Check if current date is between two dates Oracle SQL - sql

I would like to select 1 if current date falls between 2 dates through Oracle SQL.
I wrote an SQL after reading through other questions.
https://stackoverflow.com/questions/2369222/oracle-date-between-query
https://stackoverflow.com/questions/2399753/select-from-table-by-knowing-only-date-without-time-oracle
But it returned only null. sysdate is the current date that is 01/05/2014 in date format DD/MM/YYYY.
The SQL I wrote is:
select 1 from dual
WHERE to_date(sysdate,'DD/MM/YYYY')
BETWEEN TO_DATE('28/02/2014', 'DD/MM/YYYY')
AND TO_DATE('20/06/2014', 'DD/MM/YYYY');
and
select 1 from dual
WHERE to_date(sysdate,'DD/MM/YYYY') >= TO_DATE('28/02/2014', 'DD/MM/YYYY')
AND to_date(sysdate,'DD/MM/YYYY') < TO_DATE('20/06/2014', 'DD/MM/YYYY');

You don't need to apply to_date() to sysdate. It is already there:
select 1
from dual
WHERE sysdate BETWEEN TO_DATE('28/02/2014', 'DD/MM/YYYY') AND TO_DATE('20/06/2014', 'DD/MM/YYYY');
If you are concerned about the time component on the date, then use trunc():
select 1
from dual
WHERE trunc(sysdate) BETWEEN TO_DATE('28/02/2014', 'DD/MM/YYYY') AND
TO_DATE('20/06/2014', 'DD/MM/YYYY');

SELECT to_char(emp_login_date,'DD-MON-YYYY HH24:MI:SS'),A.*
FROM emp_log A
WHERE emp_login_date BETWEEN to_date(to_char('21-MAY-2015 11:50:14'),'DD-MON-YYYY HH24:MI:SS')
AND
to_date(to_char('22-MAY-2015 17:56:52'),'DD-MON-YYYY HH24:MI:SS')
ORDER BY emp_login_date

TSQL: Dates- need to look for gaps in dates between Two Date
select
distinct
e1.enddate,
e3.startdate,
DATEDIFF(DAY,e1.enddate,e3.startdate)-1 as [Datediff]
from #temp e1
join #temp e3 on e1.enddate < e3.startdate
/* Finds the next start Time */
and e3.startdate = (select min(startdate) from #temp e5
where e5.startdate > e1.enddate)
and not exists (select * /* Eliminates e1 rows if it is overlapped */
from #temp e5
where e5.startdate < e1.enddate and e5.enddate > e1.enddate);

In oracle use below,
select * from table_name where date_column_name between to_date('1-OCT-22') and ('31-OCT-22')
PS: replace table name and date column name and format accordingly

Related

How to extract No. of Days between 2 dates in oracle sql?

I want No. of days between these 2 dates using Oracle SQL
Dates:
BETWEEN "1/1/2018" AND "6/11/2018"
How to write SQL Query?
between date '2018-01-01' and date '2018-11-06'
where DATE literal looks exactly like that: DATE 'YYYY-MM-DD'
In your example:
double quote's can't be used
even if you used single quotes, that would be a string, not DATE so you'd depend on whether Oracle is capable of converting it (implicitly) to date or not
therefore, always use dates, not strings
[EDIT]
This is how you select the whole calendar between those two dates:
select date '2018-01-01' + level - 1
from dual
connect by level <= date '2018-11-06' - date '2018-01-01' + 1;
As other answers have pointed out you can simply divide two dates, but there is also no need for any additional arithmetic.
The code:
select to_date('6/11/2018', 'DD/MM/YYYY') - to_date('1/1/2018', 'DD/MM/YYYY')
from dual;
The result: 309
you can simple do:
select date1-date2 form dual;
or
select (sysdate-to_date('01-jan-2018'))-(sysdate-to_date('10-jan-2018'))from dual;
Just use
select date'2018-11-06' - date'2018-01-01' + 1 as days_difference
from dual;
DAYS_DIFFERENCE
---------------
310
or
with t( myDate ) as
(
select date'2018-11-06' from dual union all
select date'2018-01-01' from dual
)
select max(myDate) - min(myDate) + 1 as days_difference
from t;
DAYS_DIFFERENCE
---------------
310

