I am calling the data query in ssrs like this:
SELECT * FROM [DATABASE].[dbo].[mytable]
So, the current week is the last week from the query (e.g. 3/31 - 4/4) and each number represents the week before until we have reached the 12 weeks prior to this week and display in a point chart.
How can I accomplish grouping all the visits for all locations by weeks and adding it to the chart?
I suggest updating your SQL query to Group by a descending Dense_Rank of DatePart(Week,ARRIVED_DATE). In this example, I have one column for Visits because I couldn't tell which columns you were using to get your Visit count:
-- load some test data
if object_id('tempdb..#MyTable') is not null
drop table #MyTable
create table #MyTable(ARRIVED_DATE datetime,Visits int)
while (select count(*) from #MyTable) < 1000
begin
insert into #MyTable values
(dateadd(day,round(rand()*100,0),'2014-01-01'),round(rand()*1000,0))
end
-- Sum Visits by WeekNumber relative to today's WeekNumber
select
dense_rank() over(order by datepart(week,ARRIVED_DATE) desc) [Week],
sum(Visits) Visits
from #MyTable
where datepart(week,ARRIVED_DATE) >= datepart(week,getdate()) - 11
group by datepart(week,ARRIVED_DATE)
order by datepart(week,ARRIVED_DATE)
Let me know if I can provide any more detail to help you out.
You are going to want to do the grouping of the visits within SQL. You should be able to add a calculated column to your table which is something like WorkWeek and it should be calculated on the days difference from a certain day such as Sunday. This column will then by your X value rather than the date field you were using.
Here is a good article that goes into first day of week: First Day of Week
Related
In a MS Access DB I have information about clients' arrival and departure dates. Based on this I would like to calculate the number of clients that will be visiting per week.
Consider the example below. Peter arrives in the first week of January and leaves on the third week (weeks start on Sunday). Mary on the other hand arrives and leaves in the first week.
I would like the output to be as shown below, with the week number in the first column and the total number of guests in the second.
What is the best way of achieving this please?
My solution with german date format, test with ORACLE. I build some calendar table (tw_test_week) for every week to join it.
CREATE TABLE tw_test_client (
client VARCHAR2(10),
arrival DATE,
departure DATE
);
INSERT INTO tw_test_client VALUES
( 'Peter', to_date('01.01.2018','DD.MM.YYYY'), to_date('11.01.2018','DD.MM.YYYY'));
INSERT INTO tw_test_client VALUES
( 'Mary', to_date('01.01.2018','DD.MM.YYYY'), to_date('01.02.2018','DD.MM.YYYY'));
CREATE TABLE tw_test_week (
weekid INT,
started DATE,
ended DATE
);
INSERT INTO tw_test_week VALUES
( to_char(to_date('01.01.2018','DD.MM.YYYY'),'WW'),
to_date('01.01.2018','DD.MM.YYYY'),
to_date('07.01.2018','DD.MM.YYYY')
);
INSERT INTO tw_test_week VALUES
( to_char(to_date('08.01.2018','DD.MM.YYYY'),'WW'),
to_date('08.01.2018','DD.MM.YYYY'),
to_date('14.01.2018','DD.MM.YYYY')
);
INSERT INTO tw_test_week VALUES
( to_char(to_date('15.01.2018','DD.MM.YYYY'),'WW'),
to_date('15.01.2018','DD.MM.YYYY'),
to_date('21.01.2018','DD.MM.YYYY')
);
INSERT INTO tw_test_week VALUES
( to_char(to_date('22.01.2018','DD.MM.YYYY'),'WW'),
to_date('22.01.2018','DD.MM.YYYY'),
to_date('28.01.2018','DD.MM.YYYY')
);
INSERT INTO tw_test_week VALUES
( to_char(to_date('29.01.2018','DD.MM.YYYY'),'WW'),
to_date('29.01.2018','DD.MM.YYYY'),
to_date('04.02.2018','DD.MM.YYYY')
);
SELECT w.weekid, COUNT(*)
FROM tw_test_week w
JOIN tw_test_client c
ON w.started BETWEEN c.arrival and c.departure
GROUP BY w.weekid
ORDER BY w.weekid;
Result
WEEKID COUNT
1 2
2 2
3 1
4 1
5 1
Create a table containing the numbers 1 to 53. This table in my query is called WeekNumTable and contains a single field with each week number listed.
