Using tsql I want to count a numeric chars in string. For example i've got 'kick0my234ass' string and i wanna count how many (4 in that example) numbers are in that string. I can't use regex, just plain tslq.
You COULD do this I suppose:
declare #c varchar(30)
set #c = 'kick0my234ass'
select #c, len(replace(#c,' ','')) - len(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(#c,'0',''),'1',''),'2',''),'3',''),'4',''),'5',''),'6',''),'7',''),'8',''),'9',''),' ',''))
You'll first have to split the character string in its individual characters, evaluate which are numeric, and finally count those that are. This will do the trick:
DECLARE #test TABLE (Example NVARCHAR(255))
INSERT #test
VALUES ('kick0my234ass')
SELECT COUNT(1)
FROM #test AS T
INNER JOIN master..spt_values v
ON v.type = 'P'
AND v.number < len(T.Example)
WHERE SUBSTRING(T.Example, v.number + 1, 1) LIKE '[0-9]'
You could try this solution with regular expressions (if you'd allow them):
it uses recursive CTE, at every recursive step, one digit is removed from given string and the condition is to stop, when there are no digits in string. The rows are also numbered with consecutive ids, so the last id is the amount of removed digits from string.
declare #str varchar(100) = 'kick0my123ass';
with cte as (
select 1 [id], stuff(#str,PATINDEX('%[0-9]%', #str),1,'') [col]
union all
select [id] + 1, stuff([col],PATINDEX('%[0-9]%', [col]),1,'') from cte
where col like '%[0-9]%'
)
--this will give you number of digits in string
select top 1 id from cte order by id desc
Use a WHILE loop to each each character is a numeric or not.
Query
declare #text as varchar(max) = 'kick0my234ass';
declare #len as int;
select #len = len(#text);
if(#len > 0)
begin
declare #i as int = 1;
declare #count as int = 0;
while(#i <= #len)
begin
if(substring(#text, #i, 1) like '[0-9]')
set #count += 1;
set #i += 1;
end
print 'Count of Numerics in ' + #text + ' : ' + cast(#count as varchar(100));
end
else
print 'Empty string';
If simplicity & performance are important I suggest a purely set-based solution. Grab a copy of DigitsOnlyEE which will remove all non-numeric characters. Then use LEN against the output.
DECLARE #string varchar(100) = '123xxx45ff678';
SELECT string = #string, digitsOnly, DigitCount = LEN(digitsOnly)
FROM dbo.DigitsOnlyEE(#string);
Results
string digitsOnly DigitCount
------------------ ----------- ------------
123xxx45ff678 12345678 8
using a Tally Table created by an rCTE:
CREATE TABLE #Sample (S varchar(100));
INSERT INTO #Sample
VALUES ('kick0my234 ass');
GO
WITH Tally AS(
SELECT 1 AS N
UNION ALL
SELECT N + 1
FROM Tally
WHERE N + 1 <= 100)
SELECT S.S, SUM(CASE WHEN SUBSTRING(S,T.N, 1) LIKE '[0-9]' THEN 1 ELSE 0 END) AS Numbers
FROM #Sample S
JOIN Tally T ON LEN(S.S) >= T.N
GROUP BY S.S;
For future reference, also post your owns attempts please. We aren't here (really) to do your work for you.
I'm troubleshooting some strangeness in output of my SQL Server when I want to get records that are not null or empty string:
SELECT myString
FROM myTable
WHERE myString IS NOT NULL OR myString != ''
In addition to records that obviously fit (string values returned to SSMS's grid) I'm seeing records where the grid cell is blank. When I select the cell and try to copy it, my clipboard manager (clipmate.com) complains that the data is invalid.
If I output the query to file instead of to grid and then inspect via Hex char mode, sure enough - there are characters I would not expect (much less want) to be in there.
Collation of my database collation value shows as: SQL_Latin1_General_CP1_CI_AS
How would I go about eliminating any/all non-visible characters?
can try this, will remove any characters that are not printable.
CREATE FUNCTION [dbo].[RemoveNonPrintableChars]
(
#p_string varchar(max)
)
RETURNS varchar(max)
AS
BEGIN
declare #l_pos int = 1
declare #l_str varchar(max) = ''
while (#l_pos <= len(#p_string))
begin
if (ascii(substring(#p_string,#l_pos,1)) >=32)
begin
set #l_str=#l_str+substring(#p_string,#l_pos,1)
end
set #l_pos = #l_pos+1
end
return #l_str
END
declare
#l_str varchar(max) = 'andrew'--select char(7)
select dbo.[RemoveNonPrintableChars] (#l_str)
set #l_str = 'andrew'+char(7)-- add NP character
select dbo.[RemoveNonPrintableChars] (#l_str)
If by chance you can't use a UDF.
