I have two tables as shown below.
First Table tblCategory
Second Table tblWord
Required Output
On output,
TotalCount is count(*) with group by categoryid from tblWord
Played is count(*) with where isPlayed = 1 group by categoryid from tblword
So for getting result from 2 table, I tried following query which is wrong.
select (select count(*) from tblwords group by categoryid) as count, (select count(*) from tblwords where isPlayed = 1 group by categoryid) as played, categoryID, categoryname from tblcategory
Any suggestion in query to get required output or any helpful links ?
To get exact output with total count
SELECT t.categoryID, t.name,
COUNT(*) as TotalCount, SUM(isplayed) as Played
FROM tblCategory t
INNER JOIN tblWord tw
ON t.categoryID = tw.categoryID
GROUP BY t.categoryID, t.name
To get count for isPlayed = 1 only
SELECT t.categoryID, t.name,
COUNT(*) as TotalCount, SUM(isplayed) as Played
FROM tblCategory t
INNER JOIN tblWord tw
ON t.categoryID = tw.categoryID
WHERE isPlayed=1
GROUP BY t.categoryID, t.name
try this
SELECT tw.Category_ID, tc.NAME,
COUNT(*) AS TotalCount, SUM(tw.IsPlayed=1) AS Played ,SUM(tw.IsPlayed=0) AS NonPlayed
FROM Table_Category tc
INNER JOIN Table_Word tw
ON tc.Category_ID = tw.Category_ID
-- WHERE tw.IsPlayed=1
GROUP BY tc.Category_ID, tc.NAME
here SUM(tw.IsPlayed=1) AS Played ,SUM(tw.IsPlayed=0) AS NonPlayed is used ,so u will get the both Played and non played
select *
from
(select categoryID, count(isPlayed), sum(isPlayed) from tblword group by categoryID) b
left join
tblcategory a
on a.categoryID = b.categoryID
I'd aggregate first, then join.
Related
I have 2 tables: 1st is comment, 2nd is rating
SELECT * FROM comment_table a
INNER JOIN (SELECT comment_id, SUM(rating_value) AS total_rating FROM rating_table GROUP BY comment_id) b
ON a.comment_id = b.comment_id
ORDER BY b.total_rating DESC
I tried the above SQL but doesn't work!
Object is to display a list of comments order by rating points of each comments.
SELECT s.* FROM (
SELECT * FROM comment_table a
INNER JOIN (SELECT comment_id, SUM(rating_value) AS total_rating FROM rating_table GROUP BY comment_id) b
ON a.comment_id = b.comment_id
) AS s
ORDER BY s.total_rating DESC
Nest it inside an another select. It will then output the data in the correct order.
I'm trying to add together the counts of two different tables and group them by the same variable
Here is what I have so far:
SELECT a.storenumber,
Count (howmanytotal) AS total_counts_store
FROM (
SELECT month_counts.howmany,
new_counts.howmany) AS howmanytotal
from (
SELECT a.storenumber,
count (b.riid_) AS howmany
FROM $b$ b
INNER JOIN $a$ a
ON b.riid_=a.riid_
GROUP BY a.storenumber) month_counts
FROM (
SELECT a.storenumber,
count (c.riid_) AS howmany
FROM $c$ c
INNER JOIN $a$ a
ON c.riid_=a.riid_
GROUP BY a.storenumber) new_counts
ON month_counts.storenumber = new_counts.storenumber) theend
where I'm at now:
SELECT howmanytotal AS total_counts_store
FROM (
SELECT Count (howmany) AS howmanytotal)
FROM (
SELECT month_counts.howmany,
new_counts.howmany)
FROM (
SELECT a.storenumber,
count (b.riid_) AS howmany
FROM $b$ b
inner join $a$ a
ON b.riid_=a.riid_
GROUP BY a.storenumber) month_counts
UNION
(
SELECT count (c.riid_) AS howmany
FROM $c$ c
inner join $a$ a
ON c.riid_=a.riid_
GROUP BY a.storenumber) new_counts
ON month_counts.storenumber = new_counts.storenumber) ORDER BY $a$.storenumber
Getting this error: Error: java.sql.SQLSyntaxErrorException: ORA-00923: FROM keyword not found where expected
Please correct SELECT statement:
Join the subqueries:
select
storenumber,
month_counts.howmany as month_count,
new_counts.howmany as new_count,
month_counts.howmany + new_counts.howmany as total_count
from (...) month_counts
join (...) new_counts using (storenumber)
order by storenumber;
If it is possible for a storenumber to be missing from one of the subquery results, then outer join and use COALESCE or NVL to deal with the nulls. Here is a query with a full outer join, which is not available in MySQL, but in Oracle and many other DBMS.
