How do I auto indent a long method after typing in the finish semicolon in XCode5? - objective-c
I have a long method, after I type it in, it looks like this:
[someObj action1:param1 action2:param2 action3:param3 action4:param4];
But I want it to become like this... :
[someObj action1:param1
action2:param2
action3:param3
action4:param4];
...automatically after I type in the last semicolon.
I just saw a video that did this, so how do I do that?
(It is a paid video so can't give link here)
For the question text:
[someObj action1:param1 action2:param2 action3:param3 action4:param4];
if you have already entered that on one line just select the space between parameters and return
That will tend to alligh the colon ":" characters on multiple lines.
To auto-indent already entered code select the text that you would like auto-indented and then control i and that selection will be indented to Xcode rules.
I use that all the time.
If you just want to move a selected block of code to the left command [, to the right command ]
Have a look at https://github.com/travisjeffery/ClangFormat-Xcode.
It will reformat your code to adhere to style rules, like Chromium's for example, where the line length is 80 chars max.
In this case, the method will be wrapped as you mentioned if it's more than 80 chars.
You can either reformat on a particular key combination, or on each save.
Related
How to shorten the first line in the Intellij console?
I want my first line at the top of the console to look like this:
, but mine looks like this, and it's long:
How can I shorten it to like the first picture?
I'm watching Java tutorials on youtube and their first lines ("C:\programs Files\Java\jdk\whatever"...) are always so short and pretty with 3 cute dots in the end, but mine is long and annoying.
You can define the lines which should be folded: Right click on that line in the console Choose "Fold Lines Like This" Click OK You can also define special keywords/phrases in this menu, where lines, which contains the phrase will be folded with ellipsis (...) at the end.
See the ConsoleViewImpl.java file in the source code of IntelliJ IDEA This line (execution command) will be automatically hidden in case the string length is more than 1000 symbols. So, once you add something to the execution command (for example by adding libraries), the execution command is folded automatically.
How to replace some characters after a specific character to another specific character in one big sql line in notepad++
I have a big sql file with thousand user something like this:
('someone1#mydomain.com','{SSHA512}JWHCqHzazH2vGneLPfhMKkoAamzvxdNCWYOlhZ+uDx36jHdoMXwQmbEemvUMn7ZG6c9+22noXjjb2hAb99/5A/slscDJPKav','','en_US','maildir','Maildir','/home/vmail','vmail1','mydomain.com/someone1/',0,'mydomain.com','','','normal','',0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,NULL,'1970-01-01 01:01:01',0,'',NULL,NULL,'2020-03-19 13:15:58','2015-08-03 06:11:53','2020-03-19 13:15:58','9999-12-31 00:00:00',1'someone1'),
('someone2#mydomain.com','{SSHA512}UoMeyocmdC2DxM0S7B4WFdjnCNuvkngzzLus33h9nugKVlvdhlcboKmMDDuAkCHEyLBUgf8DicKWFPJVS7EOF/ytv27MQ3Ch','','en_US','maildir','Maildir','/home/vmail','vmail1','mydomain.com/someone2/',0,'mydomain.com','','','normal','',0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,NULL,'1970-01-01 01:01:01',0,'',NULL,NULL,'2015-12-17 12:27:35','2015-08-03 06:44:10','2021-06-08 06:55:33','9999-12-31 00:00:00',1'someone2'),
('someone3#mydomain.com','{SSHA512}A6ToCf4OfP3XNEU9ngEmGN/LDquH9+s9Qxme3SoJaDyVvxiWpnwwTiAALSdnmhIxDB2VQK0zhdF+jP8ARvh0N3IDL0Xv/KmL','','en_US','maildir','Maildir','/home/vmail','vmail1','mydomain.com/someone3/',0,'mydomain.com','','','normal','',0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,NULL,'1970-01-01 01:01:01',0,'',NULL,NULL,'2018-04-03 12:31:09','2015-08-03 06:50:01','2018-04-03 12:31:18','9999-12-31 00:00:00',1'someone3'),
('someone4#mydomain.com','{SSHA512}t7/JbUPQ+rtKeRTgWRH6KlETr2JsqYORBOZouzOzs4Wo6YfHYLoy0m+U4kZXk+AeNgMep2hGZSodPZdK2l2bn9MhOKHOuF/L','','en_US','maildir','Maildir','/home/vmail','vmail1','mydomain.com/someone4/',0,'mydomain.com','','','normal',''0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,NULL,'1970-01-01 01:01:01',0,'',NULL,NULL,'2020-03-18 07:48:26','2016-11-14 06:59:04','2021-06-08 05:54:28',9999-12-31 00:00:00',1'someone4')
And now I need to delete the last word ('someone1' , 'someone2' , 'someone3' , 'someone4') for every user which adjoining to 1. It will be looks like
....9999-12-31 00:00:00',1)
not like in original
....9999-12-31 00:00:00',1'someone1')
....9999-12-31 00:00:00',1'someone2')
etc
But don't forget they are not in different lines. All this is in one big line and this makes me to ask you help. Thanks a lot.
It seems that (from your examples) the rows do not contain any parentheses except their start and end characters. So you can search for one quotation mark ', and a number of letters and/or digits, and one quotation mark ', and than ). To do this; Open Replace window in Notepad++ by using ctrl+h shortcut From Search Mode section select Reqular expression Write '[a-zA-Z0-9]*?[-,_,.]*?[a-zA-Z0-9]*?[-,_,.]*?[a-zA-Z0-9]*?[-,_,.]*?[a-zA-Z0-9]*?'\) to Find what box Write '\) to Replace with box Click Replace All button. This works if user names consist of letters or digits and _, -, . at most 3 times. Be Sure that you have a copy of original file as a backup. And also be aware of that the regular expression that we use may find unrelated parts if any row contains closing parentheses except end of it.
