I have a table that can have multiple records for ip_address. However, I want to return rows where canceled=0 if multiple records of ip_address exist, otherwise get the first row where canceled=1
id ip_address username canceled
0 10.10.10.1 john 0
1 10.10.10.1 johnny 1
2 10.10.10.1 quincy 1
3 10.10.10.2 bob 1
4 10.10.10.3 kristin 0
Examples returned resultset for SELECT ip_address,username ....:
10.10.10.1 john
10.10.10.2 bob
10.10.10.3 kristin
Using SQLAlchemy/Sqlite if that is of any relevance.
SELECT
b.id,
a.ip_address,
b.username,
b.canceled
FROM (
select distinct(ip_address) from mytable order by canceled) a,
mytable b
WHERE
b.ip_address=a.ip_address;
But that is returning multiple definitions for "ip_address"
The proper query appears to be:
SELECT b.id,a.ip_address,b.username,b.canceled FROM (select distinct(ip_address) from mytable order by canceled) a, mytable b WHERE b.ip_address=a.ip_address GROUP BY b.ip_address
Assuming canceled is an int,this should work.
select *from #temp order by canceled
with cte as
(
select ip_address,username,canceled,ROW_NUMBER() over(partition by ip_address order by canceled) as rn from #temp
)
select *from cte where rn=1
Related
I've a query in MySQL and I'm looking for a query which can perform below operation using Posgres
MySQL Query :
update APT_ADHOC_DISH_SRC_TABLE_AAMIR_TCH3 a,
(
SELECT #row_number:=CASE WHEN #email=email THEN #row_number+1 ELSE 1 END AS row_number,
#email:=email AS email,id
FROM APT_ADHOC_DISH_SRC_TABLE_AAMIR_TCH3,
(SELECT #row_number:=0,#email:='') AS t
ORDER BY email
) b
set a.r_no=b.row_number where a.id=b.id
Output:
Email
Row Number
Aamir
1
Aamir
2
Aamir
3
Suresh
1
Suresh
2
Hafiz
1
WITH cte AS (
SELECT id, ROW_NUMBER() OVER (PARTITION BY email ORDER BY id) AS row_number
FROM APT_ADHOC_DISH_SRC_TABLE_AAMIR_TCH3
)
UPDATE APT_ADHOC_DISH_SRC_TABLE_AAMIR_TCH3
SET row_number = cte.row_number
FROM cte
WHERE APT_ADHOC_DISH_SRC_TABLE_AAMIR_TCH3.id = cte.id
https://www.db-fiddle.com/f/3RqNHRGFjkU74v33upyfhi/0
I'm using SQL Server Management Studio 2012. I have a similar looking output from a query shown below. I want to eliminate someone from the query who has 2 contracts.
Select
Row_Number() over (partition by ID ORDER BY ContractypeDescription DESC) as [Row_Number],
Name,
ContractDescription,
Role
From table
Output
Row_Number ID Name Contract Description Role
1 1234 Mike FullTime Admin
2 1234 Mike Temp Manager
1 5678 Dave FullTime Admin
1 9785 Liz FullTime Admin
What I would like to see
Row_Number ID Name Contract Description Role
1 5678 Dave FullTime Admin
1 9785 Liz FullTime Admin
Is there a function rather than Row_Number that allows you to group rows together so I can then use something like 'where Row_Number not like 1 and 2'?
You can use HAVING as
SELECT ID,
MAX(Name) Name,
MAX(ContractDescription) ContractDescription,
MAX(Role) Role
FROM t
GROUP BY ID
HAVING COUNT(*) = 1;
Demo
Try this:
select * from (
Select
Count(*) over (partition by ID ) as [Row_Number],
Name,
ContractDescription,
Role
From table
)t where [Row_Number] = 1
You can check this option-
SELECT *
FROM table
WHERE ID IN
(
SELECT ID
FROM table
GROUP BY ID
HAVING COUNT(*) = 1
)
You can use a CTE to get all the ids of people who got only one contract and then just join the result of the CTE with your table.
;with cte as (
select
id
,COUNT(id) as no
from #tbl
group by id
having COUNT(id) = 1
)
select
t.id
,t.name
,t.ContractDescription
,t.role
from #tbl t
inner join cte
on t.id = cte.id
Basically you need those record who have exactly one contract.
Just extend your script, (My script is not tested)
;with CTE as
(
Select
Row_Number() over (partition by ID ORDER BY ContractypeDescription DESC) as [Row_Number],
Name,
ContractDescription,
Role
From table
)
select * from CTE c where [Row_Number]=1
and not exists(select 1 from CTE c1 where c.id=c1.id and c1.[Row_Number]>1 )
Is there a function rather than Row_Number that allows you to group
rows together so I can then use something like 'where Row_Number not
like 1 and 2'?
You can use a windowed COUNT(). The key is the OVER() clause.
;WITH WindowedCount AS
(
SELECT
T.*,
WindowCount = COUNT(1) OVER (PARTITION BY T.ID)
FROM
YourTable AS T
)
DELETE W FROM
WindowedCount AS W
WHERE
W.WindowCount > 1
The COUNT() will count the amount of rows for each different ID, so if the same ID appears in 2 or more rows, those rows will be deleted.