You may notice that I don't just strip the control characters here, I replace them with a space so not to concatenate strings.
Declare #YourTable table (SomeField varchar(50))
Insert Into #YourTable values
('Michael'+char(13)+char(10)+'LastName')
Select A.*
,B.Value
From #YourTable A
Cross Apply (
Select Value = replace(replace((
Select ''+C
From (
Select N,C=case when ASCII(Substring(A.SomeField,N ,1))>31 then Substring(A.SomeField,N ,1) else '{--space--}' end
From ( Select Top (Len(A.SomeField)) N=Row_Number() Over (Order By Number) From master..spt_values ) N
) C Order by N
For XML Path('') ) ,'{--space--}',' '),' ',' ')
) B
Returns
SomeField Value
Michael Michael LastName
LastName
EDIT
However, If you do want a UDF consider the following non-linear approach
CREATE FUNCTION [dbo].[udf-Str-Strip-Control](#S varchar(max))
Returns varchar(max)
Begin
;with cte1(N) As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
cte2(C) As (Select Top (32) Char(Row_Number() over (Order By (Select NULL))-1) From cte1 a,cte1 b)
Select #S = Replace(#S,C,' ')
From cte2
Return LTrim(RTrim(Replace(Replace(#S,' ',' '),' ',' ')))
End
--Select [dbo].[udf-Str-Strip-Control]('Michael'+char(13)+char(10)+'LastName') --Returns: Michael LastName
I like John's answers better, and would probably modify them if you were looking to control whether or not to include certain control characters. This is the function I used in the past to clean up some strings.
create function dbo.fnCleanVarchar (
#StringParameter varchar(max)
, #CleanStyle tinyint = 1
) returns varchar(max) as
begin;
if #StringParameter is null
return null;
if #CleanStyle > 3 set #CleanStyle = 1;
declare #StringReturn varchar(max);
declare #StringLength int;
declare #CharacterCode int;
declare #CharacterCodePosition int;
set #StringReturn = '';
set #StringLength = len(#StringParameter);
set #CharacterCodePosition = 1;
while #CharacterCodePosition <= #StringLength
begin
set #CharacterCode = ascii(substring(#stringParameter , #CharacterCodePosition , 1))
-- Removes Unprintable Characters 0-8,12,14-31
-- If Style = 1, Remove Unprintable Characters except Tab (9), New Line (10), Carraige Return (13)
-- If Style = 2, Remove Unprintable Characters except character 9 (Tab)
-- If Style = 3, Remove Unprintable Characters and character 9 (Tab)
set #StringReturn = #StringReturn + case
when #CharacterCode >31
then char(#CharacterCode)
when #Style = 3
then ''
when #Style = 2 and #CharacterCode = 9
then char(9)
when #Style = 1 and #CharacterCode in ( 9 , 10 , 13 )
then char(#CharacterCode)
else ''
end;
set #CharacterCodePosition = #CharacterCodePosition + 1
end;
if len(#StringReturn) = 0
return null;
return #StringReturn
end;
Checking for non-visible fields is directly related to find non-visible characters, so consider these two notes:
Note 1: SQL Server will auto-trimming spaces in clauses so N' ' = N'' is true, and any continues strings of empty characters;
Empty characters are a character that is equal to N''.
Note 2: There are 65536 Unicode characters, you can view them with a query like this:
WITH CTE(i, c) AS (
SELECT 0, NCHAR(0) COLLATE SQL_Latin1_General_CP1_CI_AS --I add COLLATE to express your collation but I think it is optional
UNION ALL
SELECT i+1, NCHAR(i+1) COLLATE SQL_Latin1_General_CP1_CI_AS
FROM CTE
WHERE i < 65535
)
SELECT *
FROM CTE
OPTION ( MaxRecursion 0 );
Some of those are not visible and empty like NCHAR(0), NCHAR(12288), ...,
Some of those are not visible and not empty like NCHAR(1), ...,
Some of those are visible and empty like NCHAR(502), ... !!!!.
So if your field is a nvarchar string, you will have a big problem to filter not visible characters, and for varchar strings you have a problem but more little than that.
Side note: You can use COALESCE(myString, '') != '' instead of yours ;).
SUMMARY :
For a little pin don't create a hammer machine!.
When this behaviors are not so important for you and your project don't try to change or handle or create your own equal string function ;).
