I have a table that contains patters for phone numbers, where x can match any digit.
+----+--------------+----------------------+
| ID | phone_number | phone_number_type_id |
+----+--------------+----------------------+
| 1 | 1234x000x | 1 |
| 2 | 87654311100x | 4 |
| 3 | x111x222x | 6 |
+----+--------------+----------------------+
Now, I might have 511132228 which will match with row 3 and it should return its type. So, it's kind of like SQL wilcards, but the other way around and I'm confused on how to achieve this.
Give this a go:
select * from my_table
where '511132228' like replace(phone_number, 'x', '_')
select *
from yourtable
where '511132228' like (replace(phone_number, 'x','_'))
Try below query:
SELECT ID,phone_number,phone_number_type_id
FROM TableName
WHERE '511132228' LIKE REPLACE(phone_number,'x','_');
Query with test data:
With TableName as
(
SELECT 3 ID, 'x111x222x' phone_number, 6 phone_number_type_id from dual
)
SELECT 'true' value_available
FROM TableName
WHERE '511132228' LIKE REPLACE(phone_number,'x','_');
The above query will return data if pattern match is available and will not return any row if no match is available.
Related
I have a table with a column that contains a list of strings like below:
EXAMPLE:
STRING User_ID [...]
"[""null"",""personal"",""Other""]" 2122213 ....
"[""Other"",""to_dos_and_thing""]" 2132214 ....
"[""getting_things_done"",""TO_dos_and_thing"",""Work!!!!!""]" 4342323 ....
QUESTION:
I want to be able to get a count of the amount of times each unique string appears (strings are seperable within the strings column by commas) but only know how to do the following:
SELECT u.STRING, count(u.USERID) as cnt
FROM table u
group by u.STRING
order by cnt desc;
However the above method doesn't work as it only counts the number of user ids that use a specific grouping of strings.
The ideal output using the example above would like this!
DESIRED OUTPUT:
STRING COUNT_Instances
"null" 1223
"personal" 543
"Other" 324
"to_dos_and_thing" 221
"getting_things_done" 146
"Work!!!!!" 22
Based on your description, here is my sample table:
create table u (user_id number, string varchar);
insert into u values
(2122213, '"[""null"",""personal"",""Other""]"'),
(2132214, '"[""Other"",""to_dos_and_thing""]"'),
(2132215, '"[""getting_things_done"",""TO_dos_and_thing"",""Work!!!!!""]"' );
I used SPLIT_TO_TABLE to split each string as a row, and then REGEXP_SUBSTR to clean the data. So here's the query and output:
select REGEXP_SUBSTR( s.VALUE, '""(.*)""', 1, 1, 'i', 1 ) extracted, count(*) from u,
lateral SPLIT_TO_TABLE( string , ',' ) s
GROUP BY extracted
order by count(*) DESC;
+---------------------+----------+
| EXTRACTED | COUNT(*) |
+---------------------+----------+
| Other | 2 |
| null | 1 |
| personal | 1 |
| to_dos_and_thing | 1 |
| getting_things_done | 1 |
| TO_dos_and_thing | 1 |
| Work!!!!! | 1 |
+---------------------+----------+
SPLIT_TO_TABLE https://docs.snowflake.com/en/sql-reference/functions/split_to_table.html
REGEXP_SUBSTR https://docs.snowflake.com/en/sql-reference/functions/regexp_substr.html
| id | name | numbers |
+----+---------+----------------+
| 1 | arjun | 62,45,68,95,50 |
| 2 | yuvaraj | 45,65,85,68 |
| 3 | sahadev | 45,65,85,68 |
| 4 | yogi | 45,65,85,68 |
| 5 | krishna | 45,65,85,68 |
I want id data where number is 45
I tried
select *
from table
where number=45
but it doesn't work.
With like:
select * from table where concat(',', numbers, ',') like concat('%,', '45',',%')
because you need to transform the column's value to something like this:
,45,65,85,68,
and then apply like to the pattern '%,45,%'.
You can try using like operator
select * from table where number like '%45%'
or you can use find_in_set() for mysql database
select * from table where find_in_set(45,number)>0
using like operator with pattern as '%45%':
select * from table where numbers like '%45%'
For Postgres you can use:
select *
from the_table
where '45' = any(string_to_array(numbers, ','));
If you use like operator it will get all the records having 45 (like 345 or 12245 or 65445). if you want records having values exactly "45" You can try the below code if you are using SQL Server 2016 or higher versions.
select * from (
SELECT * FROM tablename
cross apply
STRING_SPLIT('numbers',',') )a where value='45'
I have a table with column GetDup and I'd like to the duplicate records based on the value of this column. For example, if value on is 1 in GetDup, then duplicate the record once. If value in the column is 2, then duplicate the record twice and so on and the statement has to be in looping statement.
What will be a good way to write a stored procedures for this? Please help.
Input:
+--------+--------------+---------------+
| Getdup | CustomerName | CustomerAdd |
+--------+--------------+---------------+
| 1 | John | 123 SomeWhere |
| 2 | Bob | 987 SomeWhere |
+--------+--------------+---------------+
What I want:
+--------+--------------+---------------+
| Getdup | CustomerName | CustomerAdd |
+--------+--------------+---------------+
| 1 | John | 123 SomeWhere |
| 1 | John | 123 SomeWhere |
| 2 | Bob | 987 SomeWhere |
| 2 | Bob | 987 SomeWhere |
| 2 | Bob | 987 SomeWhere |
+--------+--------------+---------------+
picture of data
Answer #2 After Clarification
Number Table to the Rescue!
The number table in my example (or tally table, if you want to call it that), is both temporary and very small. To make it bigger, just add more values to z and add more CROSS JOINs. In my opinion, a number table and a calendar table are both things that should be in every database you have. They are extremely useful.
