Casting String to Date - sql

The below one is working fine and returns date in the desired format
select TO_DATE(TO_CHAR(max(entdate), 'DD/MM/YYYY'), 'DD/MM/YYYY') as last_transaction_date from table;
After adding hh24:mm:ss and error of "format code appears twice" ORA-01810 appears
select TO_DATE(TO_CHAR(max(entdate), 'DD/MM/YYYY hh24:mm:ss'), 'DD/MM/YYYY hh24:mm:ss') as last_transaction_date from table;
I'm not able to understand the difference between both cases

MI not MM for minutes
"Some people mistakenly use the MM format code to represent minutes, thus using the MM format for both the months and the minutes."
select TO_DATE(TO_CHAR(max(entdate), 'DD/MM/YYYY HH24:MI:SS'), 'DD/MM/YYYY HH24:MI:SS') as last_transaction_date from table;

Related

How to add hours to date in 24 hours format

I would like to add, for example, 8 hours to the enddate in a 24 hour format.
I tried adding + 8/24, 'DD-MM-YYYY HH24:MI:SS' on the first line but this gives an error.
This is my query thus far.
SELECT to_char(IN_ENDDATE, 'DD-MM-YYYY HH24:MI:SS')
INTO IN_END_DATE_STRING
FROM DUAL;
Your first line converts a date to a string. You cannot then add 8/24 to it. Do the addition before the conversion:
SELECT to_char(IN_ENDDATE + 8/24.0, 'DD-MM-YYYY HH24:MI:SS')
INTO IN_END_DATE_STRING
FROM DUAL;
IN_ENDDATE really does need to be a date type to allow +8/24 to work. If it's a timestamp, add it as an interval:
IN_ENDDATE + INTERVAL '8' HOUR
This form might be safer to use for a couple of reasons:
it works on both date and timestamps
it's more readable
If IN_ENDDATE is a non-date type (eg varchar) then your query works without the +8/24 because it is being successfully implicitly converted from varchar to date, before being passed to to_char. In this case either be explicit about your conversion:
SELECT to_char(to_date(IN_ENDDATE, 'YYMMDD WHATEVER') + 8/24.0, 'DD-MM-YYYY HH24:MI:SS')
INTO IN_END_DATE_STRING
FROM DUAL
SELECT to_char(to_date(IN_ENDDATE, 'YYMMDD WHATEVER') + INTERVAL '8' HOUR, 'DD-MM-YYYY HH24:MI:SS')
INTO IN_END_DATE_STRING
FROM DUAL
Or set your IN_ENDDATE parameter to really be a date type

CAST(CURRENT_TIMESTAMP AS TIME)