A sample function to check if a string is visible(returns 1) or not(returns 0) can be like this:
CREATE FUNCTION IsVisible ( #string varchar(max) )
RETURNS bit
AS
BEGIN
DECLARE #pString varchar(max) = #string;
WITH InvisibleChars AS (
SELECT c COLLATE SQL_Latin1_General_CP1_CI_AS AS c
FROM (VALUES (CHAR(0)), (CHAR(1)), (CHAR(9)), (CHAR(10)),
(CHAR(11)), (CHAR(12)), (CHAR(13)), (CHAR(28)),
(CHAR(29)), (CHAR(30)), (CHAR(31)), (CHAR(32)),
(CHAR(160)) -- Above characters are non-visibles
) t(c)
)
SELECT #pString = REPLACE(#pString, c, '')
FROM InvisibleChars;
RETURN CASE WHEN #pString = '' THEN 0 ELSE 1 END;
END
GO
I have a procedure and input is comma separated like '1,2,3'.
I would like to query like
SELECT * FROM PERSON WHERE PERSON_ID IN(1,2,3).
Please note that PERSON_ID is integer.
I've seen this type of question so often I posted a blog on it here.
Basically you have three options (to the best of my knowledge)
The LIKE version that Gordon Lindoff suggested.
Using a split function like so.
DECLARE #InList varchar(100)
SET #InList = '1,2,3,4'
SELECT MyTable.*
FROM MyTable
JOIN DelimitedSplit8K (#InList,',') SplitString
ON MyTable.Id = SplitString.Item
Or using dynamic SQL.
DECLARE #InList varchar(100)
SET #InList = '1,2,3,4'
DECLARE #sql nvarchar(1000)
SET #sql = 'SELECT * ' +
'FROM MyTable ' +
'WHERE Id IN ('+#InList+') '
EXEC sp_executesql #sql
SearchList = ',' + inputSearchTerm + ','; /* e.g. inputSearchTerm is '1,2,3' */
SELECT * FROM PERSON WHERE CONTAINS(SearchList, ',' + cast(PERSON_ID as varchar) + ',');
Because contains seems like overkill (it is designed for fuzzy searching and uses a full text index), because charindex() is not standard SQL, and I abhor answers where varchar does not have length, let me give an alternative:
SELECT *
FROM PERSON
WHERE ','+#SearchList+',' like '%,'+cast(PERSON_ID as varchar(255))+',%';
The concatenation of commas for #SearchList makes sure that all values are surrounded by delimiters. These are then put around the particular value, to prevent 1 from matching 10.
Note that this will not be particularly efficient, because it will require a full table scan.
Here's a way of doing it using a recursive CTE:
declare #SearchList varchar(20)
set #SearchList= '1,2,3'
;with cte as
(select case charindex(',',#SearchList)
when 0 then cast(#SearchList as int)
else cast(left(#SearchList,charindex(',',#SearchList)-1) as int)
end searchVal,
case charindex(',',#SearchList)
when 0 then ''
else right(#SearchList,
len(#SearchList)-charindex(',',#SearchList) )
end remainStr
union all
select case charindex(',',remainStr)
when 0 then cast(remainStr as int)
else cast(left(remainStr,charindex(',',remainStr)-1) as int)
end searchVal,
case charindex(',',remainStr)
when 0 then ''
else right(remainStr,
len(remainStr)-charindex(',',remainStr) )
end remainStr
from cte
where remainStr > ''
)
select p.*
from cte
join person p on cte.searchVal = p.person_id
SQLFiddle here.
I have data like this:
string 1: 003Preliminary Examination Plan
string 2: Coordination005
string 3: Balance1000sheet
The output I expect is
string 1: 003
string 2: 005
string 3: 1000
And I want to implement it in SQL.
First create this UDF
CREATE FUNCTION dbo.udf_GetNumeric
(
#strAlphaNumeric VARCHAR(256)
)
RETURNS VARCHAR(256)
AS
BEGIN
DECLARE #intAlpha INT
SET #intAlpha = PATINDEX('%[^0-9]%', #strAlphaNumeric)
BEGIN
WHILE #intAlpha > 0
BEGIN
SET #strAlphaNumeric = STUFF(#strAlphaNumeric, #intAlpha, 1, '' )
SET #intAlpha = PATINDEX('%[^0-9]%', #strAlphaNumeric )
END
END
RETURN ISNULL(#strAlphaNumeric,0)
END
GO
Now use the function as
SELECT dbo.udf_GetNumeric(column_name)
from table_name
SQL FIDDLE
I hope this solved your problem.
