table 1
_id sub_id
1 32
2 34
3 42
4 44
5 47
6 50
.
table 2
_id sub_id
1 34
2 42
i want result
_id sub_id count
1 32 2
2 34 2
3 42 1
4 44 0
5 47 0
6 50 0
table 2 sub id 34 contains table 1, above 32 -> count+1
table 2 sub id 42 contains table 1, above 32, 34, 42 -> count + 1
result
32, 34 = 2
42 = 1
44, 47, 50 = 0
i try outer join, left join etc....
not correct result.
how about this correct result?
plz. help me T.T....
Try this query
SELECT _id
,sub_id
,(
SELECT count(*)
FROM table2 t2
WHERE t2.sub_id >= t1.sub_id
) count
FROM table1 t1
This is what you want :
SELECT
t1._id
,t1.sub_id
,count(t2._id) as count
FROM
table1 t1
left join table2 t2
on t2.sub_id >= t1.sub_id
GROUP BY
t1._id
,t1.sub_id
Here is the SQLfiddle demo
select distinct a.id, a.sub_id,
case when c.sub_id is not null then (select count(*) from table2 b
where a.sub_id<=b.sub_id)
else 0 end as counter
from table1 a left join table2 c on c.sub_id>=a.sub_id
SQL Fiddle
Related
How can I use countif statement in PostgreSQL?
max(COUNTIF(t1.A1:C10,t2.a1),COUNTIF(t1.A1:C10,t2.b1),COUNTIF(t1.A1:C10,t2.c1))
I have table1 which is more then a million rows
a
b
c
M5
16
27
31
3
7
27
and table2 more then 100 rows including different dates after column c
a
b
c
10
15
16
30
40
50
60
70
80
16
18
37
5
12
16
8
31
28
11
12
13
7
9
31
2
7
21
20
16
27
8
12
17
2
8
14
3
14
15
The outcome should be something like this
a
b
c
M5
16
27
31
3
3
7
27
2
Tried the below query but the outcome is not correct
UPDATE table1 SET m5 = greatest(
case When a in(select unnest(array[a,b,c]) from (select * from table2 order by date DESC limit 10) foo) then 1 else 0 END,
case When b in(select unnest(array[a,b,c]) from (select * from table2 order by date DESC limit 10) foo) then 1 else 0 END,
case When c in(select unnest(array[a,b,c]) from (select * from table2 order by date DESC limit 10) foo) then 1 else 0 END)
Assuming your columns are fixed and predictable, I think you could put all possible table values into a single column and then do counts for each occurrence:
with exploded as (
select a from table2
union all
select b from table2
union all
select c from table2
)
select a, count (*) as count
from exploded e
group by a
So for example, the value 7 occurs twice (which would be reflected in this output).
From there, you can just do the updates from the CTE:
with exploded as (
select a from table2
union all
select b from table2
union all
select c from table2
),
counted as (
select a, count (*) as count
from exploded e
group by a
)
update table1 t
set m5 = greatest (ca.count, cb.count, cc.count)
from
counted ca,
counted cb,
counted cc
where
t.a = ca.a and
t.b = cb.a and
t.c = cc.a
The only issue I see is if one of the values does not come up (the inner join fails), but in your example that doesn't seem to happen.
If it is possible, I would think that could be resolved with one more CTE to fill in missing values from table1 in the set of possible occurrences.
Let say I am working under SAS EG and I have 2 tables:
Table1:
Id Item
1 A
1 B
1 C
2 B
2 D
3 C
3 E
3 F
Table2:
Id Item Amount
1 A 99
2 C 100
1 B 100
2 A 90
1 A 93
3 B 92
1 E 93
2 B 99
1 A 93
Now I would like to take the sum conditional for my table1 from table2 (when the ID and the Item match).
Id Item Want
1 A 285
1 B 100
1 C 0
2 B 99
2 D 0
3 C 0
3 E 0
3 F 0
So what am I supposed to do in SQL?
Thanks in advance.
