I have Minutes 140. Which in hours and minutes becomes 2:20.
In this case i would love to get 2.33.
What i've tried:
select cast(140/60 as varchar(8)) + '.' + cast((140 % 60) as varchar(8))
Outputs: 2.20
select 140/60
Outputs: 2
select cast(140/60 as decimal(5,2))
Outputs: 2.00
What am i missing?
How do i convert 140 minutes to represent hours decimally?
Sorry about the quick comment, i'll try to explain a little more clearly about this.
By default, Sql will "think" that both your dividend & divisor are INT data type, that's why it returns 2.
If you specify the number with decimal, like this :
select (140.00/60.00)
now the data type is not int any more, and the result is : 2.3333333
So, you will need to convert one of the data type to float, decimal, numeric(n, n) to get the accurate result :
select cast(140 as decimal(5, 2)) / cast(60 as decimal(5, 2))
But you still can just convert only dividend or divisor, like this :
select 140 / cast(60 as decimal(5, 2))
or
select cast(140 as decimal(5, 2)) / 60
they both gave the same result, becasue the result type is the data type of the argument with the higher precedence, in this case, decimal has the higher precedence than int
you can read more here :
Divide
Data Type Precedence
Try this
Select convert(decimal(5,2),convert(float,140)/60)
or
Select cast(140.00/60 as decimal(5,2))
Related
SELECT ROUND(CEILING(36.3) / 4,2)
SELECT ROUND(37 / 4,2)
The first query returns 9.25. The second query returns 9.
Ceiling(36.3) would have returned 37. Why would there be such differences then?
The difference is due to the return type from operations. When you call Ceiling on any number or expression, the return type is of same type as the expression.
Let's look at the first one:
Ceiling(36.3) -> returns a decimal
This means that the division operation is also done on decimals which means you get a decimal result and thus could be rounded.
In the second statement, you are dividing 2 integers which would also result in a integer result (just the quotient). Thus the value will only be 9.
SELECT ROUND(CEILING(36.3) / 4,2) -- select round(decimal/int,int) => select round(decimal, int)
SELECT ROUND(37 / 4,2) -- select round(int/int,int) => select round(int, int)
You would get similar result when you do this:
SELECT ROUND((CEILING(36.3) / 4),2)
SELECT ROUND((cast(37 as decimal(10,2)) / 4),2)
I am having an issue converting a decimal such as 0.33333, which needs to show as 20 minutes. Using the formula I have it is showing as 19 minutes. I hope someone can assist please. Thank you. Currently the code I am using example.
declare #value float = 0.3333333
select
Cast(CONVERT(VARCHAR, CONVERT(INT, Floor(cast(#VALUE as Decimal (10,2)))))
+ '.' + CONVERT (VARCHAR, CONVERT(INT, (cast(#value as Decimal (10,2)) - Floor(cast(#VALUE as Decimal (10,2)))) * 60.0)) as Decimal(10,2)) [hh.mm],
cast(#value as money) [DecimalHours]
-- integer part -- fractional part -- final rounding
cast(floor(#value) + ((#value - floor(#value)) * 0.6) as dec(18,2))
Works for more than 24 hours
Probably a lot easier when you use a date/time function:
SELECT FORMAT( DATEADD(n,ROUND(60.0 * #value,0) ,0) , 'HH:mm')
I have a Table in SQL server with a column "Time" having data type as time(7). Need to call the sum of this column, and when I use the following statement, it returns result as integer only.
Eg. If total time is 1:30:00,I expect result as 1.5. But the code I use doesn't get me this, it get me result as 1. Please check if you have a solution.
The code I used is
SELECT SUM(DATEPART(ss,Time) + DATEPART(mi,Time)*60 + DATEPART(hh,Time)*3600)/3600 AS TotalTime FROM dbo.Table
SELECT (
DATEPART(hh,Time) +
DATEPART(mi,Time) / 60.0 +
DATEPART(ss,Time) / 3600.0
) AS TotalTime
FROM dbo.Table
Try below - you don't need sum() function here and in your case, it is showing 1 because your result is 5400/3600 which is 1 but you need to add a float value as you are expecting float result
SELECT (DATEPART(ss,'1:30:00') + DATEPART(mi,'1:30:00')*60 +
DATEPART(hh,'1:30:00')*3600)/3600.00
AS TotalTime FROM dbo.Table
Try this, you can change the datepart argument based on your needs here is the full list
SELECT SUM(CAST(DATEDIFF(MINUTE, '00:00:00', [Time]) as float)/60) AS TotalHours FROM [dbo].[Table]
When you divide some value by int type, the result will be also int (the fraction is just dropped). Therefore, you need to convert a divider of 3600 from int to decimal:
SELECT SUM(DATEPART(ss,Time) + DATEPART(mi,Time)*60 + DATEPART(hh,Time)*3600)/CONVERT(DECIMAL(16,4), 3600) AS TotalTime FROM dbo.Table
If you want the difference in decimal hours, then do the following:
Convert the time values to seconds.
