I have a table named 'country' with a column named 'name'
and the names in this column appears with translation followed by special character '/'.
IRELAND/IRLANDE
GREECE/GRÈCE
DENMARK/DANEMARK
Now i want only the countrynames before this special character'/' so the out put should look like this..
IRELAND
GREECE
DENMARK
please help. Thanks in advance
create table #t(name nvarchar(40))
insert into #t values('IRELAND/IRLANDE')
,('GREECE/GRÈCE')
,('DENMARK/DANEMARK')
select substring(name,0,CHARINDEX('/',name)) from #t
Why LEN(names)-CHARINDEX('/',names)?
try using CHARINDEX('/',names)+1 instead.
As far as I remember, SUBSTRING's third variables should be the length of the desired output string.
A more complex query to help you out:
DECLARE #Text VARCHAR(50) = 'IRELAND/IRLANDE GREECE/GRÈCE DENMARK/DANEMARK'
SELECT
SUBSTRING(SUBSTRING(#Text,0,CHARINDEX(' ',#Text,0)),0,CHARINDEX('/',#Text,0))
+
SUBSTRING(SUBSTRING(#Text,CHARINDEX(' ',#Text,0),CHARINDEX(' ',#Text,0)),0,CHARINDEX('/',#Text,0))
+ ' '
+
REPLACE(REVERSE(SUBSTRING(REVERSE(#Text),CHARINDEX('/',#Text,0) + 1 ,CHARINDEX('/',#Text,0))),'/', ' ')
Related
Was working on SQL-EX.ru exercises.
There is one question for DML that I could not do, but I cannot proceed to the next one, until this one is done.
the question itself: All the trailing spaces in the name column of the Battles table remove and add them at the beginning of the name.
My code:
Update Battles
set name=concat(' ',(LTRIM(RTRIM(name))))
The system does not let it go through, I understand that I am using ' ' for the concat, whereas I need to use the stuff that got trimmed. And I have no idea how...
Any help would be very much appreciated
Try Something Like:-
set name = lpad(trim(name), length(trim(name))+4, ' ')
Here use TRIM to remove space from both side. use LPAD to add something on left side with n (4) chars
I'm not familiar with SQL-EX.ru, but if it's Oracle compatible and you can use regular expressions (or you are at that point in the training) here's a way. Maybe it'll give you an idea at least. The first part is just setup and uses a WITH clause to create a table (like a temp table in memory, actually called a Common Table Expression or CTE) called battles containing a name column with 2 rows. Each name column datum has a different number of spaces at the end. Next select from that column using a regular expression that uses 2 "remembered" groups surrounded by parentheses, the first containing the string up to until but not including the first space, the second containing 0 or more space characters anchored to the end of the line. Replace that with the 2nd group (the spaces) first, followed by the first group (the first part of the string). This is surrounded by square brackets just to prove in the output the same spaces were moved to the front of the string.
SQL> with battles(name) as (
select 'test2 ' from dual union
select 'test1 ' from dual
)
select '[' || regexp_replace(name, '(.*?)([ ]*)$', '\2\1') || ']' fixed
from battles;
FIXED
----------------------------------------------------------------------------
[ test1]
[ test2]
SQL>
I hope this solution can be applied to your problem or at least give you some ideas.
Try this:
set name = case when len(name) > len(rtrim(name))
then replicate(' ', len(name) - len(rtrim(name))) + rtrim(name)
else name
end
update battles
set name = case when (len(name+'a')-1) > len(rtrim(name))
then
replicate(' ',
(len(name+'a')-1) - len(rtrim(name))) + rtrim(name)
else name
end
Len() doesn't count trailing spaces. So using (len(name+'a')-1).
Simplest answer:
UPDATE Battles
SET name = SPACE(DATALENGTH(name)-DATALENGTH(RTRIM(name))) + RTRIM(name)
But only works because name is VARCHAR.
