How can I get the difference in minutes between 2 timestamp fields in google bigquery?
The only function I know is Datediff which gives the difference in day
Thanks
Pentium10's answer works for Legacy SQL. If you're using Standard SQL you can use TIMESTAMP_DIFF and it will do the math for you:
TIMESTAMP_DIFF(timestamp_1, timestamp_2, MINUTE)
https://cloud.google.com/bigquery/docs/reference/standard-sql/functions-and-operators#timestamp-functions
Use TIMESTAMP_TO_USEC(<timestamp>) and do the math.
https://developers.google.com/bigquery/query-reference#datetimefunctions
DATETIME_DIFF(datetime_1, datetime_2, MINUTE/SECOND)
Related
I'm working on JupyterLab(SQL) and I want to get the difference of days between two columns.
The values of the columns are in the format YYYYMMDD but they aren't integers
How can I transform the columns to dates and then get the differences of days.
I'm not totally sure about JupyterLab, but in SQL Server you can use DATEDIFF() to calculate this. For example:
SELECT DATEDIFF(day, '2017/08/25', '2011/08/25') AS DateDiff;
See also:
https://www.w3schools.com/sql/func_sqlserver_datediff.asp
You did not mention the dbms so i am answering for oracle and postgres. You can use above answers but i like to convert them explicitly befor calculating difference.
so here is for
oracle -
TO_DATE('20170103','YYYYMMDD') - TO_DATE('20200103','YYYYMMDD')
postgres
EXTRACT(DAY FROM TO_TIMESTAMP('20160101', 'YYYYMMDD')-TO_TIMESTAMP('20150301', 'YYYYMMDD')
JupyterLab(SQL) supports SQLite, PostgreSQL, and MySQL databases:
MySQL:
SELECT DATEDIFF("20201005", "20201001");
PostgreSQL:
SELECT DATE_PART('day', AGE('20201005', '20201001'));
Need some help to perform this in Hive .
I do have timestamp like "2019-03-11T18:23:49-04:00"
How to I subtract the hour and minutes from the above timestamp.( -04:00)
The hour component may vary based on the timezone.
Thanks in advance.
Looks like you can't do this as easily as you can in MSSQL with dateadd. Some very good suggestions are made here. I also tested this and it works as it should.
select from_unixtime(unix_timestamp('2015-12-12 16:15:17')+8500)
I have modified this to work with your exact timestamp format
select from_unixtime(UNIX_TIMESTAMP(substring(translate("2019-03-11T18:23:49-04:00",'T',' '),1,19))+8500)
I didn't find any simple answer to this while I was looking around, so I thought I'd put it up here in case anyone was having the same problem as me with what should have been a trivial issue.
I was using ReDash analytics with Google's BigQuery and had turned on Standard SQL in the datasource settings. For the purposes of my query, I needed to convert a timestamp - unix time in milliseconds, as a string - to a Date format so that I could use the DATE_DIFF method.
As an example... "1494865480000" to "2017-05-15"
The difficulty was that casting and conversion was excessively strict and there seemed no adequate way to make it parse. See my answer down below!
(Though let me know if some SQL sensei knows a more eloquent way!)
In Standard SQL use TIMESTAMP_MICROS function together with EXTRACT(DATE FROM <timestamp>):
SELECT EXTRACT(DATE FROM TIMESTAMP_MILLIS(1494865480000))
A simpler way with TIMESTAMP_MILLIS():
#standardSQL
SELECT DATE(TIMESTAMP_MILLIS(CAST("1494865480000" AS INT64)))
2017-05-15
After much trial and error, this was my solution:
DATE_ADD( DATE'1970-01-01', INTERVAL CAST( ( CAST( epochTimestamp AS INT64 ) / 86400000 ) AS INT64 ) DAY ) AS convertedDate
That is, I took the string, cast it to an integer, divided it by the number of milliseconds in a day, then used a DATE_ADD method, and added the result to the start of Epoch time, and calculated the resulting day.
I hope this saves another junior some time!
Use UTC_USEC_TO_TIMESTAMP():
select UTC_USEC_TO_TIMESTAMP(postedon * 1000)
You can then extract the date using date():
select DATE(UTC_USEC_TO_TIMESTAMP(postedon * 1000))
This doesn't require knowing the internal format of Unix timestamps.
I need a way to substract to dates and get the result in days in sql.
I'm using PostgreSQL 8.4
When both columns you want to subtract are of date type, you can just use the - operator.
Take a look at the documentation for date functions, in particular table 9-25.
Check here the documentation of PostgreSQl...
postgresql.org/docs/8.4
I copied it from this code from this website:
age(timestamp '2001-04-10', timestamp '1957-06-13')
hope it will help you...
Is it possible to calculate difference between two timestamps in Mysql and get output result in seconds? like 2010-11-29 13:16:55 - 2010-11-29 13:13:55 should give 180 seconds.
Thank you
I do not think the accepted answer is a good universal solution!
This is because the UNIX_TIMESTAMP() function fails for DATEs before 1970-01-01 (and for dates in the far future using 32 bit integers). This may happen easily for the day of birth of many living people.
A better solution is:
SELECT TIMESTAMPDIFF(SECOND, '2010-11-29 13:13:55', '2010-11-29 13:16:55')
Which can be modified to return DAY YEAR MONTH HOUR and MINUTE too!
Use the UNIX_TIMESTAMP function to convert the DATETIME into the value in seconds, starting from Jan 1st, 1970:
SELECT UNIX_TIMESTAMP('2010-11-29 13:16:55') - UNIX_TIMESTAMP('2010-11-29 13:13:55') as output
Result:
output
-------
180
An easy way to deal with if you're not sure which value is bigger than the other -- use the ABS function:
SELECT ABS(UNIX_TIMESTAMP(t.datetime_col1) - UNIX_TIMESTAMP(t.datetime_col2)) as output
TIMESTAMPDIFF method only works with datetime format. If you want the difference between just two times like '11:10:00' minus '10:20:00' then use
select TIME_TO_SEC('11:10:00')-TIME_TO_SEC('10:20:00')