CREATE TABLE detectives(
id INTEGER NOT NULL AUTO_INCREMENT,
first_name VARCHAR(50),
last_name VARCHAR(50) NOT NULL,
phone_number VARCHAR(10) NOT NULL,
certification_date DATE NOT NULL,
CONSTRAINT detectives_pk PRIMARY KEY (id
);
It says: Incorrect syntax near 'AUTO_INCREMENT'.
Any help with this?
Missing closing ) and using incorrect syntax for an IDENTITY field.
CREATE TABLE detectives(
id INT IDENTITY,
first_name VARCHAR(50),
last_name VARCHAR(50) NOT NULL,
phone_number VARCHAR(10) NOT NULL,
certification_date DATE NOT NULL,
CONSTRAINT detectives_pk PRIMARY KEY (id)
)
Change
id INTEGER NOT NULL AUTO_INCREMENT,
To
ID INT NOT NULL IDENTITY(1,1),
you've to make the column identity if you want auto increment. your code will be
CREATE TABLE detectives(
id INT NOT NULL IDENTITY (1, 1),
first_name VARCHAR(50),
last_name VARCHAR(50) NOT NULL,
phone_number VARCHAR(10) NOT NULL,
certification_date DATE NOT NULL,
CONSTRAINT detectives_pk PRIMARY KEY (id)
);
Related
New to SQL, can't figure out what is wrong in my given code. all it says is:
Incorrect syntax near 'DESCRIBE'. [41,1]
I have tried taking off the semi-colons. I really just don't know what it wants from me.
Here is my code. Anything helps, thank you!
-- Write the query to create the 4 tables below.
CREATE TABLE client (
id INT NOT NULL IDENTITY(1,1),
first_name VARCHAR(255) NOT NULL,
last_name VARCHAR(255) NOT NULL,
dob DATE NOT NULL,
PRIMARY KEY (id),
CONSTRAINT (full_name) UNIQUE (first_name, last_name)
);
CREATE TABLE employee (
id INT NOT NULL IDENTITY(1,1),
first_name VARCHAR(255) NOT NULL,
last_name VARCHAR(255) NOT NULL,
dob DATE NOT NULL,
date_joined DATE NOT NULL,
CONSTRAINT (full_name) UNIQUE (first_name, last_name),
PRIMARY KEY (id)
);
CREATE TABLE project (
id INT NOT NULL IDENTITY(1,1),
cid INT NOT NULL,
name VARCHAR(255) NOT NULL,
notes TEXT,
UNIQUE (name),
FOREIGN KEY (cid) REFERENCES client(id)
);
CREATE TABLE works_on (
eid INT NOT NULL,
pid INT NOT NULL,
start_date DATE NOT NULL,
PRIMARY KEY (eid, pid),
FOREIGN KEY (eid) REFERENCES employee(id),
FOREIGN KEY (pid) REFERENCES project(id)
);
-- Leave the queries below untouched. These are to test your submission correctly.
-- Test that the tables were created
DESCRIBE client;
DESCRIBE employee;
DESCRIBE project;
DESCRIBE works_on;
-- Test that the correct foreign keys were created
SELECT TABLE_NAME,COLUMN_NAME,CONSTRAINT_NAME,REFERENCED_TABLE_NAME,REFERENCED_COLUMN_NAME
FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE
WHERE REFERENCED_TABLE_SCHEMA = 'grade';
For MariaDB (and MySQL) the correct syntax for IDENTITY(1,1), is AUTO_INCREMENT, and CONSTRAINT names are not enclosed in (). Any column that is defined as AUTO_INCREMENT must also be declared as a PRIMARY KEY (this is only an issue with the project table). So your CREATE TABLE commands should look like this:
CREATE TABLE client (
id INT NOT NULL AUTO_INCREMENT,
first_name VARCHAR(255) NOT NULL,
last_name VARCHAR(255) NOT NULL,
dob DATE NOT NULL,
PRIMARY KEY (id),
CONSTRAINT full_name UNIQUE (first_name, last_name)
);
CREATE TABLE employee (
id INT NOT NULL AUTO_INCREMENT,
first_name VARCHAR(255) NOT NULL,
last_name VARCHAR(255) NOT NULL,
dob DATE NOT NULL,
date_joined DATE NOT NULL,
CONSTRAINT full_name UNIQUE (first_name, last_name),
PRIMARY KEY (id)
);
CREATE TABLE project (
id INT NOT NULL AUTO_INCREMENT,
cid INT NOT NULL,
name VARCHAR(255) NOT NULL,
notes TEXT,
PRIMARY KEY (id),
UNIQUE (name),
FOREIGN KEY (cid) REFERENCES client(id)
);
CREATE TABLE works_on (
eid INT NOT NULL,
pid INT NOT NULL,
start_date DATE NOT NULL,
PRIMARY KEY (eid, pid),
FOREIGN KEY (eid) REFERENCES employee(id),
FOREIGN KEY (pid) REFERENCES project(id)
);
Demo on dbfiddle
2 errors were found during analysis.
