In Objective-C I can do the following operation:
Objective-C code:
CGFloat width = CGRectGetWidth(mView.bounds);
CGFloat total = width*[myArray count];
but in Swift, it will raise an error:
Could not find an overload for '*' that accepts the supplied arguments
How can I avoid this situation elegantly?
First, let's create some demo data
let array: NSArray = ["a", "b", "c"] //you could use a Swift array, too
let view = UIView() //just some view
Now, everything else works almost the same way as in Obj-C
let width: CGFloat = CGRectGetWidth(view.bounds)
or simply
let width = CGRectGetWidth(rect) //type of the variable is inferred
and total:
let total = width * CGFloat(array.count)
Note that we have to add a CGFloat cast for array.count. Obj-C would implicitly cast NSUInteger to CGFloat but Swift has no implicit casts, so we have to add an explicit one.
In Swift you cannot multiply two numbers of different types (NSNumber, Int, Double, etc.) directly. The width of a CGRect is of floating point type and the array count is of integer type. Here's a working example:
let myArray: Int[] = [1,2,3]
let rect: CGRect = CGRect(x:0,y:0,width:100,height:100)
let total: Double = rect.size.width * Double(myArray.count)
Swift does not allow operations between two numbers of different types. Therefore, before to multiply your array.count (Int) by your width (CGFloat), you'll have to cast it to CGFloat.
Fortunately, Swift provides a simple CGFloat initializer init(_:) that creates a new CGFloat from an Int. This initializer has the following declaration:
init<Source>(_ value: Source) where Source : BinaryInteger
Creates a new value, rounded to the closest possible representation.
The Swift 5 Playground sample code below shows how to perform your calculation by using CGFloat's initializer:
import UIKit
import CoreGraphics
// Set array and view
let array = Array(1...3)
let rect = CGRect(x: 0, y: 0, width: 100, height: 100)
let view = UIView(frame: rect)
// Perform operation
let width = view.bounds.width
let total = width * CGFloat(array.count)
print(total) // prints: 300.0
need to change All Int to CGFloat Type, or change All CGFloat to Int
let a: CGFloat = 0.25
let b: Int = 1
// wrong: Binary operator '*' cannot be applied to operands of type 'CGFloat' and 'Int'
// let c = a * b
// right: change All Int to CGFloat Type
let r = a * CGFloat(b)
// right: change All CGFloat to Int
let r = Int(a) * b
Related
In Swift I can do this:
let z = CGFloat.maximum(20.0, 50.0) // z = 50.0
Tried to convert it to Objective-C:
CGFloat z = [CGFloat maximum:20.0, 50.0]; // Also tried (CGFloat *)
But getting a compilation error:
Receiver type 'CGFloat' (aka 'double') is not an Objective-C class
To simplify example I used 2 constants, but in reality function will receive 2 CGFloat variables, if it matters.
So how can I get maximum between 2 CGFloats in Objective-C?
CGFloat z = MAX(20, 50);
CGFloat is not an object, so there is no * and no methods.
How do I transform the following ObjectiveC statements into SWIFT:
UInt32 *pixels;
pixels = (UInt32 *) calloc(height * width, sizeof(UInt32));
I tried to do the following:
var pixels: UInt32
pixels = (UInt32)calloc(height * width, sizeof(UInt32))
and I receive the error message:
Int is not convertible to UInt
and the (UInt32) Casting didn't work as well.
Can someone give me some advice please? I am struggling a little bit with SWIFT still. Thank you.
Here's an easier way of allocating that array in swift:
var pixels = [UInt32](count: height * width, repeatedValue: 0)
If that's what you actually want to do.
But, if you need a pointer from calloc for some reason, go with:
let pixels = calloc(UInt(height * width), UInt(sizeof(UInt32)))
The type of pixels though must be a type of UnsafeMutablePointer<T>, and you would handle it like a swift pointer in the rest of your code.
For Swift-3 :
UnsafeMutablePointer is replace by UnsafeMutableRawPointer
var pixels = UnsafeMutableRawPointer( calloc(height * width, MemoryLayout<UInt32>.size) )
Reference
If you really know what you are doing and insist in allocating memory unsafely using calloc:
var pixels: UnsafeMutablePointer<UInt32>
pixels = calloc(height * width, sizeof(UInt32))
or just
var pixels = calloc(height * width, sizeof(UInt32))
I want to convert this into swift, or at least find something that does the same thing.
size_t width = CGImageGetWidth(spriteImage);
size_t height = CGImageGetHeight(spriteImage);
GLubyte * spriteData = (GLubyte *) calloc(width*height*4, sizeof(GLubyte));
I need to initialize the spriteData pointer in swift of the right size.
The first two of those are of type size_t, which maps to Uint in Swift, and the last is GLubyte, which maps to UInt8. This code will initialize spriteData as an array of GLubyte, which you could pass to any C function that needs an UnsafeMutablePointer<GLubyte> or UnsafePointer<GLubyte>:
let width = CGImageGetWidth(spriteImage)
let height = CGImageGetHeight(spriteImage)
var spriteData: [GLubyte] = Array(count: Int(width * height * 4), repeatedValue: 0)
What do you need to do with spriteData?
The straightforward way is:
var spriteData = UnsafeMutablePointer<GLubyte>.alloc(Int(width * height * 4))
Note that, if you did this, you have to dealloc it manually.
spriteData.dealloc(Int(width * height * 4))
/// Deallocate `num` objects.
///
/// :param: num number of objects to deallocate. Should match exactly
/// the value that was passed to `alloc()` (partial deallocations are not
/// possible).
I'm assigning a CGFloat animatedDistance and I'm getting this error.
