I have this column
NAME
John Stephenson
James Martin
Anna Corelia
How I can select this column to this?
NAME
Stephenson, John
Martin, James
Corelia, Anna
One way
;with test(name) as (
select 'John Stephenson' union all
select 'James Martin' union all
select 'Anna J. Corelia' union all
select 'BOBBYTABLES'
)
select
case when charindex(' ', name) = 0 then name
else right(name, charindex(' ', reverse(name)) - 1) + ', ' + substring(name, 1, len(name) - charindex(' ', reverse(name))) end
from test
(No column name)
Stephenson, John
Martin, James
Corelia, Anna J.
BOBBYTABLES
Your question has nothing to do with TRIM() function. Probably you are trying to get something like below using LEFT() and RIGHT() function of SQL Server and concatanating them with ,
select right('John Stephenson',(len('John Stephenson')-charindex(' ','John Stephenson')))
+ ', ' + left('John Stephenson',(charindex(' ','John Stephenson') - 1))
which will result in
Stephenson, John
Here is a solution including how I got the final output column.
This will handle three part names, like "Rip Van Winkle", also names with no white space and will strip (trim) any leading/trailing white space from the names.
DECLARE #NAMES TABLE (NAME NVARCHAR(MAX))
INSERT INTO #NAMES (NAME) VALUES ('John Stephenson'),('James Martin'),('Anna Corelia'),('Rip Van Winkle'),('Sally')
SELECT *,
CHARINDEX(' ',LTRIM(RTRIM(NAME))) [SpaceLocation],
CASE WHEN CHARINDEX(' ',LTRIM(RTRIM(NAME)))>0 THEN RIGHT(LTRIM(RTRIM(NAME)), LEN(LTRIM(RTRIM(NAME)))-CHARINDEX(' ',LTRIM(RTRIM(NAME)))) END [LastName],
CASE WHEN CHARINDEX(' ',LTRIM(RTRIM(NAME)))>0 THEN LEFT(LTRIM(RTRIM(NAME)),CHARINDEX(' ',LTRIM(RTRIM(LTRIM(RTRIM(NAME)))))-1) END [FirstName],
CASE WHEN CHARINDEX(' ',LTRIM(RTRIM(NAME)))>0 THEN RIGHT(LTRIM(RTRIM(NAME)), LEN(LTRIM(RTRIM(NAME)))-CHARINDEX(' ',LTRIM(RTRIM(NAME)))) + ', ' +LEFT(LTRIM(RTRIM(NAME)),CHARINDEX(' ',LTRIM(RTRIM(NAME)))-1) ELSE LTRIM(RTRIM(NAME)) END [FinalOutput]
FROM #NAMES
SELECT substring(NAME+', '+NAME,charindex(' ',NAME)+1,len(NAME)+1) FROM MyTable
This also turns "Rip Van Winkle" into "Van Winkle, Rip"
SQL Fiddle Demo
There is no a single trim function but you can
select ltrim(rtrim(colname)) from tablename
which will TRIM both sides.
but what you need is:
declare #name varchar(300) ='Stephenson John';
Select
Substring(#name, 1,Charindex(' ', #name)-1) +
', ' +
Substring(#name, Charindex(' ', #name)+1, LEN(#name))
as name
Sorry I miss post
Related
I have the following select that is converting a name from Lastname, Firstname format into Firstname Lastname format. It seems to be adding extra white space between the first name and the last name
SELECT substring(D.NAME, charindex(',', replace(D.NAME, ' ', '')) + 1, len(D.NAME))
+ ' '
+ left(D.NAME, charindex(',', D.NAME) -1) AS First_Last
FROM TEST_TABLE D
Here are a few examples of the output I'm getting now:
Johnnyyy Smithsonnn
Kimmey Test1
Denise Stuffing
Desired Format (single space between first and last name):
Johnnyyy Smithsonnn
Kimmey Test1
Denise Stuffing
I tend to like this technique. In this example we use a rare replacement pattern of †‡, but you can use <> and ><
Note: The outer ltrim(rtrim( ... )) is optional, I keep it as a "just in case".
Example
Select NewValue = ltrim(rtrim(replace(replace(replace([Name],' ','†‡'),'‡†',''),'†‡',' ')))
From YourTable
Returns
NewValue
Johnnyyy Smithsonnn
Kimmey Test1
Denise Stuffing
Maybe there are names with or without , or with or without spaces after the ,, or other inconsistencies.