Reference
Try this one -
Query:
DECLARE #temp TABLE
(
string NVARCHAR(50)
)
INSERT INTO #temp (string)
VALUES
('003Preliminary Examination Plan'),
('Coordination005'),
('Balance1000sheet')
SELECT LEFT(subsrt, PATINDEX('%[^0-9]%', subsrt + 't') - 1)
FROM (
SELECT subsrt = SUBSTRING(string, pos, LEN(string))
FROM (
SELECT string, pos = PATINDEX('%[0-9]%', string)
FROM #temp
) d
) t
Output:
----------
003
005
1000
Query:
DECLARE #temp TABLE
(
string NVARCHAR(50)
)
INSERT INTO #temp (string)
VALUES
('003Preliminary Examination Plan'),
('Coordination005'),
('Balance1000sheet')
SELECT SUBSTRING(string, PATINDEX('%[0-9]%', string), PATINDEX('%[0-9][^0-9]%', string + 't') - PATINDEX('%[0-9]%',
string) + 1) AS Number
FROM #temp
Please try:
declare #var nvarchar(max)='Balance1000sheet'
SELECT LEFT(Val,PATINDEX('%[^0-9]%', Val+'a')-1) from(
SELECT SUBSTRING(#var, PATINDEX('%[0-9]%', #var), LEN(#var)) Val
)x
Getting only numbers from a string can be done in a one-liner.
Try this :
SUBSTRING('your-string-here', PATINDEX('%[0-9]%', 'your-string-here'), LEN('your-string-here'))
NB: Only works for the first int in the string, ex: abc123vfg34 returns 123.
I found this approach works about 3x faster than the top voted answer. Create the following function, dbo.GetNumbers:
CREATE FUNCTION dbo.GetNumbers(#String VARCHAR(8000))
RETURNS VARCHAR(8000)
AS
BEGIN;
WITH
Numbers
AS (
--Step 1.
--Get a column of numbers to represent
--every character position in the #String.
SELECT 1 AS Number
UNION ALL
SELECT Number + 1
FROM Numbers
WHERE Number < LEN(#String)
)
,Characters
AS (
SELECT Character
FROM Numbers
CROSS APPLY (
--Step 2.
--Use the column of numbers generated above
--to tell substring which character to extract.
SELECT SUBSTRING(#String, Number, 1) AS Character
) AS c
)
--Step 3.
--Pattern match to return only numbers from the CTE
--and use STRING_AGG to rebuild it into a single string.
SELECT #String = STRING_AGG(Character,'')
FROM Characters
WHERE Character LIKE '[0-9]'
--allows going past the default maximum of 100 loops in the CTE
OPTION (MAXRECURSION 8000)
RETURN #String
END
GO
Testing
Testing for purpose:
SELECT dbo.GetNumbers(InputString) AS Numbers
FROM ( VALUES
('003Preliminary Examination Plan') --output: 003
,('Coordination005') --output: 005
,('Balance1000sheet') --output: 1000
,('(111) 222-3333') --output: 1112223333
,('1.38hello#f00.b4r#\-6') --output: 1380046
) testData(InputString)
Testing for performance:
Start off setting up the test data...
--Add table to hold test data
CREATE TABLE dbo.NumTest (String VARCHAR(8000))
--Make an 8000 character string with mix of numbers and letters
DECLARE #Num VARCHAR(8000) = REPLICATE('12tf56se',800)
--Add this to the test table 500 times
DECLARE #n INT = 0
WHILE #n < 500
BEGIN
INSERT INTO dbo.NumTest VALUES (#Num)
SET #n = #n +1
END
Now testing the dbo.GetNumbers function:
SELECT dbo.GetNumbers(NumTest.String) AS Numbers
FROM dbo.NumTest -- Time to complete: 1 min 7s
Then testing the UDF from the top voted answer on the same data.
SELECT dbo.udf_GetNumeric(NumTest.String)
FROM dbo.NumTest -- Time to complete: 3 mins 12s
Inspiration for dbo.GetNumbers
Decimals
If you need it to handle decimals, you can use either of the following approaches, I found no noticeable performance differences between them.
change '[0-9]' to '[0-9.]'
