I need to get a report that shows distinct users per week to show user growth per week, but I need it to show cumulative distinct users.
So if I have 5 weeks of data, I want to show:
Distinct users from week 0 through week 1
Distinct users from week 0 through week 2
Distinct users from week 0 through week 3
Distinct users from week 0 through week 4
Distinct users from week 0 through week 5
I have a whole year's worth of data. The only way I know how to do this is to literally query the time ranges adjusting a week out at a time and this is very tedious. I just can't figure out how I could query everything from week 0 through week 1 all the way to week 0 through week 52.
EDIT - What I have so far:
select count(distinct user_id) as count
from tracking
where datepart(wk,login_dt_tm) >= 0 and datepart(wk,login_dt_tm) <= 1
Then I take that number, record it, and update it to -- datepart(wk,login_dt_tm) <= 2. And so on until I have all the weeks. That way I can chart a nice growth chart by week.
This is tedious and there has to be another way.
UPDATE-
I used the solution provided by #siyual but updated it to use a table variable so I could get all the results in one output.
Declare #Week Int = 0
Declare #Totals Table
(
WeekNum int,
UserCount int
)
While #Week < 52
Begin
insert into #Totals (WeekNum,UserCount)
select #Week,count(distinct user_id) as count
from tracking
where datepart(wk,login_dt_tm) >= #Week and datepart(wk,login_dt_tm) <= (#Week + 1)
Set #Week += 1
End
Select * from #Totals
Why not something like:
select count(distinct user_id) as count, datepartk(wk, login_dt_tm) as week
from tracking
group by datepart(wk,login_dt_tm)
order by week
You could try something like this:
Declare #Week Int = 1
While #Week <= 52
Begin
select count(distinct user_id) as count
from tracking
where datepart(wk,login_dt_tm) >= 0 and datepart(wk,login_dt_tm) <= #Week
Set #Week += 1
End
Just for the record, I would do this in one statement, using a recursive CTE to generate the numbers from 1 to 52 (you could also use a numbers table):
with numbers as (
select 1 as n
union all
select n + 1
from numbers
where n < 52
)
select count(distinct user_id) as count
from tracking t join
numbers n
on datepart(wk, login_dt_tm) >= 0 and datepart(wk, login_dt_tm) <= numbers.n;
Seems easier to put it all in one query.
SELECT
week_num,
distinct_count
FROM (
select distinct
datepart(wk,login_dt_tm) week_num
from #tracking
) t_week
CROSS APPLY (
select
count(distinct user_id) distinct_count
from #tracking
where datepart(wk,login_dt_tm) between 0 and t_week.week_num
) t_count
Related
I'm having trouble writing a recursive function that would count the number of active clients on any given day.
Say I have a table like this:
Client
Start Date
End Date
1
1-Jan-22
2
1-Jan-22
3-Jan-22
3
3-Jan-22
4
4-Jan-22
5-Jan-22
5
4-Jan-22
6-Jan-22
6
7-Jan-22
9-Jan-22
I want to return a table that would look like this:
Date
NumActive
1-Jan-22
2
2-Jan-22
2
3-Jan-22
3
4-Jan-22
4
5-Jan-22
4
6-Jan-22
3
7-Jan-22
3
8-Jan-22
3
9-Jan-22
4
Is there a way to do this? Ideally, I'd have a fixed start date and go to today's date.
Some pieces I have tried:
Creating a recursive date table
Truncated to Feb 1, 2022 for simplicity:
WITH DateDiffs AS (
SELECT DATEDIFF(DAY, '2022-02-02', GETDATE()) AS NumDays
)
, Numbers(Numbers) AS (
SELECT MAX(NumDays) FROM DateDiffs
UNION ALL
SELECT Numbers-1 FROM Numbers WHERE Numbers > 0
)
, Dates AS (
SELECT
Numbers
, DATEADD(DAY, -Numbers, CAST(GETDATE() -1 AS DATE)) AS [Date]
FROM Numbers
)
I would like to be able to loop over the dates in that table, such as by modifying the query below for each date, such as by #loopdate. Then UNION ALL it to a larger final query.
I'm now stuck as to how I can run the query to count the number of active users:
SELECT
COUNT(Client)
FROM clients
WHERE [Start Date] >= #loopdate AND ([End Date] <= #loopdate OR [End Date] IS NULL)
Thank you!