Anyway you can use ltrim(rtrim()) before concatenating:
select
case
when d.name like '%,%' then
ltrim(rtrim(substring(d.name, charindex(',', name) + 1, len(d.name))))
+ ' ' +
ltrim(rtrim(left(D.NAME, charindex(',', d.name) -1)))
when d.name like '% %' then
ltrim(rtrim(substring(d.name, charindex(' ', name) + 1, len(d.name))))
+ ' ' +
ltrim(rtrim(left(D.NAME, charindex(' ', d.name) -1)))
else ltrim(rtrim(d.name))
end AS First_Last
Try:
select ltrim(rtrim(left(D.NAME, charindex(',', D.NAME, 0) - 1)))
+ ' '
+ ltrim(rtrim(right(D.NAME, len(D.NAME) - charindex(',', D.NAME, 0))))
from TEST_TABLE D
This worked on some test data I used below:
insert into #Test ([Name]) values ('Johnnyyy, Smithsonnn')
insert into #Test ([Name]) values ('Kimmey, Test1')
insert into #Test ([Name]) values ('Denise, Stuffing')
Which gives the intended result:
Johnnyyy Smithsonnn
Kimmey Test1
Denise Stuffing
I think you intend to do the replace of spaces after extracting the name. So:
SELECT (replace(left(D.NAME, charindex(',', D.NAME + ',') + 1), ' ', '') +
' ' +
left(D.NAME, charindex(',', D.NAME + ',') - 1)
) AS First_Last
FROM TEST_TABLE D;
This also adds a comma for the charindex() so the comma is optional.
I have to get the forename from the c.forename if c.known_as column is null or blank.
This i achieved with case when statement using
CASE
WHEN IND.KNOWN_AS IS NULL OR ind.KNOWN_AS=''
THEN ind.FORENAMES
ELSE ind.KNOWN_AS
END AS 'Known As'
My issue is in the forename column i have name like Jhon Smith where i would like to extract only John, below is an example what i want to achieve
Desire output c.forename
John Mr John
Jhon Jhon Smith
blank Jo
blank J
So , basically it will only take forname skipping 'Mr', 2nd it should take only forename which has more than 2 character.
My current query is:
Select ind.FORENAMES,
ind.KNOWN_AS,
case when (known_as is null or known_as = '' ) and charindex(' ', forenames) > 2
then substring(forenames, 1, charindex(' ', forenames) - 1) end as FORENAMES2,
output
from individual ind
join member m on m.individual_ref=ind.individual_ref
and m.MEMBERSHIP_NO in ('001','002','003','004','005','006','007')
where m.member_status=33
You could use following case when statement to verify your conditions:
For SQL Server:
case when (c.known_as is null or c.known_as = '' )
and charindex(' ', c.forename) > 3 then substring(c.forename, 1, charindex(' ', c.forename) - 1) end
For MySQL:
case when (c.known_as is null or c.known_as = '' )
and locate(' ', c.forename) > 3 then substring(c.forename, 1, locate(' ', c.forename) - 1) end
Little explanation: if the first name must be longer than 2 characters, that means that first space must occur at least at index 4. And that what the condition is about: locate(' ', c.forename) > 3 or substring(' ', c.forename) > 3
NOTE
You have to first strip down all occurences of Mr, Mrs, Ms in c.forename column, like this (syntax for MySQL and SQL Server):
replace(replace(replace(c.forename, 'Mrs ', ''), 'Mr ', ''), 'Ms ', '')
You have to include it in your query lke this:
Select FORENAMES,
KNOWN_AS,
case when (known_as is null or known_as = '' ) and charindex(' ', FORENAMES2) > 2
then substring(FORENAMES2, 1, charindex(' ', FORENAMES2) - 1) end as FORENAMES2,
output
from (
Select ind.FORENAMES,
ind.KNOWN_AS,
replace(replace(replace(ind.FORENAMES, 'Mrs ', ''), 'Mr ', ''), 'Ms ', '') FORENAMES2,
output
from individual ind
join member m on m.individual_ref = ind.individual_ref
where m.member_status=33
and m.MEMBERSHIP_NO in ('001','002','003','004','005','006','007')
)
Try this:
DECLARE #DataSource TABLE
(
[name] VARCHAR(32)
);
INSERT INTO #DataSource ([name])
VALUES (' Mr John ')
,('Jhon Smith')
,(' Jo ')
,(' J ');
WITH SanitizeDataSoruce ([name], [name_reversed]) AS
(
SELECT LTRIM(RTRIM([name]))
,REVERSE(LTRIM(RTRIM([name])))
FROM #DataSource
)
SELECT [name]
,CASE
WHEN CHARINDEX(' ', [name]) > 1 THEN REVERSE(SUBSTRING([name_reversed], 0, CHARINDEX(' ', [name_reversed])))
ELSE ''
END
FROM SanitizeDataSoruce;
I have a list of customer whose name is given as a full name.