change Character LIKE '[0-9]' to ISNUMERIC(Character) = 1 (SQL treats a single decimal point as "numeric")
Bonus
You can easily adapt this to differing requirements by swapping out WHERE Character LIKE '[0-9]' with the following options:
WHERE Letter LIKE '[a-zA-Z]' --Get only letters
WHERE Letter LIKE '[0-9a-zA-Z]' --Remove non-alphanumeric
WHERE Letter LIKE '[^0-9a-zA-Z]' --Get only non-alphanumeric
With the previous queries I get these results:
'AAAA1234BBBB3333' >>>> Output: 1234
'-çã+0!\aº1234' >>>> Output: 0
The code below returns All numeric chars:
1st output: 12343333
2nd output: 01234
declare #StringAlphaNum varchar(255)
declare #Character varchar
declare #SizeStringAlfaNumerica int
declare #CountCharacter int
set #StringAlphaNum = 'AAAA1234BBBB3333'
set #SizeStringAlfaNumerica = len(#StringAlphaNum)
set #CountCharacter = 1
while isnumeric(#StringAlphaNum) = 0
begin
while #CountCharacter < #SizeStringAlfaNumerica
begin
if substring(#StringAlphaNum,#CountCharacter,1) not like '[0-9]%'
begin
set #Character = substring(#StringAlphaNum,#CountCharacter,1)
set #StringAlphaNum = replace(#StringAlphaNum, #Character, '')
end
set #CountCharacter = #CountCharacter + 1
end
set #CountCharacter = 0
end
select #StringAlphaNum
declare #puvodni nvarchar(20)
set #puvodni = N'abc1d8e8ttr987avc'
WHILE PATINDEX('%[^0-9]%', #puvodni) > 0 SET #puvodni = REPLACE(#puvodni, SUBSTRING(#puvodni, PATINDEX('%[^0-9]%', #puvodni), 1), '' )
SELECT #puvodni
A solution for SQL Server 2017 and later, using TRANSLATE:
DECLARE #T table (string varchar(50) NOT NULL);
INSERT #T
(string)
VALUES
('003Preliminary Examination Plan'),
('Coordination005'),
('Balance1000sheet');
SELECT
result =
REPLACE(
TRANSLATE(
T.string COLLATE Latin1_General_CI_AI,
'abcdefghijklmnopqrstuvwxyz',
SPACE(26)),
SPACE(1),
SPACE(0))
FROM #T AS T;
Output:
result
003
005
1000
The code works by:
Replacing characters a-z (ignoring case & accents) with a space
Replacing spaces with an empty string.
The string supplied to TRANSLATE can be expanded to include additional characters.
I did not have rights to create functions but had text like
["blahblah012345679"]
And needed to extract the numbers out of the middle
Note this assumes the numbers are grouped together and not at the start and end of the string.
select substring(column_name,patindex('%[0-9]%', column_name),patindex('%[0-9][^0-9]%', column_name)-patindex('%[0-9]%', column_name)+1)
from table name
Although this is an old thread its the first in google search, I came up with a different answer than what came before. This will allow you to pass your criteria for what to keep within a string, whatever that criteria might be. You can put it in a function to call over and over again if you want.
declare #String VARCHAR(MAX) = '-123. a 456-78(90)'
declare #MatchExpression VARCHAR(255) = '%[0-9]%'
declare #return varchar(max)
WHILE PatIndex(#MatchExpression, #String) > 0
begin
set #return = CONCAT(#return, SUBSTRING(#string,patindex(#matchexpression, #string),1))
SET #String = Stuff(#String, PatIndex(#MatchExpression, #String), 1, '')
end
select (#return)
This UDF will work for all types of strings:
CREATE FUNCTION udf_getNumbersFromString (#string varchar(max))
RETURNS varchar(max)
AS
BEGIN
WHILE #String like '%[^0-9]%'
SET #String = REPLACE(#String, SUBSTRING(#String, PATINDEX('%[^0-9]%', #String), 1), '')
RETURN #String
END
Just a little modification to #Epsicron 's answer
SELECT SUBSTRING(string, PATINDEX('%[0-9]%', string), PATINDEX('%[0-9][^0-9]%', string + 't') - PATINDEX('%[0-9]%',
string) + 1) AS Number
FROM (values ('003Preliminary Examination Plan'),
('Coordination005'),
('Balance1000sheet')) as a(string)
no need for a temporary variable
Firstly find out the number's starting length then reverse the string to find out the first position again(which will give you end position of number from the end). Now if you deduct 1 from both number and deduct it from string whole length you'll get only number length. Now get the number using SUBSTRING
declare #fieldName nvarchar(100)='AAAA1221.121BBBB'