Unexpected beginning of statement. (near "admin_id" at position 349)
Unrecognized statement type. (near "INT" at position 358)
CREATE TABLE Users (
user_id INT NOT NULL AUTO_INCREMENT,
email VARCHAR(80) NOT NULL,
password CHAR(41) NOT NULL,
name VARCHAR(50) NOT NULL,
phone VARCHAR(20) NOT NULL,
gender VARCHAR(6) NOT NULL,
fbinfo VARCHAR(50) NOT NULL,
age INT NOT NULL,
PRIMARY KEY (user_id),
UNIQUE INDEX (email)
)
CREATE TABLE Admin (
admin_id INT NOT NULL AUTO_INCREMENT,
email VARCHAR(80) NOT NULL,
password CHAR(41) NOT NULL,
PRIMARY KEY (admin_id),
UNIQUE INDEX (email)
)
CREATE TABLE Task (
task_id INT NOT NULL AUTO_INCREMENT,
tex VARCHAR(140) NOT NULL,
datetime DATE,
status INT,
calendar BOOLEAN,
PRIMARY KEY (task_id),
lat DECIMAL(9,6),
long DECIMAL(9,6)
)
If you are doing this in one execution, you would need to include a ; at the end of each of your table creation statements.
CREATE TABLE Users (
user_id INT NOT NULL AUTO_INCREMENT,
email VARCHAR(80) NOT NULL,
password CHAR(41) NOT NULL,
name VARCHAR(50) NOT NULL,
phone VARCHAR(20) NOT NULL,
gender VARCHAR(6) NOT NULL,
fbinfo VARCHAR(50) NOT NULL,
age INT NOT NULL,
PRIMARY KEY (user_id),
UNIQUE INDEX (email)
);
CREATE TABLE Admin (
admin_id INT NOT NULL AUTO_INCREMENT,
email VARCHAR(80) NOT NULL,
password CHAR(41) NOT NULL,
PRIMARY KEY (admin_id),
UNIQUE INDEX (email)
);
CREATE TABLE Task (
task_id INT NOT NULL AUTO_INCREMENT,
tex VARCHAR(140) NOT NULL,
datetime DATE,
status INT,
calendar BOOLEAN,
PRIMARY KEY (task_id),
lat DECIMAL(9,6),
long DECIMAL(9,6)
);
I have the following problem: when we run the code, it displays the following error:
There are primary keys or candidates in the reference Ticket table
that match the list of referencing columns in foreign key '
FK__Payment__PkTicke__1A14E395
Code:
create table SystemUser
(
PkUser int identity(1,1),
UserLogin nvarchar(20) not null unique,
UserPassword nvarchar(50) not null,
UserName nvarchar(50) not null,
UserCpf nvarchar(50) not null,
UserBirth datetime not null,
UserGender nvarchar(15) not null,
AddressCep int not null,
AddressStreet nvarchar(50) not null,
AddressNumber nvarchar(20) not null,
AddressComplement nvarchar(50) not null,
AddressCity nvarchar(50) not null,
AddressState nvarchar(50) not null,
primary key(PkUser)
)
create table Attractions
(
PkAttraction integer identity(1,1) ,
AttractionName nvarchar(50) not null unique,
AttractionDate datetime not null,
AttractionDescription nvarchar(150) not null
primary key(PkAttraction)
)
create table Ticket
(
PkTicket int identity(1,1),
PkUser int not null,
PkAttraction int not null,
TicketPrice decimal not null,
primary key(PkTicket, PkUser, PkAttraction),
foreign key(PkUser) references SystemUser(PkUser),
foreign key(PkAttraction) references Attractions(PkAttraction)
)
create table Payment
(
PkPayment int identity(1,1),
PkTicket int not null,
Portion int not null,
IdTransaction nvarchar(100) not null,
Payday datetime not null,
primary key(PkPayment, PkTicket),
foreign key(PkTicket) references Ticket(PkTicket),
)
create table FormPayment
(
PkFromPayment int identity(1,1),
PkPayment int not null,
ShareValue decimal not null,
ExpirationDate datetime not null
primary key(PkFromPayment, PkPayment),
foreign key(PkPayment) references Payment(PkPayment),
)
Your Ticket table as a primary key made up from 3 columns:
create table Ticket
(
.....
primary key(PkTicket, PkUser, PkAttraction),
....
