How would the SQL statement look like to return the bottom result from the upper table?
The last letter from the key should be removed. It stands for the language. EXP column should be split into 5 columns with the language prefix and the right value.
I'm weak at writing more or less difficult SQL statements so any help would be appreciated!
The Microsoft Access equivalent of a PIVOT in SQL Server is known as a CROSSTAB. The following query will work for Microsoft Access 2010.
TRANSFORM First(table1.Exp) AS FirstOfEXP
SELECT Left([KEY],Len([KEY])-2) AS [XKEY]
FROM table1
GROUP BY Left([KEY],Len([KEY])-2)
PIVOT Right([KEY],1);
Access will throw a circular field reference error if you try to name the row heading with KEY since that is also the name of the original table field that you are deriving it from. If you do not want XKEY as the field name, then you would need to break apart the above query into two separate queries as shown below:
qsel_table1:
SELECT Left([KEY],Len([KEY])-2) AS XKEY
, Right([KEY],1) AS [Language]
, Table1.Exp
FROM Table1
ORDER BY Left([KEY],Len([KEY])-2), Right([KEY],1);
qsel_table1_Crosstab:
TRANSFORM First(qsel_table1.Exp) AS FirstOfEXP
SELECT qsel_table1.XKEY AS [KEY]
FROM qsel_table1
GROUP BY qsel_table1.XKEY
PIVOT qsel_table1.Language;
In order to always output all language columns regardless of whether there is a value or not, you need to spike of those values into a separate table. That table will then supply the row and column values for the crosstab and the original table will supply the value expression. Using the two query solution above we would instead need to do the following:
table2:
This is a new table with a BASE_KEY TEXT*255 column and a LANG TEXT*1 column. Together these two columns will define the primary key. Populate this table with the following rows:
"AbstractItemNumberReportController.SelectPositionen", "D"
"AbstractItemNumberReportController.SelectPositionen", "E"
"AbstractItemNumberReportController.SelectPositionen", "F"
"AbstractItemNumberReportController.SelectPositionen", "I"
"AbstractItemNumberReportController.SelectPositionen", "X"
qsel_table1:
This query remains unchanged.
qsel_table1_crosstab:
The new table2 is added to this query with an outer join with the original table1. The outer join will allow all rows to be returned from table2 regardless of whether there is a matching row in the table1. Table2 now supplies the values for the row and column headings.
TRANSFORM First(qsel_table1.Exp) AS FirstOfEXP
SELECT Table2.Base_KEY AS [KEY]
FROM Table2 LEFT JOIN qsel_table1 ON (Table2.BASE_KEY = qsel_table1.XKEY)
AND (Table2.LANG = qsel_table1.Language)
GROUP BY Table2.Base_KEY
PIVOT Table2.LANG;
Try something like this:
select *
from
(
select 'abcd' as [key], right([key], 1) as id, expression
from table1
) x
pivot
(
max(expression)
for id in ([D], [E])
) p
Demo Fiddle
Related
I have two columns in one table say Column A and Column B. I need to search each value of Column A with All the values of column B each and every time and return true if the column A value is found in any of the rows of column B. How can i get this?
I have tried using the below command:
select column _A, column_B,(if (column_A =column_B), True, False) as test from sample;
If i use the above command, it is checking for that particular row alone. But I need true value, if a value of column A is found in any of the rows of column B.
How can i can check one value of column A with all the all the values of column B?
Or Is there any possibility to iterate and compare each value between two columns?
Solution
create temporary table t as select rand() as id, column_A, column_B from sample; --> Refer 1
select distinct t3.id,t3.column_A,t3.column_B,t3.match from ( --> Refer 3
select t1.id as id, t1.column_A as column_A, t1.column_B as column_B,--> Refer 2
if(t2.column_B is null, False, True) as match from t t1 LEFT OUTER JOIN
t t2 ON t1.column_A = t2.column_B
) t3;
Explanation
Create an identifier column to keep track of the rows in original table. I am using rand() here. We will take advantage of this to get the original rows in Step 3. Creating a temporary table t here for simplicity in next steps.
Use a LEFT OUTER JOIN with self to do your test that requires matching each column with another across all rows, yielding the match column. Note that here multiple duplicate rows may get created than in Sample table, but we have got a handle on the duplicates, since the id column for them will be same.
