I essentially would like to execute a statement where x=1 AND a=2. If a<>2 then return results for filter x=1.
I've tried OR statement but it ignores my a=2 filter if there is a scenario where a does equal 2. Example below
select *
from dbo.test
where (x=1 and a=2)
or
x=1
For output purposes below: type = x and Id = a
Expected result when Type = 1.
Id(a) Name Person Type(x)
2 a Mike 1
7 b Jim 1
3 c Tom 1
4 d Tim 1
5 e Dave 1
Expected result when Type = 1 and Id = 2
Id(a) Name Person Type(x)
2 a Mike 1
Expected result when Type = 1 and Id <> 2 (scenario when there is no '2' in Id column)
Id(a) Name Person Type(x)
8 a Mike 1
7 b Jim 1
3 c Tom 1
4 d Tim 1
5 e Dave 1
The issue is not when Id = 2. It is returning Type = 1 when Id <> 2. Does that mean a case statement?
select *
from dbo.test
where (x=1 and a=2)
or x=1
Is the same as:
select *
from dbo.test
where x=1
AND requires both conditions be met, and OR requires one condition to be met. The value of a is irrelevant.
UPDATE:
You can get what you're after using the RANK() function in conjunction with a CASE statement:
;WITH cte AS (SELECT *,RANK() OVER(ORDER BY CASE WHEN id = 2 THEN 1 ELSE 2 END)RNK
FROM Table1
WHERE Type = 1)
SELECT *
FROM cte
WHERE RNK = 1
If id = 2 is present in the table, only that record will be returned, otherwise all records will be returned.
Demo: SQL Fiddle
I'm guessing that you want to return a single row.
insert into test(x,a,v) values (0, 0, 'No good')
insert into test(x,a,v) values (1, 0, 'OK')
insert into test(x,a,v) values (1, 2, 'Better')
You want the row that has x=1 a=2 if it is there
You want the row that has x=1 if there is none better
You want nothing if there is no x=1 row
If that's the case then it is a bit tricky. You can score the rows using a CASE statement and then pick the row that has the best value. This may give you more than one row back if there is a tie.
SELECT v
FROM test
WHERE CASE WHEN x=1 AND a=2 THEN 1000
WHEN x=1 AND a<>2 THEN 100
ELSE 0 END =
(SELECT MAX(CASE WHEN x=1 AND a=2 THEN 1000
WHEN x=1 AND a<>2 THEN 100
ELSE 0 END)
FROM test)
Related
let's say I have the following entries in a table with two columns:
Id
Value
1
F
1
N
1
N
2
F
3
N
3
N
3
N
4
N
5
F
5
N
I only want to output the Ids that have a value of 'N' and at the same time not the value 'F' in the second column. In this example my output from the query would be the Ids: 3 & 4.
Thank you very much!
If the database supports EXISITS, you can check for the existence of a row with the id and the value F.
SELECT
DISTINCT Id
FROM mytable m1
WHERE Value = 'N'
AND NOT EXISTS(SELECT 1 FROM mytable WHERE Value = 'F' AND m1.Id = Id)
Say I have this table t:
id value
1 1 10
2 2 3
3 1 55
4 1 20
5 2 98
When drawing from t I want to add a column value2 that equals value when id == 2, otherwise 0
I tried
select id, value, max(case when id = 2 then value else 0) from t
but it did not work
Not sure why you included a max in your attempt but based on your description, this is all you should need.
select id, value, case when id = 2 then value else 0 end as value2
from t;
It sounds like you want a conditional window aggregate:
select
id,
value,
max(case when id = 2 then value end) over ()
from t;
I have following table and when I run the following query , select * from mytable , I get following result.
Column 1 Value 1
--------------------------------------
Row 1 1
Row 2 0
Row 3 1
Row 4 0
Row 5 1
Row 6 0
But I need all the values to 0, no matter if it's 1 or 0. So the representation would be something like this.
Column 1 Value 1
--------------------------------------
Row 1 0
Row 2 0
Row 3 0
Row 4 0
Row 5 0
Row 6 0
I can create a table variable and then go ahead and updte the records after inserting to it, but is there any other way?
select Column1, '0' as Value1 from mytable
UPDATE mytable SET [Value 1] = 0
Will change the value for all rows. But I have a feeling there is more to your question. Can you explain why you need the Value 1 field changed after the SELECT?