SELECT WeekNum
, COUNT(WeekNum) AS TotalClients
FROM WeekNumTable INNER JOIN ClientTable ON
WeekNumTable.WeekNum>=DatePart("ww",ClientTable.Arrival-Weekday(ClientTable.Arrival,1)+7) AND
WeekNumTable.WeekNum<=DatePart("ww",ClientTable.Departure-Weekday(ClientTable.Departure,1)+7)
GROUP BY WeekNum
Your example confused me a little as you list week 3 as having 1 client, while the data table doesn't.
Edit: The one problem that I can see with this is that if you do want to look at the next 100 weeks you'll need something to separate the years otherwise week 1 from both years will be lumped together.
You can use a series of queries to obtain this.
First, create a query named Ten:
SELECT DISTINCT Abs([id] Mod 10) AS N
FROM MSysObjects;
Then you can create a query, ClientDays, that lists all your dates between first arrival and latest departure:
SELECT DISTINCT
[Ten_0].[N]+[Ten_1].[N]*10+[Ten_2].[N]*100 AS Id,
DateAdd("d",[Ten_0].[N]+[Ten_1].[N]*10+[Ten_2].[N]*100,[StartDate]) AS [Date]
FROM
Ten AS Ten_0,
Ten AS Ten_1,
Ten AS Ten_2,
(Select
Min([Arrival]) As StartDate,
DateDiff("d", Min([Arrival]), Max([Departure])) As Days
From
ClientDates) AS T
WHERE
((([Ten_0].[N]+[Ten_1].[N]*10+[Ten_2].[N]*100)<=[Days])
AND
((Ten_0.N)<=[Days]\1)
AND
((Ten_1.N)<=[Days]\10)
AND
((Ten_2.N)<=[Days]\100));
Use this in yet a query, ClientWeeks, to find the week numbers:
SELECT
Year([Date]) AS [Year],
DatePart("ww",[Date]) AS Week,
ClientDates.Client
FROM
ClientDays,
ClientDates
WHERE
ClientDays.Date Between [Arrival] And [Departure]
GROUP BY
Year([Date]),
DatePart("ww",[Date]),
ClientDates.Client;
Finally, count the clients:
SELECT
ClientWeeks.Year,
ClientWeeks.Week,
Count(ClientWeeks.Client) AS TotalClients
FROM
ClientWeeks
GROUP BY
ClientWeeks.Year,
ClientWeeks.Week;
Please note, that you will have trouble counting around New Year as you intend to use an inconsistent week numbering method.
The only week number that is unambiguous is the ISO-8601 system of yyyy-ww because the first and/or last week will cross the calendar year boundaries.
Leave a note if you wish to implement this as it cannot be done with native VBA functions; custom functions must be used, but I don't wish to post them here if you will not use them.
In my SSRS report there are 4 parameters StartDate, EndDate, MeterId, & DisplayBy
Start Date: datetime datatype
EndDate : datetime datatype
MeterId : is a drop down list and this will populate based on SQL query
DisplayBy: is a drop down list and this has the following values (Hour,day,Month & year)
The Database that stores hourly values for Meters, the following are the DB table columns: (MeterId,ReadingDate,Hours,Quantity,Price)
When I select the startdate, end date and the meter Id and display i want to show report based on the startdate & enddate and then by display values.
If the display is hour, the we got display all the 24 hour values for the MeterId,Quantity, Price for the date range.
If the display is day, we got display total quantity and total price for the MeterId for that date range.
If the display is Month, we got display total quantity and total price for the MeterId for that date range.
If the display is Year, we got display total quantity and total price for the MeterId for that date range. Say for example If i select start date as 1-1-2016 and end date as 12-31-2016. My result should show 12 rows for each month with their total Quantity, Total price for that particular MeterID.
my DB table stores all the hourly values i know how to show the values on screen if the user selects the display dropdown as hour. But, dont know how to show the result for day/month/year or how to group it. Do I need to use "case" statement and if so what should i need to give on display parameters.
