Records between start and end date - sql

I am having two textfields which represents startDate and endDate.Now the problem I am facing is that I want all the records from the database which occured between this interval.But the field which stores date is TimeStamp and is of format :
24-APR-14 09.23.44.458000 PM or we can say dd-mm-yy hh.min.ss.milli AM/PM
Now obviously user entering the date is not going to enter it in such a format.So what should be query to select records from table say t1 between this date interval.

Saving Date data as Date or Datetime makes life easy.
You have tagged Mysql in the question so here is a Mysql Solution.
This is what you can do
select * from
test
where
date_format(str_to_date(`date`,'%d-%b-%y'),'%Y-%m-%d')
between '2014-04-15' AND '2014-04-24'
DEMO
You can format the user input as you want in the query in DATE_FORMAT().

User input will have a startdate and a enddate may be in datetime OR date variable
while trying to use these two input variables in the WHERE CLAUSE use BETWEEN CAST(#StartDate AS DATE) AND (CAST(#EndDate AS DATE) + 1)
This will fetch results that lies in both dates and the data range as well

Related

count records in specific date format with SQL

i'm trying to define a rule that count rows where date format is dd/mm/yyyy and greater than a specific date in sql but i couldn't find the right function to use.
The second part is working : SELECT COUNT (*) FROM CUSTOMER WHERE DAT_0 >= '01/01/1995' but how could i specify the format too
In Standard SQL, the WHERE clause would look like:
WHERE DAT_0 >= DATE '1995-01-01'
Many databases would simply accept this without the DATE as well:
WHERE DAT_0 >= '1995-01-01'
In your comment DATE_0 is a date column
Therefore we can change it to any format as below using to_char then to_date
to_date(to_char(DATE_0,'yyyymmdd'),'yyyy-mm-dd')
When comparing you can try this, converting the date to_number, i find it very easy
to_number(to_char(DATE_0,'yyyymmdd')) > 19950101
if datatype of "DAT_0" is date or datetime or timestamp , they are recorded as a specific format specified by default datetime setting in your database engine , therefore you can't have multiple format inside the column , so there is no concern there

Parse Time out of A DateTime Field in Access 2016

I need to check the records of an Access Database that has a SigninTime field of data type DATETIME for any sign in that occurred between 6PM and 8PM.
I've tried:
SELECT TestingStatistics.SigninTime
FROM TestingStatistics
WHERE datepart(h,TestingStatistics.SigninTime) >=18;
Which asks me to define H
And
SELECT TestingStatistics.SigninTime
FROM TestingStatistics
WHERE TestingStatistics.SigninTime >=18;
Which just returns everything.
How do you search a DATETIME Field using Time instead of a date? Furthermore what query should I run?
Try making it a string:
datepart("h", TestingStatistics.SigninTime) >= 18;
You can extract JUST the date part of a date/time column with:
DateValue( some date time)
And you can extract JUST the time part of a date/time column with:
TimeValue( some date time)
So, this query would work.
Select SignInTime from TestingStatistics
Where TimeValue(SignInTime) between #6 pm# and #8 pm#
You can try something like this:
Where TestingStatistics.SigninTime> Convert(datetime,(Replace(Convert(varchar,GETDATE(),104),'.','-')+ ' 18:00:00.000'),104) and TestingStatistics.SigninTime <= Convert(datetime,(Replace(Convert(varchar,GETDATE(),104),'.','-')+ ' 20:00:00.000'),104))
This should show you all the record of today between 18PM-20PM, but You can replace Getdate() for any date that you need.
Hope this help!