SQL Fiddle
MS SQL Server 2017 Schema Setup:
CREATE TABLE mytable ( Getdup int, CustomerName varchar(10), CustomerAdd varchar(20) ) ;
INSERT INTO mytable (Getdup, CustomerName, CustomerAdd)
VALUES (1,'John','123 SomeWhere'), (2,'Bob','987 SomeWhere')
;
Query 1:
;WITH z AS (
SELECT *
FROM ( VALUES(0),(0),(0),(0) ) v(x)
)
, numTable AS (
SELECT num
FROM (
SELECT ROW_NUMBER() OVER (ORDER BY z1.x)-1 num
FROM z z1
CROSS JOIN z z2
) s1
)
SELECT t1.Getdup, t1.CustomerName, t1.CustomerAdd
FROM mytable t1
INNER JOIN numTable ON t1.getdup >= numTable.num
ORDER BY CustomerName, CustomerAdd
Results:
| Getdup | CustomerName | CustomerAdd |
|--------|--------------|---------------|
| 2 | Bob | 987 SomeWhere |
| 2 | Bob | 987 SomeWhere |
| 2 | Bob | 987 SomeWhere |
| 1 | John | 123 SomeWhere |
| 1 | John | 123 SomeWhere |
--------------------------------------------------------------------------
ORIGINAL ANSWER
EDIT: After further clarification of the problem, this won't duplicate rows, this will only duplicate the data in a column.
Something like one of these might work.
T-SQL
SELECT replicate(mycolumn,getdup) AS x
FROM mytable
MySQL
SELECT repeat(mycolumn,getdup) AS x
FROM mytable
Oracle SQL
SELECT rpad(mycolumn,getdup*length(mycolumn),mycolumn) AS x
FROM mytable
PostgreSQL
SELECT repeat(mycolumn,getdup+1) AS x
FROM mytable
If you can provide more details for exactly what you want and what you're working with, we might be able to help you better.
NOTE 2: Depending on what you need, you may need to do some math magic. You say above if GetDup is 1 then you want one duplicate. If that means that your output should be GetDup``GetDup, then you'll want to add one in the repeat(),replicate() or rpad() functions. ie replicate(mycolumn,getdup+1). Oracle SQL will be a little different, since it uses rpad().
In standard SQL you can use a recursive CTE:
with recursive cte as (
select t.dup, . . .
from t
union all
select cte.dup - 1, . . .
from cte
where cte.dup > 1
)
select *
from cte;
Of course, not all databases support recursive CTEs (and the recursive keyword is not used in some of them).
So, you want recursive solution :
with t as (
select Getdup, CustomerName, CustomerAdd, 0 as id
from table
union all
select Getdup, CustomerName, CustomerAdd, id + 1
from t
where id < getdup
)
insert into table (col1, col2, col3)
select Getdup, CustomerName, CustomerAdd
from t
order by getdup
option (maxrecursion 0);
How do I select two most nearly fields to specific timestamp?
SELECT *
FROM 'wp_weather'
WHERE ( timestamp most nearly to 1385435000) AND city = 'Махачкала'
The table:
id | timestamp
---------------
0 | 1385410000
1 | 1385420000
2 | 1385430000
3 | 1385440000
4 | 1385450000
SELECT *
FROM wp_weather
WHERE city = 'Махачкала'
order by abs(timestamp - 1385435000)
limit 2
You may try like this:
SELECT * FROM 'wp_weather'
WHERE city = 'Махачкала'
order by abs(timestamp - 1385435000)
limit 2
Also check the ABS function
Let's say I have a table in BigQuery containing 2 columns. The first column represents a name, and the second is a delimited list of values, of arbitrary length. Example:
Name | Scores
-----+-------
Bob |10;20;20
Sue |14;12;19;90
Joe |30;15
I want to transform into columns where the first is the name, and the second is a single score value, like so:
Name,Score
Bob,10
Bob,20
Bob,20
Sue,14
Sue,12
Sue,19
Sue,90
Joe,30
Joe,15
Can this be done in BigQuery alone?
Good news everyone! BigQuery can now SPLIT()!
Look at "find all two word phrases that appear in more than one row in a dataset".
There is no current way to split() a value in BigQuery to generate multiple rows from a string, but you could use a regular expression to look for the commas and find the first value. Then run a similar query to find the 2nd value, and so on. They can all be merged into only one query, using the pattern presented in the above example (UNION through commas).
Trying to rewrite Elad Ben Akoune's answer in Standart SQL, the query becomes like this;
WITH name_score AS (
SELECT Name, split(Scores,';') AS Score
FROM (
(SELECT * FROM (SELECT 'Bob' AS Name ,'10;20;20' AS Scores))
UNION ALL
(SELECT * FROM (SELECT 'Sue' AS Name ,'14;12;19;90' AS Scores))
UNION ALL
(SELECT * FROM (SELECT 'Joe' AS Name ,'30;15' AS Scores))
))
SELECT name, score
FROM name_score
CROSS JOIN UNNEST(name_score.score) AS score;
And this outputs;
+------+-------+
| name | score |
+------+-------+
| Bob | 10 |
| Bob | 20 |
| Bob | 20 |
| Sue | 14 |
| Sue | 12 |
| Sue | 19 |
| Sue | 90 |
| Joe | 30 |
| Joe | 15 |
+------+-------+
If someone is still looking for an answer
select Name,split(Scores,';') as Score
from (
# replace the inner custome select with your source table
select *
from
(select 'Bob' as Name ,'10;20;20' as Scores),
(select 'Sue' as Name ,'14;12;19;90' as Scores),
(select 'Joe' as Name ,'30;15' as Scores)
);