You don't need anything recursive in this particular case, you need as a minimum a list of dates in the range you want to report on, ideally a permanent calendar table.
for purposes of demonstration you can create something on the fly, and use it like so, with the list of dates something you outer join to:
with dates as (
select top(9)
Convert(date,DateAdd(day, -1 + Row_Number() over(order by (select null)), '20220101')) dt
from master.dbo.spt_values
)
select d.dt [Date], c.NumActive
from dates d
outer apply (
select Count(*) NumActive
from t
where d.dt >= t.StartDate and (d.dt <= t.EndDate or t.EndDate is null)
)c
See this Demo Fiddle
I have a table A that we import based on the day that it lands on a location. We dont receive files on weekend and public holidays, and the table has multiple countries data so the public holidays vary. In essence we looking to duplicate a row multiple times till it encounters the next record for that ID (unless its the max date for that ID). A typical record looks like this:
Account Datekey Balance
1 20181012 100
1 20181112 100
1 20181212 100
1 20181512 100
1 20181712 100
And needs to look like this (sat, sun & PH added to indicate the day of week):
Account Datekey Balance
1 20181012 100
1 20181112 100
1 20181212 100
1 20181312 100 Sat
1 20181412 100 Sun
1 20181512 100
1 20181612 100 PH
1 20181712 100
Also Datekey is numeric and not a date. I tried a couple solutions suggested but found that it simply duplicates the previous row multiple times without stopping when the next dates record is found. I need to run it as an update query that would execute daily on table A and add missing records when its executed (sometimes 2 or 3 days later).
Hope you can assist.
Thanks
This question has multiple parts:
Converting an obscene date format to a date
Generating "in-between" rows
Filling in the new rows with the previous value
Determining the day of the week
The following does most of this. I refuse to regenerate the datekey format. You really need to fix that.
This also assumes that your setting are for English week day names.
with t as (
select Account, Datekey, Balance, convert(date, left(dkey, 4) + right(dkey, 2) + substring(dkey, 5, 2)) as proper_date
from yourtable
),
dates as (
select account, min(proper_date) as dte, max(proper_date) as max_dte
from t
group by account
union all
select account, dateadd(day, 1, dte), max_dte
from dates
where dte < max_dte
)
select d.account, d.dte, t.balance,
(case when datename(weekday, d.dte) in ('Saturday', 'Sunday')
then left(datename(weekday, d.dte), 3)
else 'PH'
end) as indicator
from dates d cross apply
(select top (1) t.*
from t
where t.account = d.account and
t.proper_date <= d.dte
order by t.proper_date desc
) t
option (maxrecursion 0);
Just wondering if I have two fields in a table named modified date and created date, they either have a date populate or is null. What I would like to know is the best way to count the number of occurrences and group them into a particular range like for example 0-7 days, 8-14 days, 15- 30 days etc.
I was thinking about using
sum(case when modifieddate between getdate()-7 and getdate() then 1 else 0 end)
Is this the best way to do it or is there a better way for each date range specified above. Same would go for the created date
Build a table containing the ranges on the fly, then access your table and count:
select
mindays,
maxdays,
(
select count(*)
from mytable t
where datediff(day, coalesce(t.modifieddate, t.createddate), getdate() )
between ranges.mindays and ranges.maxdays
) as cnt
from
(
select 0 as mindays, 7 as maxdays
union all
select 8 as mindays, 14 as maxdays
union all
select 15 as mindays, 30 as maxdays
) ranges;
I'm pretty new to SQL and have this problem:
I have a filled table with a date column and other not interesting columns.
date | name | name2
2015-03-20 | peter | pan
2015-03-20 | john | wick
2015-03-18 | harry | potter
What im doing right now is counting everything for a date
select date, count(*)
from testtable
where date >= current date - 10 days
group by date
what i want to do now is counting the resulting lines and only returning them if there are less then 10 resulting lines.
What i tried so far is surrounding the whole query with a temp table and the counting everything which gives me the number of resulting lines (yeah)
with temp_count (date, counter) as
(
select date, count(*)
from testtable
where date >= current date - 10 days
group by date
)
select count(*)
from temp_count
What is still missing the check if the number is smaller then 10.
I was searching in this Forum and came across some "having" structs to use, but that forced me to use a "group by", which i can't.