declare #lenSt int=(select PATINDEX('%[0-9]%', #fieldName)-1)
declare #lenEnd int=(select PATINDEX('%[0-9]%', REVERSE(#fieldName))-1)
select SUBSTRING(#fieldName, PATINDEX('%[0-9]%', #fieldName), (LEN(#fieldName) - #lenSt -#lenEnd))
T-SQL function to read all the integers from text and return the one at the indicated index, starting from left or right, also using a starting search term (optional):
create or alter function dbo.udf_number_from_text(
#text nvarchar(max),
#search_term nvarchar(1000) = N'',
#number_position tinyint = 1,
#rtl bit = 0
) returns int
as
begin
declare #result int = 0;
declare #search_term_index int = 0;
if #text is null or len(#text) = 0 goto exit_label;
set #text = trim(#text);
if len(#text) = len(#search_term) goto exit_label;
if len(#search_term) > 0
begin
set #search_term_index = charindex(#search_term, #text);
if #search_term_index = 0 goto exit_label;
end;
if #search_term_index > 0
if #rtl = 0
set #text = trim(right(#text, len(#text) - #search_term_index - len(#search_term) + 1));
else
set #text = trim(left(#text, #search_term_index - 1));
if len(#text) = 0 goto exit_label;
declare #patt_number nvarchar(10) = '%[0-9]%';
declare #patt_not_number nvarchar(10) = '%[^0-9]%';
declare #number_start int = 1;
declare #number_end int;
declare #found_numbers table (id int identity(1,1), val int);
while #number_start > 0
begin
set #number_start = patindex(#patt_number, #text);
if #number_start > 0
begin
if #number_start = len(#text)
begin
insert into #found_numbers(val)
select cast(substring(#text, #number_start, 1) as int);
break;
end;
else
begin
set #text = right(#text, len(#text) - #number_start + 1);
set #number_end = patindex(#patt_not_number, #text);
if #number_end = 0
begin
insert into #found_numbers(val)
select cast(#text as int);
break;
end;
else
begin
insert into #found_numbers(val)
select cast(left(#text, #number_end - 1) as int);
if #number_end = len(#text)
break;
else
begin
set #text = trim(right(#text, len(#text) - #number_end));
if len(#text) = 0 break;
end;
end;
end;
end;
end;
if #rtl = 0
select #result = coalesce(a.val, 0)
from (select row_number() over (order by m.id asc) as c_row, m.val
from #found_numbers as m) as a
where a.c_row = #number_position;
else
select #result = coalesce(a.val, 0)
from (select row_number() over (order by m.id desc) as c_row, m.val
from #found_numbers as m) as a
where a.c_row = #number_position;
exit_label:
return #result;
end;
Example:
select dbo.udf_number_from text(N'Text text 10 text, 25 term', N'term',2,1);
returns 10;
This is one of the simplest and easiest one. This will work on the entire String for multiple occurences as well.
CREATE FUNCTION dbo.fn_GetNumbers(#strInput NVARCHAR(500))
RETURNS NVARCHAR(500)
AS
BEGIN
DECLARE #strOut NVARCHAR(500) = '', #intCounter INT = 1
WHILE #intCounter <= LEN(#strInput)
BEGIN
SELECT #strOut = #strOut + CASE WHEN SUBSTRING(#strInput, #intCounter, 1) LIKE '[0-9]' THEN SUBSTRING(#strInput, #intCounter, 1) ELSE '' END
SET #intCounter = #intCounter + 1
END
RETURN #strOut
END
Following a solution using a single common table expression (CTE).
DECLARE #s AS TABLE (id int PRIMARY KEY, value nvarchar(max));
INSERT INTO #s
VALUES
(1, N'003Preliminary Examination Plan'),
(2, N'Coordination005'),
(3, N'Balance1000sheet');
SELECT * FROM #s ORDER BY id;
WITH t AS (
SELECT
id,
1 AS i,
SUBSTRING(value, 1, 1) AS c
FROM
#s
WHERE
LEN(value) > 0
UNION ALL
SELECT
t.id,
t.i + 1 AS i,
SUBSTRING(s.value, t.i + 1, 1) AS c
FROM
t
JOIN #s AS s ON t.id = s.id
WHERE
t.i < LEN(s.value)
)
SELECT
id,
STRING_AGG(c, N'') WITHIN GROUP (ORDER BY i ASC) AS value
FROM
t
WHERE
c LIKE '[0-9]'
GROUP BY
id
ORDER BY
id;
DECLARE #index NVARCHAR(20);
SET #index = 'abd565klaf12';
WHILE PATINDEX('%[0-9]%', #index) != 0
BEGIN
SET #index = REPLACE(#index, SUBSTRING(#index, PATINDEX('%[0-9]%', #index), 1), '');
END
SELECT #index;
One can replace [0-9] with [a-z] if numbers only are wanted with desired castings using the CAST function.
If we use the User Define Function, the query speed will be greatly reduced. This code extracts the number from the string....
