I have a table:
[letter] [Name] [status] [price]
A row1 1 11
A row1 1 15
B row2 2 9
B row2 3 23
B row2 3 30
And want to select data something like this:
SELECT letter, Name,
COUNT(*),
CASE WHEN price>10 THEN COUNT(*) ELSE NULL END
GROUP BY letter, Name
the result is:
A row1 2 2
B row2 1 null
B row2 2 2
But I want this format:
A row1 2 2
B row2 3 2
Please, help me to modify my query
Close. Probably want this instead:
SELECT letter, Name,
COUNT(*),
SUM(CASE WHEN price>10 THEN 1 ELSE 0 END)
FROM TableThatShouldHaveAppearedInTheQuestionInTheFromClause
GROUP BY letter, Name
should work. Assuming that the intention of the fourth column is to return the count of the number of rows, within each group, with a price greater than 10. It's also possible to do this as a COUNT() over a CASE then returns non-NULL and NULL results for the rows that should and should not be counted, but I find the above form easier to quickly reason about.
Since nulls are not used in aggregate functions:
SELECT letter
, name
, count(*)
, count(
case when price > 10 then 1
end
)
FROM t
GROUP BY letter, name
You were very close.
Looking to the other answers, probably this is not the best way, but it will work.
The count of the prices over 10 is made with a subquery which has a condition on price > 10 and which is joined to the current TAB record with the alias A for the same letter and name.
SELECT letter,
Name,
COUNT(*),
(SELECT COUNT(*) FROM TAB WHERE letter = A.letter and Name = A.Name WHERE price>10)
FROM TAB A
GROUP BY letter, Name
Related
Say I have this table t:
id value
1 1 10
2 2 3
3 1 55
4 1 20
5 2 98
When drawing from t I want to add a column value2 that equals value when id == 2, otherwise 0
I tried
select id, value, max(case when id = 2 then value else 0) from t
but it did not work
Not sure why you included a max in your attempt but based on your description, this is all you should need.
select id, value, case when id = 2 then value else 0 end as value2
from t;
It sounds like you want a conditional window aggregate:
select
id,
value,
max(case when id = 2 then value end) over ()
from t;
I have a table like this
Table1
=======
A B
8 5
2 9
null 4
2 5
How to find total number of rows from table1,note if any column value is null in a row then that row should be considered as 2 rows?
I have tried with count(*)*2 and nvl function it doesn't work
Try this
SELECT SUM(CASE WHEN A IS NULL OR B IS NULL THEN 2 ELSE 1 END) AS CountVal
FROM TABLE1
Fiddle Demo
O/P:
COUNTVAL
--------
5
COUNT() is rowbased.. you can tweak it using SUM() instead..
select sum(NVL2(a,NVL2(b,1,2),2)) FROM TABLE1
CASE as suggested by #Vignesh is the simplest and more readable !!
COUNT() can also done like this.. But NOT a optimal solution at all!
SELECT COUNT(1) FROM
(
SELECT NVL(a,NVL(b,1)) FROM TABLEA
UNION ALL
SELECT NVL(a,NVL(b,1)) FROM TABLEA
WHERE A OR B iS NULL
)
id Name claim priority
1 yatin 70 5
6 yatin 1 10
2 hiren 30 3
3 pankaj 40 2
4 kavin 50 1
5 jigo 10 4
7 jigo 1 10
this is my table and i want to arrange this table as shown below
id Name claim priority AlternateFlag
1 yatin 70 5 0
6 yatin 1 10 0
2 hiren 30 3 1
3 pankaj 40 2 0
4 kavin 50 1 1
5 jigo 10 4 0
7 jigo 1 10 0
It is sorted as alternate group of same row.
I am Using sql server 2005. Alternate flag starts with '0'. In my example First record with name "yatin" so set AlternateFlag as '0'.
Now second record has a same name as "yatin" so alternate flag would be '0'
Now Third record with name "hiren" is single record, so assign '1' to it
In short i want identify alternate group with same name...
