Select all the people that have the same salary - sql

Question

I have problems finding a solution to an SQL query. This is probably a very obvious beginner question but I can't seem to get the results that I'm after. I have a table that looks something like the following:
|Name |Station|Salary|
|Bob |1 |2000 |
|Steve|2 |1750 |
|Mark |3 |2050 |
|Lisa |4 |2200 |
|Hans |5 |2000 |
I would like to select the names of the people in this table that have the same salary. The result should of course be Bob and Hans.

Answer 1

If you join the table against itself on Salary but where the names are separate then this should give you any matching salaried people:
SELECT s1.Name, s1.Station, s1.Salary
FROM Staff s1
INNER JOIN Staff s2 ON s1.Salary = s2.Salary AND s1.Name <> s2.Name
Here's a SQLFiddle to show it in action

Answer 2

SELECT Name
FROM table1
WHERE Salary IN (
SELECT Salary
FROM table1
GROUP BY Salary
HAVING COUNT(*) > 1
)

Answer 3

If you determine the salary bands which have more than one employee, you can then join back to it as a derived table:
SELECT e.Name, e.Station
FROM Employee e
INNER JOIN
(
SELECT Salary
FROM Employee
GROUP BY Salary
HAVING COUNT(*) > 1
) grp ON e.Salary = grp.Salary;
SqlFiddle here

Answer 4

Most databases support window functions. The simple method to do this is to count the number of people that have a given salary. Then choose those people. Here is an easy method:
select t.*
from (select t.*, count(*) over (partition by salary) as salarycnt
from table t
) t
where salarycnt > 1
order by salary;

Answer 5

TRY THIS:
SELECT E1.Name, E1.Salary
FROM Employee E1, Employee E2
WHERE E1.Salary = E2.Salary
AND E1.Name <> E2.Name
http://sqlfiddle.com/#!2/1e34b

Answer 6

Use below Query:
with datatab as
(
select 'Bob' Name, 1 Station, 2000 Salary from dual union
select 'Steve' Name, 2 Station, 1750 Salary from dual union
select 'Mark' Name, 3 Station, 2050 Salary from dual union
select 'Lisa' Name, 4 Station, 2200 Salary from dual union
select 'Hans' Name, 5 Station, 2000 Salary from dual union
select 'Test' Name, 6 Station, 1750 Salary from dual
)
SELECT NAME, sTATION, SALARY FROM DATATAB
WHERE SALARY IN
(
SELECT Salary
FROM datatab
GROUP BY Salary
HAVING COUNT(1) > 1
);
As someone suggested in Edits, The Query would be:
SELECT NAME, sTATION, SALARY FROM TABLE_NAME
WHERE SALARY IN
(
SELECT Salary
FROM TABLE_NAME
GROUP BY Salary
HAVING COUNT(1) > 1
)

Answer 7

Select a.name, a.salary from
(
Select count(salary) as cnt, salary from staff group by salary having count(salary) > 1
)as X
Inner join staff a on a.Salary=x.salary
order by a.salary:

Answer 8

Use aliases when you have to put one and the same table two or more times:
select t1.Name,
t2.Name,
t1.Salary
from MyTable t1,
MyTable t2
where t1.Station > t2.Station and -- if Station is id
-- t1.Name > t2.Name -- if Name is in fact an id
t1.Salary = t2.Salary

Answer 9

Try this:
select COUNT(*) as NumberOfPerson,salary from tblEmployee group by salary having COUNT(*)>1

Answer 10

For MySQL:
Select * from worker
where salary in (select salary from worker
group by salary
having count(1)>1);

Answer 11

lets say table name is: employee
select distinct e.name, e.salary from employee e, employee e1 where
e.salary = e1.salary and e.name != e1.name;

Answer 12

First Solution :
Select e1.name from employee e1
inner join employee e2 on e1.salary=e2.salary AND e1.name <> e2.name
Second easy solution:
Select name from employee
where salary In (Select salary from employee
group by salary
having count(*)>1)

Answer 13

SUPPOSE WE HAVE TABLE NAMELY AS EMP3 WHICH ONTEIN COLUMNS AS FIRST_NAME,LAST_NAME,SALRY,DEPARTMENT_ID,COMMISSION ETC.
NOW WE HAVE TO SELECT RECORDS OF EMPLOYEES WHO HAVE THE SAME SALARY.
LET'S GET OUTPUT WITH THE HELP OF SELF JOIN.
HERE WE ARE JOINING THE SAME TABLE WITH ITSELFMTO GET RECORDS WHO HAVE THE SAME SALARY.
SELECT E1.FIRST_NAME AS FN,E1.SALARY FROM EMPLOYEES E1 INNER JOIN EMPLOYEES E2 ON E1.SALARY=E2.SALARY;

Answer 14

Treating same table as a separate two table.
SELECT DISTINCT T.username, T.salary
FROM account T, account T
WHERE T.salary = T.salary
AND T.username <> T.username
ORDER BY salary;

Answer 15

Do you want the quantity of people with the same salary.
SELECT count(*) FROM table GROUP BY salary