I was thinking about something like this :
with temp_count (date, counter) as
(
select date, count(*)
from testtable
where date >= current date - 10 days
group by date
)
select *
from temp_count
having count(*) < 10
maybe im too tired to think of an easy solution, but i can't solve this so far
Edit: A picture for clarification since my english is horrible
http://imgur.com/1O6zwoh
I want to see the 2 columned results ONLY IF there are less then 10 rows overall
I think you just need to move your having clause to the inner query so that it is paired with the GROUP BY:
with temp_count (date, counter) as
(
select date, count(*)
from testtable
where date >= current date - 10 days
group by date
having count(*) < 10
)
select *
from temp_count
If what you want is to know whether the total # of records (after grouping), are returned, then you could do this:
with temp_count (date, counter) as
(
select date, counter=count(*)
from testtable
where date >= current date - 10 days
group by date
)
select date, counter
from (
select date, counter, rseq=row_number() over (order by date)
from temp_count
) x
group by date, counter
having max(rseq) >= 10
This will return 0 rows if there are less than 10 total, and will deliver ALL the results if there are 10 or more (you can just get the first 10 rows if needed with this also).
In your temp_count table, you can filter results with the WHERE clause:
with temp_count (date, counter) as
(
select date, count(distinct date)
from testtable
where date >= current date - 10 days
group by date
)
select *
from temp_count
where counter < 10
Something like:
with t(dt, rn, cnt) as (
select dt, row_number() over (order by dt) as rn
, count(1) as cnt
from testtable
where dt >= current date - 10 days
group by dt
)
select dt, cnt
from t where 10 >= (select max(rn) from t);
will do what you want (I think)
My problem:
Table: trans_detail:
PhoneNo | Datetime
01234 | 2013-01-05 20:40:10
01245 | 2013-04-02 21:00:13
05678 | 2013-04-16 01:24:07
04567 | 2013-07-23 07:00:00
etc | etc
I want to get all phoneNo that appears at least once for every month in the last X month (X month can be any month between 1-12).
For example: get all phone no. that appears at least once for Every Month in the last 3 months.
I am using SQL Server 2005.
Here is a quick query that comes close to what you want:
select PhoneNo
from trans_detail d
where d.datetime >= dateadd(mm, -#X, getdate())
group by PhoneNo
having count(distinct year(datetime)*12+month(datetime)) = #X
The where clause filters the data to only include rows in the last #X months. the having clause checks that each month is in the data, by counting the number of distinct months.
The above version of the query assumes that you mean calendar months. So, it has boundary condition problems. If you run it on June 16th, then it looks back one month and makes sure that the phone number appears at least once since May 16th. I am unclear on whether you want to insist that the number appear twice (once in May and once in June) or if once (once during the time period). The solution to this is to move the current date back to the end of the previous month:
select PhoneNo
from trans_detail d cross join
(select cast(getdate() - day(getdate) + 1 as date) as FirstOfMonth const
where d.datetime >= dateadd(mm, -#X, FirstOfMonth) and
d.datetime < FirstOfMonth
group by PhoneNo
having count(distinct year(datetime)*12+month(datetime)) = #X
Here it is. First two CTEs are to find and prepare last X months, third CTE is to group your data by phones and months. At the end just join the two and return where number of matching rows are equal to number of months.
DECLARE #months INT
SET #Months = 3
;WITH CTE_Dates AS
(
SELECT GETDATE() AS Dt
UNION ALL
SELECT DATEADD(MM,-1,Dt) FROM CTE_Dates
WHERE DATEDIFF(MM, Dt,GETDATE()) < #months-1
)
, CTE_Months AS
(
SELECT MONTH(Dt) AS Mn, YEAR(Dt) AS Yr FROM CTE_Dates
)
, CTE_Trans AS
(
SELECT PhoneNo, MONTH([Datetime]) AS Mn, YEAR([Datetime]) AS Yr FROM dbo.trans_detail
GROUP BY PhoneNo, MONTH([Datetime]), YEAR([Datetime])
)
SELECT PhoneNo FROM CTE_Months m
LEFT JOIN CTE_Trans t ON m.Mn = t.Mn AND m.Yr = t.Yr
GROUP BY PhoneNo
HAVING COUNT(*) = #months
SQLFiddle Demo - with added some more data that will match for last 3 months