I have two tables Affaire(ID, Obj, ID_TA ...) and TypeAffaire(ID_TA, Label), i want to count number of each ID_TA in Affaire and show the label instead if ID_TA, I tried this but it doesnt work :
SELECT A.ID_TA
,T.Label
,count(*) AS TotalAmount
FROM Affaire AS A
LEFT JOIN TypeAffaire AS T ON T.ID_TA = A.TA
GROUP BY A.ID_TA;
it says that label can't be found
You need to group by T.Label as well. All non-aggegated fields in the select clause, must also be in the group by clause.
Add T.Label in Group By
Try this
SELECT A.ID_TA
,T.Label
,count(*) AS TotalAmount
FROM Affaire AS A
LEFT JOIN TypeAffaire AS T ON T.ID_TA = A.TA
GROUP BY A.ID_TA,T.Label;
You need to Insert T.Label in the group by clause, and correct the ON T.ID_TA = A.TA in to ON T.ID_TA = A.ID_TA
SELECT A.ID_TA ,T.Label ,count(*) AS TotalAmount
FROM Affaire AS A
LEFT JOIN TypeAffaire AS T ON T.ID_TA = A.ID_TA
GROUP BY A.ID_TA, T.Label;
Related
I have a problem
I have 2, same tables. My select should show this two columns and the last one "sup_cr" should be counted.
sup_id, sup_name, sup_cr.
This is my query without inner join. But i don't know how to use a inner join in this query.
SELECT sup.sup_id,
sup.sup_name_en AS name,
(SELECT COUNT (sup_cr.sup_id_from)
FROM t_sup_supplier AS sup_cr
WHERE sup_cr.sup_id_from = sup.sup_id ) AS cr_numbers
FROM t_sup_supplier AS sup
Sorry for my english.
You don't need a join or aggregation. You can use a window function:
SELECT sup.sup_id, sup.sup_name_en AS name,
COUNT(*) OVER (PARTITION BY sup_id) AS cr_numbers
FROM t_sup_supplier sup;
You could rephrase this a join using:
SELECT
sup.sup_id,
sup.sup_name_en AS name,
COALESCE(sup_cr.cnt, 0) AS cr_numbers
FROM t_sup_supplier
LEFT JOIN
(
SELECT sup_id_from, COUNT(*) AS cnt
FROM t_sup_supplier
GROUP BY sup_id_from
) sup_cr
ON sup_cr.sup_id_from = sup.sup_id;
I have the tables products and history and I need to group by name:
products = (id_product, name)
history = (id_history, id_product, amount)
I tried this SQL query but it isn't grouped by name:
SELECT
products.name,
sum(history.amount)
FROM history
INNER JOIN products ON history.id_product = products.id_product
GROUP BY
products.name,
history.amount,
history.id_history;
This is the result:
You should only be grouping by the attributes you need to be aggregated. In this case, you need only products.name.
SELECT
products.name,
sum(history.amount) AS [Amount]
FROM history
INNER JOIN products ON history.id_product = products.id_product
GROUP BY
products.name;
If you need to include products without history (assuming sum should be 0 instead of null in this case), then you can use an OUTER JOIN instead of INNER JOIN to include all products:
SELECT
products.name,
COALESCE(sum(history.amount), 0) AS [Amount]
FROM history
RIGHT OUTER JOIN products ON history.id_product = products.id_product
GROUP BY
products.name;
This is no answer, but too long for a comment.
For readability's sake the product table should be first. After all it is products that we select from, plus a history sum that we can access via [left] join history ... followed by an aggregation, or [left] join (<history aggregation query>), or a subselect in the select clause.
Another step to enhance readability is the use of alias names.
Join the table, then aggregate
select p.name, coalesce(sum(h.amount), 0) as total
from products p
left join history h on h.id_product = p.id_product
group by p.name
order by p.name;
Aggregate, then join
select p.name, coalesce(h.sum_amount, 0) as total
from products p
left join
(
select sum(h.amount) as sum_amount
from history
group by id_product
) h on h.id_product = p.id_product
order by p.name;
Get the sum in the select clause
select
name,
(select sum(amount) from history h where h.id_product = p.id_product) as total
from products p
order by p.name;
And as you were confused on how to use GROUP BY, here is an explanation: GROUP BY ___ means you want one result row per ___. In your original query you had GROUP BY products.name, history.amount, history.id_history saying you wanted one result row per name, amount, and id, while you actually wanted one row per name only, i.e. GROUP BY products.name.
select count(*) from ordrer
inner join ordrelinjer on ordrelinjer.ordrenr = ordrer.ordrenr
group by ordrelinjer.varetekst
This query return 4 rows, but I want to return 4 in count(*), how to do so?
You are getting 4 row because of group by. If you need distinct group count, you can try subquery.
select count(*)
from (
select count(*)
from ordrer
inner join ordrelinjer on ordrelinjer.ordrenr=ordrer.ordrenr
group by ordrelinjer.varetekst
) t
It seem that you're looking for the distinct number of values for ordrelinjer.varetekst, which would be:
select count(distinct ordrelinjer.varetekst)
from ordrer
join ordrelinjer on ordrelinjer.ordrenr = ordrer.ordrenr;
invoke without group by
select count(*) from ordrer inner join ordrelinjer on ordrelinjer.ordrenr=ordrer.ordrenr
SELECT PEOPLE.TOWNKEY, TOWN_LOOKUP.TOWN FROM PEOPLE
INNER JOIN TOWN_LOOKUP
ON PEOPLE.TOWNKEY = TOWN_LOOKUP.PK
ORDER BY TOWN
Current Table Output:
You are missing the group by clause entirely:
SELECT tl.town, COUNT(*)
FROM people p
INNER JOIN town_lookup ON p.townkey = tl.pk
GROUP BY tl.town
ORDER BY tl.town
I have 2 tables. I need to select the column name and a calculated field from Invoices called balance_due.
The result of the query should be the name and their balance due from all of their records combined.
Thanks for any help.
SELECT v.vendor_name, i.totalbalance
FROM Vendors as v
INNER JOIN (
SELECT vendor_id, sum(invoice_total-payment_total) as totalbalance
FROM invoices
GROUP BY vendor_id
) as i on i.vendor_id = v.vendor_id
Or there is another syntax:
;With i As
(
SELECT vendor_id, sum(invoice_total-payment_total) as totalbalance
FROM invoices
WHERE payment_total is not null
GROUP BY vendor_id
)
SELECT Vendors.vendor_name, i.totalbalance
From Vendors LEFT JOIN i ON Vendors.vendor_id = i.vendor_id