)
Any table that wants to reference that table Ticket must also provide all 3 columns for the foreign key.
You cannot reference only part of a primary key - if you want to reference it, you must have all columns that it contains - otherwise you cannot establish a FK relationship.
So you must add the PkUser and PkAttraction columns to your Payment table so that you can establish this FK relationship:
create table Payment
(
PkPayment int identity(1,1),
PkTicket int not null,
PkUser int not null, // add this
PkAttraction int not null, // add this
Portion int not null,
IdTransaction nvarchar(100) not null,
Payday datetime not null,
primary key(PkPayment, PkTicket),
// change to this
foreign key(PkTicket, PkUser, PkAttraction) references Ticket(PkTicket, PkUser, PkAttraction)
.....
)
When you not specify a name for FK and PK, SQL server generates a name. in this case, looks like SQL server generates duplicate name.
If you specify name for FK and PK, it will work.
Hey everyone I need some help with creating tables. I have the script below and it creates a few tables. When i try to run the script it give me this error:
psql:script.sql:10: ERROR: syntax error at or near "Group"
LINE 6: CREATE TABLE Group(
Can anyone tell me what is going on?
CREATE TABLE Group(
name varchar(40) PRIMARY KEY NOT NULL
);
CREATE TABLE Artist(
name varchar(30) PRIMARY KEY NOT NULL,
birthplace varchar(20) NOT NULL,
age int NOT NULL CHECK (age > 0),
style varchar(20) NOT NULL
);
CREATE TABLE Artwork(
title varchar(40) PRIMARY KEY NOT NULL,
artist varchar(30) NOT NULL references Artist(name),
group_name varchar(40) NOT NULL references Group(name),
year int NOT NULL CHECK (year > 0),
type varchar(30) NOT NULL,
price money NOT NULL,
);
CREATE TABLE Customer(
cust_id int PRIMARY KEY NOT NULL,
name varchar(40) NOT NULL,
address varcahr(60) NOT NULL,
amount money NOT NULL CHECK(amount > 0),
like_artist varchar(30) NOT NULL references Artist(name),
like_group varchar(40) NOT NULL references Group(name)
);
it had a lot of problems
this worked for me. In postgres, names that are not all lowercase need to be double quoted. also some of your table names are reserved words, money can't be > and int, and there was a comma out of place.
CREATE TABLE "group"( name varchar(40) PRIMARY KEY NOT NULL );
CREATE TABLE artist( name varchar(30) PRIMARY KEY NOT NULL, birthplace varchar(20) NOT NULL, age int NOT NULL CHECK (age > 0), style varchar(20) NOT NULL );
CREATE TABLE artwork( title varchar(40) PRIMARY KEY NOT NULL, artist varchar(30) NOT NULL references artist(name),
group_name varchar(40) NOT NULL references "group"(name), year int NOT NULL CHECK (year > 0), type varchar(30) NOT NULL, price money NOT NULL );
CREATE TABLE customer( cust_id int PRIMARY KEY NOT NULL, name varchar(40) NOT NULL, address varchar(60) NOT NULL,
amount money NOT NULL CHECK(amount > cast(0.0 as money)), like_artist varchar(30) NOT NULL references artist(name), like_group varchar(40) NOT NULL references "group"(name) );
I've spent a while trying to firgure it but but I can't see anything that would be causing this error. I'm thinking maybe something to do with the "Unique" statement.
Msg 1767, Level 16, State 0, Line 40
Foreign key 'FK_Loan_ItemNo__0AD2A005' references invalid table
'Item'.
