I am looking to use Teradata to group volume hourly over a date range when 'time' is a timestamp(6)
SELECT VOLUME, HOUR(time)
FROM table
GROUP BY HOUR(time)
There's no HOUR function in Teradata, according to Standard SQL it's EXTRACT:
EXTRACT(HOUR FROM timestampcol)
And of course you need a aggregate function, but i assume VOLUME will be the alias for a SUM/AVG/COUNT :-)
Related
I am trying to get data from a Bigquery table. In where clause i want to get the data on the basis of year like 2020. I am using EXTRACT(part FROM timestamp_expression [AT TIME ZONE timezone])
Query Looks like
with input as (Select created_at as timestamp_value,user_id from `seraphic-spider-311810.Demo.table2`)
SELECT
EXTRACT(Year FROM timestamp_value AT TIME ZONE "UTC") as year_value
FROM Input
where year_value like '2020%';
use WHERE EXTRACT(YEAR FROM timestamp_value) = 2020
I am using sql to calculate the average daily temperature and max daily temperature based on a date timestamp in an existing database. Is there a quick way to accomplish this?
I am using dBeaver to do all my data calculations and the following code is what I have used so far:
SELECT
convert(varchar, OBS_TIME_LOCAL , 100) AS datepart,
convert(varchar, OBS_TIME_LOCAL, 108) AS timepart,
CAST (datepart AS date) date_local,
CAST (timepart AS time) time_local
FROM
APP_RSERVERLOAD.ONC_TMS_CUR_ONCOR_WEATHER;
The data format as follows:
ID time_stamp temp
--------------------------------------------
de2145 2018-07-16 16:55 103
There are multiple IDs with 24hrs of temperature data at 1 min increments.
I am not sure if I understand what you need but I will try:
Your question: "Is there a quick way to separate date and time from a time stamp in sql?"
Answer:
select to_char(datec, 'hh24:mi')
, to_char(datec, 'yyyy-mm-dd')
from test;
Use to_char with format to select date part and time part.
You seem to want aggregation:
SELECT convert(date, OBS_TIME_LOCAL) AS datepart,
avg(temp), max(temp)
FROM APP_RSERVERLOAD.ONC_TMS_CUR_ONCOR_WEATHER
GROUP BY convert(date, OBS_TIME_LOCAL);
I have a table in BigQuery having a column Published_date with a datatype of "Timestamp". I want to calculate avg no of rows added per day (for a specific month) in that table. I have the following query
SELECT AVG(Num_Rows)
FROM (SELECT [Day]=DAY( Published_Date ), Num_Rows=COUNT(*)
FROM `mytable`
WHERE Published_Date BETWEEN '20190729' AND '20190729 '
GROUP BY DAY( Published_Date ) ) AS Z
But its generating the following error
Could not cast literal "20190729" to type TIMESTAMP
How should I deal with timestamp because I only need the date from timestamp column?
I want to calculate avg no of rows added per day (for a specific month) in that table
Below example for BigQuery Standard SQL
#standardSQL
SELECT AVG(Num_Rows) AS avg_rows_per_day
FROM (
SELECT DATE(Published_Date) AS day, COUNT(*) AS Num_Rows
FROM `project.dataset.mytable`
WHERE DATE(Published_Date) BETWEEN '2019-07-01' AND '2019-07-31'
GROUP BY day
)
Use explicit conversion:
WHERE Published_Date BETWEEN TIMESTAMP('2019-07-29') AND TIMESTAMP('2019-07-29')
Note that you have a column called "_date", but the error is saying that the value is a timestamp. I find this confusing. We use a convention of using _ts in columns that are timestamps (and _dt for datetime and _date for date).
Why is this important? The timestamp is UTC. So you might need to be careful about timezones and time components -- which is not obvious in a column called Publish_Date.
How can I extract just the hour of a timestamp using standardSQL.
I've tried everything and no function works. The problem is that I have to extract the time from a column and this column is in the following format:2018-07-09T02:40:23.652Z
If I just put the date, it works, but if I put the column it gives the error below:
Syntax error: Expected ")" but got identifier "searchIntention" at [4:32]
Follow the query below:
#standardSQL
select TOTAL, dia, hora FROM
(SELECT cast(replace(replace(searchIntention.createdDate,'T',' '),'Z','')as
DateTime) AS DIA,
FORMAT_DATETIME("%k", DATETIME searchIntention.createdDate) as HORA,
count(searchintention.id) as Total
from `searchs.searchs2016626`
GROUP BY DIA)
Please, help me. :(
How can I extract just the hour of a timestamp using standardSQL?
Below is for BigQuery Standard SQL
You can use EXTRACT(HOUR FROM yourTimeStampColumn)
for example:
SELECT EXTRACT(HOUR FROM CURRENT_TIMESTAMP())
or
SELECT EXTRACT(HOUR FROM TIMESTAMP '2018-07-09T02:40:23.652Z')
or
SELECT EXTRACT(HOUR FROM TIMESTAMP('2018-07-09T02:40:23.652Z'))
In BigQuery Standard SQL, you can use the EXTRACT timestamp function in order to return an INT64 value corresponding to the part of the timestamp that you want to retrieve, like.
The available parts includes a full list that you can check in the documentation page linked, but in your use case you can directly refer to the HOUR operator in order to retrieve the INT64 representation of the hour value in a field of TIMESTAMP type.
#standardSQL
# Create a table
WITH table AS (
SELECT TIMESTAMP("2018-07-09T02:40:23.652Z") time
)
# Extract values from a Timestamp expression
SELECT
EXTRACT(DAY FROM time) as day,
EXTRACT(MONTH FROM time) as month,
EXTRACT(YEAR FROM time) as year,
EXTRACT(HOUR FROM time) AS hour,
EXTRACT(MINUTE FROM time) as minute,
EXTRACT(SECOND from time) as second
FROM
table
How to get the date and time only up to minutes, not seconds, from timestamp in PostgreSQL. I need date as well as time.
For example:
2000-12-16 12:21:13-05
From this I need
2000-12-16 12:21 (no seconds and milliseconds only date and time in hours and minutes)
From a timestamp with time zone field, say update_time, how do I get date as well as time like above using PostgreSQL select query.
Please help me.
There are plenty of date-time functions available with postgresql:
See the list here
http://www.postgresql.org/docs/9.1/static/functions-datetime.html
e.g.
SELECT EXTRACT(DAY FROM TIMESTAMP '2001-02-16 20:38:40');
Result: 16
For formatting you can use these:
http://www.postgresql.org/docs/9.1/static/functions-formatting.html
e.g.
select to_char(current_timestamp, 'YYYY-MM-DD HH24:MI') ...
To get the date from a timestamp (or timestamptz) a simple cast is fastest:
SELECT now()::date
You get the date according to your local time zone either way.
If you want text in a certain format, go with to_char() like #davek provided.
If you want to truncate (round down) the value of a timestamp to a unit of time, use date_trunc():
SELECT date_trunc('minute', now());
This should be enough:
select now()::date, now()::time
, pg_typeof(now()), pg_typeof(now()::date), pg_typeof(now()::time)