How to Convert an Integer to a Letter? [duplicate] - objective-c

This question already has answers here:
How to convert char to integer in C? [duplicate]
(2 answers)
Closed 8 years ago.
I wanted to convert an integer to a letter. For example:
1 = A
2 = B
3 = C
...
26 = Z
Is there a way I could do this without using an array?

You could use code like
int i = 1; // or 2, 3, ... 26
char resultChar = i + 'A' - 1; // resultChar will be 'A' or 'B' etc.

Related

How Can I Convert Int To String In assembly [duplicate]

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Assembly 8086 | Sum of an array, printing multi-digit numbers
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Displaying numbers with DOS
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How do I print an integer in Assembly Level Programming without printf from the c library? (itoa, integer to decimal ASCII string)
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Closed 2 years ago.
Can I Convert Var(int) like this:
var1 db 45
That the Var1 will be "45"

Random number generator in Kotlin [duplicate]

This question already has answers here:
How can I get a random number in Kotlin?
(24 answers)
Closed 1 year ago.
Hi how can you generate a random int between 0 and 10 in kotlin ? I tried Random().nextInt() and val rnds = (0..10).random() but i can't generate one. Thanks
To generate random number you can do as follow:
val randomNumber: Int = Random().nextInt(10) // here you can set your own bound value. This will give you random number from 0 to 10

How to change values in a column from object type to float. for Example, "'€220 M" to 220,000,000? [duplicate]

This question already has answers here:
Convert the string 2.90K to 2900 or 5.2M to 5200000 in pandas dataframe
(6 answers)
Closed 3 years ago.
I have a column with data as:
1 77M
2 118.5M
3 72M
4 102M
5 93M
6 67M
I need to change this to its numerical value as:
77,000,000
and so on.
I have tried different ways but could not come up with a definite solution.
okay this should work
(df[1].str.replace('M','').astype(float) * 1000000).astype(int).astype(str).apply(lambda x : x[:-6]+','+x[-6:-3]+','+x[-3:])
Output
0 77,000,000
1 118,500,000
2 72,000,000
3 102,000,000
4 93,000,000
5 67,000,000
Name: 1, dtype: object

generate maximum number of combinations [duplicate]

This question already has answers here:
How to generate a power set of a given set?
(8 answers)
Closed 4 years ago.
I am trying to find an algorithm enabling to generate the full list of possible combinations from x given numbers.
Example: possible combinations from 3 numbers (a, b,c):
a, b, c , a +b , a + c , b + c , a+b+c
Many thanks in advance for your help!
Treat the binary representation of the numbers from 0 to 2^x-1 as set membership. E.g., for ABC:
0 = 000 = {}
1 = 001 = {C}
2 = 010 = {B}
3 = 011 = {B,C}
4 = 100 = {A}
etc...
Do you meant generate possible combination of sum of numbers?
Start with an empty set s = {0}
For each number a,b,c:
duplicate the existing set s, add each number to the duplicated set. Add the results back to s.
Example:
s = {0}
for a:
duplicate s, s' = {0}
add a to each of s', s' = {a}
add s' back to s, s = {0,a}
for b:
duplicate s, s' = {0,a}
add b to each of s' = {b,a+b}
add s' back to s, s= {0,a,b,a+b}
for c:
dupicate s, s' = {0,a,b,a+b}
add c to each of s' = {c,a+c,b+c,a+b+c}
add s' to s, s = {0,a,b,a+b,c,a+c,b+c,a+b+c}

How to use "0" before number in Visual Basic? [duplicate]

This question already has answers here:
Numbers with leading zeroes, using vb6
(3 answers)
Closed 9 years ago.
I want to print the result in my program like this: 06:03 in visual basic 6
How can I add "0" before numbers ?
m=6
h=3
print m;" : ";h
Like this?
You have to use Format()
m = 6
h = 3
Debug.Print Format(m, "00"); " : "; Format(h, "00")
Output: 06 : 03