There are two tables with the below columns:
table1: asin_details(asin,contact_id) primary key: contact_id
table2: contact_details(contact_date,contact_id,hmd_response(y or n)) primary key: contact_id
I've to find specific percentage from the above data using a formula called no. of n's/no. of y's *100 which is called as "FRR"
So, the actual question is to find the "FRR" of all the asin's with which customers contacted us between 01-jan-2013 and 31-dec-2013
I'm actually struggling with the part where you need to calculate the "FRR" from the date provided above. Please help.
Thanks,
SELECT (( select count(hmd_response) from contact_details where hmd_response= 'n')/( select count(hmd_response) from contact_details where hmd_response= 'y') )*100 as FRR
from asin_details A
join contact_details C
on c.contact_id = A.contact_id
where contact_date between '01-jan-2013' and '31-dec-2013'
OR
SELECT ( ( select count(hmd_response) from contact_details where hmd_response= 'n'
AND between '01-jan-2013' and '31-dec-2013')/
( select count(hmd_response) from contact_details where hmd_response= 'y'
AND between '01-jan-2013' and '31-dec-2013') )*100 as FRR
Try this out and let me know.
I am basically calculating the counts of y's and n's and then i am calculating the FRR.
Should be something like this:
SELECT
a.asin,
((count(case c.hmd_response when 'n' then 1 end) /
count(case c.hmd_response when 'y' then 1 end)) * 100) as FRR,
a.contact_id
from asin_details a
join contact_details c
on a.contact_id = c.contact_id
where c.contact_date between '01-jan-2013' and '31-dec-2013'
Related
I'm trying to run this code for an assignment for a class I've got. The "x" at the end of my subquery keeps on giving me errors and I can't wrap my head around why this is.
The goal of this assignment is to count (by age group) the number of reports that Carditis was a symptom after receiving a COVID shot.
Thanks in advance
Select agegroup, sum(case when died= 'Y' then 1 else 0 end) as Deaths
From (Select *,
Case
when age<=2 then 'infant'
when age<18 then 'juvenile'
when age<35 then 'adult'
when age<65 then 'old adult'
when age>=65 then 'senior'
else 'unknown' end as agegroup
from dbo.symptoms as s
join dbo.vaersvax as v on s.vaers_id=v.vaers_id
join dbo.patient as p on s.vaers_id=p.vaers_id
where v.vax_type='COVID19' and OneVax='Y' and symptom='Carditis'
) as x
Group By agegroup
Order By avg(age)
As #Schmocken already said, you can't perform a SELECT FROM a subquery that returns more than one column with the same name. As I suppose from your external query, this would do the job for you:
Select agegroup, sum(case when died= 'Y' then 1 else 0 end) as Deaths
From (Select died, age,
Case
when age<=2 then 'infant'
when age<18 then 'juvenile'
when age<35 then 'adult'
when age<65 then 'old adult'
when age>=65 then 'senior'
else 'unknown' end as agegroup
from dbo.symptoms as s
join dbo.vaersvax as v on s.vaers_id=v.vaers_id
join dbo.patient as p on s.vaers_id=p.vaers_id
where v.vax_type='COVID19' and OneVax='Y' and symptom='Carditis'
) as x
Group By agegroup
Order By avg(age)
By using Select * you have specified the same column name to be returned more than once.
As an example, you are returning both s.vaers_id and v.vaers_id, which are the same. This is not allowed; a subquery must return a unique set of column names.
You could return s.* successfully, but not all columns from all tables.
I have the following SQL:
WITH G1 AS
(SELECT G.NUM_REFE, G.GUIA AS MASTER,
(SELECT H.GUIA FROM SAAIO_GUIAS H WHERE G.NUM_REFE = H.NUM_REFE AND H.IDE_MH ="H" AND H.CONS_GUIA="1" ) AS HOUSE
FROM SAAIO_GUIAS G WHERE G.IDE_MH ="M" AND G.CONS_GUIA ="1" )
SELECT
*
FROM G1
And it returns the error
"Multiple Rows in Singleton Select".
