How can we make multiple left and inner join in SQL Server
Following query not returning all Employees because of Inner join
SELECT * from Employee E
LEFT JOIN Participants P on E.EmpID=P.EmpID
INNER JOIN HRDetails H on D. DeptID=H.DeptID
Left JOIN SalaryDetails S on S.participantID=P.participantID
You have used an alias D. which does not refer to any table, this may cause error.
But to answer your question I think inner join would reduce the number of rows if not all DeptID matches between two tables.
Column 'company_id' in field list is ambiguous
It does not seem "ambiguous", I have no idea where I should fix it:
SELECT company_id, companies.name
FROM company_contracts AS contracts
LEFT OUTER JOIN companies ON companies.id = contracts.company_id
LEFT OUTER JOIN order_logs AS logs ON companies.id = logs.company_id;
Because company_id appears on both table company_contracts and order_logs,you need to specify it
SELECT contracts.company_id,c1.name
FROM company_contracts as contracts
LEFT OUTER JOIN companies as c1 on c1.id = contracts.company_id
LEFT OUTER JOIN order_logs as logs on c1.id = logs.company_id;
You should qualify all columns names in such a query. In addition, if you really want outer joins, the second join condition should refer to the first table, not the second:
SELECT cc.company_id, c.name
FROM company_contracts cc LEFT OUTER JOIN
companies c
ON c.id = cc.company_id LEFT OUTER JOIN
order_logs ol
ON cc.company_id = ol.company_id;
Or, more likely, you want to keep all companies and the query should look like:
SELECT c.id, c.name
FROM companies c LEFT OUTER JOIN
company_contracts cc
ON c.id = cc.company_id LEFT OUTER JOIN
order_logs ol
ON c.id = ol.company_id;
I have written a SQL query to retrieve required data and it looks like given below:
SELECT distinct p.person_id,p.birth_date,p.gender_code,
wm_concat(distinct r.race_code) as race_code,p.hispanic_latino_code,
c.clinically_diagnosed_code,
wm_concat(distinct c.characteristic_code) as chara_codes,
p.prev_adopted_code,p.age_adopted,
FIRST_VALUE(pe.removed_date) OVER (ORDER BY pe.removed_date),
count(pe.removed_date) as removal_count,
LAST_VALUE(pe.discharge_date) OVER (ORDER BY pe.discharge_date),
LAST_VALUE(pe.removed_date) OVER (ORDER BY pe.removed_date) as latest_removal_date,pe.created_date,
pe.removal_circumstance_code,wm_concat(distinct rr.removal_reason_code) as removal_reasons,
ps.placement_type_code,ps.icpc_placement_flag,pe.caretaker_structure_code
FROM PERSON p left outer join RACE r on p.person_id = r.person_id
left outer join CHARACTERISTIC c on c.person_id = p.person_id
left outer join PLACEMENT_EPISODE pe on p.person_id = pe.child_id
left outer join PLACEMENT_SETTING ps on p.person_id = ps.child_id
left outer join REMOVAL_REASON rr on pe.placement_episode_id = rr.placement_episode_id
GROUP BY p.person_id,p.birth_date,p.gender_code,p.hispanic_latino_code,
c.clinically_diagnosed_code,p.prev_adopted_code,p.age_adopted,pe.removed_date,
pe.discharge_date,pe.removed_date,pe.created_date,pe.removal_circumstance_code,
ps.placement_type_code,ps.icpc_placement_flag,pe.caretaker_structure_code
ORDER BY p.person_id
In the above mentioned query, I have already selected birth date for a person. Now again in select clause I want to select birth_date for persons with following condition:
condition 1: p.person_id = pe.primary_caretaker_id
condition 2: p.person_id = pe.secondary_caretaker_id
Can someone tell me the way to select these fields(birth_date based on two different conditions) in the existing query?
Birth_date has been already selected once for individual person. Now I want to retrieve birth_date for primary_caretaker and secondary_caretaker.
