It is possible simplify this query (MSSQL)?
SELECT RIGHT(STR(MONTH('2014-05-02'))+100,2) + '-'
+ RIGHT(STR(DAY('2014-05-02'))+100,2)
I want month and day from a date but always with leading zeros if only have one digit in the month / day. In this date 2014-05-02 I want only 05-02. I can do that with this query but I don't know if there is a simply way...
SELECT CONVERT(CHAR(5), GETDATE(), 10)
Result:
05-23
Please try:
select RIGHT(CONVERT(nvarchar(10), GETDATE(), 126), 5)
For the example,
select RIGHT(CONVERT(nvarchar(10),CONVERT(DATETIME, '2014-5-2'), 126), 5)
Try this...
SELECT LEFT(CONVERT(VARCHAR(10), GETDATE(), 110),5)
OR
SELECT LEFT(CONVERT(VARCHAR(8), GETDATE(), 10),5)
Both return the same result as follows
RESULT: 05-23
I like using format.
If you have a string:
select format(convert(date, '2014-05-23', 126),'MM-dd');
If you have a date:
select format(GetDate(),'MM-dd');
This could really Help you.
DECLARE #A DATETIME = GETDATE()
SELECT CONVERT(VARCHAR(5),#A,110)
Related
How can I subtract one month from mm/yy in SQL?
For an example from 02/23 to 01/23.
Since your date format is not the recommended one. But for your scenario, you can use the following query to get your expected result.
Using DATEFROMPARTS() and string functions you can construct as a date and the DATEADD(MONTH, -1, date) will help to subtract one month.
DECLARE #TestTable TABLE (DateVal VARCHAR(5));
INSERT INTO #TestTable (DateVal) VALUES ('02/23'), ('01/23'), ('03/30');
SELECT DateVal,
RIGHT(CONVERT(VARCHAR(8), DATEADD(MONTH, -1, DATEFROMPARTS(RIGHT(DateVal, 2), LEFT(DateVal, 2), '01')), 3), 5) AS Result
FROM #TestTable
Result:
DateVal Result
----------------------
02/23 01/23
01/23 12/22
03/30 02/30
Demo on db<>fiddle
I think you need to use convert() to get a valid date, then dateadd() to subtract 1 month and finally format() to get the date in the string format:
select
format(dateadd(month, -1, convert(date, concat('01/', datecolumnname), 3)), 'MM/yy')
from tablename
See the demo.
This comes with a warning is super ugly but if you want string previous month then string again, maybe convert to date do the dateadd then back to string, horrid!
with cte_d
as
(select '01/23' as stringdate
union
select '12/17' as stringdate
)
select stringdate
,cast(Month(dateadd(month,-1,cast(right(stringdate,2)
+ left(stringdate,2) + '01' as date))) as nvarchar(2))
+'/'+
right(cast(Year(dateadd(month,-1,cast(right(stringdate,2)
+ left(stringdate,2) + '01' as date))) as nvarchar(4)),2) as [NewDate]
from cte_d
My date field has value format to be : Feb 15 2019. Is there a way to convert this to MMDDYYYY format?
Desired output: 02152019
Query I tried: SELECT convert(varchar, getdate(), 112) - this query is showing YYYYMMDD format :(
Any help?
select format( convert(date, 'Feb 15 2019'), 'MMddyyyy')
-- results to: 02152019
-- But again, your application is to take care about format!!!
Try this query,
select replace(convert(varchar, getdate(),101),'/','')
You can try this
Select convert(varchar(12), convert(date, 'Feb 15 2019'), 112)
or
SELECT REPLACE(CONVERT(VARCHAR(10), GETDATE(), 101), '/', '') AS [MMDDYYYY]
This will give output - 20190215.
You can pass different value like 101. For different output see Here.
