i want get query from 2 table but show all column overhand
first all column from table 1 Second all column from table 2 then show overhand
table1
----------
a 1 2 3
table2
----------
b 4 5 6
query Result
----------
a 1 2 3
b 4 5 6
Grateful
do you mean:
Select * from table1
Union
Select * from table2
if you want all data no matter they are repetitive or not use UNION ALL otherwise if you want to have unique result use UNION
for example if you had 1 2 3 in table2 the result with UNION will be
1 2 3
and result with UNION ALL will be
1 2 3
1 2 3
Try using UNION in your query:
select * from table1
union all
select * from table2
Related
How to update rows with a given repeating number sequence.
my table is as follows
line_type
line_val
line_pattern
A
1
null
A
2
null
B
5
null
B
6
null
C
3
null
C
4
null
Now I want to update the column value with the repeating pattern of 8532
So the table after the update will look like
line_type
line_val
line_pattern
A
1
8
A
2
5
B
5
3
B
6
2
C
3
8
C
4
5
How can I achieve this in a update statement ?
With the data you have provided it is not possible to satisfy your requirement. The data in a table is not stored in a specific order. If you want the order to be guaranteed in a select statement, you need to provide an ORDER BY clause.
In the code below there is an additional column "ORDER_BY" to specify the order in which the records need to be processed. The repeating pattern is calculated using the MOD function to convert the row number to a repeating sequence of 4 numbers and then CASE maps each of those numbers to its respective pattern location.
WITH test_data (order_by, line_type, line_val)
AS
(
SELECT 1, 'A',1 FROM DUAL UNION ALL
SELECT 2, 'A',2 FROM DUAL UNION ALL
SELECT 3, 'B',5 FROM DUAL UNION ALL
SELECT 4, 'B',6 FROM DUAL UNION ALL
SELECT 5, 'C',3 FROM DUAL UNION ALL
SELECT 6, 'C',4 FROM DUAL
)
SELECT
CASE MOD(ROW_NUMBER() OVER (ORDER BY order_by),4)
WHEN 1 THEN 8
WHEN 2 THEN 5
WHEN 3 THEN 3
WHEN 0 THEN 2
END as line_pattern,
t.*
FROM
test_data t
LINE_PATTERN ORDER_BY L LINE_VAL
------------ ---------- - ----------
8 1 A 1
5 2 A 2
3 3 B 5
2 4 B 6
8 5 C 3
5 6 C 4
If you don't care about the order then use this form:
UPDATE mytable
SET line_pattern =
CASE MOD (ROWNUM, 4)
WHEN 1 THEN 8
WHEN 2 THEN 5
WHEN 3 THEN 3
WHEN 0 THEN 2
END
I have tables in Oracle SQL like below:
Tab1
ID
-----
1
2
3
Tab2
ID
-----
3
4
5
And I need to take values from Tab1 which are not in Tab2. I made query like below:
select ID
from Tab1
where ID not in (select ID from Tab2)
Above query does not work, how can I change it to achieve result as I need:
ID
---
1
2
I can add that I prefere to use subquery in this problem, how can I do that in Oracle SQL ?
With the MINUS set operator:
SQL> with
2 tab1 (id) as
3 (select 1 from dual union all
4 select 2 from dual union all
5 select 3 from dual
6 ),
7 tab2 (id) as
8 (select 3 from dual union all
9 select 4 from dual union all
10 select 5 from dual
11 )
12 select id from tab1
13 minus
14 select id from tab2;
ID
----------
1
2
SQL>
BTW, query you used (with a subquery) returns correct result; did you mean to say that you prefer NOT to use a subquery?
<snip>
12 select id from tab1
13 where id not in (select id from tab2);
ID
----------
1
2
I tried this code and it worked fine :
select ID
from Table1
where ID not in (select ID from Table2)
You cant DROP rows from a table, but you can DELETE them.
So correcting you title to
How to use subquery to DELETE rows from Tab1 which are in Tab2 in Oracle SQL?
do so:
delete from tab1
where id in (select id from tab2);
1 row deleted.
select * from tab1;
ID
----------
1
2
Do not forget to commit to make the change permanent.
If I have two columns:
col1 col2 amount
1 2 15
2 3 12
1 3 10
3 1 4
3 2 3
And I perform a group by col1,col2 then I get a row for each combination (present) in the data.
My problem though is, that I dont always have all combinations, but I would want to return a row of each combination still. So if there isn't a combination. for example 2 -> 1 then I would want its value to be 0.
Can I somehow specify the "levels" of the group by?
I'm using SQL Oracle.
and the outcome I would want is:
1 -> 2 15
1 -> 3 10
2 -> 1 0
2 -> 3 12
3 -> 1 4
3 -> 2 3
With their respective amount, and 0 if they dont exist, or null works. ( I have a filter to exclude where col1 and col2 are same)
Generate all the rows using cross join and then filter for the ones you want:
select c1.col1, c2.col2, coalesce(t.amount, 0)
from (select 1 as co1l from dual union all
select 2 as co1l from dual union all
select 3 as co1l from dual
) c1 cross join
(select 1 as co12 from dual union all
select 2 as co12 from dual union all
select 3 as co12 from dual
) c2 left join
t
on t.col1 = c1.col1 and t.col2 = c2.col2
where c1.col1 <> c2.col2;
I have two tables A and B.
Table A Column contains values from 1 to 9 . and Table B Contains values 2,6,7.
Now my requirement is to get UNION of A and B and count of duplicate records. I'm using SqlServer.
My result should be like this
ResultColumn Count
1 1
2 2
3 1
4 1
5 1
6 2
7 2
8 1
9 1
EDIT: Use UNION ALL to account duplicates.
SELECT
[Column],
COUNT(*) AS [Count]
FROM(
SELECT [Column] FROM TableA
UNION ALL
SELECT [Column] FROM TableB
)t
GROUP BY [Column]
I want to fetch the records in order passed for IN condition.
select * from table where id in(6,3,7,1);
is returning the rows as
id name
1 abc
3 xy
6 ab
7 ac
but I want to display the records in same orders as ids passed in condition in Oracle
id name
6 ab
3 xy
7 ac
1 abc
Please help me in fetching the records in same order as in condition ids in oracle. The values in IN condition may change dynamically.
You can do this with a case statement in the order by clause or using a join.
select *
from table
where id in(6,3,7,1)
order by (case id when 6 then 1 when 3 then 2 when 7 then 3 when 1 then 4 end);
Or:
with ids as (
select 6 as id, 1 as ordering from dual union all
select 3 as id, 2 as ordering from dual union all
select 7 as id, 3 as ordering from dual union all
select 1 as id, 4 as ordering from dual
)
select *
from table t join
ids
on t.ids = ids.id
order by ids.ordering;
Note that you don't need the in in this case, because the join does the filtering.
you can use trick
select * from table where id in(6,3,7,1) order by case when id = 6 then 1
id = 3 then 2
id = 7 then 3
id = 1 then 4
end