In this step, we apply distinct to get the original rows as in Sample table. You can then ditch the id column.
Notes
Self joins are costly in terms of performance, but this is unavoidable for solution to the question.
The distinct used in Step 3, is costly too. A more performant approach would be to use Window functions where we can partition by the id and pick the first row in the window. You can explore that.
You can do a left join to itself and check if the column key is null. If it is null, then that value is not found in the other table. Use if or "case when" function to check if it is null or not.
Select t1.column_A,
t1.column_B,
IF(t2.column_B is null, 'False', 'True') as test
from Sample t1
Left Join Sample t2
On t1.column_A = t2.column_B;
I have an issue where to create a report, I need two tables to join that don't have any way to join. I did find a way they could potentially join, but it's complicated.
There is table A, which contains a column called select_criteria. Here are some examples of 3 values it contains:
SELECT DISTINCT SUM(TRANSCRIPTDETAIL.CREDIT_BILLING) FROM SOMETABLE WHERE (( STUDENTFINANCIAL.TUITION_EXEMPTION = 'EMPFT' ) OR ( STUDENTFINANCIAL.TUITION_EXEMPTION = 'EMPPT' )))
SELECT DISTINCT SUM(TRANSCRIPTDETAIL.CREDIT_BILLING) FROM SOMETABLE WHERE ( STUDENTFINANCIAL.TUITION_EXEMPTION = 'PART50' )
In table B, I have a column called tuition_exemption, which contains values like:
EMPFT
EMPPT
PART50
At the tail end of the whole value within the column in table A, there are the tuition exemption codes that match the values in table B.
Is there a way using MSSQL where I can parse out the codes from the long statement in select_criteria, so that they perfectly match the codes from table B? This is my thought on a way to join up table A and table B like I need to do. The other complication is that there is a 1:many connection between select_criteria and a tuition_exemption value, but a 1:1 connection between a tuition_exemption value and a select_criteria value.
So in the end, the join between the two tables should print, in one example, the same select_criteria value twice (I am referencing the first value in my list above from table A), but in those two rows, the two different tuition_exemption values (EMPFT and EMPPT). Or in the case of table A example 2, it would be printed once and match up to PART50 once.
I am stuck here. I have a statement that successfully grabs the select_criteria values I want:
SELECT select_criteria
WHERE (
select_criteria LIKE '%EMPFT%' OR
select_criteria LIKE '%EMPPT%' OR
select_criteria LIKE '%PART50%' OR
)
But what I need to do is this. When it grabs the select_criteria values I want, I then want to print to a new column in this table the code it matches up to. Those codes are values in table B like 'EMPFT', 'EMPPT' and 'PART50'. That is why I was thinking of basically parsing out the codes from select_criteria, and printing them into the new column in table A. That way table A and table B have a value to match up on and I write run my report. I just don't now how to do it in SQL. I kind of know in Perl, but was hoping to just do all of this in SSMS 2012.
Thanks for any help!
byobob
You can use any expression which returns a boolean as a join criteria. Since LIKE returns a bool, you should be able to just do this:
select *
from tableA
join tableB
on tableA.select_criteria like '%' + tableB.codecolumn + '%'
I have a table with, let's say, 100 records. The table has two columns. The first column (A) has unique values. The second column (B) has NULL values
For 4 elements from column A I'd like to associate some earlier defined values, and they are unique as well.
I don't care about which value from column B will be associated with the value from column A. I'd like to associate 4 unique values with another 4 unique values. Basically, like I'd cut and paste a block of values from one column to another in excel.
How can I do it without using cursors?
I'd like to use one Update statement for ALL rows instead one Update statement for EVERY row as I do now.
Try this:
UPDATE t
SET ColumnB = BValue
FROM Table t
INNER JOIN
(
SELECT 1 AValue, 'Mouse' BValue UNION
SELECT 2, 'Cat' UNION
SELECT 3, 'Dog' UNION
SELECT 4, 'Wolf'
) PreDefined ON(t.ColumnA = PreDefined.AValue)
Use any number you want in the 'PreDefined' table, as long as they are unique and within the range of values in columnA of your original table.
If you are only trying to fill a table for testing purposes, I guess you could:
A) Use the value from Column A itself (as it is already unique).
B) If they are to be different, use some function on the column A's value to obtain a column B value (something simple, like (ColumnA * 10), and this would give youA)
C) Create a temp table with a "dictionary" setting a B value for each possible A value, and then update the rows desired on your table looking up from values on this dictionary table.