I want to create a function that takes the full name as parameter and returns the first and last name separately. If this is not possible I can have two separate functions one that returns the first name and the other that returns the last name. The full name list contains names that have a maximum of three words.
What I want is this:-
When a full name is composed of two words. The first one should be
the name and the second one should be the last name.
When a full name is composed of three words. The first and middle words should be the first name while the third word should be the last name.
Example:-
**Full Name**
John Paul White
Peter Smith
Ann Marie Brown
Jack Black
Sam Olaf Turner
Result:-
**First Name Last Name**
John Paul White
Peter Smith
Ann Marie Brown
Jack Black
Sam Olaf Turner
I have search and found solutions that are not working as intended and would like some advice.
Keeping it short and simple
DECLARE #t TABLE(Fullname varchar(40))
INSERT #t VALUES('John Paul White'),('Peter Smith'),('Thomas')
SELECT
LEFT(Fullname, LEN(Fullname) - CHARINDEX(' ', REVERSE(FullName))) FirstName,
STUFF(RIGHT(FullName, CHARINDEX(' ', REVERSE(FullName))),1,1,'') LastName
FROM
#t
Result:
FirstName LastName
John Paul White
Peter Smith
Thomas NULL
If you are certain that your names will only ever be two or three words, with single spaces, then we can rely on the base string functions to extract the first and last name components.
SELECT
CASE WHEN LEN(col) = LEN(REPLACE(col, ' ', '')) + 2
THEN SUBSTRING(col, 1,
CHARINDEX(' ', col, CHARINDEX(' ', col) + 1) - 1)
ELSE SUBSTRING(col, 1, CHARINDEX(' ', col) - 1)
END AS first,
CASE WHEN LEN(col) = LEN(REPLACE(col, ' ', '')) + 2
THEN SUBSTRING(col,
CHARINDEX(' ', col, CHARINDEX(' ', col) + 1) + 1,
LEN(col) - CHARINDEX(' ', col, CHARINDEX(' ', col)))
ELSE SUBSTRING(col,
CHARINDEX(' ', col) + 1,
LEN(col) - CHARINDEX(' ', col))
END AS last
FROM yourTable;
Yuck, but it seems to work. My feeling is that you should fix your data model at some point. A more ideal place to scrub your name data would be outside the database, e.g. in Java. Or, better yet, fix the source of your data such that you record proper first and last names from the very beginning.
Demo here:
Rextester
Another option (just for fun) is to use a little XML in concert with an CROSS APPLY
Example
Select FirstName = ltrim(reverse(concat(Pos2,' ',Pos3,' ',Pos4,' ',Pos5)))
,LastName = reverse(Pos1)
From YourTable A
Cross Apply (
Select Pos1 = xDim.value('/x[1]','varchar(max)')
,Pos2 = xDim.value('/x[2]','varchar(max)')
,Pos3 = xDim.value('/x[3]','varchar(max)')
,Pos4 = xDim.value('/x[4]','varchar(max)')
,Pos5 = xDim.value('/x[5]','varchar(max)')
From (Select Cast('<x>' + replace(reverse(A.[Full Name]),' ','</x><x>')+'</x>' as xml) as xDim) XMLData
) B
Returns
FirstName LastName
John Paul White
Peter Smith
Ann Marie Brown
Jack Black
Sam Olaf Turner
Cher
Sally Anne Bella Donna Baxter
You're trying to do two things at once...I won't solve for you, but here's the direction I'd take:
1) Check this out for string splitting: https://ole.michelsen.dk/blog/split-string-to-table-using-transact-sql.html. This will allow you to parse the name into a temp table and you can perform your logic on it to create names based on your rules
2) Create this as a table-valued function so that you can return a single row of parsed FirstName, LastName from your parameter. That way you can join to it and include in your results
Have you tried by Using PARSENAME Function?