Sum the seconds.
Divide by 60 * 60
So:
select sum(datediff(second, 0, v.t)) / (60.0 * 60)
from (values (convert(time, '00:10:01')),
(convert(time, '01:00:03'))
) v(t)
There is no reason to break the value in to component parts. That just seems unnecessarily complicated.
How do I code format the return data in 2 decimals and with percentage format like 100.00% or 67.39% instead of 100.000000 or 67.391304?
SUM(qa.scripting1+qa.conduct1+qa.conduct2+qa.conduct3)*100.0/46 as 'C%'
I tried ROUND() but I got the error stating that the round function requires 2 to 3 arguments?
ROUND(SUM(qa.scripting1+qa.conduct1+qa.conduct2+qa.conduct3)*100.0/46) as 'C%'
Thanks!
You can convert to a decimal your original value:
CONVERT(VARCHAR(20), CONVERT(DECIMAL(18,2), SUM(qa.scripting1+qa.conduct1+qa.conduct2+qa.conduct3)*100.0/46) ) + '%' as 'C%'
The first number in the decimal represents the number of digits in the number including decimal places, and the second number represents the number of decimal places.
You should pass number of decimals in second parameter to round function. For formating you can cast number to money and then cast to varchar:
select cast(cast(ROUND(SUM(123.12321)*100.0/46, 2) as money) as varchar) + '%'
Using Round and Cast will work. First round to 2 decimal places then convert to a decimal with 2 places to truncate the excess zeros.
select cast(Round(yourValue, 2) as decimal(18,2))
Sql Fiddle
You can use Format function
select FORMAT(100.0000, 'N' , 'en-us')
returns 100.00
and
select FORMAT(67.391304, 'N' , 'en-us')
returns 67.39
EDIT
In version below 2012 you can do this
SELECT CAST(67.391304 AS NUMERIC(10, 2))
returns 67.39
You can just do:
select FORMAT(0.391304, '##0.00%')
But keep in mind that it implicitly multiplies by 100, so the above will display as 39.13%.
I am calculating total hours/minutes but i would like to get rid off the decimals and only show something like this 2.00 hours or 2.5 hours etc. I am getting now something like this: 2.000000 and want only to limit to 2 decimals only.
select DATEDIFF(minute, Min(FullDatetime), Max(FullDatetime)) / 60.0 as hours
from myTable
where userid = 123
You can do it by rounding but the easiest is to format for output using FORMAT().
select FORMAT(DATEDIFF(minute, Min(FullDatetime), Max(FullDatetime)) / 60.0, 'N2') as hours
from myTable
where userid = 123
Helpful original documentation: here
try use
cast('values' as decimal(18,2)) --2 decimal place.
select Cast((DATEDIFF(minute, Min(FullDatetime), Max(FullDatetime)) / 60.0 as hours)as decimal(18,2))
from myTable
where userid = 123
There are a few options out there.
I prefer to use the following when no rounding is needed
FORMAT(value, 'N2')
SQL - Rounding off to 2 decimal places
how to get 2 digits after decimal point in tsql?
just use ROUND function such as : SELECT ROUND(columnName,decimals) from table
You could use STR or CONVERT function:
DECLARE #v NUMERIC(19, 6)
SET #v = 2.189189
SELECT STR(#v, 19, 2) AS Method1_Result_VARCHAR, CONVERT(NUMERIC(15, 2), #v) AS Method2_Result_NUMERIC
/*
Method1_Result_VARCHAR Method2_Result_NUMERIC
---------------------- ----------------------
2.19 2.19
*/
Note: First argument of STR function has float type and this means that 1) SQL Server will convert this argument from numeric to float and 2) method 1 uses a non-deterministic expression.