How to reset the focus of the XAML designer? - xaml

So I right clicked the name of a DataTemplate in my XAML and selected "Go To Definition". This changed the content of the designer from showing the page I was working on to showing the DataTemplate defined in the page resources.
How do I switch the designer back to showing the page?

It turns out that you can click the icon in the top left of the Document Outline window.
Note: this is based on someone else's answer which was deleted before I could check it.

Related

Is there a way to automatically change the selected menu page in a master detail project when the detail changes?

Background:
My project uses the "Master Detail" project from Xamarin.Forms, so it comes equipped with the hamburger menu button in the top left which is supposed to be the main source of navigation throughout the app. However, my app requires the user to go through multiple of those screens without the use of the hamburger menu. But when a user uses my own buttons to change the detail, the hamburger menu still says the user is on the previous page.
For example, a user is on Page A. They click a button outside of the menu which sends them to Page B. The menu will still show Page A.
My Attempt:
I really didn't know where to start, so I tried taking the MenuItemType and passing it through the following function:
// This changes the screen without changing the menu and it works.
((MasterDetailPage)Application.Current.MainPage).Detail = new NavigationPage(new PageB());
// This was my attempt to change the menu.
(Application.Current.MainPage as MenuPage).RootPage.NavigateFromMenu((id)MenuItemType.PageB);
But that returned a Null Reference Exception when run.
I've also tried manually calling the list view associated with the hamburger menu and changing the selectedItem property, but that didn't work either. Is there any way to change the selected menu?
For Clarity:
Since StackOverflow won't let me post a video, here's a link to how the app acts. As you can see, I use the Menu to go to the "About" Page. I click a button on the screen which takes me back to the "Browse" Page. However, when I open the menu, it still says "About" is selected. I can't reselect "About" until the menu moves away, meaning I have to reopen "Browse" despite already being on that screen.
What I'm looking for is a function which will automatically change the selected menu item to "Browse" when I press that button on the "About" Page. The app is currently using a Master Detail Page which has the "Detail" component changing from the About Page to the Browse Page. The menu page is a Content Page which came built with the app beforehand.

Widget similar to Android context menu

I would like to have a widget similar to android context menu on every listview item.
I have a listview and on every item is on the right site a button (3 dots), where the user should open a popup menu for this item.
In the end it should look like this image
I tryed it with PopupMenu, but i didn't get it.
Does someone can give me a hint how to do this?
Thanks

dojox form uploader button is clickable only on the border, but not on the full button

I am using IE8
I have created dojo button as below
It has displayed button "Select Files".
Problem
When I click on top border of button its working fine. When I click on any other places on button file picker dialogbox is not displaying.
When I right click on button and select zoom in option once, I am able to click on all the coordinates of button(after selecting zoom option, it works similar to html button).
Note: I have used flash for multiple file selection.
Please tell how to make this button work by clicking in any place.
Have you checked if there is other element's borders in front of the button? Try to check with the developer tools option activated on your browser and select "inspect element" (or similar). If another element is detected when you hover over the button, you have your answer.
Apart from that I have no more ideas.

How to create a nice add button to list view like in the Weather app?

Following these steps:
Open the Weather app.
Right click
Click on places
See that little item with the + symbol? I want to do something exactly like that, the looks and behaviour.
Assuming you are just trying to get some basic ideas about metro-ui controls and you are on Release Preview.
When you do right click, the control that's being triggered is called App Bar. The "place" button is a App Bar Command. Clicking on the button will take you to another page (HTML or XAML). This page contains a ListView control with GridLayout. You can dynamically change the ListView Template and assign different actions to the itemInvoke event.
Here is a quick tutorial for App Bar and commands:
http://msdn.microsoft.com/en-us/library/windows/apps/hh465309.aspx
Here is a quick tutorial for List View control:
http://msdn.microsoft.com/en-us/library/windows/apps/hh465496.aspx

bring page to foreground? multipage editor

I'm develpping an RCP user interface. I have a multipage editor in which pages are editors (EditorPart). From a first page in my multipage editor I want to open a second one if a button is pressed. I've managed to do that but the problem that I'm facing is that the created page is visible only if we switch to it, i.e only the tab is visble.. what I want is to directly switch to the new page automatically after its creation. In other words, how can I bring the new page to foreground exactly when it is created.
Can you help me please
Kind Regards,
Jean
It seems to me that the calling the method org.eclipse.ui.part.MultiPageEditorPart.setActivePage(int) should do the trick.