The last method in splitting a full name into its corresponding first name and last name is the use of the PARSENAME string function, as can be seen from the following script:
DECLARE #FullName VARCHAR(100)
SET #FullName = 'John White Doe'
SELECT CONCAT(PARSENAME(REPLACE(#FullName, ' ', '.'), 3),' ',PARSENAME(REPLACE(#FullName, ' ', '.'), 2)) AS [FirstName],
PARSENAME(REPLACE(#FullName, ' ', '.'), 1) AS [LastName]
For more information, Goto this Site
This is the output..
Make it a table-valued function.
see here for an example
And this is the code you need to create your function. Basically you just need to split your LastName
IF OBJECT_ID(N'dbo.ufnParseName', N'TF') IS NOT NULL
DROP FUNCTION dbo.ufnParseName;
GO
CREATE FUNCTION dbo.ufnParseName(#FullName VARCHAR(300))
RETURNS #retParseName TABLE
(
-- Columns returned by the function
FirstName nvarchar(150) NULL,
LastName nvarchar(50) NULL
)
AS
-- Returns the spliced last name.
BEGIN
DECLARE
#FirstName nvarchar(250),
#LastName nvarchar(250);
-- Get common contact information
SELECT #LastName = RTRIM(RIGHT(#FullName, CHARINDEX(' ', REVERSE(#FullName)) - 1));
SELECT #FirstName = LTRIM(RTRIM(Replace(#FullName, #LastName, '')))
INSERT #retParseName
SELECT #FirstName, #LastName;
RETURN;
END
You can run as SELECT * FROM dbo.ufnParseName('M J K');
Why Table-Valued-Function
You can get rid off the duplication of your sql query and achieve DRY
You can try the below query. It is written as per your requirement and it only handles full_name with 2 or 3 parts in it.
;WITH cte AS(
SELECT full_name, (LEN(full_name) - LEN(REPLACE(full_name, ' ', '')) + 1) AS size FROM #temp
)
SELECT FirstName =
CASE
WHEN size=3 THEN PARSENAME(REPLACE(full_name, ' ', '.'), 3) + ' ' + PARSENAME(REPLACE(full_name, ' ', '.'), 2)
ELSE PARSENAME(REPLACE(full_name, ' ', '.'), 2)
END,
PARSENAME(REPLACE(full_name, ' ', '.'), 1) AS LastName
FROM cte
I am trying to get First name from employee table, in employee table full_name is like this: Dow, Mike P.
I tried with to get first name using below syntax but it comes with Middle initial - how to remove middle initial from first name if any. because not all name contain middle initial value.
-- query--
select Employee_First_Name as full_name,
SUBSTRING(
Employee_First_Name,
CHARINDEX(',', Employee_First_Name) + 1,
len(Employee_First_Name)) AS FirstName
---> remove middle initial from right side from employee
-- result
Full_name Firstname Dow,Mike P. Mike P.
--few example for Full_name data---
smith,joe j. --->joe (need result as)
smith,alan ---->alan (need result as)
Instead of specifying the len you need to use charindex again, but specify that you want the second occurrence of a space.
select Employee_First_Name as full_name,
SUBSTRING(
Employee_First_Name,
CHARINDEX(',', Employee_First_Name) + 1,
CHARINDEX(' ', Employee_First_Name, 2)) AS FirstName
One thing to note, the second charindex can return 0 if there is no second occurence. In that case, you would want to use something like the following:
select Employee_First_Name as full_name,
SUBSTRING(
Employee_First_Name,
CHARINDEX(',', Employee_First_Name) + 1,
IIF(CHARINDEX(' ', Employee_First_Name, 2) = 0, Len(Employee_First_name), CHARINDEX(' ', Employee_First_Name, 2))) AS FirstName
This removes the portion before the comma.. then uses that string and removes everything after space.