Here I'm assigning value to animatedDistance
static const CGFloat KEYBOARD_ANIMATION_DURATION = 0.3;
static const CGFloat LANDSCAPE_KEYBOARD_HEIGHT = 140;
heightFraction is CGFloat as well.
if (orientation == UIInterfaceOrientationPortrait ||
orientation == UIInterfaceOrientationPortraitUpsideDown)
{
animatedDistance = floor(PORTRAIT_KEYBOARD_HEIGHT * heightFraction);
}
else
{
animatedDistance = floor(LANDSCAPE_KEYBOARD_HEIGHT * heightFraction);
}
What type should be animatedDistace? Can someone help me?
floor returns a double. On some platforms, CGFloat is a float. animatedDistance should be typed as a double (you can cast it to a CGFloat if needed).
Use this to get a vector... CGpoint vector = ccpSub(cgpoint 1, cgpoint 2);
And if you want double/float values then do this:
CGpoint.location
for whatever you are trying to find the coordinates of, then assign a float to CGPoint.location.y and another float to CGPoint.location.x
You need cocos2d for this by the way. I think.
Sounds to me like you declared animatedDistance as holding some kind of pointer, such as NSNumber *, or a structure, such as CGSize. Either way, you can't assign a CGFloat there.
If animatedDistance holds an NSNumber object, create one around the value. Back when you asked this question, the way to do this was [NSNumber numberWithDouble:floor(…)]. Now, you can just use #(floor(…)).
If animatedDistance holds a CGSize or other structure, you're going to have to decide for yourself how to meaningfully convert from the single number you have to the kind of structure you want.
I'm attempting to define an extremely simple utility method that will save me from having to use a calculator to define RGB values as percentages. When I look into Apple's sample code called "QuartzCache", in the DrawView.m file, line 96, I see this:
float whiteColor[4] = {1, 1, 1, 1};
However, when I attempt to created a method like the following, the compiler hates me. A half-hour of intensive Googling has not produced any help.
+(float[])percentagesRGBArray:(float[])rgbArray{
float red = rgbArray[0];
float green = rgbArray[1];
float blue = rgbArray[2];
float alpha = rgbArray[3];
red = red/255;
green = green/255;
blue = blue/255;
alpha = alpha;
float percentagesRGBArray[4] = {red, green, blue, alpha};
return percentagesRGBArray;
}
What is the proper way to define such a method? What am I doing wrong here?
Define a struct that contains all of the components, or wrap up each individual component in an NSNumber. Alternatively, use an NSColor instance to contain your colour components.
struct way:
typedef struct
{
float red;
float green;
float blue;
float alpha;
} MyColor;
- (MyColor) percentagesRGBArray:(MyColor) incoming
{
MyColor result;
result.red = incoming.red / 255;
result.green = incoming.green / 255;
result.blue = incoming.blue / 255;
result.alpha = incoming.alpha;
return result;
}
NSNumber way:
- (NSArray *) percentagesRGBArray:(float[]) rgbArray
{
NSNumber *red = [NSNumber numberWithFloat:rgbArray[0] / 255];
NSNumber *green = [NSNumber numberWithFloat:rgbArray[1] / 255];
NSNumber *blue = [NSNumber numberWithFloat:rgbArray[2] / 255];
NSNumber *alpha = [NSNumber numberWithFloat:rgbArray[3]];
return [NSArray arrayWithObjects:red, green, blue, alpha, nil];
}
NSColor way:
- (NSColor *) percentagesRGBArray:(float[]) rgbArray
{
CGFloat red = rgbArray[0] / 255;
CGFloat green = rgbArray[1] / 255;
CGFloat blue = rgbArray[2] / 255;
CGFloat alpha = rgbArray[3];
return [NSColor colorWithDeviceRed:red
green:green
blue:blue
alpha:alpha];
}
Normally, you would use Cocoa's NSColor class to handle this sort of thing, but it looks like you are doing something a little more low-level.
In that case, I would do the following:
typedef struct
{
float red;
float green;
float blue;
float alpha;
}
RGBAData;
RGBAData ConvertRGBAToPercentages(const RGBAData source)
{
RGBAData percentages;
percentages.red = source.red/255;
percentages.green = source.green/255;
percentages.blue = source.blue/255;
percentages.alpha = source.alpha/255;
return percentages;
}
To be used as follows:
RGBAData original = { 0xFF, 0xFF, 0x00, 0x80 }; // 50% transparent yellow
RGBAData percents = ConvertRGBAToPercentages(original);
Both e.James and dreamlax's answers give good approaches for doing this. But to answer what was wrong with your original code:
Basically, it has to do with how C arrays work. An array is essentially equivalent to a pointer to its first element. In fact, when you pass an array to a function, it decays into a pointer. You're still allowed to name the argument float myArray[4] (you have to declare the number of elements) just to make it clear that the pointer is supposed to be to an array of 4 elements — but you're still getting a pointer. Now consider the return value. What are you returning? We already established that you can't return an array by value, because it decays into a pointer. But even if you change the return type to be a pointer, it still won't work, because the array will have gone out of scope once the function returns. In order to return an array, you have to malloc the memory, and then you're responsible for freeing it later.
This is why you should avoid working with C arrays when at all possible. They're really low-level and fiddly. Even when you do use them, it's usually a good idea to hide them behind an API that takes care of the low-level details for you.
I think i'm late) but i have just found this thread.
the C way to do this is to create an array before invoking a function;
+(void) percentagesRGBArray:(float[])inArray toArray:(float*)outArray {
...
}
float array1[4];
float array2[4];
[MyClass percentagesRGBArray:array1 toArray:array2];