Please suggest your idea...
Row Grouping:
SELECT I.CustomerName, I.ReadingDate, I.IntegratedHour, I.IntegratedUsage, I.IntegratedGeneration, DATEPART(dd, I.ReadingDate) AS [Reading Day], DATEPART(mm,
I.ReadingDate) AS [Reading Month], DATEPART(yyyy, I.ReadingDate) AS [Reading Year]
FROM IntegratedHour_MV90 AS I INNER JOIN
CustRptMeterExtract AS CT ON CT.CustomerName = I.CustomerName
WHERE (I.ReadingDate >= #StartDate) AND (I.ReadingDate <= #EndDate) AND (I.CustomerName IN (#FacilityName))
Expected Result:
SSRS Current Output: Doesnot match
Depending on your layout you could set row grouping to an expression something like this
=SWITCH
(
Parameters!ReportBy.Value=1, Fields!Hour.Value,
Parameters!ReportBy.Value=2, Fields!Day.Value,
Parameters!ReportBy.Value=3, Fields!Month.Value,
Parameters!ReportBy.Value=4, Fields!Year.Value,
True, 0)
This assumes you have already have the hours/days/months/years in your dataset, if not then you would have to replace the field references with expressions to return the relevant month etc.
Based on what I can see above you'll need to add a grouping level for Customer before the group expression. Also, you Quantity expression should be a sum something like this
=SUM(FIelds!IntegratedGeneration.Value)
You may still have a problem though. I'm assuming Price is a unit price, so it does not make sense to sum that too. To get round this, you should calculate the LineValue (Qty * Price) in your dataset then change the price expression to be something like
=(SUM(FIelds!LineValue.Value)/SUM(Fields!IntegratedGeneration.Value))
and this will give you the average price.
However, this may be slow and personally I would do the work in your dataset. Again assuming you have the months, years in your table then you could do something like this.
--DECLARE #ReportBy int = 1 -- uncomment for testing
select
MeterID, Price
, CASE #ReportBy
WHEN 1 THEN [Month]
WHEN 2 THEN [Year]
ELSE NULL
END AS GroupByColumn
INTO #t
from dbo.MyDataTable
SELECT
GroupByColumn
, SUM(Price) as Price
FROM #t
Group BY GroupByColumn
Order by GroupByColumn
This assumes your report parameter is called ReportBy, if not just swap the name out.
How to get a data when the "largest day" of the week does not exist?
For example, if Friday does not exist in my database for a particular week (assuming that Saturday and Sundays are not in my database), I would still like to be able to get the data from Thursday. If Both Friday and Thursday do not exist, I would like to get the data from Wednesday etc.
This is what I currently have (this code allows me to obtain the last day of the month from my database):
/**Select Last Day Of Month**/
SELECT * FROM [mytable]
WHERE [date] IN (SELECT MAX([date])
FROM [mytable]
GROUP BY MONTH([Date]), YEAR([Date]))
I also understand that you can use the DATEPART function to get all datas from a particular day (i.e. Friday), the thing I'm not sure about is how to get a thursday if Friday doesn't exist. I'm looking to grab all the data that has the corresponding features, not one particular week. Thanks!
As a clearer example:
Say I have four input data in my database->
1. 2016/8/19(Fri), red
2. 2016/8/18(Thu), blue
3. 2016/8/11(Thu), red
4. 2016/8/10(Wed), red
after the query is executed, I would like to have:
1. 2016/8/19(Fri), red
3. 2016/8/11(Thu), red
They are selected because the two data are the corresponding "largest" data in that week.