VBA replace certain carriage
All. I am used to programming VBA in Excel, but am new to the structures in Word. I am working through a library of text files to update them. Many of them are either OCR documents, or were manually entered. Each has a recurring pattern, the most common of which is unnecessary carriage returns. For example, I am looking at several text files where there is a double return after each line. A search and replace of all double carriage returns removes all paragraph distinctions. However, each line is approximately 30 characters long, and if I manually perform the following logic, it gives me a functional document. If there is a double carriage return after 30+ characters, I replace them with a space. If there were less than 30 characters prior to the double return, I replace them with a single return. Can anyone help me with some rudimentary code that would help me get started on that? I could then modify it for each "pattern" of text documents I have. e.g. In this case, there are more than thirty characters per line. And I will keep going to illustrate this example. This would be a new paragraph, and would be separated by another of the single returns. I want code that would return: In this case, there are more than thirty character returns. And I will keep going to illustrate this example. This would be a new paragraph, and would be separated by another of the single returns. Let me know if anyone can throw something out that I can play with!
You can do this without code (which RegEx requires), simply using Word's own wildcard Find/Replace tools, where:
Find = ([!^13]{30,})[^13]{1,}
Replace = \1^32
and, to clean up the residual multi-paragraph breaks:
Find = [^13]{2,}
Replace = ^p
You could, of course, record the above as a macro...
Here is a RegEx that might work for you: (\n\n)(?<!\.(\n\n)) The substitution is just a plain space, you can try it out (and modify / tweak it) here: https://regex101.com/r/zG9GPw/4 This 'pattern' tells the RegEx engine to look for the newline character \n which occurs x2 like this \n\n (worth noting this is from your question and might be different in your files, e.g. could be \r\n) and it assumes that a valid line break will be proceeded by a full stop: \.. In RegEx the full stop symbol is a single character wild card so it needs to be escaped with the '\' (n and r are normal characters, escaping them tells the RegEx engine they represent newline and return characters). So... the expression is looking for a group of x2 newline characters but then uses a negative look-behind to exclude any matches where the previous character was a full stop. Anyway, it's all explained on the site: Here is how you could do a RegEx find and replace using NotePad++ (I'm not sure if it comes with RegEx or if a plugin is needed, either way it is easy). But you can set a location, filters (to target specific file types), and other options (such as search in sub-directories). Other than that, as #MacroPod pointed out you could also do this with MS Word, document by document, not using any code :)
Does mIRC Scripting have an escape character?
I'm trying to write a simple multi-line Alias that says several predefined strings of characters in mIRC. The problem is that the strings can contain:
{
}
|
which are all used in the scripting language to group sections of code/commands. So I was wondering if there was an escape character I could use.
In lack of that, is there a method, or alternative way to be able to "say" multiple lines of these strings, so that this:
alias test1 {
/msg #　samplestring}contains_chars|
/msg # _that|break_continuity}{
}
Outputs this on typing /test1 on a channel:
<MyName> samplestring}contains_chars|
<MyName> _that|break_continuity}{
It doesn't have to use the /msg command specifically, either, as long as the output is the same.
So basically:
Is there an escape character of sorts I can use to differentiate code from a string in mIRC scripting?
Is there a way to tell a script to evaluate all characters in a string as a literal? Think " " quotes in languages like Java.
Is the above even possible using only mIRC scripting?
"In lack of that, is there a method, or alternative way to be able to "say" multiple lines of these strings, so that this:..."
I think you have to have to use msg # every time when you want to message a channel. Alterativelty you can use the /say command to message the active window.
Regarding the other 3 questions:
Yes, for example you can use $chr(123) instead of a {, $chr(125) instead of a } and $chr(124) instead of a | (pipe). For a full list of numbers you can go to http://www.atwebresults.com/ascii-codes.php?type=2. The code for a dot is 46 so $chr(46) will represent a dot.
I don't think there is any 'simple' way to do this. To print identifiers as plain text you have to add a ! after the $. For example '$!time' will return the plain text '$time' as $time will return the actual value of $time.
Yes.
vb.net VB 2010 Underscore and small rectangles in string outputs?
I've made some good progress with my first attempt at a program, but have hit another road block. I'm taking standard output (as a string) froma console CMD window (results of dsquery piped to dsget) and have found small rectangles in the output. I tried using Regex to clean the little bastards but it seems they are related to the _ (underscore), which I need to keep (to return 2000/NT logins). Odd thing is - when I copy the caharcter and paste it into VS2K10 Express it acts like a carrige return?? Any ideas on finding out what these little SOB's are -- and how to remove them? Going to try using /U or /A CMD switch next..
The square is often just used whenever a character is not displayable. The character could very well be a CR. You can use a Regular Expression to just get normal characters or remove the CR LF characters using string.replace.
You mentioned that you are using the string.replace function, and I am wondering if you are replacing the wrong character or something like that. If all your trying to do is remove a carriage return I would skip the regular expressions and stick with the string.replace. Something like this should work... strInputString = strInputString.replace(chr(13), "") If not could you post a line or two of code. On a side note, this might give some other examples.... Character replacement in strings in VB.NET