More generic is to do:
UPDATE Battles
SET name = SPACE(len(name+'x')-1-len(RTRIM(name))) + RTRIM(name)
simple example below ... enjoy :)
update battles set name =
Space( DATALENGTH(name) - DATALENGTH(rtrim(name))) + rtrim(name)
where date in ( select date from battles)
I need to identify repeated numbers( Eg: 1111, 33333333, 5555555555,777777777 etc.) in a column.
How can I do this in sql server without having to hard code every scenario. The max length is 10 of the column. Any help is appreciated.
This will check if the column has all the same value in it.
SELECT *
FROM tablename
WHERE columnname = REPLICATE(LEFT(columnname,1),LEN(columnname))
As Nicholas Cary notes, if the column is numbers you'd need to cast as varchar first:
SELECT *
FROM tablename
WHERE CAST(columnname AS VARCHAR(10)) = REPLICATE(LEFT(CAST(columnname AS VARCHAR(10)),1),LEN(CAST(columnname AS VARCHAR(10))))
Riffing on #Dave.Gugg's excellent answer, here's another way, using patindex() to look for a character different than the first.
select *
from some_table t
where 0 = patindex( '[^' + left(t.some_column,1) + ']' , t.some_column )
Again, this only works for string types (char,varchar, etc.). Numeric types such as int will need to be converted first.
I'm using SQL server to form file names to Ms Word documents. The format is like this
clientnumber_date_time_clientname.doc.
Problem is Ms Word doesn't accept 10:19:23 time format as file name. How to change it into 10-19-23 format?
In some cases clent name is something like this: the "Coca Cola" company. Apparently, Ws Word doesn't accept "(double quotation) mark as file name. I' ve tried to change it into '(single quotation) mark via 'replace' , but it didn't work out. How to change "xxx" into 'xxx'?
Thanks in advance
here is part of that code
convert(varchar,e.ExternalID)+'_'+left(convert(varchar,#Now,120),10) +'uved'+'_'+convert(varchar,a.OwnerName)+'.doc' as NameFile
Try like following code.
DECLARE #CName varchar(100)
DECLARE #CNumber varchar(10)
SET #CNumber ='1234'
SET #CName = '"Coca Cola"'
SELECT #CNumber + '_'
+ REPLACE(REPLACE(CONVERT(VARCHAR(19), GETDATE(), 120),':','-'),' ' ,'_')
+ '_'
+ REPLACE(#CName,'"','''')
+ '.doc'
Run this query and you will get exactly the same filename what you are expecting.
You can use REPLACE as in:
SELECT REPLACE([column],'oldstring','newstring')
FROM [MyTable]
I have a relational database with several fixed length character fields. I need to permanently replace all the embedded spaces with another character like - so JOHN DOE would become JOHN-DOE and ITSY BISTSY SPIDER would become ITSY-BISTSY-SPIDER. I can search before hand to make sure there are no strings that would conflict. I just need to be able to print the requested files with no embedded spaces. I would do the replacement in the C code but I want to make sure that there is never a future case where there is a JANE DOE and JANE-DOE in the DB.
By the way I have already made sure that there are no strings with more than one consecutive embedded space or leading spaces only trailing spaces to fill the fixed length fields.
Edit: thanks for all the help!
It looks like when I cut & pasted my question from Word to StackOverflow the trailing spaces got lost so the meaning my question was lost a bit.
I need to replace only the embedded spaces not the trailing spaces!
Note: I am using middle dot to stand in for spaces that don't show well.
Using:
SELECT REPLACE(operator_name, ' ', '-') FROM operator_info ;
the string JOHN·DOE············ became JOHN-DOE------------.
I need JOHN-DOE············.
I am thinking I need to use aliasing and the TRIM command but not sure how.
With whatever REPLACE function is built into your particular database.
MySQL:
http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_replace
Oracle:
http://psoug.org/reference/translate_replace.html
SQLServer:
http://msdn.microsoft.com/en-us/library/ms186862.aspx
Edits below based on your comment.
I've done this in SQLServer syntax so please modify the example as needed. The first example really breaks down what's going on and the second one bunches it all into a single ugly query :D
#output in this case contains your final value.