select
storenumber,
month_counts.howmany as month_count,
new_counts.howmany as new_count,
nvl(month_counts.howmany, 0) + nvl(new_counts.howmany, 0) as total_count
from (...) month_counts
full outer join (...) new_counts using (storenumber)
order by storenumber;
Ending up using sum and union to complete. Thank you for your help.
SELECT storenumber,
SUM(howmany) AS howmanytotal
FROM (SELECT a.storenumber,
Count (b.riid_) AS howmany
FROM $b$ b
inner join $a$ a
ON b.riid_ = a.riid_
GROUP BY a.storenumber
UNION
SELECT a.storenumber,
Count (c.riid_) AS howmany
FROM $c$ c
inner join $a$ a
ON c.riid_ = a.riid_
GROUP BY a.storenumber)
GROUP BY storenumber
ORDER BY storenumber
This gave me a list of store ids and how many active subscribers we have at each store (taken from two separate tables)
I am having the following query and running it on postgress
select
p.id as p_id,
p.name as p_name,
p.tags,
p.creator,
p.value
p.creation_date,
cp.id as c_part_id,
fr.distance
count(*) OVER() AS total_item
from t_p p
left join t_c_part cp on p.id = cp.p_id
left join t_fl fr on p.id = fr.p_id
where p.name = 'test'
ORDER BY p.id ASC, p.name ASC
OFFSET 0 FETCH NEXT 25 ROWS only
What is missing here is that I also need to get max(p.value) and min(p.value) not affected by the "where" clause - so calculated from total (all) values.
I am dreaming that I can do it within one query and reduce the number of transactions.
Honestly not sure if it is possible!
What I tried is something like this ->
SELECT
(SELECT COUNT(*) from t_p) as count,
(SELECT json_agg(t.*) FROM (
SELECT * FROM t_p
where ***
) AS t) AS rows
But this one did not look really nice as it require additional JSON manipulation at the backend.
I discovered that I might try to use the "with" statement to create a temporary view so the where condition is only evaluated once, but did not succeed to make it works...
You can add the extra columns as scalar subqueries in the form (select min(value) from t_p). Their values are not related to the main query so they should be totally independent.
Your original query has some minor syntax issues (missing commas). I fixed those and the result is:
select
p.id as p_id,
p.name as p_name,
p.tags,
p.creator,
p.value,
p.creation_date,
cp.p_id as c_part_id,
fr.distance,
count(*) OVER() AS total_item,
(select min(value) from t_p) as min_value,
(select max(value) from t_p) as max_value
from t_p p
left join t_c_part cp on p.id = cp.p_id
left join t_fl fr on p.id = fr.p_id
where p.name = 'test'
ORDER BY p.id ASC, p.name ASC
OFFSET 0 FETCH NEXT 25 ROWS only
See running query (without any data) at DB Fiddle.
You can join to a sub-query that calculates both MIN & MAX.
...
from t_p p
left join t_c_part cp on p.id = cp.p_id
left join t_fl fr on p.id = fr.p_id
cross join (
select
min(value) as min_value
, max(value) as max_value
, avg(value) as avg_value
from t_p
) as v
...
Then use v.min_value and v.max_value in the select.
Doesn't even have to be a LATERAL.
