Suppose I have two tables:
Table 1
Col
1
3
4
5
6
9
and Table 2
Col
2
4
6
8
How can I Merge the two tables so I have 1-9 and if a number only appears in one table, the corresponding position in the other table has a null? Thank you.
I'm assuming you want the numbers that actually exist in at least one of the tables, which won't give you a row with 7;
What you're looking for seems to be something like a FULL OUTER JOIN which works in pretty much any RDBMS except MySQL;
SELECT a.col col_a, b.col col_b
FROM Table1 a
FULL OUTER JOIN Table2 b ON a.col = b.col
ORDER BY COALESCE(a.col, b.col);
An SQLfiddle to test with.
Sadly, MySQL does not have FULL OUTER JOIN, so you'll have to do the same operation using a UNION between a LEFT JOIN and a RIGHT JOIN;
SELECT * FROM (
SELECT a.col col_a, b.col col_b
FROM Table1 a
LEFT JOIN Table2 b ON a.col = b.col
UNION
SELECT a.col col_a, b.col col_b
FROM Table1 a
RIGHT JOIN Table2 b ON a.col = b.col
)z
ORDER BY COALESCE(col_a, col_b);
Another SQLfiddle.
If i am not wrong. you need records from both table. (please correct me if i am wrong)
Try following to get data from both tables:
select col from Table1
union
select col from Table2
select col from Table1
union all
select col from Table2
NOTE:
UNION removes duplicate records (where all columns in the results are the same), UNION ALL does not.
There is a performance hit when using UNION vs UNION ALL, since the database server must do additional work to remove the duplicate rows, but usually you do not want the duplicates (especially when developing reports).
You can try this one using union:
SELECT * FROM (SELECT col AS value FROM table1
UNION
SELECT col AS value FROM table2)t1
ORDER BY value
try and post your comments:
Thanks
Related
I have multiple SELECT queries which is ran against different tables.
The output of all the queries have the same number of rows (every query when ran individually will have the same number of rows). Is there a way I can combine the output of all these queries into a single result? (Keep out from first query and add the output of next query as a column to the output of the next query). I dont want to save these tables into database as I am just doing some validation testing.
Example:
SELECT AAA,BBB,CCC FROM Table1
SELECT Table2.DDD, Table1.AAA
FROM Table2
INNER JOIN Table1
ON Table1.AAA = Table2.AAA
I tried writing combining the query as
SELECT Table1.AAA,Table1.BBB,Table1.CCC,T1.DDD
FROM Table1,
(SELECT Table2.DDD, Table1.AAA
FROM Table2
INNER JOIN Table1
ON Table1.AAA = Table2.AAA)T1
I tried doing the above combined query, but instead of getting 11 rows as output (both queries above had result of 11 rows), I am getting 35 rows as output.
Hope the question made sense!
You'll need to specify a criteria to match each row the first query with which row of the second query.
If, for example, the column AAA is unique in both queries and you want to match rows with the same values you could do:
select a.*, b.*
from (
SELECT AAA,BBB,CCC FROM Table1
) a
full join join (
SELECT Table2.DDD, Table1.AAA
FROM Table2
INNER JOIN Table1
ON Table1.AAA = Table2.AAA
) b on b.aaa = a.aaa
If there aren't any clear matching rules, you can produce an artificial row number on each result set and use it to match rows. For example:
select
a.aaa, a.bbb, a.ccc,
b.ddd, b.aaa
from (
SELECT AAA, BBB, CCC,
row_number() over(order by aaa) as rn
FROM Table1
) a
full join join (
SELECT Table2.DDD, Table1.AAA,
row_number() over(order by table1.aaa, table2.ddd) as rn
FROM Table2
INNER JOIN Table1
ON Table1.AAA = Table2.AAA
) b on b.rn = a.rn
If you have several results and want to have all of them as additional columns you can simply use ",":
create table temp1 as select '1' as c1 from DUAL;
create table temp2 as select '2' as c2 from DUAL;
create table temp3 as select '3' as c3 from DUAL;
select a.c1, b.c2, c.c3 from temp1 a, (select c2 from temp2) b, (select c3 from temp3) c;
An alternative could also be that you want to have all the results as additional rows then you would use UNION ALL between the individual results.
t2I'm trying to join 2 tables without using join keyword.Both tables have same kind of data but order is different. I want to display Rank,Airport info from both tables namely airports2017 and airports2010 when their ranks are different in 2 tables otherwise skip that row. How can i do this without using join keyword?
