It's been a while since Clang added Objective-C literal syntax for NSDictionary, NSArray, NSNumber, and BOOL literals, like #[object1, object2,] or #{key : value}
I'm looking for the selector name associated with the array literal, #[].
I tried to find out using the following code for NSArray, but I didn't see a selector that seemed right.
unsigned int methodCount = 0;
Method * methods = class_copyMethodList([NSArray class], &methodCount);
NSMutableArray * nameOfSelector = [NSMutableArray new];
for (int i = 0 ; i < methodCount; i++) {
[nameOfSelector addObject:NSStringFromSelector(method_getName(methods[i]))];
}
#[] is not a method on NSArray, so you're not going to find it there.
The compiler just translates #[] into a call to [NSArray arrayWithObjects:count:]. As in it basically finds all the #[] and replaces it with [NSArray arrayWithObjects:count:] (carrying across the arguments of course)
See the Literals section here
#[] uses +arrayWithObjects:count:
Official Clang Documentation
Array literal expressions expand to calls to +[NSArray arrayWithObjects:count:], which validates that all objects are non-nil. The variadic form, +[NSArray arrayWithObjects:] uses nil as an argument list terminator, which can lead to malformed array objects.
When you write this:
NSArray *array = #[ first, second, third ];
It expands to this:
id objects[] = { first, second, third };
NSArray *array = [NSArray arrayWithObjects:objects count:(sizeof(objects) / sizeof(id))];
Related
I'm trying to make an array of array of strings so that I can eventually pull out something like ArrayOfArrays[0][1] = "hi".
NSString *ArrayOne[] = {#"hello", #"hi"};
NSString *ArrayTwo[] = {#"goodbye", #"bye"};
NSArray *ArrayOfArrays[] = {#[*ArrayOne, *ArrayTwo]};
However when I try to do this, I get an error: Initializer element is not a compile-time constant.
I've read that this is because I'm creating an array with dynamic values, though it should be static. Not sure how to work around this.
Any advice on making an array of array of strings?
Use NSArray, or rather NSMutableArray if you want to modify it after creation:
NSMutableArray *arrayOne = [#[#"hello", #"hi"] mutableCopy];
NSMutableArray *arrayTwo = [#[#"goodbye", #"bye"] mutableCopy];
NSMutableArray *arrayOfArrays = [#[arrayOne, arrayTwo] mutableCopy];
There are other ways to initialise it, but this is the only way that allows you to use Objective-C literal syntax.
You cannot store plain ol' C arrays within an Objective-C collection class as your code attempts to do.
You wrote:
it should be static
if this is what you want then your use of C arrays is quite valid, you just got the syntax wrong. You can use:
NSString *arrayOfArrays[][2] =
{ {#"hello", #"hi"},
{#"goodbye", #"bye"},
};
Important: The 2 is the number of elements in the inner array, you do not change it when adding further pairs.
This will give you a compile-time static array.
If what you are making is a map from one word to another you might be better off with a dictionary, e.g.:
NSDictionary *wordMap =
#{ #"hello" : #"hi",
#"goodbye" : #"bye"
};
and accessing an element becomes:
wordMap[#"hello"];
Note: the dictionary "constant" here is actually executed code; the C array version can appear as a global or local initialiser, while the dictionary initialisation must be done in a method/function - but it can assign to a global.
HTH
NSArray *array = #[
#[[ #"hello", #"hi" ] mutableCopy],
#[[ #"goodbye", #"bye" ] mutableCopy],
];
NSLog(#"%# is short for %#", array[0][1], array[0][0]);
Output: hi is short for hello
i have an NSArray with bool values:
NSArray* boolResults = [super foo:values];
how can i change the value in cell 0?
i tried the following:
boolResults[0] = #NO;
this results in an error: Expected method to write array element not found on object of type 'NSArray *'
and also this:
BOOL* b = &[[array objectAtIndex:i] boolValue];
got the following error: Address expression must be an lvalue or a function designator
i don't wish to convert this NSArray to NSMutableArray in order to set this value, is there a normal way to do this?
Thanks
If the array isn't mutable, then you can't change that value. The solutions are two:
Make the array mutable;
Let the array contain mutable objects.
Since you don't want to use a mutable array, I'll make you an example with the second solution. Since there isn't a mutable number in the standard framework, I'll wrap it into NSMutableData. The example supposes that you have an array with a single object, with value #YES, and you want to change it to #NO:
NSNumber* number= #YES;
NSMutableData* data=[[NSMutableData alloc]initWithData: [NSKeyedArchiver archivedDataWithRootObject: number]];
NSArray* array= #[data]; // Now you have an array with a single value
// You want to change the first value to #NO:
number= #NO;
[array[0] setData: [NSKeyedArchiver archivedDataWithRootObject: number]];
No. NSArrays are immutable. You could reassign your pointer to the array with a modified NSArray.
NSArray *anArray = [super foo:values]
NSMutableArray *mutableCopy = [anArray mutableCopy];
// change your mutable copy and then reassign
anArray = [mutableCopy copy];
And just like NSArray, NSNumbers are also immutable, so something like [anArray[0] setBoolValue:NO] does not exist.
I'm not familiar with C. How can I pass a C array to a Objective-C function ?
I actually need an example of a class function converting NSArray to C arrays.
