextBox2.Text, TextBox2.Text.Length, 1)
Dim outputstr As String = String.Empty
Dim startNumber As Integer
Dim endNumber As Integer
startNumber = Asc(startingStr)
endNumber = Asc(endStr)
Dim TempStr As String = Mid(TextBox1.Text, 1, TextBox1.Text.Length - 1)
Dim i As Integer
For i = startNumber To endNumber
outputstr = outputstr + ", " + TempStr + Chr(i)
Next i
MsgBox(outputstr)
The First two lines will take out the Last Character of the String in the text box.
So in your case it will get A and D respectively
Then outputstr to create the series which we will use in the loop
StartNumber and EndNumber will be give the Ascii values for the character we fetched.
TempStr to Store the string which is left off of the series string like in our case AAA - AAD Tempstr will have AA
then the simple loop to get all the items fixed and show

Answer 6

in your case to achive goal you may do something like this
Dim S() As String = {"AAA", "AAB", "AAC", "AAD"}
For Each el In S
MsgBox(el.ToString)
Next
FIX FOR PREVIOUS ISSUE
Dim s1 As String = "AAA"
Dim s2 As String = "AAZ"
Dim Last As String = s1.Last
Dim LastS2 As String = s2.Last
Dim StartBase As String = s1.Substring(0, 2)
Dim result As String = String.Empty
For I As Integer = Asc(s1.Last) To Asc(s2.Last)
Dim zz As String = StartBase & Chr(I)
result += zz & vbCrLf
zz = Nothing
MsgBox(result)
Next
**UPDATE CODE VERSION**
Dim BARCODEBASE As String = "SBA0021"
Dim BarCode1 As String = "SBA0021AA1"
Dim BarCode2 As String = "SBA0021CD9"
'return AA1
Dim FirstBarCodeSuffix As String = Replace(BarCode1, BARCODEBASE, "")
'return CD9
Dim SecondBarCodeSuffix As String = Replace(BarCode2, BARCODEBASE, "")
Dim InternalSecondBarCodeSuffix = SecondBarCodeSuffix.Substring(1, 1)
Dim IsTaskCompleted As Boolean = False
For First As Integer = Asc(FirstBarCodeSuffix.First) To Asc(SecondBarCodeSuffix)
If IsTaskCompleted = True Then Exit For
For Second As Integer = Asc(FirstBarCodeSuffix.First) To Asc(InternalSecondBarCodeSuffix)
For Third As Integer = 1 To 9
Dim tmp = Chr(First) & Chr(Second) & Third
Console.WriteLine(BARCODEBASE & tmp)
If tmp = SecondBarCodeSuffix Then
IsTaskCompleted = True
End If
Next
Next
Next
Console.WriteLine("Completed")
Console.Read()
Take a look into this check it and let me know if it can help