SQL Query for Min and Max Values [duplicate] - sql

Question

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How to split a comma-separated value to columns
(38 answers)
Closed 8 years ago.
I have the following data in a table. The number of values in each row can vary and the number of rows could also vary.
The table has 1 column with csv formatted values. The values will always be numeric
Data
1,2
4
5,12, 10
6,7,8,9,10
15,17
I would like to end up with a temp table with the following
Data Lowest Highest
1,2 1 2
4 4 4
5,12, 10 5 12
6,7,8,9,10 6 10
15,17 15 17
Can anyone help with writing a sql query or function to achieve this

Answer 1

Instead of function, you can achieve by this
;WITH tmp
AS (SELECT A.rn,split.a.value('.', 'VARCHAR(100)') AS String
FROM (SELECT Row_number() OVER(ORDER BY (SELECT NULL)) AS RN,
Cast ('<M>' + Replace([data], ',', '</M><M>') + '</M>' AS XML) AS String
FROM table1) AS A
CROSS apply string.nodes ('/M') AS Split(a))
SELECT X.data,Tmp.lower,Tmp.higher
FROM (SELECT rn,Min(Cast(string AS INT)) AS Lower,Max(Cast(string AS INT)) AS Higher
FROM tmp
GROUP BY rn) Tmp
JOIN (SELECT Row_number() OVER(ORDER BY (SELECT NULL)) AS RN1,data
FROM table1) X
ON X.rn1 = Tmp.rn
FIDDLE DEMO
Output would be:
Data Lower Higher
1,2 1 2
4 4 4
5,12, 10 5 12
6,7,8,9,10 6 10
15,17 15 17

Answer 2

First create a user defined function to convert each row of 'DATA' column to a intermediate table as:
/****** Object: UserDefinedFunction [dbo].[CSVToTable]******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[CSVToTable] (#InStr VARCHAR(MAX))
RETURNS #TempTab TABLE
(id int not null)
AS
BEGIN
;-- Ensure input ends with comma
SET #InStr = REPLACE(#InStr + ',', ',,', ',')
DECLARE #SP INT
DECLARE #VALUE VARCHAR(1000)
WHILE PATINDEX('%,%', #INSTR ) <> 0
BEGIN
SELECT #SP = PATINDEX('%,%',#INSTR)
SELECT #VALUE = LEFT(#INSTR , #SP - 1)
SELECT #INSTR = STUFF(#INSTR, 1, #SP, '')
INSERT INTO #TempTab(id) VALUES (#VALUE)
END
RETURN
END
GO
Function is explained further here.
Then Using Cross Apply we can get the desired output as:
With CTE as
(
select
T.Data, Min(udf.Id) as [Lowest],Max(udf.Id) as [Highest]
from
Test T
CROSS APPLY dbo.CSVToTable(T.Data) udf
Group By Data
)
Select * from CTE
Sample Code here...
What a Cross Apply does is : it applies the right table expression to each row from the left table and produces a result table with the unified result sets.

Answer 3

Create table #temp1 (name varchar(100),value int )
Declare #len int
Select #len=(select max(LEN(name)-LEN(replace(name,',',''))) from table)
Declare #i int = 1
while (#i<=#len+1)
begin
insert into #temp1
select name,PARSENAME(REPLACE(name,',','.'),#i) from table t
set #i = #i+1
end
Select name,MIN(value) MINV,MAX(value) MAXV from #temp1 group by name

Answer 4

declare #Testdata table ( Data varchar(max))
insert #Testdata select '1,2'
insert #Testdata select '4'
insert #Testdata select '5,12, 10'
insert #Testdata select '6,7,8,9,10'
;with tmp( DataItem, Data, RN1) as (
select LEFT(Data, CHARINDEX(',',Data+',')-1),
STUFF(Data, 1, CHARINDEX(',',Data+','), ''),
ROW_NUMBER()OVER(ORDER BY (SELECT NULL))AS RN1
from #Testdata
union all
select LEFT(Data, CHARINDEX(',',Data+',')-1),
STUFF(Data, 1, CHARINDEX(',',Data+','), ''),RN1
from tmp
where Data > ''
)
Select x.data,t.Low,t.Up FROM
(Select RN1,MIN(Cast(DataItem AS INT)) As Low,
MAX(Cast(DataItem AS INT)) As Up
FROM tmp t GROUP BY t.RN1)t
JOIN (Select ROW_NUMBER()OVER(ORDER BY (SELECT NULL))AS RN,data from #Testdata)X
ON X.RN = t.RN1