You will need to join to the PERSON table twice more:
SELECT distinct p.person_id,p.birth_date,p.gender_code,
wm_concat(distinct r.race_code) as race_code,p.hispanic_latino_code,
c.clinically_diagnosed_code,
wm_concat(distinct c.characteristic_code) as chara_codes,
p.prev_adopted_code,p.age_adopted,
FIRST_VALUE(pe.removed_date) OVER (ORDER BY pe.removed_date),
count(pe.removed_date) as removal_count,
LAST_VALUE(pe.discharge_date) OVER (ORDER BY pe.discharge_date),
LAST_VALUE(pe.removed_date) OVER (ORDER BY pe.removed_date) as latest_removal_date,
pe.created_date,
pe.removal_circumstance_code,wm_concat(distinct rr.removal_reason_code) as removal_reasons,
ps.placement_type_code,ps.icpc_placement_flag,pe.caretaker_structure_code,
primCare.birth_date as primary_carer_birth_date,
secCare.birth_date as secondary_carer_birth_date,
FROM PERSON p left outer join RACE r on p.person_id = r.person_id
left outer join PERSON primCare on primCare.person_id = pe.primary_caretaker_id
left outer join PERSON secCare on secCare.person_id = pe.secondary_caretaker_id
left outer join CHARACTERISTIC c on c.person_id = p.person_id
left outer join PLACEMENT_EPISODE pe on p.person_id = pe.child_id
left outer join PLACEMENT_SETTING ps on p.person_id = ps.child_id
left outer join REMOVAL_REASON rr on pe.placement_episode_id = rr.placement_episode_id
GROUP BY p.person_id,p.birth_date,p.gender_code,p.hispanic_latino_code,
c.clinically_diagnosed_code,p.prev_adopted_code,p.age_adopted,pe.removed_date,
pe.discharge_date,pe.removed_date,pe.created_date,pe.removal_circumstance_code,
ps.placement_type_code,ps.icpc_placement_flag,pe.caretaker_structure_code, primCare.birth_date, secCare.birth_date
ORDER BY p.person_id
I'm using mssql
How do I do a outer join on three tables, one of which is a junction table?
There can be nulls in the menu or product tables and I need these included in the result.
SELECT *
from [web].[dbo].[tblMenus]
left outer JOIN [web].[dbo].[tblProductsRelMenus]
on [tblMenus].Id = [tblProductsRelMenus].MenuId
left outer JOIN [web].[dbo].[tblProducts]
on [tblProductsRelMenus].ProductId = [tblProducts].ProductId
This doesn't give menu nulls, and if I change the second left to a right, I loose the product nulls...
What is the correct way to do this?
Perhaps you are looking for a full outer join
SELECT *
from [web].[dbo].[tblMenus]
full outer JOIN [web].[dbo].[tblProductsRelMenus]
on [tblMenus].Id = [tblProductsRelMenus].MenuId
full outer JOIN [web].[dbo].[tblProducts]
on [tblProductsRelMenus].ProductId = [tblProducts].ProductId
SELECT *
FROM
[web].[dbo].[tblMenus]
LEFT JOIN
[web].[dbo].[tblProductsRelMenus]
RIGHT OUTER JOIN
[web].[dbo].[tblProducts]
ON [tblProductsRelMenus].ProductId = [tblProducts].ProductId
ON [tblMenus].Id = [tblProductsRelMenus].MenuId
I need to go to two tables to get the appropriate info
exp_member_groups
-group_id
-group_title
exp_members
-member_id
-group_id
I have the appropriate member_id
So I need to check the members table, get the group_id, then go to the groups table and match up the group_id and get the group_title from that.
INNER JOIN:
SELECT exp_member_groups.group_title
FROM exp_members
INNER JOIN exp_member_groups ON exp_members.group_id = exp_member_groups.group_id
WHERE exp_members.member_id = #memberId
SELECT g.group_title
FROM exp_members m
JOIN exp_member_groups g ON m.group_id = g.group_id
WHERE m.member_id = #YourMemberId
If there is always a matching group, or you only want rows where it is, then it would be an INNER JOIN:
SELECT g.group_title
FROM exp_members m
INNER JOIN
exp_member_groups g
ON m.group_id = g.group_id
WHERE m.member_id = #member_id
If you want rows even where group_id doesn't match, then it is a LEFT JOIN - replace INNER JOIN with LEFT JOIN in the above.