Is it possible this query:
select *
from table t
where (t.key1, t.key2, t.key3) IN ('a','b','c','d')
Condition with several columns and several values.
You have to split it in multiple statements. I didn't know whether you want to OR or AND, so I took AND in this samples:
select *
from table t
where (t.key1) IN ('a','b','c','d')
and (t.key2) IN ('a','b','c','d')
and (t.key3) IN ('a','b','c','d')
Or use a join and inline view:
select *
from table t
join ( select 'a' col
from dual
union
select 'b'
from dual
union
select 'c'
from dual
union
select 'd'
from dual
) x
on t.key1 = x.col
and t.key2 = x.col
and t.key3 = x.col
select *
from table t
where t.key1 IN ('a','b','c','d') OR
t.key2 IN ('a','b','c','d') OR
t.key3 IN ('a','b','c','d')
Related
I have a string column in Biquery like:
select 'A'
union all (select 'ab')
union all (select 'abc')
union all (select 'aa')
union all (select 'aab')
I would like to count the number of distinct characters in every row of the column, in this case the results would be:
1
2
3
1
2
Can this be done in BigQuery? How?
How about this (assuming you don't want to differentiate between uppercase and lowercase)...
WITH data AS (select 'A' AS `val`
union all (select 'ab')
union all (select 'abc')
union all (select 'aa')
union all (select 'aab'))
SELECT `val`, 26 - LENGTH(REGEXP_REPLACE('abcdefghijklmnopqrstuvwxyz', '['||LOWER(`val`)||']', ''))
FROM `data`;
A simple approach is to use the SPLIT to convert your string to an array and UNNEST to convert the resulting array to a table. You may then use COUNT and DISTINCT to determine the number of unique characters as shown below:
with my_data AS (
select 'A' as col
union all (select 'ab')
union all (select 'abc')
union all (select 'aa')
union all (select 'aab')
)
select col, (SELECT COUNT(*) FROM (
SELECT DISTINCT element FROM UNNEST(SPLIT(col,'')) as element
)) n from my_data;
or simply
WITH my_data AS (
SELECT 'A' as col UNION ALL
SELECT 'ab' UNION ALL
SELECT 'abc' UNION ALL
SELECT 'aa' UNION ALL
SELECT 'aab'
)
SELECT
col,
(
SELECT
COUNT(DISTINCT element)
FROM
UNNEST(SPLIT(col,'')) as element
) cnt
FROM
my_data;
Like previous but using COUNT with DISTINCT
with my_data AS (
select 'A' as col
union all (select 'ab')
union all (select 'abc')
union all (select 'aa')
union all (select 'aab')
)
select col, COUNT(DISTINCT element) FROM
my_data,UNNEST(SPLIT(col,'')) as element
GROUP BY col
If the data is not quite huge, I would rather go with the user-defined functions to ease up the string manipulation across different columns
CREATE TEMP FUNCTION
get_unique_char_count(x STRING)
RETURNS INT64
LANGUAGE js AS r"""
str_split = new Set(x.split(""));
return str_split.size;
""";
WITH
result AS (
SELECT
'A' AS val
UNION ALL (
SELECT
'ab')
UNION ALL (
SELECT
'abc')
UNION ALL (
SELECT
'aa')
UNION ALL (
SELECT
'aab') )
SELECT
val,
get_unique_char_count(val) unique_char_count
FROM
result
RESULT:
I need to add the third column to the first column (my desire is that the first column will include also the third column)
Current status:
Desired Results:
You want UNION ALL :
SELECT t.entity, t.activity
FROM table t
UNION ALL
SELECT t.entity2, t.activity2
FROM table t;
If you have a lot of data, you may not want to scan the table multiple times -- which is what union all does.
Instead:
select (case when n.n = 1 then entity
when n.n = 2 then entity_2
end) as entity,
(case when n.n = 1 then activity
when n.n = 2 then activity_2
end) as activity
from t cross join
(select 1 as n from dual union all
select 2 as n from dual
) n;
In Oracle 12C+, this is simplified using lateral joins:
select t.entity, s.activity
from t cross join lateral
(select t.entity, t.activity from dual union all
select t.entity_2, t.activity_2 from dual
) s;
select entity, activity from <table>
union all
select entity_2, activity_2 from <table>
in general:
select col1,col2 from table1
union all
select col3,col4 form table1;
As the title says, I'm trying to add an extra column to a table which autoincrements everytime a different string in another column changes.
I would like to do this in a query.
Example:
MyCol GroupID
Cable 1
Cable 1
Foo 2
Foo 2
Foo 2
Fuzz 3
Fizz 4
Tv 5
Tv 5
The GroupID column is what I want to accomplish.
We can be sure that MyCol's strings will be the same in each subgroup (Foo will always be Foo, etc).
Thanks in advance
If I understand correctly, you can use dense_rank():
select t.*, dense_rank() over (order by col1) as groupid
from t;
You could make a temporal table with the distinct value of the MyCol and get the groupId throught the RowNumber of the temp table, and join the rownumbered result with your table.
This is a raw example in oracle:
WITH data AS
(SELECT 'Cable' MyCol FROM dual
UNION ALL
SELECT 'Cable' FROM dual
UNION ALL
SELECT 'Foo' FROM dual
UNION ALL
SELECT 'Foo' FROM dual
UNION ALL
SELECT 'Foo' FROM dual
UNION ALL
SELECT 'Fuzz' FROM dual
UNION ALL
SELECT 'Fizz' FROM dual
UNION ALL
SELECT 'Tv' FROM dual
UNION ALL
SELECT 'Tv' FROM dual
),
tablename AS
(SELECT * FROM data
),
temp AS
( SELECT DISTINCT mycol FROM tablename
),
temp2 AS
( SELECT mycol, rownum AS groupid from temp
)
SELECT tablename.mycol, temp2.groupid FROM temp2 JOIN tablename ON temp2.mycol = tablename.mycol
You could also check for a way to implement the tabibitosan method knowing that your column condition is string.
