This question already has an answer here:
Converting special character to plain text in oracle
(1 answer)
Closed 5 years ago.
I'm a new SQL user, and I'd like to know if there is a simple way of replacing non-English characters in Oracle SQl-developer. Let's Say, I want Hernán Nuñez to show up as Hernan Nunez, but without having to actually replace "Hernán" with "Hernan". What I need is to replace everything that contains "á" to the same thing, but with "a" instead, for example. Any suggestions?
US7ASCII will give you the right result. Example:
SELECT CONVERT('BESANÇON','US7ASCII')
FROM table;
CONVERT(
--------
BESANCON
1 row selected.
Related
This question already has answers here:
SQL Server 2005 Weird varchar Behavior
(2 answers)
Closed 6 months ago.
SO I know that there are a few post like this already here, but those post don't seem to work for me. My string contains '^' in it, and replace does not seem to like that character. Because of this, SELECT * FROM STRING_SPLIT(REPLACE(#InbMsg,#CLRF,'|'),'|')
does not seem to work The example message is this:
'W^1^Wave1102^2^11
H^12345678900987654321^OD1128263^MLO^7^Bill’s Order^98712391^N^A2^3^11
D^OGMens77162^123456789009^Y^4^Medium^Red^006134^000101^11728492'
When I run it through the previous statment, I just get 'W'. Anyone know why?
You want to replace the newline between 11 and H and also between 11 and D. You can replace the newline by looking for CHAR(10) then replace it with '^'. Then you can now split the rows using '^' as delimiter.
select * from STRING_SPLIT(REPLACE('W^1^Wave1102^2^11
H^12345678900987654321^OD1128263^MLO^7^Bill’s Order^98712391^N^A2^3^11
D^OGMens77162^123456789009^Y^4^Medium^Red^006134^000101^11728492',CHAR(10),'^'),'^');
Sample result:
https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=0dc110c889af42a8b02096eedee3c393
value
W
1
Wave1102
2
11
H
12345678900987654321
OD1128263
MLO
7
…
10 rows of 26
CHAR(10) is ascii value for New Line / Line Break for SQL Server
It was a situation of not using varchar correctly. Make sure to declare variables correctly! ```SELECT * FROM STRING-SPLIT(REPLACE(#msg, #CLRF, ','),',') works in this situation!
This question already has an answer here:
Reference - What does this regex mean?
(1 answer)
Closed 3 years ago.
I have to put a string after every 5 characters in a given string (varchar2).
Given string can have different length.
I already solved it by a loop using substrings.
Is there any way i could reach the goal using REGEXP in Oracle DB?
You can use REGEXP_REPLACE to replace every 5 characters with those 5 characters followed by another string. For example:
SELECT REGEXP_REPLACE('ABCDE12345FGHIJ67890KL', '(.{5})', '\1*') FROM DUAL
Output:
ABCDE*12345*FGHIJ*67890*KL
Demo on dbfiddle
This question already has answers here:
How to extract Certain nth character from a string in SQL
(4 answers)
Closed 4 years ago.
I am trying to select a column using SQL but with a condition that would ignore all values in the column that have the 4th character of the value as 0.
For example,
my Column is called promos, and the stored values are W080045678, I want this value to be ignore since the 4th character is a 0 in the string.
What is the condition that I can add?
I have tried
AND promos <> '__'0%'
But no luck.
You are looking for NOT LIKE:
and promos not like '___0%'
This question already has answers here:
How to split string using delimiter char using T-SQL?
(4 answers)
How to split a comma-separated value to columns
(38 answers)
Split values over multiple rows [duplicate]
(2 answers)
Closed 9 years ago.
I have this piece of text that is stored in our MS-SQL database (ignore the quotes and no, I can't redesign how this work specifically):
"TEST|00000298398293|EQ5|Patient"
Now, when I do a simple select, I get that result being returned. What I'd like to do is split that string based on the "|" character and return the individual strings associated with this string, so that I could have "TEST", "0000298398293", "EQ5" and "Patient" in different fields. How can I do this? In PHP, you can use the explode method, is there something like that in MS-SQL?
It's surely not the most elegant solution but i've used in in the past:
DECLARE #Sql varchar(50) = 'TEST|00000298398293|EQ5|Patient'
SELECT
PARSENAME(REPLACE(#sql,'|','.'),4),
PARSENAME(REPLACE(#sql,'|','.'),3),
PARSENAME(REPLACE(#sql,'|','.'),2),
PARSENAME(REPLACE(#sql,'|','.'),1)
Notice : This only works if you have 3 pipes, eventually consider to redesign your database in the future!
This question already has answers here:
How to get rightmost 10 places of a string in oracle
(5 answers)
Closed 8 years ago.
I have a table containing the following fields:
version
id
set_value
marker
I want to write a SELECT statement to query them. However, the values in the column marker are not easily readable. I would like to present a substring of that column. My question is how do I do this?
You can use this:
SELECT version,
id,
set_value,
SUBSTR(marker, 1, 10) AS marker
FROM ...
to select just the first ten characters of marker, and still have the resulting column be named "marker".
(See http://docs.oracle.com/cd/B28359_01/server.111/b28286/functions169.htm.)
You can use the substr function.