t1
I really am not certain if this is what you are looking for, but this will find an list the differences in two tables that have columns col_a and col_b:
WITH
aset AS
(SELECT col_a, col_b FROM table_a
MINUS
SELECT col_a, col_b FROM table_b),
bset AS
(SELECT col_a, col_b FROM table_b
MINUS
SELECT col_a, col_b FROM table_a)
SELECT 'A unique records' AS TYPE, a.*
FROM aset a
UNION ALL
SELECT 'B unique records' AS TYPE, a.*
FROM bset a
While I am not sure why you want to do this, this query will give you what you want:
select airport, max(rank2017) as Rank2017, max(Rank2018) as Rank2018 from
(
select airport, airportrank as rank2017, 0 as rank2018 from airport2017
union
select airport, 0 as rank2017, airportrank as rank2018 from airport2018
) tabs
group by airport
If you only want ones where the rank has changed, add at the bottom:
having max(rank2017)<>max(Rank2018)
this will work as you wanted withuot using join:
select a.rank,a.airport from t1 a, t2 b
where a.rank=b.rank
thank you.
I have four tables Table A, Table B, Table C and Table D. The schema of all four tables are identical. I need to union these four tables in the following way:
If a record is present in Table A then that is considered in the output table.
If a record is present in Table B then it is considered in the output table ONLY if it is not present in Table A.
If a record is present in Table C then it is considered ONLY if it is not present in Table A and Table B.
If a record is present in Table D then it is considered ONLY if it is not present in Table A, Table B, and Table C.
Note -
Every table has a column which identifies the table itself for every record (I don't know if this is of any importance)
Records are identified based on a particular column - Column X which is not unique even within each table
You could do something like (only two cases shown but you should see how to extend this)
WITH CTE1 AS
(
SELECT 't1' as Source, X, Y
FROM t1
UNION ALL
SELECT 't2' as Source, X, Y
FROM t2
), CTE2 AS
(
SELECT *,
RANK() OVER (PARTITION BY X
ORDER BY CASE Source
WHEN 't1' THEN 1
WHEN 't2' THEN 2
END) As RN
FROM CTE1
)
SELECT X,Y
FROM CTE2
WHERE RN=1
I would be inclined to do this using not exists:
select a.*
from a
union all
select b.*
from b
where not exists (select 1 from a where a.x = b.x)
union all
select c.*
from c
where not exists (select 1 from a where a.x = c.x) and
not exists (select 1 from b where b.x = c.x)
union all
select d.*
from d
where not exists (select 1 from a where a.x = d.x) and
not exists (select 1 from b where b.x = d.x) and
not exists (select 1 from c where c.x = d.x);
If you have an index on the x column in each table, then this should be the fastest method.
This will work as long as there are no NULL columns, or if columns for a record that exists in table with higher precedence are NULL you can assume the same column will NULL in tables with lower precedence.
SELECT coalesce(a.column1, b.column1, c.column1, d.column1) column1
,coalesce(a.column2, b.column2, c.column2, d.column2) column2
,coalesce(a.column3, b.column3, c.column3, d.column3) column3
--...
,coalesce(a.columnN, b.columnN, c.columnN, d.columnN) columnN
FROM TableA a
FULL JOIN TableB b on b.ColumnX = a.ColumnX
FULL JOIN TableC c on c.ColumnX = a.ColumnX or c.ColumnX = b.ColumnX
FULL JOIN TableD d on d.ColumnX = a.ColumnX or d.ColumnX = b.ColumnX or d.ColumnX = c.ColumnX
If the NULL values matter, you can switch to a more-complicated (and likely slower) CASE version:
CASE WHEN a.columnX IS NOT NULL THEN a.column1
WHEN b.columnX IS NOT NULL THEN b.column1
WHEN c.columnX IS NOT NULL THEN c.column1
WHEN d.columnX IS NOT NULL THEN d.column1 END column1
Of course, you can mix and match, so columns that are not nullable can use the former syntax, and columns where NULL values matter use the latter.
Hopefully the purpose of this is to fix the broken schema and put this data all in the same table, where it belongs.
This might seem stupid, but if, by any chance, you can leave out the table-identifying column and you also want to eliminate duplicate records (from within one table) too then the most straightforward answer would be
select <all columns without table identifier> from tableA
union
select <all columns without table identifier> from tableB
union
select <all columns without table identifier> from tableC
...
This is exactly, what union was designed to do: add rows only if they do not already exist before.