i am trying to work with timestamps and manipulate the data out of them so i can measure different things in our database.
currently i have a column that holds a "DATE" but in fact contains a whole stamp 'DD/MM/YYYY HH24:MI:SS'
i want to be able to grab all entries where "DTIME" between "09:00" and "09:15" however have not been able to cast it correctly.
If i was to output the column without any conversion it would look like this
SELECT ia.DTIME3
FROM ISIS_AUDIT ia
WHERE ia.DTIME3 like to_date('24/01/2019', 'DD/MM/YYYY');
OUTPUT: 24/JAN/19
if i was to convert it to_char,
SELECT to_char(ia.DTIME3, 'DD/MM/YYYY HH24:MI:SS')
FROM ISIS_AUDIT ia
WHERE ia.DTIME3 like to_date('24/01/2019', 'DD/MM/YYYY');
OUTPUT: 24/01/2019 07:10:52
I want to be able to take this DTIME3 and find entries between the times but CAST and CONVERT to TIME doesnt work.
This is my working option but it outputs the date still and i dont want to have to specify the date so it can be run across any day of the week.
WHERE ia.DTIME3 between to_date('24/01/2019 09:00:00', 'DD/MM/YYYY HH24:MI:SS') and to_date('24/01/2019 09:15:00', 'DD/MM/YYYY HH24:MI:SS');
OUTPUT: 24/01/2019 09:00:01
currently i have a column that holds a "DATE" but in fact contains a whole stamp 'DD/MM/YYYY HH24:MI:SS'
That's what Oracle DATE datatype does : storing a date and time (without fractional seconds, that belong to the TIMESTAMP datatypes). There is no specific format in Oracle for date only (without time).
To filter on the time of the day, you can use the TO_CHAR() function to convert your date to a string that represents its time, and that you can compare :
TO_CHAR(ia.DTIME3, 'hh24:mi') BETWEEN '09:00' AND '09:14'
You can also CAST the date to a timestamp and use the EXTRACT() function :
EXTRACT(HOUR FROM CAST(ia.DTIME3 AS TIMESTAMP)) = 9
AND EXTRACT(MINUTE FROM CAST(ia.DTIME3 AS TIMESTAMP)) < 15
Oracle has DATE and TIMESTAMP data types; both have year, month, day, hour, minute, second components (TIMESTAMP also has fractional seconds). Oracle does not have a TIME data type.
Instead, use TRUNC() to truncate the time component to midnight and add an interval literal:
SELECT *
FROM ISIS_AUDIT
WHERE DTIME BETWEEN TRUNC( DTIME ) + INTERVAL '09:00' HOUR TO MINUTE
AND TRUNC( DTIME ) + INTERVAL '09:15' HOUR TO MINUTE;
and ia.DTIME1 not between to_date('&&S_DATE 08:50:00', 'DD/MM/YYYY HH24:MI:SS') and to_date('&&S_DATE 09:20:00', 'DD/MM/YYYY HH24:MI:SS')
and ia.DTIME1 not between to_date('&&S_DATE 11:50:00', 'DD/MM/YYYY HH24:MI:SS') and to_date('&&S_DATE 12:40:00', 'DD/MM/YYYY HH24:MI:SS')
and ia.DTIME3 not between to_date('&&S_DATE 08:50:00', 'DD/MM/YYYY HH24:MI:SS') and to_date('&&S_DATE 09:20:00', 'DD/MM/YYYY HH24:MI:SS')
and ia.DTIME3 not between to_date('&&S_DATE 11:50:00', 'DD/MM/YYYY HH24:MI:SS') and to_date('&&S_DATE 12:40:00', 'DD/MM/YYYY HH24:MI:SS')
i was trying to do this way however i noticed if i have a start time of 08:30 and a finish time of 09:30 then it falls between 09:00 and 09:15 so i want to exclude it from the table. the current WHERE clause im using is quite specific and will only exclude if the timestamp contains the values specified.
Really it would want to read "DTIME1 to DTIME3 not between 09:00 and 09:15"

oracle date format comparison ORA-01858

I have this query on production, which had no problem till yesterday:
SELECT E.ID
FROM EXAM_STUD_ENTERANCE E,
EXAM_REGISTRATION R
WHERE E.EXAM_REG_ID = R.ID
AND E.USER_NAME ='user'
AND E.BLOCK = 1
AND E.STATUS = 1
AND TO_DATE (TO_CHAR (SYSDATE, 'DD/MM/YYYY HH24:MI:SS'),
'DD/MM/YYYY HH24:MI:SS') >
TO_DATE (
TO_CHAR (R.EXAM_DATE, 'DD/MM/YYYY')
|| ' ' || R.EXAM_START_TIME
,
'DD/MM/YYYY HH24:MI:SS')
AND TO_DATE (TO_CHAR (SYSDATE, 'DD/MM/YYYY HH24:MI:SS'),
'DD/MM/YYYY HH24:MI:SS') <
TO_DATE (
TO_CHAR (R.EXAM_DATE, 'DD/MM/YYYY')
|| ' ' || R.EXAM_END_TIME
,
'DD/MM/YYYY HH24:MI:SS');
But now I receive an error
ORA-01858: a non-numeric character was found where a numeric was
expected
Type of columns EXAM_START_TIME and EXAM_END_TIME are NVARCHAR2(100), and stores data like '16:40' ; EXAM_DATE is DATE
Yesterday someone inserted a bad value into one of those time columns
Do a
SELECT * FROM EDUMAN_EXAM.EXAM_REGISTRATION
WHERE
NOT(
REGEXP_LIKE(EXAM_START_TIME, '^\d\d:\d\d:\d\d$') AND
REGEXP_LIKE(EXAM_END_TIME, '^\d\d:\d\d:\d\d$')
)
Find the bad data, and remove it
Note: you posted an sql that indicates the time columns store hh:mm:ss and you said "it was working" but then you claimed that the time columns don't store seconds. If they do store seconds, then use the query as above. If they don't store seconds, reduce the regex pattern to \d\d:\d\d
As a side commentary, you should never have made the decision to store this time data as a string. The DATETIME that holds the EXAM_START_DATE can just as easily hold a time, and if you just want the DATE without the time part, you can TRUNC(some_datetime) to remove the time component
Store the data in a column of the proper type, and you won't get this issue, and you wont have to get into this ludicrous date -> string -> concatenate -> parse process on thousands of records