See if the following query helps. It displays the last day of every week in the given input data.
declare #table table(
date datetime
)
insert into #table
values
('08/01/2016'),
('08/02/2016'),
('08/03/2016'),
('08/04/2016'),
('08/05/2016'),
('08/06/2016'),
('08/07/2016'),
('08/08/2016'),
('08/09/2016'),
('08/10/2016'),
('08/11/2016'),
('08/12/2016'),
('08/13/2016'),
('08/14/2016'),
('08/15/2016'),
('08/16/2016'),
('08/17/2016'),
('08/18/2016'),
('08/19/2016'),
('08/20/2016'),
('08/21/2016'),
('08/22/2016'),
('08/23/2016')
;with cte as
(
select date, row_number() over(partition by datepart(year,date),datepart(week,date) order by date desc) as rn from #table
)
select date,datename(weekday,date) from cte
where rn = 1
You can extract various weekparts and construct a suitable ROW_NUMBER() expression.
E.g. the following assigns the row number 1 to the latest day within each week:
ROW_NUMBER() OVER (
PARTITION BY DATEPART(year,[date]),DATEPART(week,[date])
ORDER BY DATEPART(weekday,[date]) DESC) as rn
So I have created a table that has the following columns from a transaction table with all customer purchase records:
1. Month-Year, 2.Customer ID, 3. Number of Transactions in that month.
I'm trying to create a table that has the output of
1. Month-Year, 2. Number of active customers defined by having at least 1 purchase in the previous year.
The code that I have currently is this but the case when obviously only capturing one date and the where clause isn't dynamic. Would really appreciate your help.
select month_start_date, cust_ID,
(case when month_start_Date between date and add_months(date, -12) then count(cust_ID) else 0 end) as active
from myserver.mytable
where
month_start_Date>add_months(month_start_date,-12)
group by 1,2
EDIT: I'm just trying to put a flag next to a customer if they are active in each month defined as having at least one transaction in the last year thanks!
You might use Teradata's proprietary EXPAND ON synax for creating time series:
SELECT month_start_date, COUNT(*)
FROM
( -- create one row for every month within the next year
-- after a customer's transaction
SELECT DISTINCT
BEGIN(pd) AS month_start_date,
cust_ID
FROM myserver.mytable
EXPAND ON PERIOD(month_start_date, ADD_MONTHS(month_start_date,12)) AS pd
BY ANCHOR MONTH_BEGIN -- every 1st of month
FOR PERIOD (DATE - 500, DATE) -- use this to restrict to a specific date range
) AS dt
GROUP BY month_start_date
ORDER BY month_start_date
I have a table that contains a list of community events with columns for the days the event starts and ends. If the end date is 0 then the event occurs only on the start day. I have a query that returns the number of events happening on any given day:
SELECT COUNT(*) FROM p_community e WHERE
(TO_DAYS(e.date_ends)=0 AND DATE(e.date_starts)=DATE('2009-05-13')) OR
(DATE('2009-05-13')>=DATE(e.date_starts) AND DATE('2009-05-13')<=DATE(e.date_ends))
I just sub in any date I want to test for "2009-05-13".
I need to be be able to fetch this data for every day in an entire month. I could just run the query against each day one at a time, but I'd rather run one query that can give me the entire month at once. Does anyone have any suggestions on how I might do that?
And no, I can't use a stored procedure.
Try:
SELECT COUNT(*), DATE(date) FROM table WHERE DATE(dtCreatedAt) >= DATE('2009-03-01') AND DATE(dtCreatedAt) <= DATE('2009-03-10') GROUP BY DATE(date);
This would get the amount for each day in may 2009.
UPDATED: Now works on a range of dates spanning months/years.
Unfortunately, MySQL lacks a way to generate a rowset of given number of rows.
You can create a helper table:
CREATE TABLE t_day (day INT NOT NULL PRIMARY KEY)
INSERT
INTO t_day (day)
VALUES (1),
(2),
…,
(31)
and use it in a JOIN:
SELECT day, COUNT(*)
FROM t_day
JOIN p_community e
ON day BETWEEN DATE(e.start) AND IF(DATE(e.end), DATE(e.end), DATE(e.start))
GROUP BY
day
Or you may use an ugly subquery:
SELECT day, COUNT(*)
FROM (
SELECT 1 AS day
UNION ALL
SELECT 2 AS day
…
UNION ALL
SELECT 31 AS day
) t_day
JOIN p_community e
ON day BETWEEN DATE(e.start) AND IF(DATE(e.end), DATE(e.end), DATE(e.start))
GROUP BY
day