Oracle order by year, month

I have a query which I want to order by year and then month. I have tryed order by to_date( depdate, 'mm' ) and TO_CHAR(depdate, 'YYYY/MM'). Here is an sqlfiddle to the table i am querying and the query itself sqlfiddle
You want to sort by the date value, not by the character string representation. That means that you also want to group by the date value. trunc(<<date column>>, 'mm') truncates a date to midnight on the first of the month. So something like this
SELECT to_char(trunc(DEPDATE,'MM'), 'Mon-YYYY') AS MONTH,
SUM(AMOUNTROOM) AS ROOMTOTAL,
SUM(AMOUNTEXTRAS) AS EXTRATOTAL,
SUM(AMOUNTEXTRAS + AMOUNTROOM) AS OATOTAL
FROM checkins
WHERE checkinstatus = 'D' AND depdate > TO_DATE('2013-12-01', 'yyyy/mm/dd')
AND depdate <= TO_DATE('2014-04-10', 'yyyy/mm/dd')
GROUP BY trunc(depdate,'mm')
ORDER BY trunc(depdate,'mm');
should be what you're looking for. See the updated fiddle
Check out this query. If it is a date field, just plain order by would work for you. You need not use TO_CHAR to convert to string and then sort:
WITH TAB AS
(
SELECT SYSDATE DATEVAL FROM DUAL
UNION
SELECT SYSDATE + 100 DATEVAL FROM DUAL
UNION
SELECT SYSDATE -500 DATEVAL FROM DUAL
UNION
SELECT SYSDATE + 30 DATEVAL FROM DUAL
UNION
SELECT SYSDATE -30 DATEVAL FROM DUAL
) SELECT * FROM TAB
ORDER BY DATEVAL DESC

Specific day- sql oracle

How can I find a specific day no matter the year or date in sql oracle.
as an example
i have the folowing dates in and table
id date
1 2013-02-03
2 2013-01-04
3 2012-06-13
I want to find all the ids with the day= 13
I've did this already but it doesn't work
select id
from table
where dayofmonth(date) = 13
this works in mysql but not in oracle.
Can any of you help me?
You can either use to_char() + to_num()
select to_number(to_char(sysdate, 'DD')) from dual
or use the extract() function:
select extract (day from sysdate) from dual
EDIT:
To get all rows from a table whose day is 13, just use EXTRACT in the WHERE clause:
create table my_data as
(select 1 pk, to_date('2013-01-13', 'YYYY-MM-DD') as my_date from dual union all
select 1 pk, to_date('2013-01-14', 'YYYY-MM-DD') as my_date from dual union all
select 1 pk, to_date('2013-02-13', 'YYYY-MM-DD') as my_date from dual);
select * from my_data
where extract(day from my_date) = 13;

Select Dates where time is less or equal to '12:00' Oracle

I require a query that selects rows where the time is less or equal to 12:00
I had something like this in mind:
SELECT daterow FROM datecolumn WHERE daterow <= TO_DATE('12:00, HH24:MI')
However i get an error:
ORA-01843: not a valid month
How would i go about to get all rows that have a time less than 12:00 mid-day?
Try this,
SELECT daterow FROM datecolumn WHERE daterow <= TO_DATE('12:00', 'HH24:MI');
Try This:
SELECT daterow FROM datecolumn
WHERE TO_DATE(daterow,'HH24:MI') <= TO_DATE('12:00', 'HH24:MI');
In order to select all rows where time portion of the daterow column value is less than or equal to mid-day 12:00 you can use to_char() function to extract hour and minutes and to_number() to convert it to a number for further comparison:
-- sample of data. Just for the sake of demonstration
SQL> with t1(col) as(
2 select sysdate - to_dsinterval('P0DT3H') from dual union all
3 select sysdate - to_dsinterval('P0DT2H') from dual union all
4 select sysdate - to_dsinterval('P0DT1H') from dual union all
5 select sysdate + to_dsinterval('P0DT3H') from dual union all
6 select sysdate + to_dsinterval('-P2DT0H') from dual
7 )
8 select to_char(col, 'dd.mm.yyyy hh24:mi:ss') as res
9 from t1 t
10 where to_number(to_char(col, 'hh24mi')) <= 1200
11 ;
Result:
RES
-------------------
26.08.2013 08:10:59
26.08.2013 09:10:59
26.08.2013 10:10:59
24.08.2013 11:10:59
Sorry, but <= TO_DATE('12:00', 'HH24:MI') does not work. It does not extract the hour and minute from each date and compares it to 12:00. Instead it constructs the date representing high noon on the fisrt of the current month and compares each date to this date.
If you want to extract something from a date, use the extract function.
Attention: When using extract on a date, and want to extract hours, minutes or seconds, you have first to convert the date to a timestamp.
Example:
SELECT
extract(hour FROM cast(A AS TIMESTAMP)) AS h,
extract(MINUTE FROM cast(A AS TIMESTAMP)) AS m
FROM
DEMO
;
You can find a complete example on sqlfiddle. The example also shows that the to_date method doesn't work.