Oracle : Date time subtraction

I have to calculate time difference in minutes from current(sysdate) and modified time:-
to_date(to_char(sysdate, 'YYYY-MM-DD HH24:MI:SS'), 'YYYY-MM-DD HH24:MI:SS')
- to_date(to_char(modified, 'YYYY-MM-DD HH24:MI:SS'), 'YYYY-MM-DD HH24:MI:SS')
but problem is to_char returns proper time:-
to_char(whenmodified, 'YYYY-MM-DD HH24:MI:SS')
Outputs 2016-05-23 14:55:50
and to_date doesn’t show time:-
to_date(to_char(modified, 'YYYY-MM-DD HH24:MI:SS'), 'YYYY-MM-DD HH24:MI:SS')
Outputs: 2016-05-23
Please assist how I can get time difference by converting to_char to to_date.
NOTE:
I cant do sysdate-modified because both sysdate and modified gives date without time e.g 2016-05-23
Using to_char for sysdate or modified give date with time 2016-05-23 14:55:50
As we cant subtracts dates in to_char function I am again converting back them to to_date for getting time.
I am expecting:
2016-05-23 14:55:50 - 2016-05-23 14:53:50 = 2 min
I have to calculate time difference in minutes from current(sysdate) and modified time
Oracle Setup:
CREATE TABLE table_name ( modified DATE );
INSERT INTO table_name
SELECT TIMESTAMP '2016-05-23 14:20:00' FROM DUAL UNION ALL
SELECT TIMESTAMP '2016-05-23 00:00:00' FROM DUAL UNION ALL
SELECT TIMESTAMP '2016-05-01 00:00:00' FROM DUAL UNION ALL
SELECT TIMESTAMP '2016-01-01 00:00:00' FROM DUAL;
Query:
SELECT ( sysdate - modified ) * 24 * 60 AS minute_difference
FROM table_name;
Output:
MINUTE_DIFFERENCE
-----------------
3.66666667
863.666667
32543.6667
206783.667
And to address your comment that:
to_date doesn’t show time
A date always has a time component and never has a format internally to the database (it is represented by 7 or 8 bytes) - the formatting of a date is done by the client program that you use to access the database (and often the default is not to show the time component - however, the time component still exists).
You can change this either in the preferences of your client program or, if they don't use that to control it, by changing the NLS_DATE_FORMAT session parameter:
ALTER SESSION SET NLS_DATE_FORMAT = 'YYYY-MM-DD HH24:MI:SS';

date format conversion am to date

I need a help on how to convert '09-07-15 07:41:01AM' to '2015-07-09 07:41:01'.
I have tried below query but it is not giving accurate result.
select to_char(to_date('09-07-15 07:41:01AM'
,'DD-MM-YYYY HH:MI:SS AM')
,'YYYY-MM-DD HH24:MI:SS') from dual
Have you tried
select to_char(add_months(to_date('09-07-15 07:41:01AM','DD-MM-YY HH:MI:SS AM'),24000),'YYYY-MM-DD HH24:MI:SS') from dual
It looks like you have to many Y's, and your M's ans D's are inconsistent!
I'm not sure if it should be YY-MM-DD or YY-mm-dd?