If you want all the Column 1 rows with a zero for Value 1, change your SELECT:
SELECT Column1, '0' [Value 1] FROM mytable
I have an input:
id
1
2
3
4
5
6
7
8
9
10
I want get even and odd columns separately by columns in specified output like this
id col
1 2
3 4
5 6
7 8
9 10
here id and col are separate columns id contains the odd number and col contains the even number for specified input
SELECT MIN(id) as id, MAX(id) as col
FROM YourTable
GROUP BY FLOOR((id+1)/2)
For IDs 1 and 2, (id+1)/2 are 2/2 = 1 and 3/2 = 1.5, respectively, and FLOOR then returns 1 for both of them. Similarly, for 3 and 4, this is 2, and so on. So it groups all the input rows into pairs based on this formula. Then it uses MIN and MAX within each group to get the lower and higher IDs of the pairs.
Joined the table on itself
select *
from yourTable tA
left join yourTable tb on tA.id = (tB.id - 1)
where tA.id % 2 <> 0
If you use SQL you can try:
SELECT CASE WHEN column % 2 = 1
THEN column
ELSE null
END AS odds,
CASE WHEN column % 2 = 2
THEN column
ELSE null
END AS even
FROM yourtable
but not exactl as you ask
To show odd:
Select * from MEN where (RowID % 2) = 1
To show even:
Select * from MEN where (RowID % 2) = 0
Now, just join those two result sets and that's it.
Source
still not found the solution described in update 2
thx for help
ill try to explain my issue with my poor english. hope someone can solve my problem.
i got the following table
A B
1 Y
2 null
3 Y
what result i want?
in dependency of the rank in column A i want to combine column B.
the result in that example is ... no result
the reason is because there is a null in rank 2 and the next and the last rank (=3) has a value (=Y).
next example
A B
1 Y
2 null
3 null
result i want is
A B
1 Y
because the way after is free... means 2 and the last 3 has null
another example
A B
1 null
2 N
3 null
again no result is what i want in this case. because first =1 has null value.
i try now to conclude ... if n(e.g. 2) of column B has value Y or N then the elements bevor (in this 1) must have the value Y or N.
thank you very much. i tried different technics without any success...
UPDATE 1
thank you fast comment
some example dates with expected result
example 1
A B
1 Y
2 N
3 null
4 null
expected result
A B
2 N
example 2
A B
1 N
2 Y
3 N
4 null
expected result
A B
3 N
example 3
A B
1 null
2 Y
3 Y
4 null
expected result
no result
example 4
A B
1 Y
2 Y
3 null
4 Y
expected result
no result
UPDATE 2
forget the basic case
A B
1 Y
2 N
3 Y
expected result
A B
3 N
Establish the highest value of A where B is Y or N, and the lowest value of A where B is null. Provided the first value is lower than the second value you have a valid result set.
select yt.A
, yt.B
from
( select max(case when B is not null then A else null end) as max_b_yn
, min(case when B is null then A else null end) as min_b_null
from your_table ) t1
, your_table yt
where ( t1.min_b_null is null
or t1.max_b_yn < t1.min_b_null )
and yt.A = t1.max_b_yn
/
I think you want the last row before the first NULL. If this is correct, then the following gets what you want:
select t.*
from t join
(select min(A) as NullA from t where B is NULL) t2
on t.A = t2.NullA - 1
Ah, I see. To get the last row with an "N":
select t.*
from t
where t.A in (select max(A) as MaxA
from t join
(select min(A) as NullA from t where B is NULL) t2
on t.A < t2.NullA
where t.B = 'N'
)
OK, I think I have what you need. It grabs the last row that has a value in column B as long as there isn't a row with a NULL that precedes it.
select MAX(A), B
from table_a
where B IS NOT NULL
and table_a.A > (
select MIN(A)
FROM table_a
WHERE B IS NULL
)
Group by B
select top 1 A, B
from #Temp
where B is not null
order by A desc
or
select top 1 A, B
from #Temp
where B = 'N'
order by A desc