Extract text from string starting and ending by specific char - vba

Question

I've got the code below which is extracting a string from brackets and it's ok, but now I've found out that sometimes in my string there can be more brackets with texts behind and I need to extract them too. For instance, a list or table.
e.g
hsus(irt)bla dsd (got)(rifk)
I need then: irt, got, rifk to list, how to do it?
Public Function extract_value(str As String) As String
dim str as string
dim openPos as integer
dim closePos as integer
dim midBit as string
str = "sometinhf(HELLO)sds"
openPos = instr (str, "(")
closePos = instr (str, ")")
midBit = mid (str, openPos+1, closePos - openPos - 1)
End Function

Answer 1

Sub Main()
Dim s$
s = "hsus(irt)bla dsd (got)(rifk)"
Debug.Print extract_value(s)
End Sub
Public Function extract_value$(s$)
Dim returnS$
Dim v
v = Split(s, Chr(40))
For Each Item In v
If InStr(Item, Chr(41)) Then
returnS = returnS & Chr(32) & Split(Item, ")")(0)
End If
Next
extract_value = Trim$(returnS)
End Function

Answer 2

You can use a Regexp to extract the matching strings directly
Sub Main()
Dim strTest as string
strTest = "hsus(irt)bla dsd (got)(rifk)"
MsgBox GrabIt(strTest)
End Sub
Function GrabIt(strIn As String) As String
Dim objRegex As Object
Dim objRegMC As Object
Dim objRegM As Object
Set objRegex = CreateObject("vbscript.regexp")
With objRegex
.Pattern = "\((.*?)\)"
.Global = True
If .test(strIn) Then
Set objRegMC = .Execute(strIn)
For Each objRegM In objRegMC
GrabIt = GrabIt & Chr(32) & objRegM.submatches(0)
Next
End If
End With
End Function