This is a sample of the database
Any hint will be deeply appreciated
Thanks
Your query wants to retrieve the one matching GUIA, but it seems there can be multiple entries per NUM_REFE for IDE_MH = 'H' AND CONS_GUIA = 1. Check this with
select num_refe
from saaio_guias
where ide_mh = 'H'
and cons_guia = 1
group by num_refe
having count(*) > 1;
This should give no results, but it probably does. And if it does then it cannot work for your query and you must think about which value to pick in this case. Maybe simply the minimum or maximum:
(
select min(h.guia)
from saaio_guias h
...
Or maybe you want to delete rows from the table that you consider duplicates and add a constraint (unique index on num_refe + ide_mh + cons_guia) to prevent from such records in the future.
Your query can be written simpler using conditional aggregation by the way:
select
num_refe,
any_value(case when ide_mh = 'M' then guia end) as master,
any_value(case when ide_mh = 'H' then guia end) as guia
from saaio_guias
where cons_guia = 1
group by num_refe
order by num_refe;
Thie problem is in CTE SELECT Subquery.
I think you can use CASE express instead of SELECT Subquery
WITH G1 AS
(
select
num_refe,
Case when ide_mh = 'M' then GUIA ELSE '' END as MASTER,
Case when ide_mh = 'H' then GUIA ELSE '' END as HOUSE
from saaio_guias
where cons_guia = 1
)
SELECT
*
FROM G1
OR
SELECT G.NUM_REFE, G.GUIA AS MASTER,H.GUIA
FROM SAAIO_GUIAS G
INNER JOIN
(
SELECT *
FROM SAAIO_GUIAS
WHERE IDE_MH ='H' AND CONS_GUIA='1'
) AS H ON G.NUM_REFE = H.NUM_REFE
WHERE G.IDE_MH ='M' AND G.CONS_GUIA ='1'
I don't know what is your expect result.So I guess these two query might help you.
I have a response column that stores 2 different values for a same product based on question 1 and question 2. That creates 2 rows for each product but I want only one row for each product.
Example:
select Product, XNumber from MyTable where QuestionID IN ('Q1','Q2')
result shows:
Product XNumber
Bat abc
Bat abc12
I want it to display like below:
Product Xnumber1 Xnumber2
Bat abc abc12
Please help.
Thanks.
If you always have two different values you can try this:
SELECT a.Product, a.XNumber as XNumber1, b.XNumber as XNumber2
FROM MyTable a
INNER JOIN MyTable b
ON a.Product = b.Product
WHERE a.QuestionId = 'Q1'
AND b.QuestionId = 'Q2'
I assume that XNumber1 is the result for Q1 and Xnumber2 is the result for Q2.
This will work best if you don't have answers for both Q1 and Q2 for all ids
SELECT a.Product, b.XNumber as XNumber1, c.XNumber as XNumber2
FROM (SELECT DISTINCT Product FROM MyTable) a
LEFT JOIN MyTable b ON a.Product = b.Product AND b.QuestionID = 'Q1'
LEFT JOIN MyTable c ON a.Product = c.Product AND c.QuestionID = 'Q2'
This is one way to achieve your expected results. However, it relies on knowing that only xNumber abc and abc12 are the values. If this is not the case, then a dynamic pivot would be likely needed.
SELECT product, max(case when XNumber = 'abc' then xNumber end) as XNumber1,
max(Case when xNumber = 'abc12' then xNumber end) as xNumber2
FROM MyTable
GROUP BY Product
The problem is that SQL needs to know how many columns will be in the result at the time it compiles the SQL. Since the number of columns could be dependent on the data itself (2 rows vs 5 rows) it can't complete the request. Using Dynamic SQL you can find out the number of rows, then pass those values in as the column names which is why the dynamic SQL works.
This will get you two columns, the first will be the product, and the 2nd will be a comma delimited list of xNumbers.
SELECT DISTINCT T.Product,
xNumbers = Stuff((SELECT DISTINCT ', ' + T1.XNumber
FROM MyTable T1
WHERE t.Product = T1.Product
FOR XML PATH ('')),1,1,'')
FROM MyTable T
To get what you want, we need to know how many columns there will be, what to name them, and how to determine which value goes into which column
Been using rank() a lot in current code we have been working on at my day job. So this fun variant came to mind for your solution.