Just have an sql query that has a date in the format:
"2018-05-31"
Need to convert it to:
"May-18"
You can use Format function
Select format(getdate(), 'MMM-yyyy')
Try this:
SELECT LEFT(DATENAME(MONTH,GETDATE()),3) + '-' + RIGHT('00' + CAST(YEAR(GETDATE()) AS VARCHAR),2)
SELECT FORMAT(GETDATE(),'MMM yy')
you can try below way
Declare #Date DateTime = '2018-05-31'
Select Format(#Date, N'MMM-yy')
http://sqlfiddle.com/#!18/433d6/194
FORMAT can be very slow. This looks a little less intuative, however, if you have a large dataset, will probably be much quicker:
SELECT STUFF(STUFF(CONVERT(varchar(11),GETDATE(),13),1,3,''),4,3,'-');
This here could work:
declare #date date = '2018-05-31'
select *, FORMAT(DATEFROMPARTS(1900, right(YearMonthKey,2), 1), 'MMMM', 'en-US') +'-'+ substring(YearMonthKey,3,2) as MonthYearName from (
select LEFT(CAST(CONVERT(VARCHAR(8), #date, 112) AS INT),6) as YearMonthKey
)x
I would use convert() with style code 6 :
select replace(substring(convert(varchar(12), datecol, 6), 4, 6), ' ', '-')
You can change the way that a date or timestamp column is display at any time by altering your session to re-set nls_date_format. This will work in SQL*Plus or PL/SQL:
alter session set nls_date_format = 'MON-YY';
I want to select getdate() in the format yyyy/M. I tried to write a query
SELECT FORMAT(GETDATE(), 'yyyy/M')
but it is throwing an error.
I am a beginner in SQL. How do I get the yyyy/m format if there is only single digit month? E.g. the query should return 2016/1 when there is only one digit month (it should not return 2016/01) and should return 2016/10 when the month has two digits
How about getting the YEAR and MONTH part of the date and just concatenate them:
SELECT
CAST(DATEPART(YEAR, GETDATE()) AS VARCHAR(4)) + '/' +
CAST(DATEPART(MONTH, GETDATE()) AS VARCHAR(2))
Try this:
SELECT FORMAT(GETDATE(),'yyyy/MM')
SELECT FORMAT(CAST('2015-11-15' AS smalldatetime),'yyyy/M'),
FORMAT(CAST('2015-01-15' AS smalldatetime),'yyyy/M')
Gives:
2015/11 | 2015/1
SELECT CONVERT(VARCHAR(7), GETDATE(), 111) AS [YYYY/MM]
OR
SELECT CONVERT(VARCHAR(7), GETDATE(), 111)
I have an integer column "Month"
I would like to get 2 digit number for month.
This is what I have tried: DATEPART(mm, #Date)
It returns one digit for months January to September
I am using SQL Server 2008
Anyone has suggestion?
Function
FORMAT(date,'MM')
will do the job with two digit.
there are different ways of doing it
Using RTRIM and specifing the range:
like
SELECT RIGHT('0' + RTRIM(MONTH('12-31-2012')), 2);
Using Substring to just extract the month part after converting the date into text
like
SELECT SUBSTRING(CONVERT(nvarchar(6),getdate(), 112),5,2)
see Fiddle
There may be other ways to get this.
Pinal Dave has a nice article with some examples on how to add trailing 0s to SQL numbers.
One way is using the RIGHT function, which would make the statement something like the following:
SELECT RIGHT('00' + CAST(DATEPART(mm, #date) AS varchar(2)), 2)
Another simple trick:
SELECT CONVERT(char(2), cast('2015-01-01' as datetime), 101) -- month with 2 digits
SELECT CONVERT(char(6), cast('2015-01-01' as datetime), 112) -- year (yyyy) and month (mm)
Outputs:
01
201501
CONVERT(char(2), getdate(), 101)
Alternative to DATEPART
SELECT LEFT(CONVERT(CHAR(20), GETDATE(), 101), 2)
SQLFiddle Demo
append 0 before it by checking if the value falls between 1 and 9 by first casting it to varchar
select case when DATEPART(month, getdate()) between 1 and 9
then '0' else '' end + cast(DATEPART(month, getdate()) as varchar(2))
For me the quickest solution was
DATE_FORMAT(CURDATE(),'%m')
Simply can be used:
SELECT RIGHT('0' + CAST(MONTH(#Date) AS NVARCHAR(2)), 2)
Try:
select right ('0'+convert(nvarchar(2), DATEPART(mm, getdate())),2 )
My way of doing it is:
right('0'+right(datepart(month,[StartDate]),2),2)
The reason for the internal 'right' function is to prevent SQL from doing it as math add - which will leave us with one digit again.
SELECT REPLACE(CONVERT(varchar, MONTH(GetDate()) * 0.01), '0.', '')