Getting Results from inner join differences on same row - sql

Question

Currently have sql returning a result set as below
WORKFLOWID UNMATCHEDVALUE MATCHEDADDRESS EXCEPTIONREASON
1001 UNIQUE ADDRESS1 (null)
1001 UNIQUE ADDRESS2 Some Value
What I am looking for is a result like this
WORKFLOWID UNMATCHEDVALUE MATCHEDADDRESS EXCEPTIONREASON MATCHEDADDRESS2 EXCEPTIONREASON2
1001 UNIQUE ADDRESS1 (null) ADDRESS2 Some Value
So the "variant" columns are MatchedAddress and Exception Reason, the other columns will be the same for each record. Note that for each workflow_id, will always have 2 rows coming back.
I have also created a fiddle to show the schema.
http://sqlfiddle.com/#!6/f7cde/3

Answer 1

Try this:
;WITH CTE AS
(
SELECT ws.id as WorkflowStepId,
ws.workflow_id as WorkflowId,
sg.unmatchValue as UnmatchedValue,
geo_address as MatchedAddress,
ws.exception_Value as ExceptionReason,
ROW_NUMBER() OVER(PARTITION BY ws.workflow_id ORDER BY ws.id) as RN
FROM workflow_step as ws
INNER JOIN workflow as gw
ON ws.workflow_id = gw.id
INNER JOIN super_group as sg
ON gw.super_group_id = sg.id
INNER JOIN alias on
ws.id = alias.workflow_step_id
)
SELECT WorkflowId,
UnmatchedValue,
MIN(CASE WHEN RN = 1 THEN MatchedAddress END) MatchedAddress,
MIN(CASE WHEN RN = 1 THEN ExceptionReason END) ExceptionReason,
MIN(CASE WHEN RN = 2 THEN MatchedAddress END) MatchedAddress2,
MIN(CASE WHEN RN = 2 THEN ExceptionReason END) ExceptionReason2
FROM CTE
GROUP BY WorkflowId,
UnmatchedValue
ORDER BY workflowId
Here is the modified sqlfiddle.
The results are:
╔════════════╦════════════════╦════════════════╦═════════════════╦═════════════════╦══════════════════╗
║ WORKFLOWID ║ UNMATCHEDVALUE ║ MATCHEDADDRESS ║ EXCEPTIONREASON ║ MATCHEDADDRESS2 ║ EXCEPTIONREASON2 ║
╠════════════╬════════════════╬════════════════╬═════════════════╬═════════════════╬══════════════════╣
║ 1001 ║ UNIQUE ║ ADDRESS1 ║ (null) ║ ADDRESS2 ║ Some Value ║
╚════════════╩════════════════╩════════════════╩═════════════════╩═════════════════╩══════════════════╝

Answer 2

Try this:
SELECT ws.workflow_id as WorkflowId, sg.unmatchValue as UnmatchedValue,
MAX(CASE WHEN ws.id = 1 THEN geo_address END) as MatchedAddress1,
MAX(CASE WHEN ws.id = 2 THEN geo_address END) as MatchedAddress2,
MAX(CASE WHEN ws.id = 1 THEN ws.exception_Value END) as ExceptionReason1,
MAX(CASE WHEN ws.id = 2 THEN ws.exception_Value END) as ExceptionReason2
FROM workflow_step as ws
INNER JOIN workflow as gw on ws.workflow_id = gw.id
INNER JOIN super_group as sg on gw.super_group_id = sg.id
inner JOIN alias on ws.id = alias.workflow_step_id
GROUP BY ws.workflow_id, sg.unmatchValue
SQL FIDDLE DEMO

Answer 3

Since I can't comment, I just wanted to point out that the answer given by Lamak is using a Common Table Expression. These are generally your best option for solving a recursion problem in sql.

Answer 4

This assumes you only have 2 address types. If you have more I would recommend creating a pivot table.
select a.*, MATCHEDADDRESS2,EXCEPTIONREASON2
from
(Select WORKFLOWID,UNIQUEVALUE,MATCHEDADDRESS,EXCEPTIONREASON
from "Your Table"
where MATCHEDADDRESS='ADDRESS1') a
join
(Select WORKFLOWID,UNIQUEVALUE,MATCHEDADDRESS as MATCHEDADDRESS2,EXCEPTIONREASON as XCEPTIONREASON2
from "Your Table"
where MATCHEDADDRESS='ADDRESS2') b
on a.WORKFLOWID=b.WORKFLOWID
and a.UNMATCHEDVALUE = b.UNMATCHEDVALUE