I would like to set up a schema which will store the current date as a string fitting in a varchar column of size 10. However CURDATE() returns as a date type, is there any way I can convert this when creating a table to automatically convert this to a string?
For reference I am using MonetDB and declaring the column like below, can I cast CURDATE somehow when creating a table?
tdate varchar(10) default CURDATE() ,
This works fine
create table dateexample
(
id int identity(1,1),
empname varchar(100),
dateinserted varchar(10) DEFAULT (CONVERT(VARCHAR(10),GETDATE(),101))
)
insert into dateexample (empname)
values
('johny')
select * from dateexample
-- 1 johny 04/24/2014
Related
how to create date format yyyy-mm with postgresql11
CREATE TABLE public."ASSOL"
(
id integer NOT NULL,
"ind" character(50) ,
"s_R" character(50) ,
"R" character(50) ,
"th" character(50),
"C_O" character(50) ,
"ASSOL" numeric(11,3),
date date,
CONSTRAINT "ASSOL_pkey" PRIMARY KEY (id)
This is a variation of Kaushik's answer.
You should just use the date data type. There is no need to create another type for this. However, I would implement this use a check constraint:
CREATE TABLE public.ASSOL (
id serial primary key,
ind varchar(50) ,
s_R varchar(50) ,
R varchar(50) ,
th varchar(50),
C_O varchar(50) ,
ASSOL numeric(11,3),
yyyymm date,
constraint chk_assol_date check (date = date_trunc('month', date))
);
This only allows you to insert values that are the first day of the month. Other inserts will fail.
Additional notes:
Don't use double quotes when creating tables. You then have to refer to the columns/tables using double quotes, which just clutters queries. Your identifiers should be case-insensitive.
An integer primary key would normally be a serial column.
NOT NULL is redundant for a PRIMARY KEY column.
Use reasonable names for columns. If you want a column to represent a month, then yyyymm is more informative than date.
Postgres stores varchar() and char() in the same way, but for most databases, varchar() is preferred because trailing spaces actually occupy bytes on the data pages.
for year and month you can try like below
SELECT to_char(now(),'YYYY-MM') as year_month
year_month
2019-05
You cannot create a date datatype that stores only the year and month component. There's no such option available at the data type level.
If you want to to truncate the day component to default it to start of month, you may do it. This is as good as having only the month and year component as all the dates will have day = 1 and only the month and year would change as per the time of running insert.
For Eg:
create table t ( id int, col1 text,
"date" date default date_trunc('month',current_date) );
insert into t(id,col1) values ( 1, 'TEXT1');
select * from t
d col1 date
1 TEXT1 2019-05-01
If you do not want to store a default date, simply use the date_trunc('month,date) expression wherever needed, it could either be in group by or in a select query.
I am trying to generate a sequence varchar text type, but I do not want to have to create another column to get the id to format it and insert it I want to generate it in the same column, help
create table tbl (
Id int identity not null,
CusId as 'CUS' + format(Id, '00000'),
-- ...
)
You can use sequence object that appeared in SQL Server 2012 + default value like this:
create sequence dbo.ids as int
minvalue 1;
create table dbo.tbl (
CusId varchar(100) default 'CUS' + format(NEXT VALUE FOR dbo.ids, '00000'));
insert into dbo.tbl (CusId) default values;
insert into dbo.tbl (CusId) default values;
insert into dbo.tbl (CusId) default values;
select *
from dbo.tbl;
-----
--CusId
--CUS00001
--CUS00002
--CUS00003
Believe the only viable solution is using 2 columns as you mentioned, and discussed here:
Autoincrement of primary key column with varchar datatype in it
Have not seen it achieved in a single column on its own.
I want to save the date in format 'dd.mm.yyyy'. So I read there are different formats for a date in SQL (by the way I use Visual Studio and SQL Server).
I tried this code:
CREATE TABLE APP(
ID INT NOT NULL,
DT DATE FORMAT 'dd.mm.yyyy',
ADDRESS NVARCHAR (100) ,
PRIMARY KEY (ID)
);
But it returns the error:
Incorrect syntax near 'FORMAT'.
After that I want to use this code:
INSERT INTO APP (ID, DT)
VALUES ('1','22.12.2016')
You don't need to specify the format in the table definition as dates are stored in a binary format.
CREATE TABLE APP(
ID INT NOT NULL,
DT DATE,
ADDRESS NVARCHAR (100) ,
PRIMARY KEY (ID)
);
When you try to insert into that table however, the server will try to convert the string to a date before inserting it. This can be problematic as it is unable to tell if 12.11.2017 is the 12th of November or 11th of December. To figure this out it uses the localization settings of the user account that is performing the operation.
