Frustrated with simple awk command - awk

Question

I am trying to list out the contents of a field 1 using a function:
help(){
if [[ $# -eq 0 ]] ; then
echo '######################################'
echo ''
echo 'Argument to run run name must be given: ./report.sh Name'
echo 'Report names are:'
ALLNAMES=$(cut -d '|' -f 1 $CONFIGFILE | awk '{printf $0"\n"}')
echo $ALLNAMES
echo '######################################'
exit 0
fi
}
The output I get is :
$ bin/report.sh
######################################
Argument to run run name must be given: ./report.sh Name
Report names are:
ItemA ItemB
######################################
Whereas I want:
$ bin/report.sh
######################################
Argument to run run name must be given: ./report.sh Name
Report names are:
ItemA
ItemB
######################################
If I run the cut command I get:
[david#kallibu]$ cut -d '|' -f 1 conf/report.conf
ItemA
ItemB
Whatdo I need to change to get my newline ?

Answer 1

The problem is:
echo $ALLNAMES
Should be solved with quotes:
echo "$ALLNAMES"

Answer 2

If you're not goint to use the var ALLNAMES in other place, just:
help(){
if [[ $# -eq 0 ]] ; then
echo '######################################'
echo ''
echo 'Argument to run run name must be given: ./report.sh Name'
echo 'Report names are:'
cut -d '|' -f 1 conf/report.conf
echo '######################################'
exit 0
fi
}

Answer 3

Your code would be,
help(){
if [[ $# -eq 0 ]] ; then
echo '######################################'
echo ''
echo 'Argument to run run name must be given: ./report.sh Name'
echo 'Report names are:'
ALLNAMES=$(awk -F'|' '{print $1}' $CONFIGFILE)
echo "$ALLNAMES"
echo '######################################'
exit 0
fi
}
You could try this awk -F'|' '{print $1}' $CONFIGFILE command to get the value of first column where | as delimiter.
You need to put ALLNAMES inside double quotes. So that only, the ALLNAMES variable got expanded.

Answer 4

#Tiago provided the answer to your specific problem, but overall your script should either be the shell script #klashxx posted or this awk script:
help(){
if [[ $# -eq 0 ]] ; then
awk '
BEGIN {
FS = "|"
print "######################################\n"
print "Argument to run run name must be given: ./report.sh Name"
print "Report names are:"
}
{ print $1 }
END {
print "######################################"
}
' "$CONFIGFILE"
exit 0
fi
}
or similar.