This is what I have so far:
+ (NSArray *)convertArray:(NSString*)array { //I don't think this is correct: the argument is just a NSString parameter and not an array
NSMutableArray * targetArray = [NSMutableArray array];
for (i = 0; i < SIZE; i++) //SIZE: I dunno how to get the size of a C array.
{
[targetArray addObject: [NSString stringWithString:array[i]];
}
return targetArray;
}
There are a few ways.
If your array size is fixed at compile-time, you can use the C99 static modifier:
-(void) doSomething:(NSString *[static 10]) arg
{
}
If not, you have to pass it as two separate arguments. One as a pointer to the first element of it, and the second as the length of it:
-(void) doSomething:(NSString **) arg count:(size_t) count
{
}
Now you can access your variables like any other array you may have.
Because you are dealing with a C-array of objective-c objects, you can actually use NSArray's built in constructor for turning a C-array into a NSArray:
NSArray *result = [NSArray arrayWithObjects:arg count:count];
Could I parse an NSString to have it call a method that matches its name in Objective-C? Here is an example:
If I had a string called doSomething, and I had a method called -(void) doSomething, could I do something like scanf to parse whatever text I typed in to check if there were any method matching it, and if yes then call that method?
Try NSSelectorFromString(#"methodName"); and the associated NSObject methods like respondsToSelector:
jxpx777's answer will give you the information you were looking for, but in case you want more, the runtime has a long list of C functions that provide a fairly complete introspection of objects and classes.
For instance, if you want an NSArray of method names implemented by a class, you can do something like this:
Class myClass = [self class];
unsigned int methodCount;
Method *methods = class_copyMethodList(myClass, &methodCount);
NSMutableArray *methodNames = [NSMutableArray arrayWithCapacity:10];
for (int i = 0; i < methodCount; i++) {
const char *methodNameCStr = sel_getName(method_getName(methods[i]));
NSString *methName = [NSString stringWithCString:methodNameCStr
encoding:NSASCIIStringEncoding];
[methodNames addObject:methName];
}
free(methods);
NSLog(#"Methods: %#", methodNames);
You will notice that plain C calls and Objective-C/Cocoa are mixed freely.
I thought that I knew how to use fast enumeration, but there is something I don't understand about it. If I create three NSString objects and three NSNumber objects and put them in an NSMutableArray:
NSString *str1 = #"str1";
NSString *str2 = #"str2";
NSString *str3 = #"str3";
NSNumber *nb1 = [NSNumber numberWithInt:1];
NSNumber *nb2 = [NSNumber numberWithInt:2];
NSNumber *nb3 = [NSNumber numberWithInt:3];
NSArray *array = [[NSArray alloc] initWithObjects:str1, str2, str3, nb1, nb2, nb3, nil];
then I make do fast enumeration on all NSString objects, like this:
for (NSString *str in array) {
NSLog(#"str : %#", str);
}
In the console, I get this result :
2011-08-02 13:53:12.873 FastEnumeration[14172:b603] str : str1
2011-08-02 13:53:12.874 FastEnumeration[14172:b603] str : str2
2011-08-02 13:53:12.875 FastEnumeration[14172:b603] str : str3
2011-08-02 13:53:12.875 FastEnumeration[14172:b603] str : 1
2011-08-02 13:53:12.876 FastEnumeration[14172:b603] str : 2
2011-08-02 13:53:12.876 FastEnumeration[14172:b603] str : 3
I logged only the NSStrings, but I get a line for every object in the array, even the NSNumbers and I don't understand why. Does fast enumeration always use every object contained in an array?
When you write a forin loop like that, it casts every object in the array as an NSString, then prints them out as requested.
If you want only the NSStrings, you would need to write something like this:
for (id obj in array) {
if ([obj isKindOfClass:[NSString class]]) {
NSLog(#"str: %#", obj);
}
}
The for all loop doesn't know the difference between NSStrings and Integers -- it will simply go through the entire array, cast each as an NSString, and print them out as you asked.
I'm pretty sure that fast enumeration returns all objects in the array- all that you're doing in for (NSString *str in array) is typecasting str to an NSString. In the body of the loop you need to check the class of the returned object to make sure that it is an NSString.
for(NSString *str in array)
{
if([str isKindOfClass:[NSString class]])
NSLog(#"str : %#", str);
}
Objective-C is dynamically typed, meaning that at runtime (when the loop actually runs), objects are all effectively one type (id) with different classes. The language allows optional compile-time static typing, but all that does is check whether the messages you're sending are valid for the type you've marked. It doesn't actually change the behavior of your program. If you cast an object to be a different type than it actually is, all you're doing is lying to the compiler and defeating its type-checker.
Every object that descends from NSObject implements the method - (NSString)description, %# in Objective-C formate string will take the corresponding argument for the %# and call its description method, Most subclasses of NSObject will implement there own version of - (NSString)description. The same thing happens when you type
> po anObject
in the debugger.
for (NSString *str in array) {
is a way to enumerate through all the elements in array.
You expectative that by specifying NSString you get only the objects of that type is not correct. Rather, all the objects pointers are cast to that type (NSString*).
Have a look at Fast Enumeration in The Objective-C Programming Language guide.
I don't understand where is the unexpected behavior, using the enhanced for loop in an NSMutableArray will just iterate thru every single object in the array which in your case is 6, the result is correct and expected.
The numbers will just get casted to Strings.
in fast enumeration no typecasting,just assigning the pointer into new object