Using rank to get the 1st, 2nd, and 3rd possible item identifier then grouping them to create a simulated pivot
DECLARE #T TABLE (PRODUCT VARCHAR(50), XNumber VARCHAR(50))
INSERT INTO #T VALUES
('Bat','0-12345-98765-6'),
('Bat','0-12345-98767-2'),
('Bat','0-12345-98768-1'),
('Ball','0-12345-98771-6'),
('Ball','0-12345-98772-7'),
('Ball','0-12345-98777-9'),
('Hat','0-12345-98711-6'),
('Hat','0-12345-98712-3'),
('Tee','0-12345-98465-1')
SELECT
PRODUCT,
MAX(CASE WHEN I = 1 THEN XNumber ELSE '' END) AS Xnumber1,
MAX(CASE WHEN I = 2 THEN XNumber ELSE '' END) AS Xnumber2,
MAX(CASE WHEN I = 3 THEN XNumber ELSE '' END) AS Xnumber3
FROM
(
SELECT
PRODUCT,
XNumber,
RANK() OVER(PARTITION BY PRODUCT ORDER BY XNumber) AS I
FROM #T
) AS DATA
GROUP BY
PRODUCT
I have table which list a number of cases and assigned primary and secondary technicians. What I am trying to accomplish is to aggregate the number of cases a technician has worked as a primary and secondary tech. Should look something like this...
Technician Primary Secondary
John 4 3
Stacy 3 1
Michael 5 3
The table that I am pulling that data from looks like this:
CaseID, PrimaryTech, SecondaryTech, DOS
In the past I have used something like this, but now my superiors are asking for the number of secondary cases as well...
SELECT PrimaryTech, COUNT(CaseID) as Total
GROUP BY PrimaryTech
I've done a bit of searching, but cant seem to find the answer to my problem.
Select Tech,
sum(case when IsPrimary = 1 then 1 else 0 end) as PrimaryCount,
sum(case when IsPrimary = 0 then 1 else 0 end) as SecondaryCount
from
(
SELECT SecondaryTech as Tech, 0 as IsPrimary
FROM your_table
union all
SELECT PrimaryTech as Tech, 1 as IsPrimary
FROM your_table
) x
GROUP BY Tech
You can group two subqueries together with a FULL JOIN as demonstrated in this SQLFiddle.
SELECT Technician = COALESCE(pri.Technician, sec.Technician)
, PrimaryTech
, SecondaryTech
FROM
(SELECT Technician = PrimaryTech
, PrimaryTech = COUNT(*)
FROM Cases
WHERE PrimaryTech IS NOT NULL
GROUP BY PrimaryTech) pri
FULL JOIN
(SELECT Technician = SecondaryTech
, SecondaryTech = COUNT(*)
FROM Cases
WHERE SecondaryTech IS NOT NULL
GROUP BY SecondaryTech) sec
ON pri.Technician = sec.Technician
ORDER By Technician;
SELECT COALESCE(A.NAME, B.NAME) AS NAME, CASE WHEN A.CASES IS NOT NULL THEN A.CASES ELSE 0 END AS PRIMARY_CASES,
CASE WHEN B.CASES IS NOT NULL THEN B.CASES ELSE 0 END AS SECONDARY_CASES
FROM
(
SELECT COUNT(*) AS CASES, PRIMARYTECH AS NAME FROM YOUR_TABLE
GROUP BY PRIMARYTECH
) AS A
FULL OUTER JOIN
(
SELECT COUNT(*) AS CASES, SECONDARYTECH AS NAME FROM YOUR_TABLE
GROUP BY SECONDARYTECH
) AS B
ON A.NAME = B.NAME
so basicially there is 1 question and 1 problem:
1. question - when I have like 100 columns in a table(and no key or uindex is set) and I want to join or subselect that table with itself, do I really have to write out every column name?
2. problem - the example below shows the 1. question and my actual SQL-statement problem
Example:
A.FIELD1,
(SELECT CASE WHEN B.FIELD2 = 1 THEN B.FIELD3 ELSE null FROM TABLE B WHERE A.* = B.*) AS CASEFIELD1
(SELECT CASE WHEN B.FIELD2 = 2 THEN B.FIELD4 ELSE null FROM TABLE B WHERE A.* = B.*) AS CASEFIELD2
FROM TABLE A
GROUP BY A.FIELD1
The story is: if I don't put the CASE into its own select statement then I have to put the actual rowname into the GROUP BY and the GROUP BY doesn't group the NULL-value from the CASE but the actual value from the row. And because of that I would have to either join or subselect with all columns, since there is no key and no uindex, or somehow find another solution.