You could get the minimum and maximum "on the side" like this:
select
p.id as p_id,
p.name as p_name,
p.tags,
p.creator,
p.value
p.creation_date,
cp.id as c_part_id,
fr.distance,
count(*) OVER() AS total_item,
p.min_value,
p.max_value
from (SELECT id,
name,
tags,
creator,
value,
creation_date,
min(value) OVER () AS min_value,
max(value) OVER () AS max_value,
FROM t_p) AS p
left join t_c_part cp on p.id = cp.p_id
left join t_fl fr on p.id = fr.p_id
where p.name = 'test'
ORDER BY p.id ASC, p.name ASC
OFFSET 0 FETCH NEXT 25 ROWS only;
I have the following items table:
items:
id pr1 pr2 pr3
-------------------
1 11 22 tt
...
and two tables associated with the items:
comments:
item_id text
-------------
1 "cool"
1 "very good"
...
tags:
item_id tag
-------------
1 "life"
1 "drug"
...
Now I want to get a table with columns item_id, pr1, pr2, count(comments), count(tags) with a condition WHERE pr3 = zz. What is the best way to get it? I can do this by creating additional tables, but I was wondering if there is a way achieve this by using only a single SQL statement. I'm using Postgres 9.3.
The easiest way is certainly to get the counts in the select clause:
select
id,
pr1,
pr2,
(select count(*) from comments where item_id = items.id) as comment_count,
(select count(*) from tags where item_id = items.id) as tag_count
from items;
You can just join, but you need to be careful that you don't get double count. E.g. you can use a subqueries to get what you want.
SELECT i.id,i.pr1,i.pr2, commentcount,tagcount FROM
items i
INNER JOIN
(SELECT item_id,count(*) as commentcount from comments GROUP BY item_id) c
ON i.id = c.item_id
INNER JOIN
(SELECT item_id,count(*) as tagcount from tags GROUP BY item_id) t
ON i.id = t.item_id
[EDIT] based on the comment, here's the left join version...
SELECT i.id,i.pr1,i.pr2, coalesce(commentcount,0) as commentcount,
coalesce(tagcount,0) as tagcount FROM
items i
LEFT JOIN
(SELECT item_id,count(*) as commentcount from comments GROUP BY item_id) c
ON i.id = c.item_id
LEFT JOIN
(SELECT item_id,count(*) as tagcount from tags GROUP BY item_id) t
ON i.id = t.item_id
Try this:
SELECT i.id, i.pr1, i.pr2, A.commentCount, B.tagCount
FROM items i
LEFT OUTER JOIN (SELECT item_id, COUNT(1) AS commentCount
FROM comments
GROUP BY item_id
) AS A ON i.id = A.item_id
LEFT OUTER JOIN (SELECT item_id, count(1) as tagCount
FROM tags
GROUP BY item_id
) AS B ON i.id = B.item_id;
select
i.id
, i.pr1
, i.pr2
, count(c.item_id) as count_comments
, count(t.item_id) as count_tags
from items i
left outer join comments c on i.id = c.item_id
left outer join tags t on i.id = t.item_id
group by i.id, i.pr1, i.pr2
I've used a LEFT OUTER JOIN to also return counts of zero.
I have the following query:
SELECT TOP 25 CLIENT_ID_MD5, COUNT(CLIENT_ID_MD5) TOTAL
FROM dbo.amazonlogs
GROUP BY CLIENT_ID_MD5
ORDER BY COUNT(*) DESC;
Which returns:
283fe255cbc25c804eb0c05f84ee5d52 864458
879100cf8aa8b993a8c53f0137a3a176 126122
06c181de7f35ee039fec84579e82883d 88719
69ffb6c6fd5f52de0d5535ce56286671 68863
703441aa63c0ac1f39fe9e4a4cc8239a 47434
3fd023e7b2047e78c6742e2fc5b66fce 45350
a8b72ca65ba2440e8e4028a832ec2160 39524
...