I am trying to do a multi query but I don't want to use sub queries i.e:
SELECT column1
FROM table1
WHERE
EXISTS (SELECT column1 FROM table2 WHERE table1.column1 = table2.column1);)
I thought of using a JOIN but so far my best result was this:
SELECT *
FROM table1
JOIN table2 ON table1.t1id = table2.t2id
WHERE table1.id = 5;
This would be good except of the fact that I get a duplicate column (the id in table 1 and 2 are foreign keys).
How do I remove the duplicate column if possible?
UPDATE:
Table1:
tableA_ID, TABLEB_ID
1, 1
1, 4
3, 2
4, 3
TableA: ID, COL1, COL2
1, A, B
2, A, B
3, A, B
4, A, B
TableB: ID, Col3, COL4
1, C, D
2, C, D
3, C, D
4, C, D
I want to get all or some of the columns from TableA according to a condition
Sample: Lets say the condition is that tableA_ID = 1 which will result in the 2 first rows in the table then I want to get all or some of the columns in TableA that respond to the ID that I got from Table1.
Sample: The result from before was [{1,1}{1,4}] which means I want from TableA the results:
TableA.ID, TableA.COL1, TableA.COL2
1,A,B
4,A,B
The actual results I get is:
Table1.tableA_ID, Table1.TABLEB_ID, TableA.ID, TableA.COL1, TableA.COL2
1,1,1,A,B
1,4,4,A,B
Is this what you're looking for?
select a.id, a.column1, b.column2
from table1 a
left join table2 b on a.id = b.otherid;
You can't change the column list of a query based on the values it returns. It just isn't the way that SQL is designed to operate. At best, you can return all of the columns from the second table and ignore the ones that aren't relevant based on other values in that row.
I'm not even sure how a variable column list would work. In your scenario, you're looking for two discrete values separately. But that's not the only scenario: what if the condition is tableA_ID in (1,2). Would you want different numbers of columns in different rows as part of a single result set?
Getting just the columns you want (just from specific tables, as you say) is the easy part (btw -- don't use '*' if you can help it -- topic for another discussion):
SELECT
A.ID,
A.COL1,
A.COL2
FROM
TABLE1 Bridge
LEFT JOIN TABLEA A
ON Bridge.TABLEA_ID = A.ID
LEFT JOIN TABLEB B
ON Bridge.TABLEB_ID = B.ID
Getting the rows you want will be the harder part (influenced by your choice of joins, among several other things).
I think you'll need to select only the fields of table A and use a distinct clause. Rest of your query will remain as it is. i.e.
SELECT distinct table1.*
FROM table1
JOIN table2 ON table1.t1id = table2.t2id
WHERE table1.id = 5;
If I run the two statements in batch will they return one table to two to my sqlcommand object with the data merged. What I am trying to do is optimize a search by searching twice, the first time on one set of data and then a second on another. They have the same fields and I’d like to have all the records from both tables show and be added to each other. I need this so that I can sort the data between both sets of data but short of writing a stored procedure I can’t think of a way of doing this.
Eg. Table 1 has columns A and B, Table 2 has these same columns but different data source. I then wan to merge them so that if a only exists in one column it is added to the result set and if both exist it eh tables the column B will be summed between the two.
Please note that this is not the same as a full outer join operation as that does not merge the data.
[EDIT]
Here's what the code looks like:
Select * From
(Select ID,COUNT(*) AS Count From [Table1]) as T1
full outer join
(Select ID,COUNT(*) AS Count From [Table2]) as T2
on t1.ID = T2.ID
Perhaps you're looking for UNION?
IE:
SELECT A, B FROM Table1
UNION
SELECT A, B FROM Table2
Possibly:
select table1.a, table1.b
from table1
where table1.a not in (select a from table2)
union all
select table1.a, table1.b+table2.b as b
from table1
inner join table2 on table1.a = table2.a
edit: perhaps you would benefit from unioning the tables before counting. e.g.
select id, count() as count from
(select id from table1
union all
select id from table2)
I'm not sure if I understand completely but you seem to be asking about a UNION
SELECT A,B
FROM tableX
UNION ALL
SELECT A,B
FROM tableY
To do it, you would go:
SELECT * INTO TABLE3 FROM TABLE1
UNION
SELECT * FROM TABLE2
Provided both tables have the same columns
I think what you are looking for is this, but I am not sure I am understanding your language correctly.
select id, sum(count) as count
from (
select id, count() as count
from table1
union all
select id, count() as count
from table2
) a
group by id