SELECT
Reverse(substring(Reverse(rtrim(ltrim( substring([FieldName] , patindex('%[0-9]%', [FieldName] ) , len([FieldName]) )))) , patindex('%[0-9]%', Reverse(rtrim(ltrim( substring([FieldName] , patindex('%[0-9]%', [FieldName] ) , len([FieldName]) )))) ), len(Reverse(rtrim(ltrim( substring([FieldName] , patindex('%[0-9]%', [FieldName] ) , len([FieldName]) ))))) )) NumberValue
FROM dbo.TableName
CREATE OR REPLACE FUNCTION count_letters_and_numbers(input_string TEXT)
RETURNS TABLE (letters INT, numbers INT) AS $$
BEGIN
RETURN QUERY SELECT
sum(CASE WHEN input_string ~ '[A-Za-z]' THEN 1 ELSE 0 END) as letters,
sum(CASE WHEN input_string ~ '[0-9]' THEN 1 ELSE 0 END) as numbers
FROM unnest(string_to_array(input_string, '')) as input_string;
END;
$$ LANGUAGE plpgsql;
For the hell of it...
This solution is different to all earlier solutions, viz:
There is no need to create a function
There is no need to use pattern matching
There is no need for a temporary table
This solution uses a recursive common table expression (CTE)
But first - note the question does not specify where such strings are stored. In my solution below, I create a CTE as a quick and dirty way to put these strings into some kind of "source table".
Note also - this solution uses a recursive common table expression (CTE) - so don't get confused by the usage of two CTEs here. The first is simply to make the data avaliable to the solution - but it is only the second CTE that is required in order to solve this problem. You can adapt the code to make this second CTE query your existing table, view, etc.
Lastly - my coding is verbose, trying to use column and CTE names that explain what is going on and you might be able to simplify this solution a little. I've added in a few pseudo phone numbers with some (expected and atypical, as the case may be) formatting for the fun of it.
with SOURCE_TABLE as (
select '003Preliminary Examination Plan' as numberString
union all select 'Coordination005' as numberString
union all select 'Balance1000sheet' as numberString
union all select '1300 456 678' as numberString
union all select '(012) 995 8322 ' as numberString
union all select '073263 6122,' as numberString
),
FIRST_CHAR_PROCESSED as (
select
len(numberString) as currentStringLength,
isNull(cast(try_cast(replace(left(numberString, 1),' ','z') as tinyint) as nvarchar),'') as firstCharAsNumeric,
cast(isNull(cast(try_cast(nullIf(left(numberString, 1),'') as tinyint) as nvarchar),'') as nvarchar(4000)) as newString,
cast(substring(numberString,2,len(numberString)) as nvarchar) as remainingString
from SOURCE_TABLE
union all
select
len(remainingString) as currentStringLength,
cast(try_cast(replace(left(remainingString, 1),' ','z') as tinyint) as nvarchar) as firstCharAsNumeric,
cast(isNull(newString,'') as nvarchar(3999)) + isNull(cast(try_cast(nullIf(left(remainingString, 1),'') as tinyint) as nvarchar(1)),'') as newString,
substring(remainingString,2,len(remainingString)) as remainingString
from FIRST_CHAR_PROCESSED fcp2
where fcp2.currentStringLength > 1
)
select
newString
,* -- comment this out when required
from FIRST_CHAR_PROCESSED
where currentStringLength = 1
So what's going on here?
Basically in our CTE we are selecting the first character and using try_cast (see docs) to cast it to a tinyint (which is a large enough data type for a single-digit numeral). Note that the type-casting rules in SQL Server say that an empty string (or a space, for that matter) will resolve to zero, so the nullif is added to force spaces and empty strings to resolve to null (see discussion) (otherwise our result would include a zero character any time a space is encountered in the source data).
The CTE also returns everything after the first character - and that becomes the input to our recursive call on the CTE; in other words: now let's process the next character.
Lastly, the field newString in the CTE is generated (in the second SELECT) via concatenation. With recursive CTEs the data type must match between the two SELECT statements for any given column - including the column size. Because we know we are adding (at most) a single character, we are casting that character to nvarchar(1) and we are casting the newString (so far) as nvarchar(3999). Concatenated, the result will be nvarchar(4000) - which matches the type casting we carry out in the first SELECT.
If you run this query and exclude the WHERE clause, you'll get a sense of what's going on - but the rows may be in a strange order. (You won't necessarily see all rows relating to a single input value grouped together - but you should still be able to follow).
Hope it's an interesting option that may help a few people wanting a strictly expression-based solution.