oracle SQL how to remove time from date

I have a column named StartDate containing a date in this format: 03-03-2012 15:22
What I need is to convert it to date. It should be looking like this: DD/MM/YYYY
What I have tried without success is:
select
p1.PA_VALUE as StartDate,
p2.PA_VALUE as EndDate
from WP_Work p
LEFT JOIN PARAMETER p1 on p1.WP_ID=p.WP_ID AND p1.NAME = 'StartDate'
LEFT JOIN PARAMETER p2 on p2.WP_ID=p.WP_ID AND p2.NAME = 'Date_To'
WHERE p.TYPE = 'EventManagement2'
AND TO_DATE(p1.PA_VALUE, 'DD/MM/YYYY') >= TO_DATE('25/10/2012', 'DD/MM/YYYY')
AND TO_DATE(p2.PA_VALUE, 'DD/MM/YYYY') <= TO_DATE('26/10/2012', 'DD/MM/YYYY')
Is there a way to do this?
EDIT1: the PA_VALUE column is: VARCHAR2
You can use TRUNC on DateTime to remove Time part of the DateTime. So your where clause can be:
AND TRUNC(p1.PA_VALUE) >= TO_DATE('25/10/2012', 'DD/MM/YYYY')
The TRUNCATE (datetime) function returns date with the time portion of
the day truncated to the unit specified by the format model.
When you convert your string to a date you need to match the date mask to the format in the string. This includes a time element, which you need to remove with truncation:
select
p1.PA_VALUE as StartDate,
p2.PA_VALUE as EndDate
from WP_Work p
LEFT JOIN PARAMETER p1 on p1.WP_ID=p.WP_ID AND p1.NAME = 'StartDate'
LEFT JOIN PARAMETER p2 on p2.WP_ID=p.WP_ID AND p2.NAME = 'Date_To'
WHERE p.TYPE = 'EventManagement2'
AND trunc(TO_DATE(p1.PA_VALUE, 'DD-MM-YYYY HH24:MI')) >= TO_DATE('25/10/2012', 'DD/MM/YYYY')
AND trunc(TO_DATE(p2.PA_VALUE, 'DD-MM-YYYY HH24:MI')) <= TO_DATE('26/10/2012', 'DD/MM/YYYY')
Outside the scope of the question, but storing dates as strings is bad practice, and storing date times is even worse.
We need to convert the strings to dates in order to do any form of date processing (arithmetic, interval assessment, etc) on them
Strings offer no guarantees regarding format, so we run the risk of date corruption crashing our code. We can defend against this by employing VALIDATE_CONVERSION() (available since 12c, find out more ) but it's still a PITN
Using non-standard datatypes makes it harder to reason about the data model and the code we build over it.
We can use TRUNC function in Oracle DB. Here is an example.
SELECT TRUNC(TO_DATE('01 Jan 2018 08:00:00','DD-MON-YYYY HH24:MI:SS')) FROM DUAL
Output:
1/1/2018
Try
SELECT to_char(p1.PA_VALUE,'DD/MM/YYYY') as StartDate,
to_char(p2.PA_VALUE,'DD/MM/YYYY') as EndDate
...
If your column with DATE datatype has value like below : -
value in column : 10-NOV-2005 06:31:00
Then, You can Use TRUNC function in select query to convert your date-time value to only date like - DD/MM/YYYY or DD-MON-YYYY
select TRUNC(column_1) from table1;
result : 10-NOV-2005
You will see above result - Provided that NLS_DATE_FORMAT is set as like below :-
Alter session NLS_DATE_FORMAT = 'DD-MON-YYYY HH24:MI:SS';
there is also extended usage like this:
WITH dates AS (
SELECT date'2015-01-01' d FROM dual union
SELECT date'2015-01-10' d FROM dual union
SELECT date'2015-02-01' d FROM dual union
SELECT timestamp'2015-03-03 23:45:00' d FROM dual union
SELECT timestamp'2015-04-11 12:34:56' d FROM dual
)
SELECT d "Original Date",
trunc(d) "Nearest Day, Time Removed",
trunc(d, 'ww') "Nearest Week",
trunc(d, 'iw') "Start of Week",
trunc(d, 'mm') "Start of Month",
trunc(d, 'year') "Start of Year"
FROM dates;
Oracle Offical Help Page