I'm trying to do a query in SQL Server 2008. This is the structure of my table
Recno ClientNo ServiceNo
---------------------------------
1234 17 27
2345 19 34
3456 20 33
4567 17 34
I'm trying to select RecNo however, filtering by distinct ClientNo, so for some clients such as client no 17 - they have more than 1 entry, I'm trying to count that client only once. So basically, looking at this table, I'm only supposed to see 3 RecNo's, since there are only 3 distinct clients. Please help
Select RecNo, Count(ClientNo)
from TblA
where Count(clientNo)<2
Something like this?
EDIT:
The value of RecNo is not relevant, I only need to have an accurate number of records. In this case, I'd like to have 3 records.
oaky you are getting some crazy answers probably becuase your desired result is not clear so I suggest if some of these are not what you need that you clarify your desired result.
If you want the answer 3, I can only assume you want a count of DISTINCT ClientNo's if so it is simply aggregation.
SELECT COUNT(DISTINCT ClientNo) as ClientNoDistinctCount
FROM
TblA
GROUP BY
ClientNo
Ok, this will give you the count that you want:
WITH CTE AS
(
SELECT *,
RN = ROW_NUMBER() OVER(PARTITION BY ClientNo ORDER BY Recno)
FROM TblA
)
SELECT COUNT(DISTINCT Recno) N
FROM CTE
WHERE RN = 1;
Try this..
;with cte1
As(SELECT Recno,clientno
,row_number() over(partition by clientno order by Recno )RNO FROM TblA)
Select Recno,clientno
From cre1 where RNO=1
Choose only ClientNo having the max Recno (or replace < with > to choose the min one).
Select *
from TblA t1
where not exists(select 1
from TblA t2
where t1.ClientNo = t2.ClientNo and t1.Recno < t2.Recno )
BTW, the other solution already mentioned, utilizing row_number() needs no CTE in this case
SELECT TOP(1) WITH TIES *
FROM TblA
ORDER BY ROW_NUMBER() OVER(PARTITION BY ClientNo ORDER BY Recno)
I have a SQL table Customer with the following columns:
Customer_ID, Actioncode
I have another table with 1000+ actioncodes. Now I want to update the records in the Customer table with a unique code from the actioncode table.
I use this select statement at the moment:
update t
set t.actiecode = (select top 1 actiecode from data_mgl_campagnemails_codes)
from data_mgl_campagnemails_transfer t;
The result is that all records are updated with the same actiecode. The top 1 is responsible for that. When I remove that I got an error:
Subquery returned more than 1 value
This seems logical. How can I do this without using a cursor?
There is no relationship between the Customer and Code table.
Table structure:
data_mgl_campagnemails_transfer
id customer_id actioncode actioncode_id
1 1 - -
2 3 - -
3 4 - -
data_mgl_campagnemails_codes
id actioncode active
1 TTTT
2 RRRR
3 VVVV
4 RRRW
The result should be:
data_mgl_campagnemails_transfer
id customer_id actioncode actioncode_id
1 1 TTTT 1
2 3 RRRR 2
3 4 VVVV 3
data_mgl_campagnemails_codes
id actioncode active
1 TTTT YES
2 RRRR YES
3 VVVV YES
4 RRRW
This can be a bit tricky using a single statement, because SQL Server likes to optimize things. So the obvious:
update t
set t.actiecode = (select top 1 actiecode
from data_mgl_campagnemails_codes
order by newid()
)
from data_mgl_campagnemails_transfer t;
Also doesn't work. One method is to enumerate things and use a join or correlated subquery:
with t as (
select t.*, row_number() over (order by newid()) as seqnum
from data_mgl_campagnemails_transfer t
),
a as (
select a.*, row_number() over (order by newid()) as seqnum
from data_mgl_campagnemails_codes a
)
update t
set t.actiecode = (select top 1 actiecode from a)
from t join
a
on t.seqnum = a.seqnum;
Another way is to "trick" SQL Server into running the correlated subquery more than once. I think something like this:
update t
set t.actiecode = (select top 1 actiecode
from data_mgl_campagnemails_codes
where t.CustomerId is not null -- references the outer table but really does nothing
order by newid()
)
from data_mgl_campagnemails_transfer t;
I tried this with solutions avaialble online, but none worked for me.
Table :
Id rank
1 100
1 100
2 75
2 45
3 50
3 50
I want Ids 1 and 3 returned, beacuse they have duplicates.
I tried something like
select * from A where rank in (
select rank from A group by rank having count(rank) > 1
This also returned ids without any duplicates. Please help.
Try this:
select id from table
group by id, rank
having count(*) > 1
select id, rank
from
(
select id, rank, count(*) cnt
from rank_tab
group by id, rank
having count(*) > 1
) t
This general idea should work:
SELECT id
FROM your_table
GROUP BY id
HAVING COUNT(*) > 1 AND COUNT(DISTINCT rank) = 1
In plain English: get every id that exists in multiple rows, but all these rows have the same value in rank.
If you want ids that have some duplicated ranks (but not necessarily all), something like this should work:
SELECT id
FROM your_table
GROUP BY id
HAVING COUNT(*) > COUNT(DISTINCT rank)