DECLARE #input VARCHAR (100) = ' some test ';
DECLARE #trimmed VARCHAR (100);
DECLARE #replaced VARCHAR (100);
DECLARE #output VARCHAR (100);
-- Get just the inner text without the preceding / trailing spaces.
SET #trimmed = LTRIM (RTRIM (#input));
-- Replace the spaces *inside* the trimmed text with a dash.
SET #replaced = REPLACE (#trimmed, ' ', '-');
-- Take the original text and replace the trimmed version (with the inner spaces) with the dash version.
SET #output = REPLACE (#input, #trimmed, #replaced);
-- Show each step of the process!
SELECT #input AS INPUT,
#trimmed AS TRIMMED,
#replaced AS REPLACED,
#output AS OUTPUT;
And as a SELECT statement.
DECLARE #inputTable TABLE (Value VARCHAR (100) NOT NULL);
INSERT INTO #inputTable (Value)
VALUES (' some test '),
(' another test ');
SELECT REPLACE (Value,
LTRIM (RTRIM (Value)),
REPLACE (LTRIM (RTRIM (Value)), ' ', '-'))
FROM #inputTable;
If you are using MSSQL:
SELECT REPLACE(field_name,' ','-');
Edit: After the requirement about skipping the trailing spaces.
You can try this one-liner:
SELECT REPLACE(RTRIM(#name), ' ', '-') + SUBSTRING(#name, LEN(RTRIM(#name)) + 1, LEN(#NAME))
However I would recommend that you put it into a user defined function instead.
assuming SQL Server:
update TABLE set column = replace (column, ' ','-')
SELECT REPLACE(field_name,' ','-');
Edit: After the requirement about skipping the trailing spaces. You can try this one-liner:
SELECT REPLACE(RTRIM(#name), ' ', '-') + SUBSTRING(#name, LEN(RTRIM(#name)) + 1;
I have declare #a varchar(100) = 'abc bcd cde def'. What I need is to select from a table where a column is like 'abc' or 'bcd' or 'cde' or 'def'. I can use a split function and a while to get what I want, but somewhere I saw a smart solution using replace or something similar and I just can't remember it.
I know I can use an xml variable, and parse it that way. However, the value is part of a large procedure, and the best way for me is to use it in string form.
I know I can solve this by building a dynamic sql query, but that is not an option in the domain I'm working in.
Damn, I just can remember the solution. Its a hack, a little dirty trick that do the job.
Anyways, I ll use the code bellow (Im over SQL Server 2008), is it a good idea? I prefer it over the dirty split. Is it more performatic?
declare #w varchar(100) = 'some word'
declare #f xml
set #f = '<word>' + replace(#w, ' ', '</word><word>') + '</word>'
select
template.item.value('.', 'varchar(100)') as word
from #f.nodes('/word') template(item)
Use a function to split the individual items into a table, one record per item. Then you simply join to that table.
insert into #FilterTable (filters)
select Items from dbo.Split(#YourFilterString)
select *
from YourTable yt
join #FilterTable f on f.filters = yt.YourColumn
Of course my example is using equality. It gets more complicated if you truly intend to use "like" with wildcards.
In tsql you can use a pattern col like '[abcd]'
http://msdn.microsoft.com/en-us/library/ms179859.aspx
For matching multiple words (not letter) and without dynamic SQL, you'll have to get the values into a temp table. For a split function try this page http://www.sommarskog.se/arrays-in-sql-2005.html#iterative and look at the List of Strings function iter_charlist_to_table.
Or maybe you are thinking of this little trick Parameterize an SQL IN clause from the SO CEO.
for 4 sections max
WHERE
PARSENAME(REPLACE(#a, ' ', '.'), 1) = 'xxx'
OR
PARSENAME(REPLACE(#a, ' ', '.'), 2) = 'xxx'
OR
PARSENAME(REPLACE(#a, ' ', '.'), 3) = 'xxx'
OR
PARSENAME(REPLACE(#a, ' ', '.'), 4) = 'xxx'