DBServer is DB2.
So now to describing it just with words and no SQL:
I have "order items" which can be divided into "ZD" and "EK" (1 = ZD, 2 = EK) and can be grouped by "distributor". Even though "order items" can have one of two different "departements"(ZD, EK), the fields/rows for "ZD" and "EK" are always both filled. I need the grouping to consider the "departement" and only if the designated "departement" (ZD or EK) is changing, then I want a new group to be created.
SELECT
(CASE WHEN TABLE.DEPARTEMENT = 1 THEN TABLE.ZD ELSE null END) AS ZD,
(CASE WHEN TABLE.DEPARTEMENT = 2 THEN TABLE.EK ELSE null END) AS EK,
TABLE.DISTRIBUTOR,
sum(TABLE.SOMETHING) AS SOMETHING,
FROM TABLE
GROUP BY
ZD
EK
TABLE.DISTRIBUTOR
TABLE.DEPARTEMENT
This here worked in the SELECT and ZD, EK in the GROUP BY. Only problem was, even if EK was not the designated DEPARTEMENT, it still opened a new group if it changed, because he was using the real EK value and not the NULL from the CASE, as I was already explaining up top.
And here ladies and gentleman is the solution to the problem:
SELECT
(CASE WHEN TABLE.DEPARTEMENT = 1 THEN TABLE.ZD ELSE null END) AS ZD,
(CASE WHEN TABLE.DEPARTEMENT = 2 THEN TABLE.EK ELSE null END) AS EK,
TABLE.DISTRIBUTOR,
sum(TABLE.SOMETHING) AS SOMETHING,
FROM TABLE
GROUP BY
(CASE WHEN TABLE.DEPARTEMENT = 1 THEN TABLE.ZD ELSE null END),
(CASE WHEN TABLE.DEPARTEMENT = 2 THEN TABLE.EK ELSE null END),
TABLE.DISTRIBUTOR,
TABLE.DEPARTEMENT
#t-clausen.dk: Thank you!
#others: ...
Actually there is a wildcard equality test.
I am not sure why you would group by field1, that would seem impossible in your example. I tried to fit it into your question:
SELECT FIELD1,
CASE WHEN FIELD2 = 1 THEN FIELD3 END AS CASEFIELD1,
CASE WHEN FIELD2 = 2 THEN FIELD4 END AS CASEFIELD2
FROM
(
SELECT * FROM A
INTERSECT
SELECT * FROM B
) C
UNION -- results in a distinct
SELECT
A.FIELD1,
null,
null
FROM
(
SELECT * FROM A
EXCEPT
SELECT * FROM B
) C
This will fail for datatypes that are not comparable
No, there's no wildcard equality test. You'd have to list every field you want tested individually. If you don't want to test each individual field, you could use a hack such as concatenating all the fields, e.g.
WHERE (a.foo + a.bar + a.baz) = (b.foo + b.bar + b.az)
but either way, you're listing all of the fields.
I might tend to solve it something like this
WITH q as
(SELECT
Department
, (CASE WHEN DEPARTEMENT = 1 THEN ZD
WHEN DEPARTEMENT = 2 THEN EK
ELSE null
END) AS GRP
, DISTRIBUTOR
, SOMETHING
FROM mytable
)
SELECT
Department
, Grp
, Distributor
, sum(SOMETHING) AS SumTHING
FROM q
GROUP BY
DEPARTEMENT
, GRP
, DISTRIBUTOR
If you need to find all rows in TableA that match in TableB, how about INTERSECT or INTERSECT DISTINCT?
select * from A
INTERSECT DISTINCT
select * from B
However, if you only want rows from A where the entire row matches the values in a row from B, then why does your sample code take some values from A and others from B? If the row matches on all columns, then that would seem pointless. (Perhaps your question could be explained a bit more fully?)