Detect Print Screen keyup and keydown in Keyboard Tester app VB NET - vb.net

Question

I have a problem when I try to make Keyboard Tester application for my small office.
I cant detect print screen keycode e.keycode = keys.PrintScreen.
I will do something like change picturebox back color when a key down, but it seems doesnt work with print screen, nothing happen.
my code is:
Private Sub keyboardmenu_KeyDown(sender As Object, e As KeyEventArgs) Handles Me.KeyDown
'Esc + Function Keys -----------------------------------------
If e.KeyCode = Keys.Escape Then
EscBox.BackColor = Color.Red
End If
If e.KeyCode = Keys.F1 Then
F1Box.BackColor = Color.Red
End If
If e.KeyCode = Keys.F2 Then
F2Box.BackColor = Color.Red
End If
If e.KeyCode = Keys.F3 Then
F3Box.BackColor = Color.Red
End If
If e.KeyCode = Keys.F4 Then
F4Box.BackColor = Color.Red
End If
If e.KeyCode = Keys.F5 Then
F5Box.BackColor = Color.Red
End If
If e.KeyCode = Keys.F6 Then
F6Box.BackColor = Color.Red
End If
If e.KeyCode = Keys.F7 Then
F7Box.BackColor = Color.Red
End If
If e.KeyCode = Keys.F8 Then
F8Box.BackColor = Color.Red
End If
If e.KeyCode = Keys.F9 Then
F9Box.BackColor = Color.Red
End If
If e.KeyCode = Keys.F10 Then
F10Box.BackColor = Color.Red
End If
If e.KeyCode = Keys.F11 Then
F11Box.BackColor = Color.Red
End If
If e.KeyCode = Keys.F12 Then
F12Box.BackColor = Color.Red
End If
'End of Esc + Function Keys -----------------------------------------
Private Sub keyboardmenu_KeyUp(sender As Object, e As KeyEventArgs) Handles Me.KeyUp
'Esc + Function Keys ----------------------------------------
If e.KeyCode = Keys.F1 Then
F1Box.BackColor = Color.Transparent
End If
If e.KeyCode = Keys.F2 Then
F2Box.BackColor = Color.Transparent
End If
If e.KeyCode = Keys.F3 Then
F3Box.BackColor = Color.Transparent
End If
If e.KeyCode = Keys.F4 Then
F4Box.BackColor = Color.Transparent
End If
If e.KeyCode = Keys.F5 Then
F5Box.BackColor = Color.Transparent
End If
If e.KeyCode = Keys.F6 Then
F6Box.BackColor = Color.Transparent
End If
If e.KeyCode = Keys.F7 Then
F7Box.BackColor = Color.Transparent
End If
If e.KeyCode = Keys.F8 Then
F8Box.BackColor = Color.Transparent
End If
If e.KeyCode = Keys.F9 Then
F9Box.BackColor = Color.Transparent
End If
If e.KeyCode = Keys.F10 Then
F10Box.BackColor = Color.Transparent
End If
If e.KeyCode = Keys.F11 Then
F11Box.BackColor = Color.Transparent
End If
If e.KeyCode = Keys.F12 Then
F12Box.BackColor = Color.Transparent
End If
'End of Esc + Function Keys -----------------------------------------
End Sub
Please help me. Idk if there are more keys like print screen problem.
Thank You

Answer 1

I'm not sure of the real reason, but I've read about it before and came to the conclusion that Windows is protecting that key's event from being easily handled. Someone else probably knows better, but this works:
Protected Overrides Function ProcessKeyEventArgs(ByRef msg As Message) As Boolean
If msg.WParam = Keys.PrintScreen Then
MessageBox.Show("PrintScreen key press detected!")
End If
Return MyBase.ProcessKeyEventArgs(msg)
End Function
Also, you should put all of those if statements in a Select Case statement:
Private Sub keyboardmenu_KeyDown(ByVal sender As Object, ByVal e As KeyEventArgs) Handles Me.KeyDown
Select Case e.KeyCode
Case Keys.Escape
EscBox.BackColor = Color.Red
Case Keys.F1
F1Box.BackColor = Color.Red
Case Keys.F2
F2Box.BackColor = Color.Red
'Etc
End Select
End Sub

Answer 2

This comment is on the IF statements and CASE suggestion, otherwise I concur with the answer by Keith.
I use this sort of thing fairly often, but it's crazy to put all those IF statements, OR the Case statement:
Simply name the boxes to match the enumeration, then (assuming Controls is the parent container of all the boxes)
Controls(e.keycode.tostring & "box").backcolor = Color.Red
and
Controls(e.keycode.tostring & "box").backcolor = Color.Transparent
This one line will replace everything (if you rename the escbox to escapebox)
Of course, you might want to do some checking like
If Controls.ContainsKey(e.keycode.tostring & "box") Then ...