In Oracle
You can get what you want using this:
SUBSTR('ABCD1234EFGH',REGEXP_INSTR ('ABCD1234EFGH', '[[:digit:]]'),REGEXP_COUNT ('ABCD1234EFGH', '[[:digit:]]'))
Sample Query:
SELECT SUBSTR('003Preliminary Examination Plan ',REGEXP_INSTR ('003Preliminary Examination Plan ', '[[:digit:]]'),REGEXP_COUNT ('003Preliminary Examination Plan ', '[[:digit:]]')) SAMPLE1,
SUBSTR('Coordination005',REGEXP_INSTR ('Coordination005', '[[:digit:]]'),REGEXP_COUNT ('Coordination005', '[[:digit:]]')) SAMPLE2,
SUBSTR('Balance1000sheet',REGEXP_INSTR ('Balance1000sheet', '[[:digit:]]'),REGEXP_COUNT ('Balance1000sheet', '[[:digit:]]')) SAMPLE3 FROM DUAL
If you are using Postgres and you have data like '2000 - some sample text' then try substring and position combination, otherwise if in your scenario there is no delimiter, you need to write regex:
SUBSTRING(Column_name from 0 for POSITION('-' in column_name) - 1) as
number_column_name
I have a string:
#string='TEST RESULTS\TEST 1\RESULT 1
The string/text remains the same except for the numbers
need the 1 from TEST
need 1 from RESULT
to be used in a query like:
SET #sql = "SELECT *
FROM TABLE
WHERE test = (expression FOR CASE 1 resulting IN INT 1)
AND result = (expression FOR CASE 2 resulting IN INT 1)"
Looks like you already have a solution that met your needs but I have a little trick that I use to extract numbers from strings that I thought might benefit someone. It takes advantage of the FOR XML statement and avoids explicit loops. It makes a good inline table function or simple scalar. Do with it what you will :)
DECLARE #String varchar(255) = 'This1 Is2 my3 Test4 For Number5 Extr#ct10n';
SELECT
CAST((
SELECT CASE --// skips alpha. make sure comparison is done on upper case
WHEN ( ASCII(UPPER(SUBSTRING(#String, Number, 1))) BETWEEN 48 AND 57 )
THEN SUBSTRING(#String, Number, 1)
ELSE ''END
FROM
(
SELECT TOP 255 --// east way to get a list of numbers
--// change value as needed.
ROW_NUMBER() OVER ( ORDER BY ( SELECT 1 ) ) AS Number
FROM master.sys.all_columns a
CROSS JOIN master.sys.all_columns b
) AS n
WHERE Number <= LEN(#String)
--// use xml path to pivot the results to a row
FOR XML PATH('') ) AS varchar(255)) AS Result
Result ==> 1234510
You can script an sql function which can used through your search queries.
Here is the sample code.
CREATE FUNCTION udf_extractInteger(#string VARCHAR(2000))
RETURNS VARCHAR(2000)
AS
BEGIN
DECLARE #count int
DECLARE #intNumbers VARCHAR(1000)
SET #count = 0
SET #intNumbers = ''
WHILE #count <= LEN(#string)
BEGIN
IF SUBSTRING(#string, #count, 1)>='0' and SUBSTRING (#string, #count, 1) <='9'
BEGIN
SET #intNumbers = #intNumbers + SUBSTRING (#string, #count, 1)
END
SET #count = #count + 1
END
RETURN #intNumbers
END
GO
QUERY :
SELECT dbo.udf_extractInteger('hello 123 world456') As output
OUTPUT:
123456
Referred from : http://www.ittutorials.in/source/sql/sql-function-to-extract-only-numbers-from-string.aspx
Since you have stable text and only 2 elements, you can make good use of replace and parsename:
declare #string varchar(100) = 'TEST RESULTS\TEST 1\RESULT 2'
select cast(parsename(replace(replace(#string, 'TEST RESULTS\TEST ', ''), '\RESULT ', '.'), 2) as int) as Test
, cast(parsename(replace(replace(#string, 'TEST RESULTS\TEST ', ''), '\RESULT ', '.'), 1) as int) as Result
/*
Test Result
----------- -----------
1 2
*/
The replace portion does assume the same text and spacing always, and sets up for parsename with the period.
This method uses SUBSTRING, PARSENAME, and PATINDEX:
SELECT
SUBSTRING(PARSENAME(c,2), PATINDEX('%[0-9]%',PARSENAME(c,2)), LEN(c)) Test,
SUBSTRING(PARSENAME(c,1), PATINDEX('%[0-9]%',PARSENAME(c,1)), LEN(c)) Result
FROM ( SELECT REPLACE(#val, '\', '.') c) t
Use PARSENAME to split the string. The text of the string won't matter -- it will just need to contain the 2 back slashes to parse to 3 elements. Use PATINDEX with a regular expression to replace non-numeric values from the result. This would need adjusting if the text in front of the number ever contained numbers.
If needed, CAST/CONVERT the results to int or the appropriate data type.
Here is some sample Fiddle.
Good luck.