Often you will find that the account that is running the operation is set to USA format, month day then year (MDY), when what you want is day month year (DMY) format. One way to tell it what the sequence of the date's parts is to use the DATEFORMAT setting like this:
SET DATEFORMAT dmy;
INSERT INTO APP (ID, DT)
VALUES (1,'22.12.2016')
Another alternative is to cast the string to a date using the CONVERT function and tell it what the date format is. The formats have numeric codes like 104 for German format Like this:
INSERT INTO APP (ID, DT)
VALUES (2,CONVERT(date,'22.12.2016',104))
Dates are stored in an internal format. Formats only make sense for input and output.
In your case you want the date in a German format (104), so you can use:
select convert(varchar(255), dt, 104)
If you like, you can include the formatted date as a separate column:
CREATE TABLE APP (
ID INT NOT NULL,
DT DATE,
ADDRESS NVARCHAR(100),
DT_FORMATTED AS (convert(varchar(255), dt, 104)),
PRIMARY KEY (ID)
);
You can then refer to dt_formatted to get the string in the format you want.
Use this:
CREATE TABLE APP(
ID INT NOT NULL,
DT DATE ,
ADDRESS NVARCHAR (100) ,
PRIMARY KEY (ID)
);
Its default setting is yyyy-MM-dd.
No, it's not. There is no formatting information at all associated with the field.
The value is not formatted by the database. It's returned only as a point in time. Formatting that value into its textual representation is done by the application that is getting the data from the database.
So, there is nothing that you can do in the database to change how the date value is formatted. You have to change that where the data is displayed.
Dates are stored in an internal format.
Formats only make sense for input and output.
You can include the formatted date as a separate column:
SQL Server supports the date format. You have to use the below date format.
With century (yyyy) | Standard | Input/Output
103 | British/French | 103 = dd/mm/yyyy
CREATE TABLE [dbo].[Post]
(
[Id] INT IDENTITY (1, 1) NOT NULL,
[Name] VARCHAR(MAX) NULL,
[RowNo] INT NULL,
[ColNo] INT NULL,
[Deadline] (CONVERT(VARCHAR(255), dt, 103)), -- Include the formatted date as a separate column
CONSTRAINT [PK_KtoCo]
PRIMARY KEY CLUSTERED ([Id] ASC)
);
Use this.
CREATE TABLE:
CREATE TABLE EMP
(EID NUMBER(20),
ENAME VARCHAR2(20),
DT DATE,
SAL NUMBER(20));
INSERT INTO THE TABLE:
INSERT INTO EMP (EID,ENAME,DT,SAL) VALUES(01,'ABCDE','11.NOV.2011',10000);
O/P OF ABOVE TABLE:
SELECT * FROM EMP;
EID ENAME DT SAL
01 ABCDE 11-DEC-11 10000
I have create a table with
create table tblConsultationHour
(
consultationID int primary key identity,
cday varchar(50),
cstartTime datetime,
cendTime datetime
)
I want to insert value of the day name into cday, and i should know the day name from the cstarttime of date part. what i know on how to get the day name with this code
SELECT DATENAME(dw,'2011-10-26 12:35:29.123')
may i know how can i insert this on the fly ?
or is that possible to insert in this way ?
insert into tblConsultationHour values
(SELECT DATENAME(dw,'2011-10-26 12:35:29.123'),'2011-10-26 12:35', '2011-10-26 14:35')
You were close:
INSERT INTO tblConsultationHour
SELECT DATENAME(dw,'2011-10-26 12:35:29.123'),'2011-10-26 12:35', '2011-10-26 14:35'
Also check out this question for other examples: SQL INSERT from SELECT
Another approach to consider is a computed column:
create table tblConsultationHour
(
consultationID int primary key identity,
cday as DateName(dw,cStarttime),
cstartTime datetime,
cendTime datetime
)
In your example, cDay is a redundant column. As written, if someone changes the cStarttime value, they must also remember to update the cDay field. While it might not occur or be an issue, it is something to keep in mind...
I have a temp table that needs the values of a Stored procedure. So the SP inserts 3 columns into the temp table, then I want to add a datetime to every row without modifying the SP.
Since I call the SP 3 times, each time with a different datetime, I can't just update the whole temp table.
Any Suggestions?
DECLARE #temp TABLE
(
id INT IDENTITY(1,1),
Name VARCHAR(150),
Address VARCHAR(25),
Date DATETIME
)
WHILE (#count>=#daysBack)
BEGIN
SET #date=DATEADD(dd, #count, GETDATE())
INSERT INTO #temp (Name,Address)
EXEC[dbo].StoredProc#date
--I Want to check for Null and insert the date there
Update #temp SET Date=#date WHERE Date=''
SET #count=#count-1
Yes. Create the temp table and in the added date column that does not have representation from your sproc put a default value constraint of getdate() or whatever date formula you need. In the insert statement specify the columns explicitly and omit the date column and it should work. As the rows are added the default value constraint will kick in and fill that column for you.
example:
create table #tmp (c1 int, c2 int, dt datetime default(getdate()) )
insert into #tmp
(c1, c2)
exec mysproc