Hope you understand my problem
Thanks in advance
Try
SELECT t.*, f.AlternateFlag
FROM tbl t
JOIN (
SELECT [name],
AlternateFlag = ~CAST(ROW_NUMBER() OVER(ORDER BY MIN(ID)) % 2 AS BIT)
FROM tbl
GROUP BY name
) f ON f.name = t.name
demo
You could use probably an aggregate function COUNT() and then HAVING() and then UNION both Table, like:
SELECT id, A.Name, Claim, Priority, 0 as AlternateFlag
FROM YourTable
INNER JOIN (
SELECT Name, COUNT(*) as NameCount
FROM YourTable
GROUP BY Name
HAVING COUNT(*) > 1 ) A
ON YourTable.Name = A.Name
UNION ALL
SELECT id, B.Name, Claim, Priority, 1 as AlternateFlag
FROM YourTable
INNER JOIN (
SELECT Name, COUNT(*) as NameCount
FROM YourTable
GROUP BY Name
HAVING COUNT(*) = 1 ) B
ON YourTable.Name = B.Name
Now, this assumes that the Names are unique meaning the names like Yatin for example although has two counts is only associated to one person.
See my SqlFiddle Demo
You can use Row_Number() function with OVER that will give you enumeration, than use the reminder of integer division it by 2 - so you'll get 1s and 0s in your SELECT or in the view.
I'd like to get the max integer from a specific column excluding a value that will always be the max if present. Data may look like the following:
score, empid
1 3
3 3
10 3
1 5
2 5
1 8
2 8
3 8
10 8
In the above, I'd like MAX score less than 10. MAX(score) doesn't work in this case since it will bring back 10. Results should look like this:
score, empid
3 3
2 5
3 8
Any suggestions?
Here's an alternative method:
SELECT
MAX(CASE WHEN score = 10 THEN NULL ELSE score END) AS [max_score],
empid
FROM
table
GROUP BY
empid
This may be preferable if you prefer to avoid the sub-select.
select max(score) , empid
from table
where score < (select max(score) from table )
group by empid
Following Ben English's answer, if you are excluding only 1 value, you can also use NULLIF for less typing.
SELECT MAX(NULLIF(score, 10)), ...
FROM ...
GROUP BY ...
With CASE WHEN it's possible to exclude a range of values. Here we exclude all scores more than 10:
SELECT MAX(CASE WHEN score > 10 THEN NULL ELSE score), ...
FROM ...
GROUP BY ...
And here is the IIF version for less typing:
SELECT MAX(IIF(score > 10, NULL, score)), ...
FROM ...
GROUP BY ...
I'm struggling to find a solution to the following problem.
Assume, one has a table like this
COL1 FLAG
aaa 1
aaa 0
aaa 1
bbb 0
I need to write a query to get the following output:
COL1_VALUE FLAGGED TOTAL
aaa 2 3
bbb 0 1
where FLAGGED column contains the total count of the 'aaa' row values for which FLAG=1, and TOTAL column is the total number of rows containing 'aaa', in other words find how many rows containing 'aaa' are flagged in relation to total number of rows containing 'aaa'. Is it possible with a single query? (i.e. without using temp tables etc.)
(MSSQL2008)
SELECT COL1 AS COL1_VALUE,
COUNT(CASE WHEN FLAG = 1 THEN 1 END) AS FLAGGED,
COUNT(*) AS TOTAL
FROM YourTable
GROUP BY COL1
SELECT COL1, SUM(FLAG) AS FLAGGED, Count(*) AS TOTAL from tbl GROUP BY COL1
SELECT Tab.COL1 AS COL1_VALUE,
SUM(CASE WHEN Tab.FLAG = 1 THEN 1 ELSE 0 END) AS FLAGGED,
COUNT(*) AS TOTAL
FROM Tab
GROUP BY Tab.COL1