Convert Data from yyyy-dd-mm to mm/dd/yyyy Issue

I have a column in my table with Dates in the format yyyy-mm-dd I want to convert all the dates in that column to the format mm/dd/yyyy
I am using the below query
UPDATE Test.dbo.Status
SET DateIn = CONVERT(DATE,DateIn ,101)
The DateIn column is defined as Date in my table (DateIn DATE NULL)
The query does no change to the data. am I doing some thing wrong here?
You can change the default format in which SQL Server displays a date, but you can't alter the way a DATE value is stored via CONVERT(). You can format a date however you want if you store it as a string, but you lose functionality when you do that and it's not advisable. If you are hell-bent on storing a formatted version, you might want to create a new VARCHAR() field so you can preserve your DATE version.
You're better off formatting the date at the application level.
The reason your query does nothing is that the actual DATE values are equivalent. Notice when you take any valid date format and CAST() it as DATE the resulting format is the same regardless of the input:
SELECT CAST('20040510' AS DATE)
SELECT CAST('2004-05-10' AS DATE)
SELECT CAST('May 10, 2004' AS DATE)
All return: 2004-05-10 on my instance of SQL Server.

Validating date has expired with current system date

I am trying to compare the database stored date value with the current system date. The date format is (YYYY-MM-DD). and the sql date i written compare is as follows.
select id from table1 where tabel1.date > current_date
And i want to get result if the date has been expired or not.
Please find me the correct sql.
Thanks in advance
Well, when tabel1.date > current_date the date stored in your database is in the future.
Try
select id from table1 where tabel1.date < CURDATE();

Between operation for date in SQLite database

I have a table student with the following columns:
no - integer
name - string
startdate - date
enddate - date.
Date format is MM/DD/YYYY.
I will give a date as input. Now I need a query the inputdate which found in between the start and end date.
For an example I will give 04/14/2012, then the query should return the 1st record as in the figure.
(because input date (04/14/2012) is found in between the 04/10/2012 to 04/20/2012)
Please help me.
The issue you are having is caused by your assumption that sqlite has a date/datetime type when in fact it doesn't.
I suggest you read the following http://www.sqlite.org/datatype3.html to have a better understanding of sqlite types.
The dates in the MM/DD/YYYY format are handled as TEXT by sqlite, and so those dates are compared as strings. For example, 02/01/2012 is considered bigger than 01/02/2012by sqlite if compared directly.
You will need to transform those dates to a format that can be string-compared. Here is an example:
sqlite> create table foo (d TEXT);
sqlite> insert into foo values ('02/01/2012');
sqlite> select substr(d, 7, 4) || substr(d, 1, 2) || substr(d, 4, 2) from foo;
20120201
You should post what you have tried so far.
There should be a between clause that you can use:
select * from table
where inputdate between startdate and enddate
Dates as a date type in SQLite don't exist. There are a number of approaches to dealing with dates - store them as integer seconds since 1 Jan 1970 (unixepoch) or store them as strings, but if you do, then you really need to store them in 'YYYY-MM-DD' format because that is what the date functions require as input.
Assuming you use the string format in the format I suggested then your query would look something like
SELECT * FROM Table WHERE Date(Inputdate) BETWEEEN Date(startDate) AND Date(EndDate);
(although you may want to format the output of the date columns to US date format with
SELECT Strftime("%m/%d/%Y",startDate) As StartDate ...
If you use seconds since 1970 its somewhat easier because the seconds just compare without needing the convert them to dates, although you still might want to output in US date format, so ...
SELECT Strftime("%m/%d/%Y",startDate) As StartDate ... FROM Table WHERE inputDate BETWEEN startDate and EndDate;
sqlite> select *from tbl_node where mydate between '2014-02-02' and '2014-02-06';
it show the output :-
1|1|123|456|12eb-ab|1|1|254|123|19|2014-02-03 16:00:44
2|1|123|456|12eb-ab|1|1|254|123|19|2014-02-03 16:01:03
3|1|123|456|12eb-ab|1|1|254|123|19|2014-02-03 16:00:57
4|1|123|456|12eb-ab|1|1|254|123|19|2014-02-03 16:00:34
Here mydate is column name in tbl_node;
we can also use from current time , using now.
sqlite> select *from tbl_node where mydate between '2014-02-02' and 'now';