Use a correlated subquery to SUM:
select t1.Id, t1.Item,
(select sum(t2.amount) from table2 t2 where t2.id = t1.id and t2.item = t1.item)
from table1 t1
This looks like aggregation to me, with a left join:
select t1.id, t1.item,
coalesce(sum(t2.amount), 0) as want
from table1 t1 left join
table2 t2
on t1.id = t2.id and t2.item = t2.item
group by t1.id, t1.item;
I need to get the sum of all TOTAL fields where the ID, RECNO and DRCR fields have the same value, while also displaying these fields in the result set.
eg
ID RECNO SECRECNO DRCR TOTAL
1 9 5 D 25
1 9 12 D 22
1 9 6 C 33
1 9 5 D 50
1 8 2 D 12
1 8 2 C 23
2 9 5 D 100
So the results of the query should be
ID RECNO SECRECNO DRCR SUM(TOTAL)
1 9 5 D 75
1 9 12 D 22
1 9 6 C 33
1 8 2 D 12
1 8 2 C 23
2 9 5 D 100
This query will give the results set, without the TOTAL:
select distinct t1.recno, t1.secrecno
from table t1, table t2
where t1.recno = t2.recno and t.id = '1' and t1.drcr = 'D'
But I can't see how to SUM the TOTAL of these results.
How to do this?
select t1.id,
t1.recno,
t1.secrecno,
t1.drcr,
SUM( TOTAL )
from table t1
INNER JOIN
table t2
ON ( t1.recno = t2.recno )
WHERE t1.id = '1'
AND t1.drcr = 'D'
GROUP BY
t1.id,
t1.recno,
t1.secrecno,
t1.drcr
I have two table like
id Name allocation
2 Ash 15
3 Alam 18
4 Rifat 20
and
Date Id Present
24 2 10
24 3 15
25 2 10
25 3 12
25 4 12
Now i want to get the following result
Date Id Alloc Present
24 2 15 10
24 3 18 15
24 4 20 NULL
25 2 15 10
25 3 18 12
25 4 20 12
I've tried JOIN query but it does not give desired result
How to get the above result?
SELECT
t1.id
, dd.date
, t1.allocation
, t2.present
FROM
table1 AS t1 --- all items
CROSS JOIN
( SELECT DISTINCT date
FROM table2
) AS dd --- all dates
LEFT JOIN
table2 AS t2 --- present allocations
ON t2.id = t1.id
AND t2.date = dd.date ;
Tested at SQL-Fiddle: test (thank you #JW.)
There is also an interesting other way:
SELECT
t2.date,
t1.id,
t1.allocation,
MAX(CASE WHEN t1.id = t2.id THEN t2.Present ELSE NULL END)
FROM
table1 t1, table2 t2
GROUP BY
t1.id, t2.date, t1.allocation
ORDER BY
t2.date, t1.id
Stolen from: SQL query inner join with 0 values
http://www.sqlfiddle.com/#!3/d2ded/44
I have dozen of tables with following format:
Table 1
[idA] [numA]
NULL 8
1 10
2 15
3 16
Table 2
[idB] [numB]
2 14
3 30
4 32
Table 3
[idC] [numC]
NULL 56
1 24
4 37
5 36
...
Now, I'm not sure how to formulate T-Sql query in order to produce following result:
[id] [numA] [numB] [numC] ...
NULL 8 0 56
1 10 0 24
2 15 14 0
3 16 30 0
4 0 32 37
5 0 0 36
Are there any suggestions on how to solve this?
I offer a solution with the full outer join, because that seems like the natural approach:
SELECT coalesce(a.id, b.id, c.id, . . .) as id,
a.NumA, b.NumB, c.NumC, . . .
FROM TableA a full outer join
TableB b
on a.id = b.id full outer join
TableC c
on coalesce(a.id, b.id) = c.id
However, the query needs to be written carefully, to keep the coalesces in line. The one advantage of this approach is that it should use indexes on the id columns for the query.
please try this
select id, max(numa),max(numb),max(numc) from
(
select id,numa,0 as numb,0 as numc from tb1
union all
select id,0 as numa,numb as numb,0 as numc from tb2
union all
select id,0 as numa,0 as numb,numc as numc from tb3
)X
group by id
order by id
Thanks
Rajath
SELECT Maintable.id,
Table1.numA,
Table2.numB,
Table3.numC
FROM (SELECT ida AS id
FROM Table1
UNION
SELECT idb AS id
FROM Table2
UNION
SELECT idc AS id
FROM Table3) MainTable
LEFT JOIN Table1
ON Maintable.id = Table1.Ida
LEFT JOIN Table2
ON Maintable.id = Table2.idB
LEFT JOIN Table3
ON Maintable.id = Table3.idC