I'm currently working with my report parameter list of value that is dependent in another parameter.
I have come up with this idea, is there any possible way to for this to work?
WITH A AS (
SELECT DISTINCT columnA1 FROM Table1
UNION SELECT DISTINCT columnA2 FROM Table1
UNION SELECT DISTINCT columnA3 FROM Table1)
WITH B AS (SELECT DISTINCT columnB1 FROM Table1
UNION SELECT DISTINCT columnB2 FROM Table1
UNION SELECT DISTINCT columnB3 FROM Table1)
Select * from CASE WHEN (:PM_Parameter1 = 'A')
THEN A
ELSE B
END;
Assuming this is Oracle SQL, you can use a the EXISTS function to check for the parameter value, then combine the sets using UNION.
Try playing with this SQL:
select * from
(
select 'A' from dual
union
select 'B' from dual
)
where exists
(SELECT 'Y'
FROM dual
where 'parameter' = 'parameter'
)
union
select * from
(
select 'X' from dual
union
select 'Y' from dual
)
where exists
(SELECT 'Y'
FROM dual
where 'parameter' != 'parameter'
)
If you reverse both the conditions 'parameter' = 'parameter' and 'parameter' != 'parameter', it will return two different row sets.
I am sure this can be optimized again, hope it works out for you.
I have a quick question about a select statement condition.
I have the following table with the following items. What I need to get is the object id that matches both type id's.
TypeId ObjectId
1 10
2 10
1 11
So I need to get both object 10 because it matches type id 1 and 2.
SELECT ObjectId
FROM Table
WHERE TypeId = 1
AND TypeId = 2
Obviously this doesn't work because it won't match both conditions for the same row. How do I perform this query?
Also note that I may pass in 2 or more type id's to narrow down the results.
Self-join:
SELECT t1.ObjectId
FROM Table AS t1
INNER JOIN Table AS t2
ON t1.ObjectId = t2.ObjectId
AND t1.TypeId = 1
AND t2.TypeId = 2
Note sure how you want the behavior to work when passing in values, but that's a start.
I upvoted the answer from #Cade Roux, and that's how I would do it.
But FWIW, here's an alternative solution:
SELECT ObjectId
FROM Table
WHERE TypeId IN (1, 2)
GROUP BY ObjectId
HAVING COUNT(*) = 2;
Assuming uniqueness over TypeId, ObjectId.
Re the comment from #Josh that he may need to search for three or more TypeId values:
The solution using JOIN requires a join per value you're searching for. The solution above using GROUP BY may be easier if you find yourself searching for an increasing number of values.
This code is written with Oracle in mind. It should be general enough for other flavors of SQL
select t1.ObjectId from Table t1
join Table t2 on t2.TypeId = 2 and t1.ObjectId = t2.ObjectId
where t1.TypeId = 1;
To add additional TypeIds, you just have to add another join:
select t1.ObjectId from Table t1
join Table t2 on t2.TypeId = 2 and t1.ObjectId = t2.ObjectId
join Table t3 on t3.TypeId = 3 and t1.ObjectId = t3.ObjectId
join Table t4 on t4.TypeId = 4 and t1.ObjectId = t4.ObjectId
where t1.TypeId = 1;
Important note: as you add more joins, performance will suffer a LOT.
In regards to Bill's answer you can change it to the following to get rid of the need to assume uniqueness:
SELECT ObjectId
FROM (SELECT distinct ObjectId, TypeId from Table)
WHERE TypeId IN (1, 2)
GROUP BY ObjectId
HAVING COUNT(*) = 2;
His way of doing it scales better as the number of types gets larger.
Try this
Sample Input:(Case 1)
declare #t table(Typeid int,ObjectId int)
insert into #t
select 1,10 union all select 2,10 union all
select 1,11
select * from #t
Sample Input:(Case 2)
declare #t table(Typeid int,ObjectId int)
insert into #t
select 1,10 union all select 2,10 union all
select 3,10 union all select 4,10 union all
select 5,10 union all select 6,10 union all
select 1,11 union all select 2,11 union all
select 3,11 union all select 4,11 union all
select 5,11 union all select 1,12 union all
select 2,12 union all select 3,12 union all
select 4,12 union all select 5,12 union all
select 6,12
select * from #t
Sample Input:(Case 3)[Duplicate entries are there]
declare #t table(Typeid int,ObjectId int)
insert into #t
select 1,10 union all select 2,10 union all
select 1,10 union all select 2,10 union all
select 3,10 union all select 4,10 union all
select 5,10 union all select 6,10 union all
select 1,11 union all select 2,11 union all
select 3,11 union all select 4,11 union all
select 5,11 union all select 1,12 union all
select 2,12 union all select 3,12 union all
select 4,12 union all select 5,12 union all
select 6,12 union all select 3,12
For case 1, the output should be 10
For case 2 & 3, the output should be 10 and 12
Query:
select X.ObjectId from
(
select
T.ObjectId
,count(ObjectId) cnt
from(select distinct ObjectId,Typeid from #t)T
where T.Typeid in(select Typeid from #t)
group by T.ObjectId )X
join (select max(Typeid) maxcnt from #t)Y
on X.cnt = Y.maxcnt