WITH cte AS (
SELECT *
FROM (VALUES('smith,joe j.'),('smith,alan'),('joe smith')) t(fullname)
)
SELECT
SUBSTRING(
LTRIM(SUBSTRING(fullname,CHARINDEX(',',fullname) + 1,LEN(fullname))),
0,
COALESCE(NULLIF(CHARINDEX(' ',LTRIM(SUBSTRING(fullname,CHARINDEX(',',fullname) + 1,LEN(fullname)))),0),LEN(fullname)))
FROM cte
output
------
joe
alan
joe
To be honest, this is most easily expressed using multiple levels of logic. One way is using outer apply:
select ttt.firstname
from t outer apply
(select substring(t.full_name, charindex(', ', t.full_name) + 2, len(t.full_name) as firstmi
) tt outer apply
(select (case when tt.firstmi like '% %'
then left(tt.firstmi, charindex(' ', tt.firstmi)
else tt.firstmi
end) as firstname
) as ttt
If you want to put this all in one complicated statement, I would suggest a computed column:
alter table t
add firstname as (stuff((case when full_name like '%, % %.',
then left(full_name,
charindex(' ', full_name, charindex(', ', full_name) + 2)
)
else full_name
end),
1,
charindex(', ', full_name) + 2,
'')
If format of this full_name field is the same for all rows, you may utilize power of SQL FTS word breaker for this task:
SELECT N'Dow, Mike P.' AS full_name INTO #t
SELECT display_term FROM #t
CROSS APPLY sys.dm_fts_parser(N'"' + full_name + N'"', 1033, NULL, 1) p
WHERE occurrence = 2
DROP TABLE #t
I have a need to retrieve a hierarchy of managers and the column which stores the manager names for a given person are formatted like this Smith, Mr. William (Bill). I want this output to simply be William Smith. So far I have put this together:
SELECT DISTINCT RIGHT(u.manager, LEN(u.manager)-(1+CHARINDEX(', ', u.manager))) + ' ' +
LEFT(u.manager, CHARINDEX(', ', u.manager) - 1) as ManagerName
FROM Users u
The current result from that query using my example above is Mr. William (Bill) Smith. This CHARINDEX and SUBSTRING stuff always gives me a lot of trouble so I am not really sure what the easiest way to do this is. This is also a one-off, so I am not sure a function would be useful here.
DEMO
SELECT
SUBSTRING(manager,0,CHARINDEX(',', manager)) as surname,
SUBSTRING(manager,CHARINDEX('. ', manager)+2, LEN(manager)-CHARINDEX(' (', manager)+1) as name,
CONCAT(SUBSTRING(manager,CHARINDEX('. ', manager)+2, LEN(manager)-CHARINDEX(' (', manager)+1),
' ',
SUBSTRING(manager,0,CHARINDEX(',', manager))) as 'name surname'
FROM
Users
Result:
+-------------+-----------+--------------+
| surname | name | name surname |
+-------------+-----------+--------------+
Smith William William Smith
I took your query and modified a little bit:
SELECT
---this is the tricky part: inner part finds the first instance of '(' parenthesis
--and substract it from the length of the first name and get only the left part of the first name by subtracting it
CONCAT (
LEFT(t.FirstName, LEN(t.FirstName) - (LEN(t.FirstName) - CHARINDEX('(', t.FirstName) + 1))
,t.LastName
)
FROM (
--basically separating your above syntax to two columns
SELECT RIGHT('Smith, Mr. William (Bill)', LEN('Smith, Mr. William (Bill)') - CHARINDEX('.', 'Smith, Mr. William (Bill)') - 1) AS FirstName
,LEFT('Smith, Mr. William (Bill)', CHARINDEX(', ', 'Smith, Mr. William (Bill)') - 1) AS LastName
) t
Here is the query that should work with your table name and column:
SELECT
---Use case when statement to determine if there are any instances of '(' in the first name
CONCAT (
CASE
WHEN CHARINDEX('(', t.FirstName) > 0
THEN LEFT(t.FirstName, LEN(t.FirstName) - (LEN(t.FirstName) - CHARINDEX('(', t.FirstName) + 1))
ELSE t.FirstName + ' '
END
,t.LastName
)
FROM (
SELECT
RIGHT(u.manager, LEN(u.manager) - CHARINDEX('.', u.manager) - 1) AS FirstName
,LEFT(u.manager, CHARINDEX(', ', u.manager) - 1) AS LastName from Users u
) t
SELECT RIGHT(NameStripped, LEN(NameStripped) - (1 + CHARINDEX(', ', NameStripped))) + ' ' + LEFT(NameStripped, CHARINDEX(', ', NameStripped) - 1) AS ManagerName --Your original code
FROM (
SELECT replace(replace(
LEFT(u.manager, CHARINDEX('(', u.manager) - 2) --Get rid of nickname
, 'Mr. ', ''), 'Ms.', '') AS NameStripped --Get rid of Mr/Ms
from MyTable u) a
This should work - I used the code you posted, but added a subquery to remove the nicknames and prefixes.
Note that you may need to adjust this if a) you have more prefix options than this (in which case you could add additional replaces) and/or b) not everyone in your database has a nickname (in which case you'll want to wrap that part in a case statement, most likely).