Here's the code if someone wants to use it to replicate problem:
CREATE DATABASE LibrarySystem10
GO
USE LibrarySystem10
GO
CREATE TABLE MemberType(
MemberTypeNo int NOT NULL,
Name varchar(50) NOT NULL,
Description varchar(250) NOT NULL,
MaxNumberLoans int NOT NULL,
MaxLoanDuration int NOT NULL
PRIMARY KEY (MemberTypeNo)
)
insert into MemberType values ('0','UnderGraduate','A student at a college or university who has not yet earned a bachelor''s or equivalent degree.','5','10')
insert into MemberType values ('1','PostGraduate','A student undertaking study after completing a first degree.','10','10')
insert into MemberType values ('2','Staff','Staff at the university','15','15')
CREATE TABLE Member(
MemberNo int NOT NULL,
MemberTypeNo int NOT NULL,
FirstName varchar(150) NOT NULL,
LastName varchar(150) NULL,
DateOfBirth varchar (200) NULL,
HouseNo int NOT NULL,
Street varchar(50) NOT NULL,
Suburb varchar(100) NOT NULL,
PostCode int NOT NULL,
EmailAddress varchar(250) NULL,
HomePhoneNo varchar(250) NULL,
MobileNo varchar(250) NULL,
MembershipStartDate varchar (200) NOT NULL,
MembershipEndDate varchar (200) NOT NULL,
MembershipStatus varchar(100) NOT NULL,
PinNo int NOT NULL
PRIMARY KEY (MemberNo)
FOREIGN KEY (MemberTypeNo)REFERENCES MemberType ON UPDATE CASCADE
)
insert into member values ('0','0','Shane','Lindsay','15-11-1992','90','fake st','FauxTon','2250','shane#hotmai.com','0243296356','0415657164','15-11-2010','15-11-2020','current','0105')
insert into member values ('1','0','Shaune','Lincoln','18-12-1992','92','faken st','FauxTone','2350','shaune27#hotmai.com','0243253357','041565757','14-12-2010','14-12-2020','deferred','0123')
insert into member values ('2','0','Sarah','richards','08-08-1990','45','Small st','Hornsby','2279','Sarah67#hotmai.com','02432567154','0416451845','01-01-2012','01-01-2022','current','0123')
CREATE TABLE Loan(
MemberNo int NOT NULL FOREIGN KEY(MemberNo) REFERENCES Member ON UPDATE CASCADE,
ItemNo int NOT NULL FOREIGN KEY(ItemNo) REFERENCES Item ON UPDATE CASCADE,
DateLoaned varchar (50) NOT NULL,
DueDate varchar (50) NOT NULL,
Status varchar(50) NOT NULL,
FinesImposed bit NOT NULL DEFAULT '0' CHECK (finesImposed IN ('0','1')) ,
Renewed bit NOT NULL DEFAULT '0' CHECK (Renewed IN ('0','1')),
UNIQUE(MemberNo,ItemNo,DateLoaned)
)
insert into Loan values ('0','0','10-10-2012','15-10-2012','loaned','0','0')
insert into Loan values ('1','0','12-10-2012','15-10-2012','loaned','0','1')
CREATE TABLE Item(
ItemNo int NOT NULL,
Title varchar(50) NOT NULL,
Subject varchar(100) NULL,
ISBN int NULL,
PhysicalDescription varchar(150) NULL,
Author varchar(75) NULL,
PRIMARY KEY (ItemNo)
)
insert into Item values ('0','Book1','IT','0501425252','Big,42pages','John Doe')
insert into Item values ('1','Book2','IT','0501425253','Big,42pages','John Doe')
CREATE TABLE ItemCopy(
ItemNo int NOT NULL,
CallNumber varchar(50) NOT NULL,
Condition varchar(50) NULL,
UNIQUE(ItemNo,CallNumber),
PRIMARY KEY (CallNumber)
)
insert into ItemCopy values ('0','0','good')
CREATE TABLE Hold(
HoldNo int NOT NULL,
MemberNo int NOT NULL FOREIGN KEY(MemberNo) REFERENCES Member ON UPDATE CASCADE,
ItemNo int NOT NULL FOREIGN KEY(ItemNo) REFERENCES Item ON UPDATE CASCADE,
DateTimeHeld datetime NOT NULL,
comments varchar(200) NULL,
Status varchar(50) NOT NULL
PRIMARY KEY (HoldNo)
)
CREATE TABLE Fine(
FineNo int NOT NULL,
MemberNo int NOT NULL FOREIGN KEY(MemberNo) REFERENCES Member ON UPDATE CASCADE,
Description varchar(50) NULL,
Amount int NOT NULL,
PRIMARY KEY (FineNo)
)
CREATE TABLE AudioRecording(
Length varchar(50) NULL,
BitRate varchar(50) NULL,
Size varchar(50) NULL
)
CREATE TABLE ItemCollection(
ItemNo int NULL,
CollectionName varchar(75) NULL
UNIQUE (ItemNo,CollectionName)
)
CREATE TABLE Collection(
CollectionName varchar(75)NOT NULL
PRIMARY KEY (CollectionName)
)
CREATE TABLE Book(
PublisherInfo varchar(150) NULL,
Edition int NULL,
Notes varchar(250) NULL,
Status varchar(50) NULL
)
CREATE TABLE Journal(
Series int NULL,
Notes varchar(250) NULL,
OtherTitles varchar(150) NULL,
PriorTitles varchar(250) NULL
)
SELECT m.FirstName, l.Status, l.DueDate
FROM Member m, Loan l
WHERE m.MemberNo = '0' AND l.MemberNo = m.MemberNo
Loan references Item, but you create Loan before you create Item. Create the Item table first.