Anyway, if you explain a little further your purpose it will be easier to try suggesting you a solution.
if your animal data is already in a database table, then you can use a single update statement like this:
update target_table t4
set columnb = (
select animal_name
from (select columna, animal_name
from (select rownum rowNumber, animal_name from animal_table) t1
join (select rownum rowNumber, columna from target_table t1 where columnb is null) t2
on t1.rowNumber = t2.rowNumber
) t3
where t4.columna = t3.columna
)
;
this works by selecting a sequence number and animal name from the source table, then selecting a sequence number and columna value from your target table. by joining those records on the sequence number you guarantee you get exactly 1 animal name for each columna value. you can then join those columna-to-animal records to your target table to do an update of columnb.
for more background on updating one table from values in another, you might consider the solutions presented here: Update rows in one table with data from another table based on one column in each being equal. the only difference is that in your example, you do not have any column that matches between your target table and your animal names table, so you need to use the rownum to create an arbitrary 1-to-1 matching of records.
if your unique options are in a text file or spreadsheet, then you can format them into a fixed-width space-padded string and pick the one you want using the rownum index like so:
update table_name
set columnb = trim(substr('mouse cat dog wolf ', rownum*6-6, 6))
where columnb is null;
I have two different tables, we will call table 1 and table 2. Within table 1, I have a column known as featureid which is a numerical value that corresponds to a numerical value in table 2 known as the termid. Also, within this table 2, each of the different termid corresponds to a plain text description of that termid.
What I am attempting to do is join the featureid in table 1 to the termid in table 2, but have the output be a two column display of the plain text description and occurrence of each within table 1.
I know I need to use the JOIN and COUNT syntax within SQL, but not sure how to correctly write the command.
Thanks!
You actually only need one column in the GROUP BY. It's also good practice to specify which values are coming from which table, like so:
SELECT
table2.textDesc,
COUNT(table1.featureid) AS OccurrenceCount
FROM
table1
INNER JOIN
table2 ON
table1.featureid = table2.termid
GROUP BY table2.textDesc
I think this is what you are looking for:
SELECT textDesc, COUNT(featureid)
FROM table1, table2
WHERE featureid=termid
GROUP BY featureid, textDesc
Alternatively, you can use a different syntax (with the same end result) like so:
SELECT textDesc, COUNT(featureid)
FROM table1 INNER JOIN table2
ON featureid=termid
GROUP BY featureid, textDesc
Let's say that we have a table named Data with Id and Weather columns. Other columns in that table are not important to this problem. The Weather column can be null.
I want to display all rows where Weather fits a condition, but if there is a null value in weather then display null value.
My SQL so far:
SELECT *
FROM Data d
WHERE (d.Weather LIKE '%'+COALESCE(NULLIF('',''),'sunny')+'%' OR d.Weather IS NULL)
My results are wrong, because that statement also shows values where Weather is null if condition is not correct (let's say that users mistyped wrong).
I found similar topic, but there I do not find appropriate answer.
SQL WHERE clause not returning rows when field has NULL value
Please help me out.
Your query is correct for the general task of treating NULLs as a match. If you wish to suppress NULLs when there are no other results, you can add an AND EXISTS ... condition to your query, like this:
SELECT *
FROM Data d
WHERE d.Weather LIKE '%'+COALESCE(NULLIF('',''),'sunny')+'%'
OR (d.Weather IS NULL AND EXISTS (SELECT * FROM Data dd WHERE dd.Weather LIKE '%'+COALESCE(NULLIF('',''),'sunny')+'%'))
The additional condition ensures that NULLs are treated as matches only if other matching records exist.
You can also use a common table expression to avoid duplicating the query, like this:
WITH cte (id, weather) AS
(
SELECT *
FROM Data d
WHERE d.Weather LIKE '%'+COALESCE(NULLIF('',''),'sunny')+'%'
)
SELECT * FROM cte
UNION ALL
SELECT * FROM Data WHERE weather is NULL AND EXISTS (SELECT * FROM cte)
statement show also values where Wether is null if condition is not correct (let say that users typed wrong sunny).
This suggests that the constant 'sunny' is coming from end-user's input. If that is the case, you need to parameterize your query to avoid SQL injection attacks.