I want to retrieve the corresponding client name (FIRM) using the returned MD5 from this query, so a row might look like:
879100cf8aa8b993a8c53f0137a3a176 126122 Burger King
So I made this query:
SELECT a.CLIENT_ID_MD5, COUNT(a.CLIENT_ID_MD5) TOTAL, c.FIRM
FROM dbo.amazonlogs a
INNER JOIN dbo.customers c
ON c.CLIENT_ID_MD5 = a.CLIENT_ID_MD5
GROUP BY a.CLIENT_ID_MD5, c.FIRM
ORDER BY COUNT(*) DESC;
This returns something like:
879100cf8aa8b993a8c53f0137a3a176 126122 Burger King
06c181de7f35ee039fec84579e82883d 88719 McDonalds
703441aa63c0ac1f39fe9e4a4cc8239a 47434 Wendy's
3fd023e7b2047e78c6742e2fc5b66fce 45350 Tim Horton's
Which works, except I need to return an empty value for c.FIRM if there is no corresponding FIRM for a given MD5. For example:
879100cf8aa8b993a8c53f0137a3a176 126122 Burger King
06c181de7f35ee039fec84579e82883d 88719 McDonalds
69ffb6c6fd5f52de0d5535ce56286671 68863
703441aa63c0ac1f39fe9e4a4cc8239a 47434 Wendy's
3fd023e7b2047e78c6742e2fc5b66fce 45350 Tim Horton's
How should I modify the query to still return a row even if there is no corresponding c.FIRM?
Replace INNER JOIN with LEFT JOIN
use LEFT JOIN instead of INNER JOIN
Instead of doing an INNER join, you should do a LEFT OUTER join:
SELECT
a.CLIENT_ID_MD5,
COUNT(a.CLIENT_ID_MD5) TOTAL,
ISNULL(c.FIRM,'')
FROM
dbo.amazonlogs a LEFT OUTER JOIN
dbo.customers c ON c.CLIENT_ID_MD5 = a.CLIENT_ID_MD5
GROUP BY
a.CLIENT_ID_MD5,
c.FIRM
ORDER BY COUNT(0) DESC
http://www.w3schools.com/sql/sql_join.asp
An inner join excludes NULLs; you want a LEFT OUTER join.
SELECT a.CLIENT_ID_MD5, COUNT(a.CLIENT_ID_MD5) TOTAL, IsNull(c.FIRM, 'Unknown') as Firm
FROM dbo.amazonlogs a
LEFT JOIN dbo.customers c ON c.CLIENT_ID_MD5 = a.CLIENT_ID_MD5
GROUP BY a.CLIENT_ID_MD5, c.FIRM ORDER BY COUNT(*) DESC;
This will give you a value of "Unknown" when records in the customers table don't exist. You could obviously drop that part and just return c.FIRM if you want to have actual nulls instead.
Change your INNER JOIN to an OUTER JOIN...
SELECT a.CLIENT_ID_MD5, COUNT(a.CLIENT_ID_MD5) TOTAL, c.FIRM
FROM dbo.amazonlogs a
LEFT OUTER JOIN dbo.customers c
ON c.CLIENT_ID_MD5 = a.CLIENT_ID_MD5
GROUP BY a.CLIENT_ID_MD5, c.FIRM
ORDER BY COUNT(*) DESC;
WITH amazonlogs_Tallies
AS
(
SELECT a.CLIENT_ID_MD5, COUNT(a.CLIENT_ID_MD5) TOTAL
FROM dbo.amazonlogs a
GROUP
BY a.CLIENT_ID_MD5
),
amazonlogs_Tallies_Firms
AS
(
SELECT a.CLIENT_ID_MD5, a.TOTAL, c.FIRM
FROM amazonlogs_Tallies a
INNER JOIN dbo.customers c
ON c.CLIENT_ID_MD5 = a.CLIENT_ID_MD5
)
SELECT CLIENT_ID_MD5, TOTAL, FIRM
FROM amazonlogs_Tallies_Firms
UNION
SELECT CLIENT_ID_MD5, TOTAL, '{{NOT_KNOWN}}'
FROM amazonlogs_Tallies
EXCEPT
SELECT CLIENT_ID_MD5, TOTAL, '{{NOT_KNOWN}}'
FROM amazonlogs_Tallies_Firms;